MySQL - Count and CASE WHEN
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0
My google and stockoverflow searches failed me so need your help. I have a below table
+------+------+------+------------+
| id | Loc | MEL | COUNT(MEL) |
+------+------+------+------------+
| 1 | AAA | A | 1 |
| 2 | BBB | B | 1 |
| 3 | CCC | C | 1 |
| 4 | AAA | D | 1 |
| 5 | AAA | A | 1 |
| 6 | BBB | B | 1 |
| 7 | BBB | C | 1 |
| 8 | AAA | D | 1 |
+------+------+------+------------+
I want to transform it to the following table:
+------+------+------+------+
| MEL | AAA | BBB | CCC |
+------+------+------+------+
| A | 2 | | |
| B | | 2 | |
| C | | 1 | 1 |
| D | 2 | | 1 |
+------+------+------+------+
All conbinations of COUNT and CASE WHEN did not work?
Code to get the below tables:
CREATE TABLE Orders
(
id INT,
Loc char(255),
MEL char (10))
insert into Orders values
(1, "AAA", "A"),
(2, "BBB", "B"),
(3, "CCC", "C"),
(4, "AAA", "D"),
(5, "AAA", "A"),
(6, "BBB", "B"),
(7, "BBB", "C"),
(8, "AAA", "D");
mysql
edited Nov 15 '18 at 14:31
Strawberry
26.8k83250
asked Nov 15 '18 at 14:25
KalenjiKalenji
269316
add a comment |
0
My google and stockoverflow searches failed me so need your help. I have a below table
+------+------+------+------------+
| id | Loc | MEL | COUNT(MEL) |
+------+------+------+------------+
| 1 | AAA | A | 1 |
| 2 | BBB | B | 1 |
| 3 | CCC | C | 1 |
| 4 | AAA | D | 1 |
| 5 | AAA | A | 1 |
| 6 | BBB | B | 1 |
| 7 | BBB | C | 1 |
| 8 | AAA | D | 1 |
+------+------+------+------------+
I want to transform it to the following table:
+------+------+------+------+
| MEL | AAA | BBB | CCC |
+------+------+------+------+
| A | 2 | | |
| B | | 2 | |
| C | | 1 | 1 |
| D | 2 | | 1 |
+------+------+------+------+
All conbinations of COUNT and CASE WHEN did not work?
Code to get the below tables:
CREATE TABLE Orders
(
id INT,
Loc char(255),
MEL char (10))
insert into Orders values
(1, "AAA", "A"),
(2, "BBB", "B"),
(3, "CCC", "C"),
(4, "AAA", "D"),
(5, "AAA", "A"),
(6, "BBB", "B"),
(7, "BBB", "C"),
(8, "AAA", "D");
mysql
edited Nov 15 '18 at 14:31
Strawberry
26.8k83250
asked Nov 15 '18 at 14:25
KalenjiKalenji
269316
1
try googling or searching PIVOT
– Randy
Nov 15 '18 at 14:36
1
Alternatively, consider handling issues of data display in application code.
– Strawberry
Nov 15 '18 at 14:37
I have this code but as I had said before it did not work.SELECT MEL, COUNT(Loc = 'AAA')AS 'AAA', COUNT(Loc = 'BBB')AS 'BBB', COUNT(Loc = 'CCC')AS 'CCC', COUNT(Loc = 'DDD')AS 'DDD' FROM ORDERS GROUP BY MEL;
– Kalenji
Nov 15 '18 at 14:41
You probably need conditional aggregation and dynamic sql.
– P.Salmon
Nov 15 '18 at 14:41
add a comment |
0
0
0
My google and stockoverflow searches failed me so need your help. I have a below table
+------+------+------+------------+
| id | Loc | MEL | COUNT(MEL) |
+------+------+------+------------+
| 1 | AAA | A | 1 |
| 2 | BBB | B | 1 |
| 3 | CCC | C | 1 |
| 4 | AAA | D | 1 |
| 5 | AAA | A | 1 |
| 6 | BBB | B | 1 |
| 7 | BBB | C | 1 |
| 8 | AAA | D | 1 |
+------+------+------+------------+
I want to transform it to the following table:
+------+------+------+------+
| MEL | AAA | BBB | CCC |
+------+------+------+------+
| A | 2 | | |
| B | | 2 | |
| C | | 1 | 1 |
| D | 2 | | 1 |
+------+------+------+------+
All conbinations of COUNT and CASE WHEN did not work?
