How do you use a variable in a regular expression?









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I would like to create a String.replaceAll() method in JavaScript and I'm thinking that using a RegEx would be most terse way to do it. However, I can't figure out how to pass a variable in to a RegEx. I can do this already which will replace all the instances of "B" with "A".



"ABABAB".replace(/B/g, "A");


But I want to do something like this:



String.prototype.replaceAll = function(replaceThis, withThis) 
this.replace(/replaceThis/g, withThis);
;


But obviously this will only replace the text "replaceThis"...so how do I pass this variable in to my RegEx string?










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  • 3




    Note that we're currently working on adding this functionality to JavaScript if you have an opinion about it please join the discussion.
    – Benjamin Gruenbaum
    Jun 23 '15 at 11:38














up vote
1033
down vote

favorite
204












I would like to create a String.replaceAll() method in JavaScript and I'm thinking that using a RegEx would be most terse way to do it. However, I can't figure out how to pass a variable in to a RegEx. I can do this already which will replace all the instances of "B" with "A".



"ABABAB".replace(/B/g, "A");


But I want to do something like this:



String.prototype.replaceAll = function(replaceThis, withThis) 
this.replace(/replaceThis/g, withThis);
;


But obviously this will only replace the text "replaceThis"...so how do I pass this variable in to my RegEx string?










share|improve this question



















  • 3




    Note that we're currently working on adding this functionality to JavaScript if you have an opinion about it please join the discussion.
    – Benjamin Gruenbaum
    Jun 23 '15 at 11:38












up vote
1033
down vote

favorite
204









up vote
1033
down vote

favorite
204






204





I would like to create a String.replaceAll() method in JavaScript and I'm thinking that using a RegEx would be most terse way to do it. However, I can't figure out how to pass a variable in to a RegEx. I can do this already which will replace all the instances of "B" with "A".



"ABABAB".replace(/B/g, "A");


But I want to do something like this:



String.prototype.replaceAll = function(replaceThis, withThis) 
this.replace(/replaceThis/g, withThis);
;


But obviously this will only replace the text "replaceThis"...so how do I pass this variable in to my RegEx string?










share|improve this question















I would like to create a String.replaceAll() method in JavaScript and I'm thinking that using a RegEx would be most terse way to do it. However, I can't figure out how to pass a variable in to a RegEx. I can do this already which will replace all the instances of "B" with "A".



"ABABAB".replace(/B/g, "A");


But I want to do something like this:



String.prototype.replaceAll = function(replaceThis, withThis) 
this.replace(/replaceThis/g, withThis);
;


But obviously this will only replace the text "replaceThis"...so how do I pass this variable in to my RegEx string?







javascript regex






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edited Dec 5 '16 at 3:05







user663031

















asked Jan 30 '09 at 0:11









JC Grubbs

13.7k266072




13.7k266072







  • 3




    Note that we're currently working on adding this functionality to JavaScript if you have an opinion about it please join the discussion.
    – Benjamin Gruenbaum
    Jun 23 '15 at 11:38












  • 3




    Note that we're currently working on adding this functionality to JavaScript if you have an opinion about it please join the discussion.
    – Benjamin Gruenbaum
    Jun 23 '15 at 11:38







3




3




Note that we're currently working on adding this functionality to JavaScript if you have an opinion about it please join the discussion.
– Benjamin Gruenbaum
Jun 23 '15 at 11:38




Note that we're currently working on adding this functionality to JavaScript if you have an opinion about it please join the discussion.
– Benjamin Gruenbaum
Jun 23 '15 at 11:38












18 Answers
18






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up vote
1451
down vote



accepted










Instead of using the /regex/g syntax, you can construct a new RegExp object:



var replace = "regex";
var re = new RegExp(replace,"g");


You can dynamically create regex objects this way. Then you will do:



"mystring".replace(re, "newstring");





share|improve this answer


















  • 220




    If you need to use an expression like //word:w*$/, be sure to escape your backslashes: new RegExp( '\/word\:\w*$' ).
    – Jonathan Swinney
    Nov 9 '10 at 23:04






  • 2




    @gravityboy You can do ('' + myNumber).replace(/10/g, 'a') or if you want hex numbers, you can do parseInt('' + myNumber, 16) to convert to hex from decimal.
    – Eric Wendelin
    Jun 21 '11 at 15:19






  • 5




    Full escape explanation: stackoverflow.com/a/6969486/151312
    – CoolAJ86
    Jun 3 '12 at 1:33






  • 16




    The question suggests that the RegEx is only used to do a constant string replacement. So this is answer is wrong as it would fail if the string contains RegEx meta characters. Sad it is voted this high, will make many headaches...
    – dronus
    Feb 12 '14 at 20:32






  • 9




    An example of this passing a variable would make this a good answer. I'm still struggling after reading this.
    – Goose
    Jun 5 '15 at 18:44

















up vote
173
down vote













As Eric Wendelin mentioned, you can do something like this:



str1 = "pattern"
var re = new RegExp(str1, "g");
"pattern matching .".replace(re, "regex");


This yields "regex matching .". However, it will fail if str1 is ".". You'd expect the result to be "pattern matching regex", replacing the period with "regex", but it'll turn out to be...



regexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregex


This is because, although "." is a String, in the RegExp constructor it's still interpreted as a regular expression, meaning any non-line-break character, meaning every character in the string. For this purpose, the following function may be useful:



 RegExp.quote = function(str) 
return str.replace(/([.?*+^$[]\();


Then you can do:



str1 = "."
var re = new RegExp(RegExp.quote(str1), "g");
"pattern matching .".replace(re, "regex");


yielding "pattern matching regex".






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  • 4




    You know that the first parameter to replace can be a normal string and don't have to be a regexp? str1 = "."; alert("pattern matching .".replace(str1, "string"));
    – some
    Jan 30 '09 at 10:31










  • @some: of course. That's because the above example is trivial. When you need to search for or replace a pattern combined with a regular string, do str.match(new RegExp("https?://" + RegExp.escape(myDomainName)), for instance. It's annoying that the escape function is not built in.
    – Gracenotes
    Jan 30 '09 at 19:57










  • (continued) Plus, apparentl JC Grubbs required a global replace; implementing a global replace with String.replace(String, String) could be slow for large input. I'm just saying, the top two solutions are buggy, and will fail unexpected on certain input.
    – Gracenotes
    Jan 30 '09 at 20:00






  • 4




    developer.mozilla.org/en-US/docs/JavaScript/Guide/… offers a similar function, but they exclude -, and include =!:/.
    – chbrown
    Dec 15 '12 at 21:12






  • 4




    The correct term is "escape", not "quote". Just BTW.
    – Lawrence Dol
    Dec 4 '15 at 5:19

















up vote
89
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"ABABAB".replace(/B/g, "A");




As always: don't use regex unless you have to. For a simple string replace, the idiom is:



'ABABAB'.split('B').join('A')


Then you don't have to worry about the quoting issues mentioned in Gracenotes's answer.






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  • 5




    Cool idea, wouldn't have thought of doing that!
    – devios1
    May 31 '12 at 19:01






  • 8




    And have you measured that this is faster than regex?
    – Mitar
    Apr 10 '13 at 3:12






  • 2




    This seems preferable, especially when needing to match on special regex characters like '.'
    – Krease
    Apr 24 '13 at 18:41






  • 1




    Uhm... Doesn't split take a RegExp too; if so, wouldn't it cause the same problem ? Anyway... .split().join() may be slower on some platforms, because it's two operations, whereas .replace() is one operation and may be optimized.
    – user1985657
    Jun 12 '13 at 22:47







  • 5




    @PacMan--: both split and replace can take either a string or a RegExp object. The problem that replace has that split doesn't is that when you use a string you only get a single replacement.
    – bobince
    Jun 13 '13 at 9:05

















up vote
28
down vote













For anyone looking to use variable with the match method, this worked for me



var alpha = 'fig';
'food fight'.match(alpha + 'ht')[0]; // fight





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    up vote
    22
    down vote













    This:



    var txt=new RegExp(pattern,attributes);


    is equivalent to this:



    var txt=/pattern/attributes;


    See http://www.w3schools.com/jsref/jsref_obj_regexp.asp.






    share|improve this answer
















    • 11




      yep, but in first example it uses pattern as variable, in 2nd as a string
      – vladkras
      Jul 9 '13 at 4:16











    • I actually find this to be the clearest answer.
      – Teekin
      Aug 18 at 16:17

















    up vote
    14
    down vote













    this.replace( new RegExp( replaceThis, 'g' ), withThis );





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      up vote
      9
      down vote













      String.prototype.replaceAll = function (replaceThis, withThis) 
      var re = new RegExp(replaceThis,"g");
      return this.replace(re, withThis);
      ;
      var aa = "abab54..aba".replaceAll("\.", "v");


      Test with this tool






      share|improve this answer





























        up vote
        7
        down vote













        You want to build the regular expression dynamically and for this the proper solutuion is to use the new RegExp(string) constructor. In order for constructor to treat special characters literally, you must escape them. There is a built-in function in jQuery UI autocomplete widget called $.ui.autocomplete.escapeRegex:




        [...] you can make use of the built-in
        $.ui.autocomplete.escapeRegex function. It'll take a single string
        argument and escape all regex characters, making the result safe to
        pass to new RegExp().




