XSLT problem with output when meet an IF condition

I can't handle with the following issue. I want to use an XSLT to transform an import xml in the needed format for the extension I am using. I want to set a specific value for a parameter when it met a specific IF condition.

This is the input xml:

<?xml version="1.0" encoding="UTF-8"?>
<items>
<item><InStock>In Stock</InStock></item>
<item><InStock>Out of Stock</InStock></item>
</items>

This is what I am trying to use:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:g="http://base.google.com/ns/1.0">
 <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
 <xsl:template match="product">
 <xsl:element name="Items">
 <xsl:for-each select="item">
 <xsl:element name="Item">
 <xsl:element name="quantity_and_stock_status">
 <xsl:if test="InStock = 'In Stock'">
 1
 </xsl:if>
 <xsl:if test="InStock = 'Out of Stock'">
 0
 </xsl:if>
 </xsl:element>
 </xsl:element>
 </xsl:for-each>
 </xsl:element>
 </xsl:template>
</xsl:stylesheet>

asked Nov 14 '18 at 11:22

lyuben.yurukov

You have a template matching product, but there is no such element in your XML. Did you mean to match items here?

– Tim C
Nov 14 '18 at 11:36

The type of the template is choosing on the previous step in the extension, then it comes the XSLT transformation based on the previous choice.

– lyuben.yurukov
Nov 14 '18 at 12:20

You may need to explain more about this extension. At the moment, all that can be said that the XSLT will not apply to your XML, as the XSLT is looking to match product which is not in your XML. It might help if you also said what output you are currently getting, and what you expect. Thank you!

– Tim C
Nov 14 '18 at 13:43

You haven't asked a question. You've said what you're doing (good!) but you haven't said what output you want to produce and how your current code fails.

– Michael Kay
Nov 14 '18 at 15:04

XML is case sensitive, you are using "Item" and "item" as if they were interchangeable.

– Michael Kay
Nov 14 '18 at 15:05

add a comment |

This is the input xml:

<?xml version="1.0" encoding="UTF-8"?>
<items>
<item><InStock>In Stock</InStock></item>
<item><InStock>Out of Stock</InStock></item>
</items>

This is what I am trying to use:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:g="http://base.google.com/ns/1.0">
 <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
 <xsl:template match="product">
 <xsl:element name="Items">
 <xsl:for-each select="item">
 <xsl:element name="Item">
 <xsl:element name="quantity_and_stock_status">
 <xsl:if test="InStock = 'In Stock'">
 1
 </xsl:if>
 <xsl:if test="InStock = 'Out of Stock'">
 0
 </xsl:if>
 </xsl:element>
 </xsl:element>
 </xsl:for-each>
 </xsl:element>
 </xsl:template>
</xsl:stylesheet>

asked Nov 14 '18 at 11:22

lyuben.yurukov

You have a template matching product, but there is no such element in your XML. Did you mean to match items here?

– Tim C
Nov 14 '18 at 11:36

The type of the template is choosing on the previous step in the extension, then it comes the XSLT transformation based on the previous choice.

– lyuben.yurukov
Nov 14 '18 at 12:20

You may need to explain more about this extension. At the moment, all that can be said that the XSLT will not apply to your XML, as the XSLT is looking to match product which is not in your XML. It might help if you also said what output you are currently getting, and what you expect. Thank you!

– Tim C
Nov 14 '18 at 13:43

You haven't asked a question. You've said what you're doing (good!) but you haven't said what output you want to produce and how your current code fails.

– Michael Kay
Nov 14 '18 at 15:04

XML is case sensitive, you are using "Item" and "item" as if they were interchangeable.

