Find a specific kind of string in CSV using VBScript
I have a question because I cannot figure out how to use the patterns in VBScript.
I have a CSV, first line is a name, the second one will contain an "xml" so to say, that I have to search in it for a specific string. I cannot convert it to XML and search the node because the node is dynamic.
The string I am looking for is "ABC12345", it will always have the same 3 characters "ABC" at the beginning and 5 random numbers after the ABC.
So I need a script that will open up a CSV, and output another CSV with the first line with the name and the second will be the specific string I mentioned earlier.
So far I have found this:
Const ForReading = 1
Set objRegEx = CreateObject("VBScript.RegExp")
objRegEx.Pattern = "^[1-9]...GRP"
Set objFSO = CreateObject("Scripting.FileSystemObject")
Set objFile = objFSO.OpenTextFile("C:ScriptsTest.txt", ForReading)
Do Until objFile.AtEndOfStream
strSearchString = objFile.ReadLine
Set colMatches = objRegEx.Execute(strSearchString)
If colMatches.Count > 0 Then
For Each strMatch In colMatches
WScript.Echo strSearchString
Next
End If
Loop
objFile.Close
But I didn't find out how to output another CSV and find the string like above.
csv vbscript
add a comment |
I have a question because I cannot figure out how to use the patterns in VBScript.
I have a CSV, first line is a name, the second one will contain an "xml" so to say, that I have to search in it for a specific string. I cannot convert it to XML and search the node because the node is dynamic.
The string I am looking for is "ABC12345", it will always have the same 3 characters "ABC" at the beginning and 5 random numbers after the ABC.
So I need a script that will open up a CSV, and output another CSV with the first line with the name and the second will be the specific string I mentioned earlier.
So far I have found this:
Const ForReading = 1
Set objRegEx = CreateObject("VBScript.RegExp")
objRegEx.Pattern = "^[1-9]...GRP"
Set objFSO = CreateObject("Scripting.FileSystemObject")
Set objFile = objFSO.OpenTextFile("C:ScriptsTest.txt", ForReading)
Do Until objFile.AtEndOfStream
strSearchString = objFile.ReadLine
Set colMatches = objRegEx.Execute(strSearchString)
If colMatches.Count > 0 Then
For Each strMatch In colMatches
WScript.Echo strSearchString
Next
End If
Loop
objFile.Close
But I didn't find out how to output another CSV and find the string like above.
csv vbscript
3
You should useABCd5?bregex if you know that the string format isn't changing. So ABC is hardcoded and then you are finding 5 digits. I have used a word boundary just to ensure that I only pick ABC00000 format strings.
– Pankaj Jaju
Nov 12 '18 at 8:28
Reference.
– Ansgar Wiechers
Nov 12 '18 at 8:59
add a comment |
I have a question because I cannot figure out how to use the patterns in VBScript.
I have a CSV, first line is a name, the second one will contain an "xml" so to say, that I have to search in it for a specific string. I cannot convert it to XML and search the node because the node is dynamic.
The string I am looking for is "ABC12345", it will always have the same 3 characters "ABC" at the beginning and 5 random numbers after the ABC.
So I need a script that will open up a CSV, and output another CSV with the first line with the name and the second will be the specific string I mentioned earlier.
So far I have found this:
Const ForReading = 1
Set objRegEx = CreateObject("VBScript.RegExp")
objRegEx.Pattern = "^[1-9]...GRP"
Set objFSO = CreateObject("Scripting.FileSystemObject")
Set objFile = objFSO.OpenTextFile("C:ScriptsTest.txt", ForReading)
Do Until objFile.AtEndOfStream
strSearchString = objFile.ReadLine
Set colMatches = objRegEx.Execute(strSearchString)
If colMatches.Count > 0 Then
For Each strMatch In colMatches
WScript.Echo strSearchString
Next
End If
Loop
objFile.Close
But I didn't find out how to output another CSV and find the string like above.
csv vbscript
I have a question because I cannot figure out how to use the patterns in VBScript.
I have a CSV, first line is a name, the second one will contain an "xml" so to say, that I have to search in it for a specific string. I cannot convert it to XML and search the node because the node is dynamic.
The string I am looking for is "ABC12345", it will always have the same 3 characters "ABC" at the beginning and 5 random numbers after the ABC.
So I need a script that will open up a CSV, and output another CSV with the first line with the name and the second will be the specific string I mentioned earlier.
So far I have found this:
Const ForReading = 1
Set objRegEx = CreateObject("VBScript.RegExp")
objRegEx.Pattern = "^[1-9]...GRP"
Set objFSO = CreateObject("Scripting.FileSystemObject")
Set objFile = objFSO.OpenTextFile("C:ScriptsTest.txt", ForReading)
Do Until objFile.AtEndOfStream
strSearchString = objFile.ReadLine
Set colMatches = objRegEx.Execute(strSearchString)
If colMatches.Count > 0 Then
For Each strMatch In colMatches
WScript.Echo strSearchString
Next
End If
Loop
objFile.Close
But I didn't find out how to output another CSV and find the string like above.
csv vbscript
csv vbscript
edited Nov 12 '18 at 9:02
Ansgar Wiechers
141k13125185
141k13125185
asked Nov 12 '18 at 6:22
Marin Alexandru RaduMarin Alexandru Radu
61
61
3
You should useABCd5?bregex if you know that the string format isn't changing. So ABC is hardcoded and then you are finding 5 digits. I have used a word boundary just to ensure that I only pick ABC00000 format strings.
– Pankaj Jaju
Nov 12 '18 at 8:28
Reference.
– Ansgar Wiechers
Nov 12 '18 at 8:59
add a comment |
3
You should useABCd5?bregex if you know that the string format isn't changing. So ABC is hardcoded and then you are finding 5 digits. I have used a word boundary just to ensure that I only pick ABC00000 format strings.
– Pankaj Jaju
Nov 12 '18 at 8:28
Reference.
– Ansgar Wiechers
Nov 12 '18 at 8:59
3
3
You should use
ABCd5?b regex if you know that the string format isn't changing. So ABC is hardcoded and then you are finding 5 digits. I have used a word boundary just to ensure that I only pick ABC00000 format strings.– Pankaj Jaju
Nov 12 '18 at 8:28
You should use
ABCd5?b regex if you know that the string format isn't changing. So ABC is hardcoded and then you are finding 5 digits. I have used a word boundary just to ensure that I only pick ABC00000 format strings.– Pankaj Jaju
Nov 12 '18 at 8:28
Reference.
– Ansgar Wiechers
Nov 12 '18 at 8:59
Reference.
– Ansgar Wiechers
Nov 12 '18 at 8:59
add a comment |
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3
You should use
ABCd5?bregex if you know that the string format isn't changing. So ABC is hardcoded and then you are finding 5 digits. I have used a word boundary just to ensure that I only pick ABC00000 format strings.– Pankaj Jaju
Nov 12 '18 at 8:28
Reference.
– Ansgar Wiechers
Nov 12 '18 at 8:59