        If you are using jQuery UI you can use that function, or copy its definition from the source:



        function escapeRegex(value) #s]/g, "\$&" );



        And use it like this:



        "[z-a][z-a][z-a]".replace(new RegExp(escapeRegex("[z-a]"), "g"), "[a-z]");
        // escapeRegex("[z-a]") -> "[z-a]"
        // new RegExp(escapeRegex("[z-a]"), "g") -> /[z-a]/g
        // end result -> "[a-z][a-z][a-z]"





        share|improve this answer





























          up vote
          5
          down vote













          If you want to get ALL occurrences (g), be case insensitive (i), and use boundaries so that it isn't a word within another word (\b):



          re = new RegExp(`\b$replaceThis\b`, 'gi');



          Example:



          let inputString = "I'm John, or johnny, but I prefer john.";
          let replaceThis = "John";
          let re = new RegExp(`\b$replaceThis\b`, 'gi');
          console.log(inputString.replace(re, "Jack")); // I'm Jack, or johnny, but I prefer Jack.





          share|improve this answer



























            up vote
            4
            down vote













            Here's another replaceAll implementation:



             String.prototype.replaceAll = function (stringToFind, stringToReplace) 
            if ( stringToFind == stringToReplace) return this;
            var temp = this;
            var index = temp.indexOf(stringToFind);
            while (index != -1)
            temp = temp.replace(stringToFind, stringToReplace);
            index = temp.indexOf(stringToFind);

            return temp;
            ;





            share|improve this answer



























              up vote
              3
              down vote













              While you can make dynamically-created RegExp's (as per the other responses to this question), I'll echo my comment from a similar post: The functional form of String.replace() is extremely useful and in many cases reduces the need for dynamically-created RegExp objects. (which are kind of a pain 'cause you have to express the input to the RegExp constructor as a string rather than use the slashes /[A-Z]+/ regexp literal format)






              share|improve this answer





























                up vote
                3
                down vote













                To satisfy my need to insert a variable/alias/function into a Regular Expression, this is what I came up with:



                oldre = /xx("")/;
                function newre(e)
                return RegExp(e.toString().replace(///g,"").replace(/xx/g, yy), "g")
                ;

                String.prototype.replaceAll = this.replace(newre(oldre), "withThis");


                where 'oldre' is the original regexp that I want to insert a variable,
                'xx' is the placeholder for that variable/alias/function,
                and 'yy' is the actual variable name, alias, or function.






                share|improve this answer





























                  up vote
                  3
                  down vote













                  String.prototype.replaceAll = function(a, b) 
                  return this.replace(new RegExp(a.replace(/([.?*+^$[]\()


                  Test it like:



                  var whatever = 'Some [b]random[/b] text in a [b]sentence.[/b]'

                  console.log(whatever.replaceAll("[", "<").replaceAll("]", ">"))





                  share|improve this answer



























                    up vote
                    3
                    down vote













                    And the coffeescript version of Steven Penny's answer, since this is #2 google result....even if coffee is just javascript with a lot of characters removed...;)



                    baz = "foo"
                    filter = new RegExp(baz + "d")
                    "food fight".match(filter)[0] // food


                    and in my particular case



                    robot.name=hubot
                    filter = new RegExp(robot.name)
                    if msg.match.input.match(filter)
                    console.log "True!"





                    share|improve this answer






















                    • why a downvote? coffeescript -IS- javascript with it's own specific syntax.
                      – keen
                      Aug 26 '15 at 15:53

















                    up vote
                    1
                    down vote













                    You can use this if $1 not work with you



                    var pattern = new RegExp("amman","i");
                    "abc Amman efg".replace(pattern,"<b>"+"abc Amman efg".match(pattern)[0]+"</b>");





                    share|improve this answer



























                      up vote
                      1
                      down vote













                      You can always use indexOf repeatedly:



                      String.prototype.replaceAll = function(substring, replacement) 
                      var result = '';
                      var lastIndex = 0;

                      while(true)
                      var index = this.indexOf(substring, lastIndex);
                      if(index === -1) break;
                      result += this.substring(lastIndex, index) + replacement;
                      lastIndex = index + substring.length;


                      return result + this.substring(lastIndex);
                      ;


                      This doesn’t go into an infinite loop when the replacement contains the match.






                      share|improve this answer



























                        up vote
                        1
                        down vote













                        Your solution is here:



                        Pass a variable to regular expression.



                        The one which I have implemented is by taking the value from a text field which is the one you want to replace and another is the "replace with" text field, getting the value from text-field in a variable and setting the variable to RegExp function to further replace. In my case I am using Jquery, you also can do it by only JavaScript too.



                        JavaScript code:



                         var replace =document.getElementById("replace}"); // getting a value from a text field with I want to replace
                        var replace_with = document.getElementById("with"); //Getting the value from another text fields with which I want to replace another string.

                        var sRegExInput = new RegExp(replace, "g");
                        $("body").children().each(function()
                        $(this).html($(this).html().replace(sRegExInput,replace_with));
                        );


                        This code is on Onclick event of a button, you can put this in a function to call.



                        So now You can pass variable in replace function.






                        share|improve this answer






















                        • Your replace_with variable will contain the DOM element not the value itself
                          – Ben Taliadoros
                          Oct 27 '17 at 14:26

















                        up vote
                        0
                        down vote













                        None of these answers were clear to me. I eventually found a good explanation at http://burnignorance.com/php-programming-tips/how-to-use-a-variable-in-replace-function-of-javascript/



                        The simple answer is:



                        var search_term = new RegExp(search_term, "g"); 
                        text = text.replace(search_term, replace_term);


                        For example:






                        $("button").click(function() 
                        Find_and_replace("Lorem", "Chocolate");
                        Find_and_replace("ipsum", "ice-cream");
                        );

                        function Find_and_replace(search_term, replace_term)
                        text = $("textbox").html();
                        var search_term = new RegExp(search_term, "g");
                        text = text.replace(search_term, replace_term);
                        $("textbox").html(text);

                        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                        <textbox>
                        Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum
                        </textbox>
                        <button>Click me</button>








                        share|improve this answer




















                        • You're overwriting a closure variable, no need to use var here. Also, if you pass b or 1 it would break.
                          – CyberAP
                          Nov 6 at 19:00









                        protected by Community Sep 19 at 9:52



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                        18 Answers
                        18






                        active

                        oldest

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                        18 Answers
                        18






                        active

                        oldest

                        votes









                        active

                        oldest

                        votes






                        active

                        oldest

                        votes








                        up vote
                        1451
                        down vote



                        accepted










                        Instead of using the /regex/g syntax, you can construct a new RegExp object:



                        var replace = "regex";
                        var re = new RegExp(replace,"g");


                        You can dynamically create regex objects this way. Then you will do:



                        "mystring".replace(re, "newstring");





                        share|improve this answer


















                        • 220




                          If you need to use an expression like //word:w*$/, be sure to escape your backslashes: new RegExp( '\/word\:\w*$' ).
                          – Jonathan Swinney
                          Nov 9 '10 at 23:04






                        • 2




                          @gravityboy You can do ('' + myNumber).replace(/10/g, 'a') or if you want hex numbers, you can do parseInt('' + myNumber, 16) to convert to hex from decimal.
                          – Eric Wendelin
                          Jun 21 '11 at 15:19






                        • 5




                          Full escape explanation: stackoverflow.com/a/6969486/151312
                          – CoolAJ86
                          Jun 3 '12 at 1:33






                        • 16




                          The question suggests that the RegEx is only used to do a constant string replacement. So this is answer is wrong as it would fail if the string contains RegEx meta characters. Sad it is voted this high, will make many headaches...
                          – dronus
                          Feb 12 '14 at 20:32






                        • 9




                          An example of this passing a variable would make this a good answer. I'm still struggling after reading this.
                          – Goose
                          Jun 5 '15 at 18:44














                        up vote
                        1451
                        down vote



                        accepted










                        Instead of using the /regex/g syntax, you can construct a new RegExp object:



                        var replace = "regex";
                        var re = new RegExp(replace,"g");


                        You can dynamically create regex objects this way. Then you will do:



                        "mystring".replace(re, "newstring");





                        share|improve this answer


















                        • 220




                          If you need to use an expression like //word:w*$/, be sure to escape your backslashes: new RegExp( '\/word\:\w*$' ).
                          – Jonathan Swinney
                          Nov 9 '10 at 23:04






                        • 2




                          @gravityboy You can do ('' + myNumber).replace(/10/g, 'a') or if you want hex numbers, you can do parseInt('' + myNumber, 16) to convert to hex from decimal.
                          – Eric Wendelin
                          Jun 21 '11 at 15:19






                        • 5




                          Full escape explanation: stackoverflow.com/a/6969486/151312
                          – CoolAJ86
                          Jun 3 '12 at 1:33






                        • 16




                          The question suggests that the RegEx is only used to do a constant string replacement. So this is answer is wrong as it would fail if the string contains RegEx meta characters. Sad it is voted this high, will make many headaches...
                          – dronus
                          Feb 12 '14 at 20:32






                        • 9




                          An example of this passing a variable would make this a good answer. I'm still struggling after reading this.
                          – Goose
                          Jun 5 '15 at 18:44












                        up vote
                        1451
                        down vote



                        accepted







                        up vote
                        1451
                        down vote



                        accepted






                        Instead of using the /regex/g syntax, you can construct a new RegExp object:



                        var replace = "regex";
                        var re = new RegExp(replace,"g");


                        You can dynamically create regex objects this way. Then you will do:



                        "mystring".replace(re, "newstring");





                        share|improve this answer














                        Instead of using the /regex/g syntax, you can construct a new RegExp object:



                        var replace = "regex";
                        var re = new RegExp(replace,"g");


                        You can dynamically create regex objects this way. Then you will do:



                        "mystring".replace(re, "newstring");






                        share|improve this answer














                        share|improve this answer



                        share|improve this answer








                        edited Dec 17 '16 at 9:53









                        jcubic

                        32.9k28115219




                        32.9k28115219










                        answered Jan 30 '09 at 0:15









                        Eric Wendelin

                        29.4k85482




                        29.4k85482







                        • 220




                          If you need to use an expression like //word:w*$/, be sure to escape your backslashes: new RegExp( '\/word\:\w*$' ).
                          – Jonathan Swinney
                          Nov 9 '10 at 23:04






                        • 2




                          @gravityboy You can do ('' + myNumber).replace(/10/g, 'a') or if you want hex numbers, you can do parseInt('' + myNumber, 16) to convert to hex from decimal.
                          – Eric Wendelin
                          Jun 21 '11 at 15:19






                        • 5




                          Full escape explanation: stackoverflow.com/a/6969486/151312
                          – CoolAJ86
                          Jun 3 '12 at 1:33






                        • 16




                          The question suggests that the RegEx is only used to do a constant string replacement. So this is answer is wrong as it would fail if the string contains RegEx meta characters. Sad it is voted this high, will make many headaches...
                          – dronus
                          Feb 12 '14 at 20:32






                        • 9




                          An example of this passing a variable would make this a good answer. I'm still struggling after reading this.
                          – Goose
                          Jun 5 '15 at 18:44












                        • 220




                          If you need to use an expression like //word:w*$/, be sure to escape your backslashes: new RegExp( '\/word\:\w*$' ).
                          – Jonathan Swinney
                          Nov 9 '10 at 23:04






                        • 2




                          @gravityboy You can do ('' + myNumber).replace(/10/g, 'a') or if you want hex numbers, you can do parseInt('' + myNumber, 16) to convert to hex from decimal.
                          – Eric Wendelin
                          Jun 21 '11 at 15:19






                        • 5




                          Full escape explanation: stackoverflow.com/a/6969486/151312
                          – CoolAJ86
                          Jun 3 '12 at 1:33






                        • 16




                          The question suggests that the RegEx is only used to do a constant string replacement. So this is answer is wrong as it would fail if the string contains RegEx meta characters. Sad it is voted this high, will make many headaches...
                          – dronus
                          Feb 12 '14 at 20:32






