sql formating and extracting items (json)
So basically I should sum and list all products based on their name they should differ.
This would work properly if I only selected the $[]. item from the table but if I were to select all items with $[].
I will get the following
ROW:
["brand_name": "Product 1", "brand_id": "4", "quantity": 1, "brand_name": "Product 2", "brand_id": "5", "quantity": 3]
RESULT:
"brand_id": "["4", "5"]",
"brand_name": "["Product 1", "Product 2"]",
"quantity": 0
EXPECTED RESULT:
"brand_id": "4",
"brand_name": "Product 1",
"quantity": 1
"brand_id": "5",
"brand_name": "Product 2",
"quantity": 3
QUERY ELOQUENT:
public function scopegetBasicMeans($query)
$query->where('type', 1)
->join('report_asset', 'report_asset.report_id', '=', 'reports.id')->select(
DB::raw('JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].name")) as brand_name'),
DB::raw('JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].brand_id")) as brand_id'),
DB::raw('SUM(JSON_EXTRACT(resources, "$[*].quantity")) as quantity')
)->orderBy('quantity', 'DESC')
->groupBy(DB::raw('JSON_EXTRACT(resources, "$[*].name")'));
QUERY RAW:
select JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].name")) as brand_name, JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].brand_id")) as brand_id, SUM(JSON_EXTRACT(resources, "$[*].quantity")) as quantity, `reports`.`created_at`, `commercialist_id`, `type` from `reports` inner join `report_asset` on `report_asset`.`report_id` = `reports`.`id` where `reports`.`object_id` = ? and `reports`.`object_id` is not null and `type` = ? and `reports`.`deleted_at` is null group by JSON_EXTRACT(resources, "$[*].name") order by `quantity` desc
Basically I should sum the quality of all items with specific name and group them by their name which will get me the unique results.
This would work if i were to select only first item from the table for example: $[0].name[0] but not on multiple.
Any suggestions?
structure
php mysql json laravel
|
show 14 more comments
So basically I should sum and list all products based on their name they should differ.
This would work properly if I only selected the $[]. item from the table but if I were to select all items with $[].
I will get the following
ROW:
["brand_name": "Product 1", "brand_id": "4", "quantity": 1, "brand_name": "Product 2", "brand_id": "5", "quantity": 3]
RESULT:
"brand_id": "["4", "5"]",
"brand_name": "["Product 1", "Product 2"]",
"quantity": 0
EXPECTED RESULT:
"brand_id": "4",
"brand_name": "Product 1",
"quantity": 1
"brand_id": "5",
"brand_name": "Product 2",
"quantity": 3
QUERY ELOQUENT:
public function scopegetBasicMeans($query)
$query->where('type', 1)
->join('report_asset', 'report_asset.report_id', '=', 'reports.id')->select(
DB::raw('JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].name")) as brand_name'),
DB::raw('JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].brand_id")) as brand_id'),
DB::raw('SUM(JSON_EXTRACT(resources, "$[*].quantity")) as quantity')
)->orderBy('quantity', 'DESC')
->groupBy(DB::raw('JSON_EXTRACT(resources, "$[*].name")'));
QUERY RAW:
select JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].name")) as brand_name, JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].brand_id")) as brand_id, SUM(JSON_EXTRACT(resources, "$[*].quantity")) as quantity, `reports`.`created_at`, `commercialist_id`, `type` from `reports` inner join `report_asset` on `report_asset`.`report_id` = `reports`.`id` where `reports`.`object_id` = ? and `reports`.`object_id` is not null and `type` = ? and `reports`.`deleted_at` is null group by JSON_EXTRACT(resources, "$[*].name") order by `quantity` desc
Basically I should sum the quality of all items with specific name and group them by their name which will get me the unique results.
This would work if i were to select only first item from the table for example: $[0].name[0] but not on multiple.
Any suggestions?
structure
php mysql json laravel
you appear to have got double-encoded JSON, because you're outputting a JSON string and then putting it inside another object which is then itself encoded as JSON. instead, output all your data into an object and then encode the final object, once.
– ADyson
Nov 13 '18 at 9:21
I have trouble with indexes, arrays are multi dimensional and i dont know how to extract by index of each item
– Nathaniel
Nov 13 '18 at 10:27
you appear to be extracting from the same "resources" table each time. What's wrong with a simple SELECT statement which selects all the columns you need? Perhaps if you show the actual SQL data structure and sample of raw data it would be clearer.
– ADyson
Nov 13 '18 at 10:31
That would be cool but i need unique items for example there is multiple rows with name product 1 and for example quantity of 2 and 3, query should return only one product 1 and sum the quantity which in this case would be 5 if you understand.
