Pivot Rows to Column By Group in SQL Server
I am looking for a code which can transpose row to column using the group by in the SQL Server 2008.
This is my table :
Name | Stdy | Val
-------+---------+-------
Kunjan | Technic | 80
Kunjan | Sains | 90
Kunjan | Sport | 60
Shone | Technic | 60
Shone | Sains | 80
Shone | Sport | 70
Peudd | Technic | 85
Peudd | Sains | 75
Peudd | Sport | 90
What I want to eventually display is something like this (for the data above):
Stdy | Kunjan | Shone | Peudd
--------+--------+-------+-------
Technic | 80 | 60 | 85
Sains | 90 | 80 | 75
Sport | 60 | 70 | 90
Any help would be appreciated.
Thanks in advance.
sql-server sql-server-2008 pivot
add a comment |
I am looking for a code which can transpose row to column using the group by in the SQL Server 2008.
This is my table :
Name | Stdy | Val
-------+---------+-------
Kunjan | Technic | 80
Kunjan | Sains | 90
Kunjan | Sport | 60
Shone | Technic | 60
Shone | Sains | 80
Shone | Sport | 70
Peudd | Technic | 85
Peudd | Sains | 75
Peudd | Sport | 90
What I want to eventually display is something like this (for the data above):
Stdy | Kunjan | Shone | Peudd
--------+--------+-------+-------
Technic | 80 | 60 | 85
Sains | 90 | 80 | 75
Sport | 60 | 70 | 90
Any help would be appreciated.
Thanks in advance.
sql-server sql-server-2008 pivot
mssqltips.com/sqlservertip/2783/…
– Aaron Bertrand
Nov 15 '18 at 2:35
add a comment |
I am looking for a code which can transpose row to column using the group by in the SQL Server 2008.
This is my table :
Name | Stdy | Val
-------+---------+-------
Kunjan | Technic | 80
Kunjan | Sains | 90
Kunjan | Sport | 60
Shone | Technic | 60
Shone | Sains | 80
Shone | Sport | 70
Peudd | Technic | 85
Peudd | Sains | 75
Peudd | Sport | 90
What I want to eventually display is something like this (for the data above):
Stdy | Kunjan | Shone | Peudd
--------+--------+-------+-------
Technic | 80 | 60 | 85
Sains | 90 | 80 | 75
Sport | 60 | 70 | 90
Any help would be appreciated.
Thanks in advance.
sql-server sql-server-2008 pivot
I am looking for a code which can transpose row to column using the group by in the SQL Server 2008.
This is my table :
Name | Stdy | Val
-------+---------+-------
Kunjan | Technic | 80
Kunjan | Sains | 90
Kunjan | Sport | 60
Shone | Technic | 60
Shone | Sains | 80
Shone | Sport | 70
Peudd | Technic | 85
Peudd | Sains | 75
Peudd | Sport | 90
What I want to eventually display is something like this (for the data above):
Stdy | Kunjan | Shone | Peudd
--------+--------+-------+-------
Technic | 80 | 60 | 85
Sains | 90 | 80 | 75
Sport | 60 | 70 | 90
Any help would be appreciated.
Thanks in advance.
