Why my Async and Await still not do the job of sequence execution










0















I'm a newbie to Node.js and not sure if I understood Async/Await correctly. Here's what I'm trying to do



I'm passing values to a function and I'm expecting it to work like



Step 1. add both values
Step 2. Fetch a document from db based on value from step 1
Step 3. return the document fetched from step 2.



But the result I see is



Step 1. add both values
Step 2. return undefined while db query is running
step 3. finish running query



How do I achieve desired output from this.



var someFunction = async (a,b)=>
var k;
try
k = a+b;
catch(err)
return(err);


var document;
try
document = await db.collection(somecollection).findOne(_id:k)
catch(err)
return(err);

return(document);


someFunction(4,5).then((result)=>
console.log(result);
);









share|improve this question






















  • Which database are you using? Are you sure that db.collection(somecollection).findOne(_id:k) returns a promise?

    – jfriend00
    Nov 15 '18 at 3:01
















0















I'm a newbie to Node.js and not sure if I understood Async/Await correctly. Here's what I'm trying to do



I'm passing values to a function and I'm expecting it to work like



Step 1. add both values
Step 2. Fetch a document from db based on value from step 1
Step 3. return the document fetched from step 2.



But the result I see is



Step 1. add both values
Step 2. return undefined while db query is running
step 3. finish running query



How do I achieve desired output from this.



var someFunction = async (a,b)=>
var k;
try
k = a+b;
catch(err)
return(err);


var document;
try
document = await db.collection(somecollection).findOne(_id:k)
catch(err)
return(err);

return(document);


someFunction(4,5).then((result)=>
console.log(result);
);









share|improve this question






















  • Which database are you using? Are you sure that db.collection(somecollection).findOne(_id:k) returns a promise?

    – jfriend00
    Nov 15 '18 at 3:01














0












0








0








I'm a newbie to Node.js and not sure if I understood Async/Await correctly. Here's what I'm trying to do



I'm passing values to a function and I'm expecting it to work like



Step 1. add both values
Step 2. Fetch a document from db based on value from step 1
Step 3. return the document fetched from step 2.



But the result I see is



Step 1. add both values
Step 2. return undefined while db query is running
step 3. finish running query



How do I achieve desired output from this.



var someFunction = async (a,b)=>
var k;
try
k = a+b;
catch(err)
return(err);


var document;
try
document = await db.collection(somecollection).findOne(_id:k)
catch(err)
return(err);

return(document);


someFunction(4,5).then((result)=>
console.log(result);
);









share|improve this question














I'm a newbie to Node.js and not sure if I understood Async/Await correctly. Here's what I'm trying to do



I'm passing values to a function and I'm expecting it to work like



Step 1. add both values
Step 2. Fetch a document from db based on value from step 1
Step 3. return the document fetched from step 2.



But the result I see is



Step 1. add both values
Step 2. return undefined while db query is running
step 3. finish running query



How do I achieve desired output from this.



var someFunction = async (a,b)=>
var k;
try
k = a+b;
catch(err)
return(err);


var document;
try
document = await db.collection(somecollection).findOne(_id:k)
catch(err)
return(err);

return(document);


someFunction(4,5).then((result)=>
console.log(result);
);






javascript angularjs node.js async-await






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asked Nov 15 '18 at 1:59









DavidDavid

106




106












  • Which database are you using? Are you sure that db.collection(somecollection).findOne(_id:k) returns a promise?

    – jfriend00
    Nov 15 '18 at 3:01


















  • Which database are you using? Are you sure that db.collection(somecollection).findOne(_id:k) returns a promise?

    – jfriend00
    Nov 15 '18 at 3:01

















Which database are you using? Are you sure that db.collection(somecollection).findOne(_id:k) returns a promise?

– jfriend00
Nov 15 '18 at 3:01






Which database are you using? Are you sure that db.collection(somecollection).findOne(_id:k) returns a promise?

– jfriend00
Nov 15 '18 at 3:01













1 Answer
1






active

oldest

votes


















1














findone may return undefined if no match found
findOne returns undefined on the server



In the first try...catch block, why do you worry about an exception of adding two variables? that never result on error in javascript.



Also make sure you're passing the _id correctly to findone, Mongo uses UUID to calculate _id and I don't think that can be returned from adding a + b






share|improve this answer

























  • This is an example I've taken here in real the first try will have much more to do. in the second block document exists but takes time to run the query, if I print the document in second block it prints moments later undefined is printed which shows that return statement is executed before the second block is finished executing.