                        • 9




                          An example of this passing a variable would make this a good answer. I'm still struggling after reading this.
                          – Goose
                          Jun 5 '15 at 18:44







                        220




                        220




                        If you need to use an expression like //word:w*$/, be sure to escape your backslashes: new RegExp( '\/word\:\w*$' ).
                        – Jonathan Swinney
                        Nov 9 '10 at 23:04




                        If you need to use an expression like //word:w*$/, be sure to escape your backslashes: new RegExp( '\/word\:\w*$' ).
                        – Jonathan Swinney
                        Nov 9 '10 at 23:04




                        2




                        2




                        @gravityboy You can do ('' + myNumber).replace(/10/g, 'a') or if you want hex numbers, you can do parseInt('' + myNumber, 16) to convert to hex from decimal.
                        – Eric Wendelin
                        Jun 21 '11 at 15:19




                        @gravityboy You can do ('' + myNumber).replace(/10/g, 'a') or if you want hex numbers, you can do parseInt('' + myNumber, 16) to convert to hex from decimal.
                        – Eric Wendelin
                        Jun 21 '11 at 15:19




                        5




                        5




                        Full escape explanation: stackoverflow.com/a/6969486/151312
                        – CoolAJ86
                        Jun 3 '12 at 1:33




                        Full escape explanation: stackoverflow.com/a/6969486/151312
                        – CoolAJ86
                        Jun 3 '12 at 1:33




                        16




                        16




                        The question suggests that the RegEx is only used to do a constant string replacement. So this is answer is wrong as it would fail if the string contains RegEx meta characters. Sad it is voted this high, will make many headaches...
                        – dronus
                        Feb 12 '14 at 20:32




                        The question suggests that the RegEx is only used to do a constant string replacement. So this is answer is wrong as it would fail if the string contains RegEx meta characters. Sad it is voted this high, will make many headaches...
                        – dronus
                        Feb 12 '14 at 20:32




                        9




                        9




                        An example of this passing a variable would make this a good answer. I'm still struggling after reading this.
                        – Goose
                        Jun 5 '15 at 18:44




                        An example of this passing a variable would make this a good answer. I'm still struggling after reading this.
                        – Goose
                        Jun 5 '15 at 18:44












                        up vote
                        173
                        down vote













                        As Eric Wendelin mentioned, you can do something like this:



                        str1 = "pattern"
                        var re = new RegExp(str1, "g");
                        "pattern matching .".replace(re, "regex");


                        This yields "regex matching .". However, it will fail if str1 is ".". You'd expect the result to be "pattern matching regex", replacing the period with "regex", but it'll turn out to be...



                        regexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregex


                        This is because, although "." is a String, in the RegExp constructor it's still interpreted as a regular expression, meaning any non-line-break character, meaning every character in the string. For this purpose, the following function may be useful:



                         RegExp.quote = function(str) 
                        return str.replace(/([.?*+^$[]\();


                        Then you can do:



                        str1 = "."
                        var re = new RegExp(RegExp.quote(str1), "g");
                        "pattern matching .".replace(re, "regex");


                        yielding "pattern matching regex".






                        share|improve this answer


















                        • 4




                          You know that the first parameter to replace can be a normal string and don't have to be a regexp? str1 = "."; alert("pattern matching .".replace(str1, "string"));
                          – some
                          Jan 30 '09 at 10:31










                        • @some: of course. That's because the above example is trivial. When you need to search for or replace a pattern combined with a regular string, do str.match(new RegExp("https?://" + RegExp.escape(myDomainName)), for instance. It's annoying that the escape function is not built in.
                          – Gracenotes
                          Jan 30 '09 at 19:57










                        • (continued) Plus, apparentl JC Grubbs required a global replace; implementing a global replace with String.replace(String, String) could be slow for large input. I'm just saying, the top two solutions are buggy, and will fail unexpected on certain input.
                          – Gracenotes
                          Jan 30 '09 at 20:00






                        • 4




                          developer.mozilla.org/en-US/docs/JavaScript/Guide/… offers a similar function, but they exclude -, and include =!:/.
                          – chbrown
                          Dec 15 '12 at 21:12






                        • 4




                          The correct term is "escape", not "quote". Just BTW.
                          – Lawrence Dol
                          Dec 4 '15 at 5:19














                        up vote
                        173
                        down vote













                        As Eric Wendelin mentioned, you can do something like this:



                        str1 = "pattern"
                        var re = new RegExp(str1, "g");
                        "pattern matching .".replace(re, "regex");


                        This yields "regex matching .". However, it will fail if str1 is ".". You'd expect the result to be "pattern matching regex", replacing the period with "regex", but it'll turn out to be...



                        regexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregex


                        This is because, although "." is a String, in the RegExp constructor it's still interpreted as a regular expression, meaning any non-line-break character, meaning every character in the string. For this purpose, the following function may be useful:



                         RegExp.quote = function(str) 
                        return str.replace(/([.?*+^$[]\();


                        Then you can do:



                        str1 = "."
                        var re = new RegExp(RegExp.quote(str1), "g");
                        "pattern matching .".replace(re, "regex");


                        yielding "pattern matching regex".






                        share|improve this answer


















                        • 4




                          You know that the first parameter to replace can be a normal string and don't have to be a regexp? str1 = "."; alert("pattern matching .".replace(str1, "string"));
                          – some
                          Jan 30 '09 at 10:31










                        • @some: of course. That's because the above example is trivial. When you need to search for or replace a pattern combined with a regular string, do str.match(new RegExp("https?://" + RegExp.escape(myDomainName)), for instance. It's annoying that the escape function is not built in.
                          – Gracenotes
                          Jan 30 '09 at 19:57










                        • (continued) Plus, apparentl JC Grubbs required a global replace; implementing a global replace with String.replace(String, String) could be slow for large input. I'm just saying, the top two solutions are buggy, and will fail unexpected on certain input.
                          – Gracenotes
                          Jan 30 '09 at 20:00






                        • 4




                          developer.mozilla.org/en-US/docs/JavaScript/Guide/… offers a similar function, but they exclude -, and include =!:/.
                          – chbrown
                          Dec 15 '12 at 21:12






                        • 4




                          The correct term is "escape", not "quote". Just BTW.
                          – Lawrence Dol
                          Dec 4 '15 at 5:19












                        up vote
                        173
                        down vote










                        up vote
                        173
                        down vote









                        As Eric Wendelin mentioned, you can do something like this:



                        str1 = "pattern"
                        var re = new RegExp(str1, "g");
                        "pattern matching .".replace(re, "regex");


                        This yields "regex matching .". However, it will fail if str1 is ".". You'd expect the result to be "pattern matching regex", replacing the period with "regex", but it'll turn out to be...



                        regexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregex


                        This is because, although "." is a String, in the RegExp constructor it's still interpreted as a regular expression, meaning any non-line-break character, meaning every character in the string. For this purpose, the following function may be useful:



                         RegExp.quote = function(str) 
                        return str.replace(/([.?*+^$[]\();


                        Then you can do:



                        str1 = "."
                        var re = new RegExp(RegExp.quote(str1), "g");
                        "pattern matching .".replace(re, "regex");


                        yielding "pattern matching regex".






                        share|improve this answer














                        As Eric Wendelin mentioned, you can do something like this:



                        str1 = "pattern"
                        var re = new RegExp(str1, "g");
                        "pattern matching .".replace(re, "regex");


                        This yields "regex matching .". However, it will fail if str1 is ".". You'd expect the result to be "pattern matching regex", replacing the period with "regex", but it'll turn out to be...



                        regexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregexregex


                        This is because, although "." is a String, in the RegExp constructor it's still interpreted as a regular expression, meaning any non-line-break character, meaning every character in the string. For this purpose, the following function may be useful:



                         RegExp.quote = function(str) 
                        return str.replace(/([.?*+^$[]\();


                        Then you can do:



                        str1 = "."
                        var re = new RegExp(RegExp.quote(str1), "g");
                        "pattern matching .".replace(re, "regex");


                        yielding "pattern matching regex".







                        share|improve this answer














                        share|improve this answer



                        share|improve this answer








                        edited Jun 19 '12 at 8:15









                        Qtax

                        27k55297




                        27k55297










                        answered Jan 30 '09 at 1:02









                        Gracenotes

                        1,9141108




                        1,9141108







                        • 4




                          You know that the first parameter to replace can be a normal string and don't have to be a regexp? str1 = "."; alert("pattern matching .".replace(str1, "string"));
                          – some
                          Jan 30 '09 at 10:31










                        • @some: of course. That's because the above example is trivial. When you need to search for or replace a pattern combined with a regular string, do str.match(new RegExp("https?://" + RegExp.escape(myDomainName)), for instance. It's annoying that the escape function is not built in.
                          – Gracenotes
                          Jan 30 '09 at 19:57










                        • (continued) Plus, apparentl JC Grubbs required a global replace; implementing a global replace with String.replace(String, String) could be slow for large input. I'm just saying, the top two solutions are buggy, and will fail unexpected on certain input.
                          – Gracenotes
                          Jan 30 '09 at 20:00






                        • 4




                          developer.mozilla.org/en-US/docs/JavaScript/Guide/… offers a similar function, but they exclude -, and include =!:/.
                          – chbrown
                          Dec 15 '12 at 21:12






                        • 4




                          The correct term is "escape", not "quote". Just BTW.
                          – Lawrence Dol
                          Dec 4 '15 at 5:19












                        • 4




                          You know that the first parameter to replace can be a normal string and don't have to be a regexp? str1 = "."; alert("pattern matching .".replace(str1, "string"));
                          – some
                          Jan 30 '09 at 10:31










                        • @some: of course. That's because the above example is trivial. When you need to search for or replace a pattern combined with a regular string, do str.match(new RegExp("https?://" + RegExp.escape(myDomainName)), for instance. It's annoying that the escape function is not built in.
                          – Gracenotes
                          Jan 30 '09 at 19:57










                        • (continued) Plus, apparentl JC Grubbs required a global replace; implementing a global replace with String.replace(String, String) could be slow for large input. I'm just saying, the top two solutions are buggy, and will fail unexpected on certain input.
                          – Gracenotes
                          Jan 30 '09 at 20:00






                        • 4




                          developer.mozilla.org/en-US/docs/JavaScript/Guide/… offers a similar function, but they exclude -, and include =!:/.
                          – chbrown
                          Dec 15 '12 at 21:12






                        • 4




                          The correct term is "escape", not "quote". Just BTW.
                          – Lawrence Dol
                          Dec 4 '15 at 5:19







                        4




                        4




                        You know that the first parameter to replace can be a normal string and don't have to be a regexp? str1 = "."; alert("pattern matching .".replace(str1, "string"));
                        – some
                        Jan 30 '09 at 10:31




