Returning Failure if File does not exist
I am running the below script in SQL Server Agent.
All the subsequent steps in job are dependent upon this step. This is pretty simple Looking for a file and exits with failure if file is not found.
$file = "C:\Data\FileDrop\.done"
$CheckFile = Test-Path -Path $file
if (!($CheckFile)) exit 1
However when the agent job runs, it says the step failed because file not found and existing with code 0 - success.
What am I doing wrong here?
powershell
add a comment |
I am running the below script in SQL Server Agent.
All the subsequent steps in job are dependent upon this step. This is pretty simple Looking for a file and exits with failure if file is not found.
$file = "C:\Data\FileDrop\.done"
$CheckFile = Test-Path -Path $file
if (!($CheckFile)) exit 1
However when the agent job runs, it says the step failed because file not found and existing with code 0 - success.
What am I doing wrong here?
powershell
I'm not sure what the issue is but if you don't need to store the result of test-path then you can just use if(!t(test-path -path $file)). You can also use if((test-path -path $file) -eq $false))
– emanresu
Nov 14 '18 at 21:15
Thank you for your response. The issue is, it exits with code=0 success. How do I fail this if file is not found?
– Lucky
Nov 14 '18 at 21:22
1
Don't escape backslashes in PowerShell string literals:`
is PowerShell's escape character), so it doesn't need escaping. That said, in file paths double backslashes are usually benign (treated the same as a single backslash). Is the file the job reports as not found reallyC:DataFileDrop.done
? In your invocation scenario, is any exit code from your PowerShell script reflected in the job?
– mklement0
Nov 15 '18 at 3:16
add a comment |
I am running the below script in SQL Server Agent.
All the subsequent steps in job are dependent upon this step. This is pretty simple Looking for a file and exits with failure if file is not found.
$file = "C:\Data\FileDrop\.done"
$CheckFile = Test-Path -Path $file
if (!($CheckFile)) exit 1
However when the agent job runs, it says the step failed because file not found and existing with code 0 - success.
What am I doing wrong here?
powershell
I am running the below script in SQL Server Agent.
All the subsequent steps in job are dependent upon this step. This is pretty simple Looking for a file and exits with failure if file is not found.
$file = "C:\Data\FileDrop\.done"
$CheckFile = Test-Path -Path $file
if (!($CheckFile)) exit 1
However when the agent job runs, it says the step failed because file not found and existing with code 0 - success.
What am I doing wrong here?
powershell
powershell
asked Nov 14 '18 at 20:59
LuckyLucky
597
597
I'm not sure what the issue is but if you don't need to store the result of test-path then you can just use if(!t(test-path -path $file)). You can also use if((test-path -path $file) -eq $false))
– emanresu
Nov 14 '18 at 21:15
Thank you for your response. The issue is, it exits with code=0 success. How do I fail this if file is not found?
– Lucky
Nov 14 '18 at 21:22
1
Don't escape backslashes in PowerShell string literals:`
is PowerShell's escape character), so it doesn't need escaping. That said, in file paths double backslashes are usually benign (treated the same as a single backslash). Is the file the job reports as not found reallyC:DataFileDrop.done
? In your invocation scenario, is any exit code from your PowerShell script reflected in the job?
– mklement0
Nov 15 '18 at 3:16
add a comment |
I'm not sure what the issue is but if you don't need to store the result of test-path then you can just use if(!t(test-path -path $file)). You can also use if((test-path -path $file) -eq $false))
– emanresu
Nov 14 '18 at 21:15
Thank you for your response. The issue is, it exits with code=0 success. How do I fail this if file is not found?
– Lucky
Nov 14 '18 at 21:22
1
Don't escape backslashes in PowerShell string literals:`
is PowerShell's escape character), so it doesn't need escaping. That said, in file paths double backslashes are usually benign (treated the same as a single backslash). Is the file the job reports as not found reallyC:DataFileDrop.done
? In your invocation scenario, is any exit code from your PowerShell script reflected in the job?
– mklement0
Nov 15 '18 at 3:16
I'm not sure what the issue is but if you don't need to store the result of test-path then you can just use if(!t(test-path -path $file)). You can also use if((test-path -path $file) -eq $false))
– emanresu
Nov 14 '18 at 21:15
I'm not sure what the issue is but if you don't need to store the result of test-path then you can just use if(!t(test-path -path $file)). You can also use if((test-path -path $file) -eq $false))
– emanresu
Nov 14 '18 at 21:15
Thank you for your response. The issue is, it exits with code=0 success. How do I fail this if file is not found?