sql-server sql-server-2008 pivot
sql-server sql-server-2008 pivot
edited Nov 15 '18 at 5:18
marc_s
583k13011241270
583k13011241270
asked Nov 15 '18 at 1:10
dayatdayat
104
104
mssqltips.com/sqlservertip/2783/…
– Aaron Bertrand
Nov 15 '18 at 2:35
add a comment |
mssqltips.com/sqlservertip/2783/…
– Aaron Bertrand
Nov 15 '18 at 2:35
mssqltips.com/sqlservertip/2783/…
– Aaron Bertrand
Nov 15 '18 at 2:35
mssqltips.com/sqlservertip/2783/…
– Aaron Bertrand
Nov 15 '18 at 2:35
add a comment |
1 Answer
1
active
oldest
votes
this can be done using PIVOT
operator
select *
from yourtable
pivot
(
max(Val)
for Name in ([Kunjan], [Shone], [Peudd])
) p
or conditional CASE
statement. There are lots of example, just do a search on it
EDIT : for dynamic case
declare @sql nvarchar(max),
@col nvarchar(max)
select @col = isnull(@col + ',', '') + Name
from yourtable
group by Name
print @col
select @sql =
'
select *
from youtable
pivot
(
max(Val)
for Name in (' + @col + ')
) p
'
print @sql
exec sp_executesql @sql
but then how do I make the name flexible, because the Count of names or the name is not always the same
– dayat
Nov 15 '18 at 1:49
1
then you will requiredDynamic SQL
. Give me few mins, I will update my answer
– Squirrel
Nov 15 '18 at 1:55
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53311054%2fpivot-rows-to-column-by-group-in-sql-server%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
this can be done using PIVOT
operator
select *
from yourtable
pivot
(
max(Val)
for Name in ([Kunjan], [Shone], [Peudd])
) p
or conditional CASE
statement. There are lots of example, just do a search on it
EDIT : for dynamic case
declare @sql nvarchar(max),
@col nvarchar(max)
select @col = isnull(@col + ',', '') + Name
from yourtable
group by Name
print @col
select @sql =
'
select *
from youtable
pivot
(
max(Val)
for Name in (' + @col + ')
) p
'
print @sql
exec sp_executesql @sql
but then how do I make the name flexible, because the Count of names or the name is not always the same
– dayat
Nov 15 '18 at 1:49
1
then you will requiredDynamic SQL
. Give me few mins, I will update my answer
– Squirrel
Nov 15 '18 at 1:55
add a comment |
this can be done using PIVOT
operator
select *
from yourtable
pivot
(
max(Val)
for Name in ([Kunjan], [Shone], [Peudd])
) p
or conditional CASE
statement. There are lots of example, just do a search on it
EDIT : for dynamic case
declare @sql nvarchar(max),
@col nvarchar(max)
select @col = isnull(@col + ',', '') + Name
from yourtable
group by Name
print @col
select @sql =
'
select *
from youtable
pivot
(
max(Val)
for Name in (' + @col + ')
) p
'
print @sql
exec sp_executesql @sql
but then how do I make the name flexible, because the Count of names or the name is not always the same
– dayat
Nov 15 '18 at 1:49
1
then you will requiredDynamic SQL
. Give me few mins, I will update my answer
– Squirrel
Nov 15 '18 at 1:55
add a comment |
this can be done using PIVOT
operator
select *
from yourtable
pivot
(
max(Val)
for Name in ([Kunjan], [Shone], [Peudd])
) p
or conditional CASE
statement. There are lots of example, just do a search on it
EDIT : for dynamic case
declare @sql nvarchar(max),
@col nvarchar(max)
select @col = isnull(@col + ',', '') + Name
from yourtable
group by Name
print @col
select @sql =
'
select *
from youtable
pivot
(
max(Val)
for Name in (' + @col + ')
) p
'
print @sql
exec sp_executesql @sql
this can be done using PIVOT
operator
select *
from yourtable
pivot
(
max(Val)
for Name in ([Kunjan], [Shone], [Peudd])
) p
or conditional CASE
statement. There are lots of example, just do a search on it
EDIT : for dynamic case
declare @sql nvarchar(max),
@col nvarchar(max)
select @col = isnull(@col + ',', '') + Name
from yourtable
group by Name
print @col
select @sql =
'
select *
from youtable
pivot
(
max(Val)
for Name in (' + @col + ')
) p
'
print @sql
exec sp_executesql @sql
edited Nov 15 '18 at 2:02
answered Nov 15 '18 at 1:34
SquirrelSquirrel
12.1k22228
12.1k22228
but then how do I make the name flexible, because the Count of names or the name is not always the same
– dayat
Nov 15 '18 at 1:49
1
then you will requiredDynamic SQL
. Give me few mins, I will update my answer
– Squirrel
Nov 15 '18 at 1:55
add a comment |
but then how do I make the name flexible, because the Count of names or the name is not always the same
– dayat
Nov 15 '18 at 1:49
1
then you will requiredDynamic SQL
. Give me few mins, I will update my answer
– Squirrel
Nov 15 '18 at 1:55
but then how do I make the name flexible, because the Count of names or the name is not always the same
– dayat
Nov 15 '18 at 1:49
but then how do I make the name flexible, because the Count of names or the name is not always the same
– dayat
Nov 15 '18 at 1:49
1
1
then you will required
Dynamic SQL
. Give me few mins, I will update my answer– Squirrel
Nov 15 '18 at 1:55
then you will required
Dynamic SQL
. Give me few mins, I will update my answer– Squirrel
Nov 15 '18 at 1:55
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53311054%2fpivot-rows-to-column-by-group-in-sql-server%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
mssqltips.com/sqlservertip/2783/…
– Aaron Bertrand
Nov 15 '18 at 2:35