                        You know that the first parameter to replace can be a normal string and don't have to be a regexp? str1 = "."; alert("pattern matching .".replace(str1, "string"));
                        – some
                        Jan 30 '09 at 10:31












                        @some: of course. That's because the above example is trivial. When you need to search for or replace a pattern combined with a regular string, do str.match(new RegExp("https?://" + RegExp.escape(myDomainName)), for instance. It's annoying that the escape function is not built in.
                        – Gracenotes
                        Jan 30 '09 at 19:57




                        @some: of course. That's because the above example is trivial. When you need to search for or replace a pattern combined with a regular string, do str.match(new RegExp("https?://" + RegExp.escape(myDomainName)), for instance. It's annoying that the escape function is not built in.
                        – Gracenotes
                        Jan 30 '09 at 19:57












                        (continued) Plus, apparentl JC Grubbs required a global replace; implementing a global replace with String.replace(String, String) could be slow for large input. I'm just saying, the top two solutions are buggy, and will fail unexpected on certain input.
                        – Gracenotes
                        Jan 30 '09 at 20:00




                        (continued) Plus, apparentl JC Grubbs required a global replace; implementing a global replace with String.replace(String, String) could be slow for large input. I'm just saying, the top two solutions are buggy, and will fail unexpected on certain input.
                        – Gracenotes
                        Jan 30 '09 at 20:00




                        4




                        4




                        developer.mozilla.org/en-US/docs/JavaScript/Guide/… offers a similar function, but they exclude -, and include =!:/.
                        – chbrown
                        Dec 15 '12 at 21:12




                        developer.mozilla.org/en-US/docs/JavaScript/Guide/… offers a similar function, but they exclude -, and include =!:/.
                        – chbrown
                        Dec 15 '12 at 21:12




                        4




                        4




                        The correct term is "escape", not "quote". Just BTW.
                        – Lawrence Dol
                        Dec 4 '15 at 5:19




                        The correct term is "escape", not "quote". Just BTW.
                        – Lawrence Dol
                        Dec 4 '15 at 5:19










                        up vote
                        89
                        down vote














                        "ABABAB".replace(/B/g, "A");




                        As always: don't use regex unless you have to. For a simple string replace, the idiom is:



                        'ABABAB'.split('B').join('A')


                        Then you don't have to worry about the quoting issues mentioned in Gracenotes's answer.






                        share|improve this answer


















                        • 5




                          Cool idea, wouldn't have thought of doing that!
                          – devios1
                          May 31 '12 at 19:01






                        • 8




                          And have you measured that this is faster than regex?
                          – Mitar
                          Apr 10 '13 at 3:12






                        • 2




                          This seems preferable, especially when needing to match on special regex characters like '.'
                          – Krease
                          Apr 24 '13 at 18:41






                        • 1




                          Uhm... Doesn't split take a RegExp too; if so, wouldn't it cause the same problem ? Anyway... .split().join() may be slower on some platforms, because it's two operations, whereas .replace() is one operation and may be optimized.
                          – user1985657
                          Jun 12 '13 at 22:47







                        • 5




                          @PacMan--: both split and replace can take either a string or a RegExp object. The problem that replace has that split doesn't is that when you use a string you only get a single replacement.
                          – bobince
                          Jun 13 '13 at 9:05














                        up vote
                        89
                        down vote














                        "ABABAB".replace(/B/g, "A");




                        As always: don't use regex unless you have to. For a simple string replace, the idiom is:



                        'ABABAB'.split('B').join('A')


                        Then you don't have to worry about the quoting issues mentioned in Gracenotes's answer.






                        share|improve this answer


















                        • 5




                          Cool idea, wouldn't have thought of doing that!
                          – devios1
                          May 31 '12 at 19:01






                        • 8




                          And have you measured that this is faster than regex?
                          – Mitar
                          Apr 10 '13 at 3:12






                        • 2




                          This seems preferable, especially when needing to match on special regex characters like '.'
                          – Krease
                          Apr 24 '13 at 18:41






                        • 1




                          Uhm... Doesn't split take a RegExp too; if so, wouldn't it cause the same problem ? Anyway... .split().join() may be slower on some platforms, because it's two operations, whereas .replace() is one operation and may be optimized.
                          – user1985657
                          Jun 12 '13 at 22:47







                        • 5




                          @PacMan--: both split and replace can take either a string or a RegExp object. The problem that replace has that split doesn't is that when you use a string you only get a single replacement.
                          – bobince
                          Jun 13 '13 at 9:05












                        up vote
                        89
                        down vote










                        up vote
                        89
                        down vote










                        "ABABAB".replace(/B/g, "A");




                        As always: don't use regex unless you have to. For a simple string replace, the idiom is:



                        'ABABAB'.split('B').join('A')


                        Then you don't have to worry about the quoting issues mentioned in Gracenotes's answer.






                        share|improve this answer















                        "ABABAB".replace(/B/g, "A");




                        As always: don't use regex unless you have to. For a simple string replace, the idiom is:



                        'ABABAB'.split('B').join('A')


                        Then you don't have to worry about the quoting issues mentioned in Gracenotes's answer.







                        share|improve this answer














                        share|improve this answer



                        share|improve this answer








                        edited Jan 30 at 11:45









                        Liam

                        15.7k1675125




                        15.7k1675125










                        answered Feb 1 '09 at 3:43









                        bobince

                        437k88560763




                        437k88560763







                        • 5




                          Cool idea, wouldn't have thought of doing that!
                          – devios1
                          May 31 '12 at 19:01






                        • 8




                          And have you measured that this is faster than regex?
                          – Mitar
                          Apr 10 '13 at 3:12






                        • 2




                          This seems preferable, especially when needing to match on special regex characters like '.'
                          – Krease
                          Apr 24 '13 at 18:41






                        • 1




                          Uhm... Doesn't split take a RegExp too; if so, wouldn't it cause the same problem ? Anyway... .split().join() may be slower on some platforms, because it's two operations, whereas .replace() is one operation and may be optimized.
                          – user1985657
                          Jun 12 '13 at 22:47







                        • 5




                          @PacMan--: both split and replace can take either a string or a RegExp object. The problem that replace has that split doesn't is that when you use a string you only get a single replacement.
                          – bobince
                          Jun 13 '13 at 9:05












                        • 5




                          Cool idea, wouldn't have thought of doing that!
                          – devios1
                          May 31 '12 at 19:01






                        • 8




                          And have you measured that this is faster than regex?
                          – Mitar
                          Apr 10 '13 at 3:12






                        • 2




                          This seems preferable, especially when needing to match on special regex characters like '.'
                          – Krease
                          Apr 24 '13 at 18:41






                        • 1




                          Uhm... Doesn't split take a RegExp too; if so, wouldn't it cause the same problem ? Anyway... .split().join() may be slower on some platforms, because it's two operations, whereas .replace() is one operation and may be optimized.
                          – user1985657
                          Jun 12 '13 at 22:47







                        • 5




                          @PacMan--: both split and replace can take either a string or a RegExp object. The problem that replace has that split doesn't is that when you use a string you only get a single replacement.
                          – bobince
                          Jun 13 '13 at 9:05







                        5




                        5




                        Cool idea, wouldn't have thought of doing that!
                        – devios1
                        May 31 '12 at 19:01




                        Cool idea, wouldn't have thought of doing that!
                        – devios1
                        May 31 '12 at 19:01




                        8




                        8




                        And have you measured that this is faster than regex?
                        – Mitar
                        Apr 10 '13 at 3:12




                        And have you measured that this is faster than regex?
                        – Mitar
                        Apr 10 '13 at 3:12




                        2




                        2




                        This seems preferable, especially when needing to match on special regex characters like '.'
                        – Krease
                        Apr 24 '13 at 18:41




                        This seems preferable, especially when needing to match on special regex characters like '.'
                        – Krease
                        Apr 24 '13 at 18:41




                        1




                        1




                        Uhm... Doesn't split take a RegExp too; if so, wouldn't it cause the same problem ? Anyway... .split().join() may be slower on some platforms, because it's two operations, whereas .replace() is one operation and may be optimized.
                        – user1985657
                        Jun 12 '13 at 22:47





                        Uhm... Doesn't split take a RegExp too; if so, wouldn't it cause the same problem ? Anyway... .split().join() may be slower on some platforms, because it's two operations, whereas .replace() is one operation and may be optimized.
                        – user1985657
                        Jun 12 '13 at 22:47





                        5




                        5




                        @PacMan--: both split and replace can take either a string or a RegExp object. The problem that replace has that split doesn't is that when you use a string you only get a single replacement.
                        – bobince
                        Jun 13 '13 at 9:05




                        @PacMan--: both split and replace can take either a string or a RegExp object. The problem that replace has that split doesn't is that when you use a string you only get a single replacement.
                        – bobince
                        Jun 13 '13 at 9:05










                        up vote
                        28
                        down vote













                        For anyone looking to use variable with the match method, this worked for me



                        var alpha = 'fig';
                        'food fight'.match(alpha + 'ht')[0]; // fight





                        share|improve this answer


























                          up vote
                          28
                          down vote













                          For anyone looking to use variable with the match method, this worked for me



                          var alpha = 'fig';
                          'food fight'.match(alpha + 'ht')[0]; // fight





                          share|improve this answer
























                            up vote
                            28
                            down vote










                            up vote
                            28
                            down vote









                            For anyone looking to use variable with the match method, this worked for me



                            var alpha = 'fig';
                            'food fight'.match(alpha + 'ht')[0]; // fight





                            share|improve this answer














                            For anyone looking to use variable with the match method, this worked for me



                            var alpha = 'fig';
                            'food fight'.match(alpha + 'ht')[0]; // fight






                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited May 9 '15 at 17:48

























                            answered Nov 28 '12 at 15:32









                            Steven Penny

                            1




                            1




















                                up vote
                                22
                                down vote













                                This:



                                var txt=new RegExp(pattern,attributes);


                                is equivalent to this:



                                var txt=/pattern/attributes;


                                See http://www.w3schools.com/jsref/jsref_obj_regexp.asp.






                                share|improve this answer
















                                • 11




                                  yep, but in first example it uses pattern as variable, in 2nd as a string
                                  – vladkras
                                  Jul 9 '13 at 4:16











                                • I actually find this to be the clearest answer.
                                  – Teekin
                                  Aug 18 at 16:17














                                up vote
                                22
                                down vote













                                This:



                                var txt=new RegExp(pattern,attributes);


                                is equivalent to this:



                                var txt=/pattern/attributes;


                                See http://www.w3schools.com/jsref/jsref_obj_regexp.asp.