– Nathaniel
Nov 13 '18 at 10:34
use SUM and GROUP BY, then. But it can still be a single SELECT.
– ADyson
Nov 13 '18 at 10:34
|
show 14 more comments
So basically I should sum and list all products based on their name they should differ.
This would work properly if I only selected the $[]. item from the table but if I were to select all items with $[].
I will get the following
ROW:
["brand_name": "Product 1", "brand_id": "4", "quantity": 1, "brand_name": "Product 2", "brand_id": "5", "quantity": 3]
RESULT:
"brand_id": "["4", "5"]",
"brand_name": "["Product 1", "Product 2"]",
"quantity": 0
EXPECTED RESULT:
"brand_id": "4",
"brand_name": "Product 1",
"quantity": 1
"brand_id": "5",
"brand_name": "Product 2",
"quantity": 3
QUERY ELOQUENT:
public function scopegetBasicMeans($query)
$query->where('type', 1)
->join('report_asset', 'report_asset.report_id', '=', 'reports.id')->select(
DB::raw('JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].name")) as brand_name'),
DB::raw('JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].brand_id")) as brand_id'),
DB::raw('SUM(JSON_EXTRACT(resources, "$[*].quantity")) as quantity')
)->orderBy('quantity', 'DESC')
->groupBy(DB::raw('JSON_EXTRACT(resources, "$[*].name")'));
QUERY RAW:
select JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].name")) as brand_name, JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].brand_id")) as brand_id, SUM(JSON_EXTRACT(resources, "$[*].quantity")) as quantity, `reports`.`created_at`, `commercialist_id`, `type` from `reports` inner join `report_asset` on `report_asset`.`report_id` = `reports`.`id` where `reports`.`object_id` = ? and `reports`.`object_id` is not null and `type` = ? and `reports`.`deleted_at` is null group by JSON_EXTRACT(resources, "$[*].name") order by `quantity` desc
Basically I should sum the quality of all items with specific name and group them by their name which will get me the unique results.
This would work if i were to select only first item from the table for example: $[0].name[0] but not on multiple.
Any suggestions?
structure
php mysql json laravel
So basically I should sum and list all products based on their name they should differ.
This would work properly if I only selected the $[]. item from the table but if I were to select all items with $[].
I will get the following
ROW:
["brand_name": "Product 1", "brand_id": "4", "quantity": 1, "brand_name": "Product 2", "brand_id": "5", "quantity": 3]
RESULT:
"brand_id": "["4", "5"]",
"brand_name": "["Product 1", "Product 2"]",
"quantity": 0
EXPECTED RESULT:
"brand_id": "4",
"brand_name": "Product 1",
"quantity": 1
"brand_id": "5",
"brand_name": "Product 2",
"quantity": 3
QUERY ELOQUENT:
public function scopegetBasicMeans($query)
$query->where('type', 1)
->join('report_asset', 'report_asset.report_id', '=', 'reports.id')->select(
DB::raw('JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].name")) as brand_name'),
DB::raw('JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].brand_id")) as brand_id'),
DB::raw('SUM(JSON_EXTRACT(resources, "$[*].quantity")) as quantity')
)->orderBy('quantity', 'DESC')
->groupBy(DB::raw('JSON_EXTRACT(resources, "$[*].name")'));
QUERY RAW:
select JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].name")) as brand_name, JSON_UNQUOTE(JSON_EXTRACT(resources, "$[*].brand_id")) as brand_id, SUM(JSON_EXTRACT(resources, "$[*].quantity")) as quantity, `reports`.`created_at`, `commercialist_id`, `type` from `reports` inner join `report_asset` on `report_asset`.`report_id` = `reports`.`id` where `reports`.`object_id` = ? and `reports`.`object_id` is not null and `type` = ? and `reports`.`deleted_at` is null group by JSON_EXTRACT(resources, "$[*].name") order by `quantity` desc
Basically I should sum the quality of all items with specific name and group them by their name which will get me the unique results.
This would work if i were to select only first item from the table for example: $[0].name[0] but not on multiple.
Any suggestions?
structure
php mysql json laravel
php mysql json laravel
edited Nov 13 '18 at 11:16
Nathaniel
asked Nov 13 '18 at 8:58
NathanielNathaniel
62
62
you appear to have got double-encoded JSON, because you're outputting a JSON string and then putting it inside another object which is then itself encoded as JSON. instead, output all your data into an object and then encode the final object, once.
– ADyson
Nov 13 '18 at 9:21
I have trouble with indexes, arrays are multi dimensional and i dont know how to extract by index of each item
– Nathaniel
Nov 13 '18 at 10:27
you appear to be extracting from the same "resources" table each time. What's wrong with a simple SELECT statement which selects all the columns you need? Perhaps if you show the actual SQL data structure and sample of raw data it would be clearer.