    – David
    Nov 15 '18 at 2:28












  • try to cast k to ObjectId, add var ObjectId = require('mongodb').ObjectId in top and then await db.collection(somecollection).findOne(_id: new ObjectId(k) )

    – doc_id
    Nov 15 '18 at 4:47










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














findone may return undefined if no match found
findOne returns undefined on the server



In the first try...catch block, why do you worry about an exception of adding two variables? that never result on error in javascript.



Also make sure you're passing the _id correctly to findone, Mongo uses UUID to calculate _id and I don't think that can be returned from adding a + b






share|improve this answer

























  • This is an example I've taken here in real the first try will have much more to do. in the second block document exists but takes time to run the query, if I print the document in second block it prints moments later undefined is printed which shows that return statement is executed before the second block is finished executing.

    – David
    Nov 15 '18 at 2:28












  • try to cast k to ObjectId, add var ObjectId = require('mongodb').ObjectId in top and then await db.collection(somecollection).findOne(_id: new ObjectId(k) )

    – doc_id
    Nov 15 '18 at 4:47















1














findone may return undefined if no match found
findOne returns undefined on the server



In the first try...catch block, why do you worry about an exception of adding two variables? that never result on error in javascript.



Also make sure you're passing the _id correctly to findone, Mongo uses UUID to calculate _id and I don't think that can be returned from adding a + b






share|improve this answer

























  • This is an example I've taken here in real the first try will have much more to do. in the second block document exists but takes time to run the query, if I print the document in second block it prints moments later undefined is printed which shows that return statement is executed before the second block is finished executing.

    – David
    Nov 15 '18 at 2:28












  • try to cast k to ObjectId, add var ObjectId = require('mongodb').ObjectId in top and then await db.collection(somecollection).findOne(_id: new ObjectId(k) )

    – doc_id
    Nov 15 '18 at 4:47













1












1








1







findone may return undefined if no match found
findOne returns undefined on the server



In the first try...catch block, why do you worry about an exception of adding two variables? that never result on error in javascript.



Also make sure you're passing the _id correctly to findone, Mongo uses UUID to calculate _id and I don't think that can be returned from adding a + b






share|improve this answer















findone may return undefined if no match found
findOne returns undefined on the server



In the first try...catch block, why do you worry about an exception of adding two variables? that never result on error in javascript.



Also make sure you're passing the _id correctly to findone, Mongo uses UUID to calculate _id and I don't think that can be returned from adding a + b







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 15 '18 at 2:18

























answered Nov 15 '18 at 2:12









doc_iddoc_id

890931




890931












  • This is an example I've taken here in real the first try will have much more to do. in the second block document exists but takes time to run the query, if I print the document in second block it prints moments later undefined is printed which shows that return statement is executed before the second block is finished executing.

    – David
    Nov 15 '18 at 2:28












  • try to cast k to ObjectId, add var ObjectId = require('mongodb').ObjectId in top and then await db.collection(somecollection).findOne(_id: new ObjectId(k) )

    – doc_id
    Nov 15 '18 at 4:47

















  • This is an example I've taken here in real the first try will have much more to do. in the second block document exists but takes time to run the query, if I print the document in second block it prints moments later undefined is printed which shows that return statement is executed before the second block is finished executing.

    – David
    Nov 15 '18 at 2:28












  • try to cast k to ObjectId, add var ObjectId = require('mongodb').ObjectId in top and then await db.collection(somecollection).findOne(_id: new ObjectId(k) )

    – doc_id
    Nov 15 '18 at 4:47
















This is an example I've taken here in real the first try will have much more to do. in the second block document exists but takes time to run the query, if I print the document in second block it prints moments later undefined is printed which shows that return statement is executed before the second block is finished executing.

– David
Nov 15 '18 at 2:28






This is an example I've taken here in real the first try will have much more to do. in the second block document exists but takes time to run the query, if I print the document in second block it prints moments later undefined is printed which shows that return statement is executed before the second block is finished executing.

– David
Nov 15 '18 at 2:28














try to cast k to ObjectId, add var ObjectId = require('mongodb').ObjectId in top and then await db.collection(somecollection).findOne(_id: new ObjectId(k) )

– doc_id
Nov 15 '18 at 4:47





try to cast k to ObjectId, add var ObjectId = require('mongodb').ObjectId in top and then await db.collection(somecollection).findOne(_id: new ObjectId(k) )

– doc_id
Nov 15 '18 at 4:47



















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