                                share|improve this answer
















                                • 11




                                  yep, but in first example it uses pattern as variable, in 2nd as a string
                                  – vladkras
                                  Jul 9 '13 at 4:16











                                • I actually find this to be the clearest answer.
                                  – Teekin
                                  Aug 18 at 16:17












                                up vote
                                22
                                down vote










                                up vote
                                22
                                down vote









                                This:



                                var txt=new RegExp(pattern,attributes);


                                is equivalent to this:



                                var txt=/pattern/attributes;


                                See http://www.w3schools.com/jsref/jsref_obj_regexp.asp.






                                share|improve this answer












                                This:



                                var txt=new RegExp(pattern,attributes);


                                is equivalent to this:



                                var txt=/pattern/attributes;


                                See http://www.w3schools.com/jsref/jsref_obj_regexp.asp.







                                share|improve this answer












                                share|improve this answer



                                share|improve this answer










                                answered Jan 30 '09 at 0:19









                                Jeremy Ruten

                                122k34155184




                                122k34155184







                                • 11




                                  yep, but in first example it uses pattern as variable, in 2nd as a string
                                  – vladkras
                                  Jul 9 '13 at 4:16











                                • I actually find this to be the clearest answer.
                                  – Teekin
                                  Aug 18 at 16:17












                                • 11




                                  yep, but in first example it uses pattern as variable, in 2nd as a string
                                  – vladkras
                                  Jul 9 '13 at 4:16











                                • I actually find this to be the clearest answer.
                                  – Teekin
                                  Aug 18 at 16:17







                                11




                                11




                                yep, but in first example it uses pattern as variable, in 2nd as a string
                                – vladkras
                                Jul 9 '13 at 4:16





                                yep, but in first example it uses pattern as variable, in 2nd as a string
                                – vladkras
                                Jul 9 '13 at 4:16













                                I actually find this to be the clearest answer.
                                – Teekin
                                Aug 18 at 16:17




                                I actually find this to be the clearest answer.
                                – Teekin
                                Aug 18 at 16:17










                                up vote
                                14
                                down vote













                                this.replace( new RegExp( replaceThis, 'g' ), withThis );





                                share|improve this answer


























                                  up vote
                                  14
                                  down vote













                                  this.replace( new RegExp( replaceThis, 'g' ), withThis );





                                  share|improve this answer
























                                    up vote
                                    14
                                    down vote










                                    up vote
                                    14
                                    down vote









                                    this.replace( new RegExp( replaceThis, 'g' ), withThis );





                                    share|improve this answer














                                    this.replace( new RegExp( replaceThis, 'g' ), withThis );






                                    share|improve this answer














                                    share|improve this answer



                                    share|improve this answer








                                    edited Jan 16 '12 at 16:22









                                    Mike Samuel

                                    91.6k23169212




                                    91.6k23169212










                                    answered Jan 30 '09 at 0:16









                                    tvanfosson

                                    420k78639747




                                    420k78639747




















                                        up vote
                                        9
                                        down vote













                                        String.prototype.replaceAll = function (replaceThis, withThis) 
                                        var re = new RegExp(replaceThis,"g");
                                        return this.replace(re, withThis);
                                        ;
                                        var aa = "abab54..aba".replaceAll("\.", "v");


                                        Test with this tool






                                        share|improve this answer


























                                          up vote
                                          9
                                          down vote













                                          String.prototype.replaceAll = function (replaceThis, withThis) 
                                          var re = new RegExp(replaceThis,"g");
                                          return this.replace(re, withThis);
                                          ;
                                          var aa = "abab54..aba".replaceAll("\.", "v");


                                          Test with this tool






                                          share|improve this answer
























                                            up vote
                                            9
                                            down vote










                                            up vote
                                            9
                                            down vote









                                            String.prototype.replaceAll = function (replaceThis, withThis) 
                                            var re = new RegExp(replaceThis,"g");
                                            return this.replace(re, withThis);
                                            ;
                                            var aa = "abab54..aba".replaceAll("\.", "v");


                                            Test with this tool






                                            share|improve this answer














                                            String.prototype.replaceAll = function (replaceThis, withThis) 
                                            var re = new RegExp(replaceThis,"g");
                                            return this.replace(re, withThis);
                                            ;
                                            var aa = "abab54..aba".replaceAll("\.", "v");


                                            Test with this tool







                                            share|improve this answer














                                            share|improve this answer



                                            share|improve this answer








                                            edited Feb 1 '09 at 9:28

























                                            answered Feb 1 '09 at 9:14









                                            unigogo

                                            47948




                                            47948




















                                                up vote
                                                7
                                                down vote













                                                You want to build the regular expression dynamically and for this the proper solutuion is to use the new RegExp(string) constructor. In order for constructor to treat special characters literally, you must escape them. There is a built-in function in jQuery UI autocomplete widget called $.ui.autocomplete.escapeRegex:




                                                [...] you can make use of the built-in
                                                $.ui.autocomplete.escapeRegex function. It'll take a single string
                                                argument and escape all regex characters, making the result safe to
                                                pass to new RegExp().




                                                If you are using jQuery UI you can use that function, or copy its definition from the source:



                                                function escapeRegex(value) #s]/g, "\$&" );



                                                And use it like this:



                                                "[z-a][z-a][z-a]".replace(new RegExp(escapeRegex("[z-a]"), "g"), "[a-z]");
                                                // escapeRegex("[z-a]") -> "[z-a]"
                                                // new RegExp(escapeRegex("[z-a]"), "g") -> /[z-a]/g
                                                // end result -> "[a-z][a-z][a-z]"





                                                share|improve this answer


























                                                  up vote
                                                  7
                                                  down vote













                                                  You want to build the regular expression dynamically and for this the proper solutuion is to use the new RegExp(string) constructor. In order for constructor to treat special characters literally, you must escape them. There is a built-in function in jQuery UI autocomplete widget called $.ui.autocomplete.escapeRegex:




                                                  [...] you can make use of the built-in
                                                  $.ui.autocomplete.escapeRegex function. It'll take a single string
                                                  argument and escape all regex characters, making the result safe to
                                                  pass to new RegExp().




                                                  If you are using jQuery UI you can use that function, or copy its definition from the source:



                                                  function escapeRegex(value) #s]/g, "\$&" );



                                                  And use it like this:



                                                  "[z-a][z-a][z-a]".replace(new RegExp(escapeRegex("[z-a]"), "g"), "[a-z]");
                                                  // escapeRegex("[z-a]") -> "[z-a]"
                                                  // new RegExp(escapeRegex("[z-a]"), "g") -> /[z-a]/g
                                                  // end result -> "[a-z][a-z][a-z]"





                                                  share|improve this answer
























                                                    up vote
                                                    7
                                                    down vote










                                                    up vote
                                                    7
                                                    down vote









                                                    You want to build the regular expression dynamically and for this the proper solutuion is to use the new RegExp(string) constructor. In order for constructor to treat special characters literally, you must escape them. There is a built-in function in jQuery UI autocomplete widget called $.ui.autocomplete.escapeRegex:




                                                    [...] you can make use of the built-in
                                                    $.ui.autocomplete.escapeRegex function. It'll take a single string
                                                    argument and escape all regex characters, making the result safe to
                                                    pass to new RegExp().




                                                    If you are using jQuery UI you can use that function, or copy its definition from the source:



                                                    function escapeRegex(value) #s]/g, "\$&" );



                                                    And use it like this:



                                                    "[z-a][z-a][z-a]".replace(new RegExp(escapeRegex("[z-a]"), "g"), "[a-z]");
                                                    // escapeRegex("[z-a]") -> "[z-a]"
                                                    // new RegExp(escapeRegex("[z-a]"), "g") -> /[z-a]/g
                                                    // end result -> "[a-z][a-z][a-z]"





                                                    share|improve this answer














                                                    You want to build the regular expression dynamically and for this the proper solutuion is to use the new RegExp(string) constructor. In order for constructor to treat special characters literally, you must escape them. There is a built-in function in jQuery UI autocomplete widget called $.ui.autocomplete.escapeRegex:




                                                    [...] you can make use of the built-in
                                                    $.ui.autocomplete.escapeRegex function. It'll take a single string
                                                    argument and escape all regex characters, making the result safe to
                                                    pass to new RegExp().




                                                    If you are using jQuery UI you can use that function, or copy its definition from the source:



                                                    function escapeRegex(value) #s]/g, "\$&" );



                                                    And use it like this:



                                                    "[z-a][z-a][z-a]".replace(new RegExp(escapeRegex("[z-a]"), "g"), "[a-z]");
                                                    // escapeRegex("[z-a]") -> "[z-a]"
                                                    // new RegExp(escapeRegex("[z-a]"), "g") -> /[z-a]/g
                                                    // end result -> "[a-z][a-z][a-z]"






                                                    share|improve this answer














                                                    share|improve this answer



                                                    share|improve this answer








                                                    edited Jan 27 '16 at 6:24

























                                                    answered Sep 14 '14 at 19:55









                                                    Salman A

                                                    170k65327413




                                                    170k65327413




















                                                        up vote
                                                        5
                                                        down vote













                                                        If you want to get ALL occurrences (g), be case insensitive (i), and use boundaries so that it isn't a word within another word (\b):



                                                        re = new RegExp(`\b$replaceThis\b`, 'gi');



                                                        Example:



                                                        let inputString = "I'm John, or johnny, but I prefer john.";
                                                        let replaceThis = "John";
                                                        let re = new RegExp(`\b$replaceThis\b`, 'gi');
                                                        console.log(inputString.replace(re, "Jack")); // I'm Jack, or johnny, but I prefer Jack.





                                                        share|improve this answer
























                                                          up vote
                                                          5
                                                          down vote













                                                          If you want to get ALL occurrences (g), be case insensitive (i), and use boundaries so that it isn't a word within another word (\b):



                                                          re = new RegExp(`\b$replaceThis\b`, 'gi');



                                                          Example:



                                                          let inputString = "I'm John, or johnny, but I prefer john.";
                                                          let replaceThis = "John";
                                                          let re = new RegExp(`\b$replaceThis\b`, 'gi');
                                                          console.log(inputString.replace(re, "Jack")); // I'm Jack, or johnny, but I prefer Jack.





                                                          share|improve this answer






















                                                            up vote
                                                            5
                                                            down vote










                                                            up vote
                                                            5
                                                            down vote









                                                            If you want to get ALL occurrences (g), be case insensitive (i), and use boundaries so that it isn't a word within another word (\b):



                                                            re = new RegExp(`\b$replaceThis\b`, 'gi');



                                                            Example:



                                                            let inputString = "I'm John, or johnny, but I prefer john.";
                                                            let replaceThis = "John";
                                                            let re = new RegExp(`\b$replaceThis\b`, 'gi');
                                                            console.log(inputString.replace(re, "Jack")); // I'm Jack, or johnny, but I prefer Jack.