– ADyson
Nov 13 '18 at 10:31
That would be cool but i need unique items for example there is multiple rows with name product 1 and for example quantity of 2 and 3, query should return only one product 1 and sum the quantity which in this case would be 5 if you understand.
– Nathaniel
Nov 13 '18 at 10:34
use SUM and GROUP BY, then. But it can still be a single SELECT.
– ADyson
Nov 13 '18 at 10:34
|
show 14 more comments
you appear to have got double-encoded JSON, because you're outputting a JSON string and then putting it inside another object which is then itself encoded as JSON. instead, output all your data into an object and then encode the final object, once.
– ADyson
Nov 13 '18 at 9:21
I have trouble with indexes, arrays are multi dimensional and i dont know how to extract by index of each item
– Nathaniel
Nov 13 '18 at 10:27
you appear to be extracting from the same "resources" table each time. What's wrong with a simple SELECT statement which selects all the columns you need? Perhaps if you show the actual SQL data structure and sample of raw data it would be clearer.
– ADyson
Nov 13 '18 at 10:31
That would be cool but i need unique items for example there is multiple rows with name product 1 and for example quantity of 2 and 3, query should return only one product 1 and sum the quantity which in this case would be 5 if you understand.
– Nathaniel
Nov 13 '18 at 10:34
use SUM and GROUP BY, then. But it can still be a single SELECT.
– ADyson
Nov 13 '18 at 10:34
you appear to have got double-encoded JSON, because you're outputting a JSON string and then putting it inside another object which is then itself encoded as JSON. instead, output all your data into an object and then encode the final object, once.
– ADyson
Nov 13 '18 at 9:21
you appear to have got double-encoded JSON, because you're outputting a JSON string and then putting it inside another object which is then itself encoded as JSON. instead, output all your data into an object and then encode the final object, once.
– ADyson
Nov 13 '18 at 9:21
I have trouble with indexes, arrays are multi dimensional and i dont know how to extract by index of each item
– Nathaniel
Nov 13 '18 at 10:27
I have trouble with indexes, arrays are multi dimensional and i dont know how to extract by index of each item
– Nathaniel
Nov 13 '18 at 10:27
you appear to be extracting from the same "resources" table each time. What's wrong with a simple SELECT statement which selects all the columns you need? Perhaps if you show the actual SQL data structure and sample of raw data it would be clearer.
– ADyson
Nov 13 '18 at 10:31
you appear to be extracting from the same "resources" table each time. What's wrong with a simple SELECT statement which selects all the columns you need? Perhaps if you show the actual SQL data structure and sample of raw data it would be clearer.
– ADyson
Nov 13 '18 at 10:31
That would be cool but i need unique items for example there is multiple rows with name product 1 and for example quantity of 2 and 3, query should return only one product 1 and sum the quantity which in this case would be 5 if you understand.
– Nathaniel
Nov 13 '18 at 10:34
That would be cool but i need unique items for example there is multiple rows with name product 1 and for example quantity of 2 and 3, query should return only one product 1 and sum the quantity which in this case would be 5 if you understand.
– Nathaniel
Nov 13 '18 at 10:34
use SUM and GROUP BY, then. But it can still be a single SELECT.
– ADyson
Nov 13 '18 at 10:34
use SUM and GROUP BY, then. But it can still be a single SELECT.
– ADyson
Nov 13 '18 at 10:34
|
show 14 more comments
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53277203%2fsql-formating-and-extracting-items-json%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53277203%2fsql-formating-and-extracting-items-json%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
you appear to have got double-encoded JSON, because you're outputting a JSON string and then putting it inside another object which is then itself encoded as JSON. instead, output all your data into an object and then encode the final object, once.
– ADyson
Nov 13 '18 at 9:21
I have trouble with indexes, arrays are multi dimensional and i dont know how to extract by index of each item
– Nathaniel
Nov 13 '18 at 10:27
you appear to be extracting from the same "resources" table each time. What's wrong with a simple SELECT statement which selects all the columns you need? Perhaps if you show the actual SQL data structure and sample of raw data it would be clearer.
– ADyson
Nov 13 '18 at 10:31
That would be cool but i need unique items for example there is multiple rows with name product 1 and for example quantity of 2 and 3, query should return only one product 1 and sum the quantity which in this case would be 5 if you understand.
– Nathaniel
Nov 13 '18 at 10:34
use SUM and GROUP BY, then. But it can still be a single SELECT.
– ADyson
Nov 13 '18 at 10:34