Python date conversion and checking
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I want to be able to convert string to date and then do operation to check if it's before or after a certain date.
Input format : d/m/yyyy
6/7/2018
I want to check if the date above is before today's date 10/11/2018
How do I go about doing this? This is what I have:
import datetime
dateInput= '10/11/2018'
dateFormat = '%d/%m/%Y'
dateObj= datetime.datetime.strptime(dateInput, dateFormat )
How do I do the checking if it's before or after a certain date e.g 10/11/2018 ?
python datetime
add a comment |
up vote
0
down vote
favorite
I want to be able to convert string to date and then do operation to check if it's before or after a certain date.
Input format : d/m/yyyy
6/7/2018
I want to check if the date above is before today's date 10/11/2018
How do I go about doing this? This is what I have:
import datetime
dateInput= '10/11/2018'
dateFormat = '%d/%m/%Y'
dateObj= datetime.datetime.strptime(dateInput, dateFormat )
How do I do the checking if it's before or after a certain date e.g 10/11/2018 ?
python datetime
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I want to be able to convert string to date and then do operation to check if it's before or after a certain date.
Input format : d/m/yyyy
6/7/2018
I want to check if the date above is before today's date 10/11/2018
How do I go about doing this? This is what I have:
import datetime
dateInput= '10/11/2018'
dateFormat = '%d/%m/%Y'
dateObj= datetime.datetime.strptime(dateInput, dateFormat )
How do I do the checking if it's before or after a certain date e.g 10/11/2018 ?
python datetime
I want to be able to convert string to date and then do operation to check if it's before or after a certain date.
Input format : d/m/yyyy
6/7/2018
I want to check if the date above is before today's date 10/11/2018
How do I go about doing this? This is what I have:
import datetime
dateInput= '10/11/2018'
dateFormat = '%d/%m/%Y'
dateObj= datetime.datetime.strptime(dateInput, dateFormat )
How do I do the checking if it's before or after a certain date e.g 10/11/2018 ?
python datetime
python datetime
asked Nov 10 at 5:34
Abeart
112
112
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
Just use date1 > date2 …
$ cat timebomb.py
#!/bin/env python
import datetime
date_format = '%d/%m/%Y'
boom_time = datetime.datetime.strptime('10/11/2018', date_format )
start_day = '01/11/2018'
day = datetime.datetime.strptime(start_day, date_format )
while day < boom_time:
print ("Tick Tock.")
day += datetime.timedelta(days=1)
print ("BOOM")
Run it ...
$ ./timebomb.py
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
BOOM
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
Just use date1 > date2 …
$ cat timebomb.py
#!/bin/env python
import datetime
date_format = '%d/%m/%Y'
boom_time = datetime.datetime.strptime('10/11/2018', date_format )
start_day = '01/11/2018'
day = datetime.datetime.strptime(start_day, date_format )
while day < boom_time:
print ("Tick Tock.")
day += datetime.timedelta(days=1)
print ("BOOM")
Run it ...
$ ./timebomb.py
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
BOOM
add a comment |
up vote
1
down vote
Just use date1 > date2 …
$ cat timebomb.py
#!/bin/env python
import datetime
date_format = '%d/%m/%Y'
boom_time = datetime.datetime.strptime('10/11/2018', date_format )
start_day = '01/11/2018'
day = datetime.datetime.strptime(start_day, date_format )
while day < boom_time:
print ("Tick Tock.")
day += datetime.timedelta(days=1)
print ("BOOM")
Run it ...
$ ./timebomb.py
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
BOOM
add a comment |
up vote
1
down vote
up vote
1
down vote
Just use date1 > date2 …
$ cat timebomb.py
#!/bin/env python
import datetime
date_format = '%d/%m/%Y'
boom_time = datetime.datetime.strptime('10/11/2018', date_format )
start_day = '01/11/2018'
day = datetime.datetime.strptime(start_day, date_format )
while day < boom_time:
print ("Tick Tock.")
day += datetime.timedelta(days=1)
print ("BOOM")
Run it ...
$ ./timebomb.py
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
BOOM
Just use date1 > date2 …
$ cat timebomb.py
#!/bin/env python
import datetime
date_format = '%d/%m/%Y'
boom_time = datetime.datetime.strptime('10/11/2018', date_format )
start_day = '01/11/2018'
day = datetime.datetime.strptime(start_day, date_format )
while day < boom_time:
print ("Tick Tock.")
day += datetime.timedelta(days=1)
print ("BOOM")
Run it ...
$ ./timebomb.py
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
Tick Tock.
BOOM
edited Nov 10 at 6:21
answered Nov 10 at 5:40
Red Cricket
4,14683381
4,14683381
add a comment |
add a comment |
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