                                                            share|improve this answer












                                                            If you want to get ALL occurrences (g), be case insensitive (i), and use boundaries so that it isn't a word within another word (\b):



                                                            re = new RegExp(`\b$replaceThis\b`, 'gi');



                                                            Example:



                                                            let inputString = "I'm John, or johnny, but I prefer john.";
                                                            let replaceThis = "John";
                                                            let re = new RegExp(`\b$replaceThis\b`, 'gi');
                                                            console.log(inputString.replace(re, "Jack")); // I'm Jack, or johnny, but I prefer Jack.






                                                            share|improve this answer












                                                            share|improve this answer



                                                            share|improve this answer










                                                            answered Jun 13 at 2:52









                                                            JBallin

                                                            803919




                                                            803919




















                                                                up vote
                                                                4
                                                                down vote













                                                                Here's another replaceAll implementation:



                                                                 String.prototype.replaceAll = function (stringToFind, stringToReplace) 
                                                                if ( stringToFind == stringToReplace) return this;
                                                                var temp = this;
                                                                var index = temp.indexOf(stringToFind);
                                                                while (index != -1)
                                                                temp = temp.replace(stringToFind, stringToReplace);
                                                                index = temp.indexOf(stringToFind);

                                                                return temp;
                                                                ;





                                                                share|improve this answer
























                                                                  up vote
                                                                  4
                                                                  down vote













                                                                  Here's another replaceAll implementation:



                                                                   String.prototype.replaceAll = function (stringToFind, stringToReplace) 
                                                                  if ( stringToFind == stringToReplace) return this;
                                                                  var temp = this;
                                                                  var index = temp.indexOf(stringToFind);
                                                                  while (index != -1)
                                                                  temp = temp.replace(stringToFind, stringToReplace);
                                                                  index = temp.indexOf(stringToFind);

                                                                  return temp;
                                                                  ;





                                                                  share|improve this answer






















                                                                    up vote
                                                                    4
                                                                    down vote










                                                                    up vote
                                                                    4
                                                                    down vote









                                                                    Here's another replaceAll implementation:



                                                                     String.prototype.replaceAll = function (stringToFind, stringToReplace) 
                                                                    if ( stringToFind == stringToReplace) return this;
                                                                    var temp = this;
                                                                    var index = temp.indexOf(stringToFind);
                                                                    while (index != -1)
                                                                    temp = temp.replace(stringToFind, stringToReplace);
                                                                    index = temp.indexOf(stringToFind);

                                                                    return temp;
                                                                    ;





                                                                    share|improve this answer












                                                                    Here's another replaceAll implementation:



                                                                     String.prototype.replaceAll = function (stringToFind, stringToReplace) 
                                                                    if ( stringToFind == stringToReplace) return this;
                                                                    var temp = this;
                                                                    var index = temp.indexOf(stringToFind);
                                                                    while (index != -1)
                                                                    temp = temp.replace(stringToFind, stringToReplace);
                                                                    index = temp.indexOf(stringToFind);

                                                                    return temp;
                                                                    ;






                                                                    share|improve this answer












                                                                    share|improve this answer



                                                                    share|improve this answer










                                                                    answered May 8 '13 at 10:30









                                                                    scripto

                                                                    2,1331911




                                                                    2,1331911




















                                                                        up vote
                                                                        3
                                                                        down vote













                                                                        While you can make dynamically-created RegExp's (as per the other responses to this question), I'll echo my comment from a similar post: The functional form of String.replace() is extremely useful and in many cases reduces the need for dynamically-created RegExp objects. (which are kind of a pain 'cause you have to express the input to the RegExp constructor as a string rather than use the slashes /[A-Z]+/ regexp literal format)






                                                                        share|improve this answer


























                                                                          up vote
                                                                          3
                                                                          down vote













                                                                          While you can make dynamically-created RegExp's (as per the other responses to this question), I'll echo my comment from a similar post: The functional form of String.replace() is extremely useful and in many cases reduces the need for dynamically-created RegExp objects. (which are kind of a pain 'cause you have to express the input to the RegExp constructor as a string rather than use the slashes /[A-Z]+/ regexp literal format)






                                                                          share|improve this answer
























                                                                            up vote
                                                                            3
                                                                            down vote










                                                                            up vote
                                                                            3
                                                                            down vote









                                                                            While you can make dynamically-created RegExp's (as per the other responses to this question), I'll echo my comment from a similar post: The functional form of String.replace() is extremely useful and in many cases reduces the need for dynamically-created RegExp objects. (which are kind of a pain 'cause you have to express the input to the RegExp constructor as a string rather than use the slashes /[A-Z]+/ regexp literal format)






                                                                            share|improve this answer














                                                                            While you can make dynamically-created RegExp's (as per the other responses to this question), I'll echo my comment from a similar post: The functional form of String.replace() is extremely useful and in many cases reduces the need for dynamically-created RegExp objects. (which are kind of a pain 'cause you have to express the input to the RegExp constructor as a string rather than use the slashes /[A-Z]+/ regexp literal format)







                                                                            share|improve this answer














                                                                            share|improve this answer



                                                                            share|improve this answer








                                                                            edited May 23 '17 at 12:10









                                                                            Community

                                                                            11




                                                                            11










                                                                            answered Jan 30 '09 at 1:02









                                                                            Jason S

                                                                            105k133473810




                                                                            105k133473810




















                                                                                up vote
                                                                                3
                                                                                down vote













                                                                                To satisfy my need to insert a variable/alias/function into a Regular Expression, this is what I came up with:



                                                                                oldre = /xx("")/;
                                                                                function newre(e)
                                                                                return RegExp(e.toString().replace(///g,"").replace(/xx/g, yy), "g")
                                                                                ;

                                                                                String.prototype.replaceAll = this.replace(newre(oldre), "withThis");


                                                                                where 'oldre' is the original regexp that I want to insert a variable,
                                                                                'xx' is the placeholder for that variable/alias/function,
                                                                                and 'yy' is the actual variable name, alias, or function.






                                                                                share|improve this answer


























                                                                                  up vote
                                                                                  3
                                                                                  down vote













                                                                                  To satisfy my need to insert a variable/alias/function into a Regular Expression, this is what I came up with:



                                                                                  oldre = /xx("")/;
                                                                                  function newre(e)
                                                                                  return RegExp(e.toString().replace(///g,"").replace(/xx/g, yy), "g")
                                                                                  ;

                                                                                  String.prototype.replaceAll = this.replace(newre(oldre), "withThis");


                                                                                  where 'oldre' is the original regexp that I want to insert a variable,
                                                                                  'xx' is the placeholder for that variable/alias/function,
                                                                                  and 'yy' is the actual variable name, alias, or function.






                                                                                  share|improve this answer
























                                                                                    up vote
                                                                                    3
                                                                                    down vote










                                                                                    up vote
                                                                                    3
                                                                                    down vote









                                                                                    To satisfy my need to insert a variable/alias/function into a Regular Expression, this is what I came up with:



                                                                                    oldre = /xx("")/;
                                                                                    function newre(e)
                                                                                    return RegExp(e.toString().replace(///g,"").replace(/xx/g, yy), "g")
                                                                                    ;

                                                                                    String.prototype.replaceAll = this.replace(newre(oldre), "withThis");


                                                                                    where 'oldre' is the original regexp that I want to insert a variable,
                                                                                    'xx' is the placeholder for that variable/alias/function,
                                                                                    and 'yy' is the actual variable name, alias, or function.






                                                                                    share|improve this answer














                                                                                    To satisfy my need to insert a variable/alias/function into a Regular Expression, this is what I came up with:



                                                                                    oldre = /xx("")/;
                                                                                    function newre(e)
                                                                                    return RegExp(e.toString().replace(///g,"").replace(/xx/g, yy), "g")
                                                                                    ;

                                                                                    String.prototype.replaceAll = this.replace(newre(oldre), "withThis");


                                                                                    where 'oldre' is the original regexp that I want to insert a variable,
                                                                                    'xx' is the placeholder for that variable/alias/function,
                                                                                    and 'yy' is the actual variable name, alias, or function.







                                                                                    share|improve this answer














                                                                                    share|improve this answer



                                                                                    share|improve this answer








                                                                                    edited Jun 5 '13 at 4:38

























                                                                                    answered Jun 5 '13 at 4:22









                                                                                    Alex Li

                                                                                    312




                                                                                    312




















                                                                                        up vote
                                                                                        3
                                                                                        down vote













                                                                                        String.prototype.replaceAll = function(a, b) 
                                                                                        return this.replace(new RegExp(a.replace(/([.?*+^$[]\()


                                                                                        Test it like:



                                                                                        var whatever = 'Some [b]random[/b] text in a [b]sentence.[/b]'

                                                                                        console.log(whatever.replaceAll("[", "<").replaceAll("]", ">"))





                                                                                        share|improve this answer
























                                                                                          up vote
                                                                                          3
                                                                                          down vote













                                                                                          String.prototype.replaceAll = function(a, b) 
                                                                                          return this.replace(new RegExp(a.replace(/([.?*+^$[]\()


                                                                                          Test it like:



                                                                                          var whatever = 'Some [b]random[/b] text in a [b]sentence.[/b]'

                                                                                          console.log(whatever.replaceAll("[", "<").replaceAll("]", ">"))





                                                                                          share|improve this answer






















                                                                                            up vote
                                                                                            3
                                                                                            down vote










                                                                                            up vote
                                                                                            3
                                                                                            down vote









                                                                                            String.prototype.replaceAll = function(a, b) 
                                                                                            return this.replace(new RegExp(a.replace(/([.?*+^$[]\()


                                                                                            Test it like:



                                                                                            var whatever = 'Some [b]random[/b] text in a [b]sentence.[/b]'

                                                                                            console.log(whatever.replaceAll("[", "<").replaceAll("]", ">"))





                                                                                            share|improve this answer












                                                                                            String.prototype.replaceAll = function(a, b) 
                                                                                            return this.replace(new RegExp(a.replace(/([.?*+^$[]\()


                                                                                            Test it like:



                                                                                            var whatever = 'Some [b]random[/b] text in a [b]sentence.[/b]'

                                                                                            console.log(whatever.replaceAll("[", "<").replaceAll("]", ">"))






                                                                                            share|improve this answer












                                                                                            share|improve this answer



                                                                                            share|improve this answer










                                                                                            answered Aug 20 '13 at 12:35









                                                                                            MetalGodwin

                                                                                            2,438299




                                                                                            2,438299




















                                                                                                up vote
                                                                                                3
                                                                                                down vote













                                                                                                And the coffeescript version of Steven Penny's answer, since this is #2 google result....even if coffee is just javascript with a lot of characters removed...;)



                                                                                                baz = "foo"
                                                                                                filter = new RegExp(baz + "d")
                                                                                                "food fight".match(filter)[0] // food


                                                                                                and in my particular case



                                                                                                robot.name=hubot
                                                                                                filter = new RegExp(robot.name)
                                                                                                if msg.match.input.match(filter)
                                                                                                console.log "True!"