Code to get the below tables:
CREATE TABLE Orders
(
id INT,
Loc char(255),
MEL char (10))
insert into Orders values
(1, "AAA", "A"),
(2, "BBB", "B"),
(3, "CCC", "C"),
(4, "AAA", "D"),
(5, "AAA", "A"),
(6, "BBB", "B"),
(7, "BBB", "C"),
(8, "AAA", "D");
mysql
edited Nov 15 '18 at 14:31
Strawberry
26.8k83250
asked Nov 15 '18 at 14:25
KalenjiKalenji
269316
My google and stockoverflow searches failed me so need your help. I have a below table
+------+------+------+------------+
| id | Loc | MEL | COUNT(MEL) |
+------+------+------+------------+
| 1 | AAA | A | 1 |
| 2 | BBB | B | 1 |
| 3 | CCC | C | 1 |
| 4 | AAA | D | 1 |
| 5 | AAA | A | 1 |
| 6 | BBB | B | 1 |
| 7 | BBB | C | 1 |
| 8 | AAA | D | 1 |
+------+------+------+------------+
I want to transform it to the following table:
+------+------+------+------+
| MEL | AAA | BBB | CCC |
+------+------+------+------+
| A | 2 | | |
| B | | 2 | |
| C | | 1 | 1 |
| D | 2 | | 1 |
+------+------+------+------+
All conbinations of COUNT and CASE WHEN did not work?
Code to get the below tables:
CREATE TABLE Orders
(
id INT,
Loc char(255),
MEL char (10))
insert into Orders values
(1, "AAA", "A"),
(2, "BBB", "B"),
(3, "CCC", "C"),
(4, "AAA", "D"),
(5, "AAA", "A"),
(6, "BBB", "B"),
(7, "BBB", "C"),
(8, "AAA", "D");
mysql
mysql
edited Nov 15 '18 at 14:31
Strawberry
26.8k83250
asked Nov 15 '18 at 14:25
KalenjiKalenji
269316
edited Nov 15 '18 at 14:31
Strawberry
26.8k83250
asked Nov 15 '18 at 14:25
KalenjiKalenji
269316
edited Nov 15 '18 at 14:31
Strawberry
26.8k83250
edited Nov 15 '18 at 14:31
Strawberry
26.8k83250
edited Nov 15 '18 at 14:31
Strawberry
26.8k83250
26.8k83250
asked Nov 15 '18 at 14:25
KalenjiKalenji
269316
asked Nov 15 '18 at 14:25
KalenjiKalenji
269316
asked Nov 15 '18 at 14:25
KalenjiKalenji
269316
269316
1
try googling or searching PIVOT
– Randy
Nov 15 '18 at 14:36
1
Alternatively, consider handling issues of data display in application code.
– Strawberry
Nov 15 '18 at 14:37
I have this code but as I had said before it did not work.SELECT MEL, COUNT(Loc = 'AAA')AS 'AAA', COUNT(Loc = 'BBB')AS 'BBB', COUNT(Loc = 'CCC')AS 'CCC', COUNT(Loc = 'DDD')AS 'DDD' FROM ORDERS GROUP BY MEL;
– Kalenji
Nov 15 '18 at 14:41
You probably need conditional aggregation and dynamic sql.
– P.Salmon
Nov 15 '18 at 14:41
add a comment |
1
try googling or searching PIVOT
– Randy
Nov 15 '18 at 14:36
1
Alternatively, consider handling issues of data display in application code.
– Strawberry
Nov 15 '18 at 14:37
I have this code but as I had said before it did not work.SELECT MEL, COUNT(Loc = 'AAA')AS 'AAA', COUNT(Loc = 'BBB')AS 'BBB', COUNT(Loc = 'CCC')AS 'CCC', COUNT(Loc = 'DDD')AS 'DDD' FROM ORDERS GROUP BY MEL;
– Kalenji
Nov 15 '18 at 14:41
You probably need conditional aggregation and dynamic sql.
– P.Salmon
Nov 15 '18 at 14:41
1
1
try googling or searching PIVOT
– Randy
Nov 15 '18 at 14:36
try googling or searching PIVOT
– Randy
Nov 15 '18 at 14:36
1
1
Alternatively, consider handling issues of data display in application code.
– Strawberry
Nov 15 '18 at 14:37
Alternatively, consider handling issues of data display in application code.
– Strawberry
Nov 15 '18 at 14:37
I have this code but as I had said before it did not work.
SELECT MEL, COUNT(Loc = 'AAA')AS 'AAA', COUNT(Loc = 'BBB')AS 'BBB', COUNT(Loc = 'CCC')AS 'CCC', COUNT(Loc = 'DDD')AS 'DDD' FROM ORDERS GROUP BY MEL;– Kalenji
Nov 15 '18 at 14:41
I have this code but as I had said before it did not work.