– Michael Kay
Nov 14 '18 at 15:05

add a comment |

This is the input xml:

<?xml version="1.0" encoding="UTF-8"?>
<items>
<item><InStock>In Stock</InStock></item>
<item><InStock>Out of Stock</InStock></item>
</items>

This is what I am trying to use:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:g="http://base.google.com/ns/1.0">
 <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
 <xsl:template match="product">
 <xsl:element name="Items">
 <xsl:for-each select="item">
 <xsl:element name="Item">
 <xsl:element name="quantity_and_stock_status">
 <xsl:if test="InStock = 'In Stock'">
 1
 </xsl:if>
 <xsl:if test="InStock = 'Out of Stock'">
 0
 </xsl:if>
 </xsl:element>
 </xsl:element>
 </xsl:for-each>
 </xsl:element>
 </xsl:template>
</xsl:stylesheet>

asked Nov 14 '18 at 11:22

lyuben.yurukov

This is the input xml:

<?xml version="1.0" encoding="UTF-8"?>
<items>
<item><InStock>In Stock</InStock></item>
<item><InStock>Out of Stock</InStock></item>
</items>

This is what I am trying to use:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:g="http://base.google.com/ns/1.0">
 <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
 <xsl:template match="product">
 <xsl:element name="Items">
 <xsl:for-each select="item">
 <xsl:element name="Item">
 <xsl:element name="quantity_and_stock_status">
 <xsl:if test="InStock = 'In Stock'">
 1
 </xsl:if>
 <xsl:if test="InStock = 'Out of Stock'">
 0
 </xsl:if>
 </xsl:element>
 </xsl:element>
 </xsl:for-each>
 </xsl:element>
 </xsl:template>
</xsl:stylesheet>

xml xslt

asked Nov 14 '18 at 11:22

lyuben.yurukov

asked Nov 14 '18 at 11:22

lyuben.yurukov

asked Nov 14 '18 at 11:22

lyuben.yurukov

asked Nov 14 '18 at 11:22

lyuben.yurukov

asked Nov 14 '18 at 11:22

lyuben.yurukov

You have a template matching product, but there is no such element in your XML. Did you mean to match items here?

– Tim C
Nov 14 '18 at 11:36

The type of the template is choosing on the previous step in the extension, then it comes the XSLT transformation based on the previous choice.

– lyuben.yurukov
Nov 14 '18 at 12:20

You may need to explain more about this extension. At the moment, all that can be said that the XSLT will not apply to your XML, as the XSLT is looking to match product which is not in your XML. It might help if you also said what output you are currently getting, and what you expect. Thank you!

– Tim C
Nov 14 '18 at 13:43

You haven't asked a question. You've said what you're doing (good!) but you haven't said what output you want to produce and how your current code fails.

– Michael Kay
Nov 14 '18 at 15:04

XML is case sensitive, you are using "Item" and "item" as if they were interchangeable.

– Michael Kay
Nov 14 '18 at 15:05

add a comment |

You have a template matching product, but there is no such element in your XML. Did you mean to match items here?

– Tim C
Nov 14 '18 at 11:36

The type of the template is choosing on the previous step in the extension, then it comes the XSLT transformation based on the previous choice.

– lyuben.yurukov
Nov 14 '18 at 12:20

You may need to explain more about this extension. At the moment, all that can be said that the XSLT will not apply to your XML, as the XSLT is looking to match product which is not in your XML. It might help if you also said what output you are currently getting, and what you expect. Thank you!

– Tim C
Nov 14 '18 at 13:43

You haven't asked a question. You've said what you're doing (good!) but you haven't said what output you want to produce and how your current code fails.

– Michael Kay
Nov 14 '18 at 15:04

XML is case sensitive, you are using "Item" and "item" as if they were interchangeable.

– Michael Kay
Nov 14 '18 at 15:05

You have a template matching product, but there is no such element in your XML. Did you mean to match items here?

– Tim C
Nov 14 '18 at 11:36

The type of the template is choosing on the previous step in the extension, then it comes the XSLT transformation based on the previous choice.

– lyuben.yurukov
Nov 14 '18 at 12:20

You may need to explain more about this extension. At the moment, all that can be said that the XSLT will not apply to your XML, as the XSLT is looking to match product which is not in your XML. It might help if you also said what output you are currently getting, and what you expect. Thank you!

– Tim C
Nov 14 '18 at 13:43

You haven't asked a question. You've said what you're doing (good!) but you haven't said what output you want to produce and how your current code fails.

– Michael Kay
Nov 14 '18 at 15:04

XML is case sensitive, you are using "Item" and "item" as if they were interchangeable.

– Michael Kay
Nov 14 '18 at 15:05

add a comment |

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