                                                                                                share|improve this answer






















                                                                                                • why a downvote? coffeescript -IS- javascript with it's own specific syntax.
                                                                                                  – keen
                                                                                                  Aug 26 '15 at 15:53














                                                                                                up vote
                                                                                                3
                                                                                                down vote













                                                                                                And the coffeescript version of Steven Penny's answer, since this is #2 google result....even if coffee is just javascript with a lot of characters removed...;)



                                                                                                baz = "foo"
                                                                                                filter = new RegExp(baz + "d")
                                                                                                "food fight".match(filter)[0] // food


                                                                                                and in my particular case



                                                                                                robot.name=hubot
                                                                                                filter = new RegExp(robot.name)
                                                                                                if msg.match.input.match(filter)
                                                                                                console.log "True!"





                                                                                                share|improve this answer






















                                                                                                • why a downvote? coffeescript -IS- javascript with it's own specific syntax.
                                                                                                  – keen
                                                                                                  Aug 26 '15 at 15:53












                                                                                                up vote
                                                                                                3
                                                                                                down vote










                                                                                                up vote
                                                                                                3
                                                                                                down vote









                                                                                                And the coffeescript version of Steven Penny's answer, since this is #2 google result....even if coffee is just javascript with a lot of characters removed...;)



                                                                                                baz = "foo"
                                                                                                filter = new RegExp(baz + "d")
                                                                                                "food fight".match(filter)[0] // food


                                                                                                and in my particular case



                                                                                                robot.name=hubot
                                                                                                filter = new RegExp(robot.name)
                                                                                                if msg.match.input.match(filter)
                                                                                                console.log "True!"





                                                                                                share|improve this answer














                                                                                                And the coffeescript version of Steven Penny's answer, since this is #2 google result....even if coffee is just javascript with a lot of characters removed...;)



                                                                                                baz = "foo"
                                                                                                filter = new RegExp(baz + "d")
                                                                                                "food fight".match(filter)[0] // food


                                                                                                and in my particular case



                                                                                                robot.name=hubot
                                                                                                filter = new RegExp(robot.name)
                                                                                                if msg.match.input.match(filter)
                                                                                                console.log "True!"






                                                                                                share|improve this answer














                                                                                                share|improve this answer



                                                                                                share|improve this answer








                                                                                                edited Oct 29 '15 at 15:49

























                                                                                                answered Nov 25 '14 at 23:31









                                                                                                keen

                                                                                                637710




                                                                                                637710











                                                                                                • why a downvote? coffeescript -IS- javascript with it's own specific syntax.
                                                                                                  – keen
                                                                                                  Aug 26 '15 at 15:53
















                                                                                                • why a downvote? coffeescript -IS- javascript with it's own specific syntax.
                                                                                                  – keen
                                                                                                  Aug 26 '15 at 15:53















                                                                                                why a downvote? coffeescript -IS- javascript with it's own specific syntax.
                                                                                                – keen
                                                                                                Aug 26 '15 at 15:53




                                                                                                why a downvote? coffeescript -IS- javascript with it's own specific syntax.
                                                                                                – keen
                                                                                                Aug 26 '15 at 15:53










                                                                                                up vote
                                                                                                1
                                                                                                down vote













                                                                                                You can use this if $1 not work with you



                                                                                                var pattern = new RegExp("amman","i");
                                                                                                "abc Amman efg".replace(pattern,"<b>"+"abc Amman efg".match(pattern)[0]+"</b>");





                                                                                                share|improve this answer
























                                                                                                  up vote
                                                                                                  1
                                                                                                  down vote













                                                                                                  You can use this if $1 not work with you



                                                                                                  var pattern = new RegExp("amman","i");
                                                                                                  "abc Amman efg".replace(pattern,"<b>"+"abc Amman efg".match(pattern)[0]+"</b>");





                                                                                                  share|improve this answer






















                                                                                                    up vote
                                                                                                    1
                                                                                                    down vote










                                                                                                    up vote
                                                                                                    1
                                                                                                    down vote









                                                                                                    You can use this if $1 not work with you



                                                                                                    var pattern = new RegExp("amman","i");
                                                                                                    "abc Amman efg".replace(pattern,"<b>"+"abc Amman efg".match(pattern)[0]+"</b>");





                                                                                                    share|improve this answer












                                                                                                    You can use this if $1 not work with you



                                                                                                    var pattern = new RegExp("amman","i");
                                                                                                    "abc Amman efg".replace(pattern,"<b>"+"abc Amman efg".match(pattern)[0]+"</b>");






                                                                                                    share|improve this answer












                                                                                                    share|improve this answer



                                                                                                    share|improve this answer










                                                                                                    answered Jun 13 '13 at 11:13









                                                                                                    Fareed Alnamrouti

                                                                                                    19.3k25955




                                                                                                    19.3k25955




















                                                                                                        up vote
                                                                                                        1
                                                                                                        down vote













                                                                                                        You can always use indexOf repeatedly:



                                                                                                        String.prototype.replaceAll = function(substring, replacement) 
                                                                                                        var result = '';
                                                                                                        var lastIndex = 0;

                                                                                                        while(true)
                                                                                                        var index = this.indexOf(substring, lastIndex);
                                                                                                        if(index === -1) break;
                                                                                                        result += this.substring(lastIndex, index) + replacement;
                                                                                                        lastIndex = index + substring.length;


                                                                                                        return result + this.substring(lastIndex);
                                                                                                        ;


                                                                                                        This doesn’t go into an infinite loop when the replacement contains the match.






                                                                                                        share|improve this answer
























                                                                                                          up vote
                                                                                                          1
                                                                                                          down vote













                                                                                                          You can always use indexOf repeatedly:



                                                                                                          String.prototype.replaceAll = function(substring, replacement) 
                                                                                                          var result = '';
                                                                                                          var lastIndex = 0;

                                                                                                          while(true)
                                                                                                          var index = this.indexOf(substring, lastIndex);
                                                                                                          if(index === -1) break;
                                                                                                          result += this.substring(lastIndex, index) + replacement;
                                                                                                          lastIndex = index + substring.length;


                                                                                                          return result + this.substring(lastIndex);
                                                                                                          ;


                                                                                                          This doesn’t go into an infinite loop when the replacement contains the match.






                                                                                                          share|improve this answer






















                                                                                                            up vote
                                                                                                            1
                                                                                                            down vote










                                                                                                            up vote
                                                                                                            1
                                                                                                            down vote









                                                                                                            You can always use indexOf repeatedly:



                                                                                                            String.prototype.replaceAll = function(substring, replacement) 
                                                                                                            var result = '';
                                                                                                            var lastIndex = 0;

                                                                                                            while(true)
                                                                                                            var index = this.indexOf(substring, lastIndex);
                                                                                                            if(index === -1) break;
                                                                                                            result += this.substring(lastIndex, index) + replacement;
                                                                                                            lastIndex = index + substring.length;


                                                                                                            return result + this.substring(lastIndex);
                                                                                                            ;


                                                                                                            This doesn’t go into an infinite loop when the replacement contains the match.






                                                                                                            share|improve this answer












                                                                                                            You can always use indexOf repeatedly:



                                                                                                            String.prototype.replaceAll = function(substring, replacement) 
                                                                                                            var result = '';
                                                                                                            var lastIndex = 0;

                                                                                                            while(true)
                                                                                                            var index = this.indexOf(substring, lastIndex);
                                                                                                            if(index === -1) break;
                                                                                                            result += this.substring(lastIndex, index) + replacement;
                                                                                                            lastIndex = index + substring.length;


                                                                                                            return result + this.substring(lastIndex);
                                                                                                            ;


                                                                                                            This doesn’t go into an infinite loop when the replacement contains the match.







                                                                                                            share|improve this answer












                                                                                                            share|improve this answer



                                                                                                            share|improve this answer










                                                                                                            answered Aug 16 '13 at 19:53









                                                                                                            Ry-

                                                                                                            165k36333354




                                                                                                            165k36333354




















                                                                                                                up vote
                                                                                                                1
                                                                                                                down vote













                                                                                                                Your solution is here:



                                                                                                                Pass a variable to regular expression.



                                                                                                                The one which I have implemented is by taking the value from a text field which is the one you want to replace and another is the "replace with" text field, getting the value from text-field in a variable and setting the variable to RegExp function to further replace. In my case I am using Jquery, you also can do it by only JavaScript too.



                                                                                                                JavaScript code:



                                                                                                                 var replace =document.getElementById("replace}"); // getting a value from a text field with I want to replace
                                                                                                                var replace_with = document.getElementById("with"); //Getting the value from another text fields with which I want to replace another string.

                                                                                                                var sRegExInput = new RegExp(replace, "g");
                                                                                                                $("body").children().each(function()
                                                                                                                $(this).html($(this).html().replace(sRegExInput,replace_with));
                                                                                                                );


                                                                                                                This code is on Onclick event of a button, you can put this in a function to call.



                                                                                                                So now You can pass variable in replace function.






                                                                                                                share|improve this answer






















                                                                                                                • Your replace_with variable will contain the DOM element not the value itself
                                                                                                                  – Ben Taliadoros
                                                                                                                  Oct 27 '17 at 14:26














                                                                                                                up vote
                                                                                                                1
                                                                                                                down vote













                                                                                                                Your solution is here:



                                                                                                                Pass a variable to regular expression.



                                                                                                                The one which I have implemented is by taking the value from a text field which is the one you want to replace and another is the "replace with" text field, getting the value from text-field in a variable and setting the variable to RegExp function to further replace. In my case I am using Jquery, you also can do it by only JavaScript too.



                                                                                                                JavaScript code:



                                                                                                                 var replace =document.getElementById("replace}"); // getting a value from a text field with I want to replace
                                                                                                                var replace_with = document.getElementById("with"); //Getting the value from another text fields with which I want to replace another string.

                                                                                                                var sRegExInput = new RegExp(replace, "g");
                                                                                                                $("body").children().each(function()
                                                                                                                $(this).html($(this).html().replace(sRegExInput,replace_with));
                                                                                                                );


                                                                                                                This code is on Onclick event of a button, you can put this in a function to call.