SELECT MEL, COUNT(Loc = 'AAA')AS 'AAA', COUNT(Loc = 'BBB')AS 'BBB', COUNT(Loc = 'CCC')AS 'CCC', COUNT(Loc = 'DDD')AS 'DDD' FROM ORDERS GROUP BY MEL;– Kalenji
Nov 15 '18 at 14:41
You probably need conditional aggregation and dynamic sql.
– P.Salmon
Nov 15 '18 at 14:41
You probably need conditional aggregation and dynamic sql.
– P.Salmon
Nov 15 '18 at 14:41
add a comment |
1 Answer
1
active
oldest
votes
3
select mel,
sum(Loc="AAA") AS AAA,
sum(Loc="BBB") AS BBB /* and so on */
from Orders group by mel;
You need to use sum instead of count, because the boolean expression returns 0 or 1. count doesn't care about that, it just counts, whether it's 0 or 1 doesn't matter.
answered Nov 15 '18 at 14:41
fancyPantsfancyPants
40.1k167085
fiddle: sqlfiddle.com/#!9/e2bb6c/20
– vivoconunxino
Nov 15 '18 at 14:52
add a comment |
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1 Answer
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1 Answer
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oldest
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oldest
votes
3
select mel,
sum(Loc="AAA") AS AAA,
sum(Loc="BBB") AS BBB /* and so on */
from Orders group by mel;
You need to use sum instead of count, because the boolean expression returns 0 or 1. count doesn't care about that, it just counts, whether it's 0 or 1 doesn't matter.
answered Nov 15 '18 at 14:41
fancyPantsfancyPants
40.1k167085
fiddle: sqlfiddle.com/#!9/e2bb6c/20
– vivoconunxino
Nov 15 '18 at 14:52
add a comment |
3
select mel,
sum(Loc="AAA") AS AAA,
sum(Loc="BBB") AS BBB /* and so on */
from Orders group by mel;
You need to use sum instead of count, because the boolean expression returns 0 or 1. count doesn't care about that, it just counts, whether it's 0 or 1 doesn't matter.
answered Nov 15 '18 at 14:41
fancyPantsfancyPants
40.1k167085
fiddle: sqlfiddle.com/#!9/e2bb6c/20
– vivoconunxino
Nov 15 '18 at 14:52
add a comment |
3
3
3
select mel,
sum(Loc="AAA") AS AAA,
sum(Loc="BBB") AS BBB /* and so on */
from Orders group by mel;
You need to use sum instead of count, because the boolean expression returns 0 or 1. count doesn't care about that, it just counts, whether it's 0 or 1 doesn't matter.
answered Nov 15 '18 at 14:41
fancyPantsfancyPants
40.1k167085
select mel,
sum(Loc="AAA") AS AAA,
sum(Loc="BBB") AS BBB /* and so on */
from Orders group by mel;
You need to use sum instead of count, because the boolean expression returns 0 or 1. count doesn't care about that, it just counts, whether it's 0 or 1 doesn't matter.
answered Nov 15 '18 at 14:41
fancyPantsfancyPants
40.1k167085
answered Nov 15 '18 at 14:41
fancyPantsfancyPants
40.1k167085
answered Nov 15 '18 at 14:41
fancyPantsfancyPants
40.1k167085
answered Nov 15 '18 at 14:41
fancyPantsfancyPants
40.1k167085
40.1k167085
fiddle: sqlfiddle.com/#!9/e2bb6c/20
– vivoconunxino
Nov 15 '18 at 14:52
add a comment |
fiddle: sqlfiddle.com/#!9/e2bb6c/20
– vivoconunxino
Nov 15 '18 at 14:52
fiddle: sqlfiddle.com/#!9/e2bb6c/20
– vivoconunxino
Nov 15 '18 at 14:52
fiddle: sqlfiddle.com/#!9/e2bb6c/20
– vivoconunxino
Nov 15 '18 at 14:52
add a comment |
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1
try googling or searching PIVOT
– Randy
Nov 15 '18 at 14:36
1
Alternatively, consider handling issues of data display in application code.
– Strawberry
Nov 15 '18 at 14:37
I have this code but as I had said before it did not work.
SELECT MEL, COUNT(Loc = 'AAA')AS 'AAA', COUNT(Loc = 'BBB')AS 'BBB', COUNT(Loc = 'CCC')AS 'CCC', COUNT(Loc = 'DDD')AS 'DDD' FROM ORDERS GROUP BY MEL;– Kalenji
Nov 15 '18 at 14:41
You probably need conditional aggregation and dynamic sql.
– P.Salmon
Nov 15 '18 at 14:41