Masking a string in ionic [closed]

I want to mask a string in Ionic-4, the format of the string will be 1234567890987. I want output as 123xxxxxxx987 (i.e) first 3 characters and last 3 characters should be plain and remaining all characters should be masked. Please let me know, how to implement this?

asked Nov 15 '18 at 7:17

user7413163

1215

closed as too broad by Suraj Rao, Owen Pauling, greg-449, Pearly Spencer, Janusz Nov 15 '18 at 14:18

Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

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asked Nov 15 '18 at 7:17

user7413163

1215

closed as too broad by Suraj Rao, Owen Pauling, greg-449, Pearly Spencer, Janusz Nov 15 '18 at 14:18

add a comment |

asked Nov 15 '18 at 7:17

user7413163

1215

angular ionic-framework hybrid

asked Nov 15 '18 at 7:17

user7413163

1215

asked Nov 15 '18 at 7:17

user7413163

1215

asked Nov 15 '18 at 7:17

user7413163

1215

asked Nov 15 '18 at 7:17

user7413163

1215

asked Nov 15 '18 at 7:17

user7413163

1215

closed as too broad by Suraj Rao, Owen Pauling, greg-449, Pearly Spencer, Janusz Nov 15 '18 at 14:18

add a comment |

2 Answers
2

active

oldest

votes

Define a function replaceAt as like this -

function replaceAt(str, pos, value)
 var arr = str.split('');
 arr[pos]=value;
 return arr.join('');


var s = "1234567890987";
for(var i=3;i<s.length-3;i++) s = replaceAt(s, i, 'x');
console.log(s);

answered Nov 15 '18 at 7:41

Harunur Rashid

1,373713

Thank you for reply. It worked perfectly.

– user7413163
Nov 15 '18 at 9:23

add a comment |

you can do something like this:

const number:string = "123456789";

const hideMiddleString = (text: string): string => 
 if(text.length <= 6) 
 return text;
 
 const beginString = text.substr(0, 3); // Take 3first chars
 const endString = text.substr(-3); // take 3 last chars
 // x.repeat will create string of xxxx base on string length - 3 first chars - 3 last chars
 return beginString + "x".repeat(text.length - 6) + endString;
;

console.log(hideMiddleString(number));

live sample

answered Nov 15 '18 at 7:37

Yanis-git

2,4341724

add a comment |

2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

Define a function replaceAt as like this -

function replaceAt(str, pos, value)
 var arr = str.split('');
 arr[pos]=value;
 return arr.join('');


var s = "1234567890987";
for(var i=3;i<s.length-3;i++) s = replaceAt(s, i, 'x');
console.log(s);

answered Nov 15 '18 at 7:41

Harunur Rashid

1,373713

Thank you for reply. It worked perfectly.

– user7413163
Nov 15 '18 at 9:23

add a comment |

Define a function replaceAt as like this -

function replaceAt(str, pos, value)
 var arr = str.split('');
 arr[pos]=value;
 return arr.join('');


var s = "1234567890987";
for(var i=3;i<s.length-3;i++) s = replaceAt(s, i, 'x');
console.log(s);

answered Nov 15 '18 at 7:41

Harunur Rashid

1,373713

Thank you for reply. It worked perfectly.

– user7413163
Nov 15 '18 at 9:23

add a comment |

Define a function replaceAt as like this -

function replaceAt(str, pos, value)
 var arr = str.split('');
 arr[pos]=value;
 return arr.join('');


var s = "1234567890987";
for(var i=3;i<s.length-3;i++) s = replaceAt(s, i, 'x');
console.log(s);

answered Nov 15 '18 at 7:41

Harunur Rashid

1,373713

Define a function replaceAt as like this -

function replaceAt(str, pos, value)
 var arr = str.split('');
 arr[pos]=value;
 return arr.join('');


var s = "1234567890987";
for(var i=3;i<s.length-3;i++) s = replaceAt(s, i, 'x');
console.log(s);

function replaceAt(str, pos, value)
 var arr = str.split('');
 arr[pos]=value;
 return arr.join('');


var s = "1234567890987";
for(var i=3;i<s.length-3;i++) s = replaceAt(s, i, 'x');
console.log(s);

function replaceAt(str, pos, value)
 var arr = str.split('');
 arr[pos]=value;
 return arr.join('');


var s = "1234567890987";
for(var i=3;i<s.length-3;i++) s = replaceAt(s, i, 'x');
console.log(s);

answered Nov 15 '18 at 7:41

Harunur Rashid

1,373713

answered Nov 15 '18 at 7:41

Harunur Rashid

1,373713

answered Nov 15 '18 at 7:41

Harunur Rashid

1,373713

answered Nov 15 '18 at 7:41

Harunur Rashid

1,373713

Thank you for reply. It worked perfectly.

– user7413163
Nov 15 '18 at 9:23

add a comment |

Thank you for reply. It worked perfectly.

– user7413163
Nov 15 '18 at 9:23

Thank you for reply. It worked perfectly.

– user7413163
Nov 15 '18 at 9:23

add a comment |

you can do something like this:

const number:string = "123456789";

const hideMiddleString = (text: string): string => 
 if(text.length <= 6) 
 return text;
 
 const beginString = text.substr(0, 3); // Take 3first chars
 const endString = text.substr(-3); // take 3 last chars
 // x.repeat will create string of xxxx base on string length - 3 first chars - 3 last chars
 return beginString + "x".repeat(text.length - 6) + endString;
;

console.log(hideMiddleString(number));

live sample

answered Nov 15 '18 at 7:37

Yanis-git

2,4341724

add a comment |

you can do something like this:

const number:string = "123456789";

const hideMiddleString = (text: string): string => 
 if(text.length <= 6) 
 return text;
 
 const beginString = text.substr(0, 3); // Take 3first chars
 const endString = text.substr(-3); // take 3 last chars
 // x.repeat will create string of xxxx base on string length - 3 first chars - 3 last chars
 return beginString + "x".repeat(text.length - 6) + endString;
;

console.log(hideMiddleString(number));

live sample

answered Nov 15 '18 at 7:37

Yanis-git

2,4341724

add a comment |

you can do something like this:

const number:string = "123456789";

const hideMiddleString = (text: string): string => 
 if(text.length <= 6) 
 return text;
 
 const beginString = text.substr(0, 3); // Take 3first chars
 const endString = text.substr(-3); // take 3 last chars
 // x.repeat will create string of xxxx base on string length - 3 first chars - 3 last chars
 return beginString + "x".repeat(text.length - 6) + endString;
;

console.log(hideMiddleString(number));

live sample

answered Nov 15 '18 at 7:37

Yanis-git

2,4341724

you can do something like this:

const number:string = "123456789";

const hideMiddleString = (text: string): string => 
 if(text.length <= 6) 
 return text;
 
 const beginString = text.substr(0, 3); // Take 3first chars
 const endString = text.substr(-3); // take 3 last chars
 // x.repeat will create string of xxxx base on string length - 3 first chars - 3 last chars
 return beginString + "x".repeat(text.length - 6) + endString;
;

console.log(hideMiddleString(number));

live sample

answered Nov 15 '18 at 7:37

Yanis-git

2,4341724

answered Nov 15 '18 at 7:37

Yanis-git

2,4341724

answered Nov 15 '18 at 7:37

Yanis-git

2,4341724

answered Nov 15 '18 at 7:37

Yanis-git

2,4341724

add a comment |

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