                                                                                                                So now You can pass variable in replace function.






                                                                                                                share|improve this answer






















                                                                                                                • Your replace_with variable will contain the DOM element not the value itself
                                                                                                                  – Ben Taliadoros
                                                                                                                  Oct 27 '17 at 14:26












                                                                                                                up vote
                                                                                                                1
                                                                                                                down vote










                                                                                                                up vote
                                                                                                                1
                                                                                                                down vote









                                                                                                                Your solution is here:



                                                                                                                Pass a variable to regular expression.



                                                                                                                The one which I have implemented is by taking the value from a text field which is the one you want to replace and another is the "replace with" text field, getting the value from text-field in a variable and setting the variable to RegExp function to further replace. In my case I am using Jquery, you also can do it by only JavaScript too.



                                                                                                                JavaScript code:



                                                                                                                 var replace =document.getElementById("replace}"); // getting a value from a text field with I want to replace
                                                                                                                var replace_with = document.getElementById("with"); //Getting the value from another text fields with which I want to replace another string.

                                                                                                                var sRegExInput = new RegExp(replace, "g");
                                                                                                                $("body").children().each(function()
                                                                                                                $(this).html($(this).html().replace(sRegExInput,replace_with));
                                                                                                                );


                                                                                                                This code is on Onclick event of a button, you can put this in a function to call.



                                                                                                                So now You can pass variable in replace function.






                                                                                                                share|improve this answer














                                                                                                                Your solution is here:



                                                                                                                Pass a variable to regular expression.



                                                                                                                The one which I have implemented is by taking the value from a text field which is the one you want to replace and another is the "replace with" text field, getting the value from text-field in a variable and setting the variable to RegExp function to further replace. In my case I am using Jquery, you also can do it by only JavaScript too.



                                                                                                                JavaScript code:



                                                                                                                 var replace =document.getElementById("replace}"); // getting a value from a text field with I want to replace
                                                                                                                var replace_with = document.getElementById("with"); //Getting the value from another text fields with which I want to replace another string.

                                                                                                                var sRegExInput = new RegExp(replace, "g");
                                                                                                                $("body").children().each(function()
                                                                                                                $(this).html($(this).html().replace(sRegExInput,replace_with));
                                                                                                                );


                                                                                                                This code is on Onclick event of a button, you can put this in a function to call.



                                                                                                                So now You can pass variable in replace function.







                                                                                                                share|improve this answer














                                                                                                                share|improve this answer



                                                                                                                share|improve this answer








                                                                                                                edited Jul 12 at 6:56









                                                                                                                Saikat

                                                                                                                2,29053255




                                                                                                                2,29053255










                                                                                                                answered Oct 27 '15 at 5:56









                                                                                                                Ajit Hogade

                                                                                                                599320




                                                                                                                599320











                                                                                                                • Your replace_with variable will contain the DOM element not the value itself
                                                                                                                  – Ben Taliadoros
                                                                                                                  Oct 27 '17 at 14:26
















                                                                                                                • Your replace_with variable will contain the DOM element not the value itself
                                                                                                                  – Ben Taliadoros
                                                                                                                  Oct 27 '17 at 14:26















                                                                                                                Your replace_with variable will contain the DOM element not the value itself
                                                                                                                – Ben Taliadoros
                                                                                                                Oct 27 '17 at 14:26




                                                                                                                Your replace_with variable will contain the DOM element not the value itself
                                                                                                                – Ben Taliadoros
                                                                                                                Oct 27 '17 at 14:26










                                                                                                                up vote
                                                                                                                0
                                                                                                                down vote













                                                                                                                None of these answers were clear to me. I eventually found a good explanation at http://burnignorance.com/php-programming-tips/how-to-use-a-variable-in-replace-function-of-javascript/



                                                                                                                The simple answer is:



                                                                                                                var search_term = new RegExp(search_term, "g"); 
                                                                                                                text = text.replace(search_term, replace_term);


                                                                                                                For example:






                                                                                                                $("button").click(function() 
                                                                                                                Find_and_replace("Lorem", "Chocolate");
                                                                                                                Find_and_replace("ipsum", "ice-cream");
                                                                                                                );

                                                                                                                function Find_and_replace(search_term, replace_term)
                                                                                                                text = $("textbox").html();
                                                                                                                var search_term = new RegExp(search_term, "g");
                                                                                                                text = text.replace(search_term, replace_term);
                                                                                                                $("textbox").html(text);

                                                                                                                <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                                                                                                                <textbox>
                                                                                                                Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum
                                                                                                                </textbox>
                                                                                                                <button>Click me</button>








                                                                                                                share|improve this answer




















                                                                                                                • You're overwriting a closure variable, no need to use var here. Also, if you pass b or 1 it would break.
                                                                                                                  – CyberAP
                                                                                                                  Nov 6 at 19:00














                                                                                                                up vote
                                                                                                                0
                                                                                                                down vote













                                                                                                                None of these answers were clear to me. I eventually found a good explanation at http://burnignorance.com/php-programming-tips/how-to-use-a-variable-in-replace-function-of-javascript/



                                                                                                                The simple answer is:



                                                                                                                var search_term = new RegExp(search_term, "g"); 
                                                                                                                text = text.replace(search_term, replace_term);


                                                                                                                For example:






                                                                                                                $("button").click(function() 
                                                                                                                Find_and_replace("Lorem", "Chocolate");
                                                                                                                Find_and_replace("ipsum", "ice-cream");
                                                                                                                );

                                                                                                                function Find_and_replace(search_term, replace_term)
                                                                                                                text = $("textbox").html();
                                                                                                                var search_term = new RegExp(search_term, "g");
                                                                                                                text = text.replace(search_term, replace_term);
                                                                                                                $("textbox").html(text);

                                                                                                                <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                                                                                                                <textbox>
                                                                                                                Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum
                                                                                                                </textbox>
                                                                                                                <button>Click me</button>








                                                                                                                share|improve this answer




















                                                                                                                • You're overwriting a closure variable, no need to use var here. Also, if you pass b or 1 it would break.
                                                                                                                  – CyberAP
                                                                                                                  Nov 6 at 19:00












                                                                                                                up vote
                                                                                                                0
                                                                                                                down vote










                                                                                                                up vote
                                                                                                                0
                                                                                                                down vote









                                                                                                                None of these answers were clear to me. I eventually found a good explanation at http://burnignorance.com/php-programming-tips/how-to-use-a-variable-in-replace-function-of-javascript/



                                                                                                                The simple answer is:



                                                                                                                var search_term = new RegExp(search_term, "g"); 
                                                                                                                text = text.replace(search_term, replace_term);


                                                                                                                For example:






                                                                                                                $("button").click(function() 
                                                                                                                Find_and_replace("Lorem", "Chocolate");
                                                                                                                Find_and_replace("ipsum", "ice-cream");
                                                                                                                );

                                                                                                                function Find_and_replace(search_term, replace_term)
                                                                                                                text = $("textbox").html();
                                                                                                                var search_term = new RegExp(search_term, "g");
                                                                                                                text = text.replace(search_term, replace_term);
                                                                                                                $("textbox").html(text);

                                                                                                                <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                                                                                                                <textbox>
                                                                                                                Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum
                                                                                                                </textbox>
                                                                                                                <button>Click me</button>








                                                                                                                share|improve this answer












                                                                                                                None of these answers were clear to me. I eventually found a good explanation at http://burnignorance.com/php-programming-tips/how-to-use-a-variable-in-replace-function-of-javascript/



                                                                                                                The simple answer is:



                                                                                                                var search_term = new RegExp(search_term, "g"); 
                                                                                                                text = text.replace(search_term, replace_term);


                                                                                                                For example:






                                                                                                                $("button").click(function() 
                                                                                                                Find_and_replace("Lorem", "Chocolate");
                                                                                                                Find_and_replace("ipsum", "ice-cream");
                                                                                                                );

                                                                                                                function Find_and_replace(search_term, replace_term)
                                                                                                                text = $("textbox").html();
                                                                                                                var search_term = new RegExp(search_term, "g");
                                                                                                                text = text.replace(search_term, replace_term);
                                                                                                                $("textbox").html(text);

                                                                                                                <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                                                                                                                <textbox>
                                                                                                                Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum
                                                                                                                </textbox>
                                                                                                                <button>Click me</button>








                                                                                                                $("button").click(function() 
                                                                                                                Find_and_replace("Lorem", "Chocolate");
                                                                                                                Find_and_replace("ipsum", "ice-cream");
                                                                                                                );

                                                                                                                function Find_and_replace(search_term, replace_term)
                                                                                                                text = $("textbox").html();
                                                                                                                var search_term = new RegExp(search_term, "g");
                                                                                                                text = text.replace(search_term, replace_term);
                                                                                                                $("textbox").html(text);

                                                                                                                <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                                                                                                                <textbox>
                                                                                                                Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum
                                                                                                                </textbox>
                                                                                                                <button>Click me</button>





                                                                                                                $("button").click(function() 
                                                                                                                Find_and_replace("Lorem", "Chocolate");
                                                                                                                Find_and_replace("ipsum", "ice-cream");
                                                                                                                );

                                                                                                                function Find_and_replace(search_term, replace_term)
                                                                                                                text = $("textbox").html();
                                                                                                                var search_term = new RegExp(search_term, "g");
                                                                                                                text = text.replace(search_term, replace_term);
                                                                                                                $("textbox").html(text);

                                                                                                                <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                                                                                                                <textbox>
                                                                                                                Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum
                                                                                                                </textbox>
                                                                                                                <button>Click me</button>






                                                                                                                share|improve this answer












                                                                                                                share|improve this answer



                                                                                                                share|improve this answer










                                                                                                                answered Oct 18 at 18:37









                                                                                                                Paul Jones

                                                                                                                1489




                                                                                                                1489











                                                                                                                • You're overwriting a closure variable, no need to use var here. Also, if you pass b or 1 it would break.
                                                                                                                  – CyberAP
                                                                                                                  Nov 6 at 19:00
















                                                                                                                • You're overwriting a closure variable, no need to use var here. Also, if you pass b or 1 it would break.
                                                                                                                  – CyberAP
                                                                                                                  Nov 6 at 19:00















                                                                                                                You're overwriting a closure variable, no need to use var here. Also, if you pass b or 1 it would break.
                                                                                                                – CyberAP
                                                                                                                Nov 6 at 19:00




                                                                                                                You're overwriting a closure variable, no need to use var here. Also, if you pass b or 1 it would break.
                                                                                                                – CyberAP
                                                                                                                Nov 6 at 19:00





                                                                                                                protected by Community Sep 19 at 9:52



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