– Lucky
Nov 14 '18 at 21:22
Thank you for your response. The issue is, it exits with code=0 success. How do I fail this if file is not found?
– Lucky
Nov 14 '18 at 21:22
1
1
Don't escape backslashes in PowerShell string literals:
has no special meaning (`
is PowerShell's escape character), so it doesn't need escaping. That said, in file paths double backslashes are usually benign (treated the same as a single backslash). Is the file the job reports as not found really C:DataFileDrop.done
? In your invocation scenario, is any exit code from your PowerShell script reflected in the job?– mklement0
Nov 15 '18 at 3:16
Don't escape backslashes in PowerShell string literals:
has no special meaning (`
is PowerShell's escape character), so it doesn't need escaping. That said, in file paths double backslashes are usually benign (treated the same as a single backslash). Is the file the job reports as not found really C:DataFileDrop.done
? In your invocation scenario, is any exit code from your PowerShell script reflected in the job?– mklement0
Nov 15 '18 at 3:16
add a comment |
3 Answers
3
active
oldest
votes
I don't think the return value / error code of the job has anything to do with whatever value the script returns.
If you want to fail with an error message, try this:
# make sure to stop on errors
$ErrorActionPreference = 'Stop'
$path = 'C:DataFileDrop.done'
# check for file explicitly (in case a directory with that name exists)
if(![System.IO.File]::Exists($path))
# throwing an exception will abort the job
throw (New-Object System.IO.FileNotFoundException("File not found: $path", $path))
# anything after this will not be executed on error...
This should fail the job entirely and show the error message in the job's history.
If the OP doesn't actually care about the setting the exit code and just wants to ensure that the job fails in this condition then I think this is the correct answer.
– emanresu
Nov 16 '18 at 17:09
add a comment |
Maybe this is what you're looking for:
if(!(Test-Path "C:DataFileDrop.done"))
return 1
else
return 0
add a comment |
This is not going to be a great answer because I have not found the documentation that explains this but the use of Exit followed by a number seems to not have any effect on the exit code.
The following example works, with the general idea taken from a blog.
First create a test script like the following:
$host.SetShouldExit(12345)
exit
Next call this script from the Powershell command line as in the following example:
$command = "C:YourTestScriptPathAndName.ps1"
Powershell -NonInteractive -NoProfile -Command $command
The script will run and exit, and we can then check the exit code from the Powershell prompt by writing out the contents of $LASTEXISTCODE
$LASTEXITCODE
In this case $LASTEXISTCODE would contain 12345.
In the case of using this with Test-Path it would look like this:
#using a path that does not exist
if(Test-Path -Path 'C:nope')
$host.SetShouldExit(1234)
else
$host.SetShouldExit(2222)
This sets the exit code to 2222 when invoked from the command line, but when I invoke that test script from another script instead of from the command line the $LASTEXITCODE variable is set to 0 still.
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53308618%2freturning-failure-if-file-does-not-exist%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
I don't think the return value / error code of the job has anything to do with whatever value the script returns.
If you want to fail with an error message, try this:
# make sure to stop on errors
$ErrorActionPreference = 'Stop'
$path = 'C:DataFileDrop.done'
# check for file explicitly (in case a directory with that name exists)
if(![System.IO.File]::Exists($path))
# throwing an exception will abort the job
throw (New-Object System.IO.FileNotFoundException("File not found: $path", $path))
# anything after this will not be executed on error...
This should fail the job entirely and show the error message in the job's history.
If the OP doesn't actually care about the setting the exit code and just wants to ensure that the job fails in this condition then I think this is the correct answer.
– emanresu
Nov 16 '18 at 17:09
add a comment |
I don't think the return value / error code of the job has anything to do with whatever value the script returns.
If you want to fail with an error message, try this:
# make sure to stop on errors
$ErrorActionPreference = 'Stop'
$path = 'C:DataFileDrop.done'
# check for file explicitly (in case a directory with that name exists)
if(![System.IO.File]::Exists($path))
# throwing an exception will abort the job
throw (New-Object System.IO.FileNotFoundException("File not found: $path", $path))
# anything after this will not be executed on error...
This should fail the job entirely and show the error message in the job's history.
If the OP doesn't actually care about the setting the exit code and just wants to ensure that the job fails in this condition then I think this is the correct answer.
– emanresu
Nov 16 '18 at 17:09
add a comment |
I don't think the return value / error code of the job has anything to do with whatever value the script returns.
If you want to fail with an error message, try this:
# make sure to stop on errors
$ErrorActionPreference = 'Stop'
$path = 'C:DataFileDrop.done'
# check for file explicitly (in case a directory with that name exists)
if(![System.IO.File]::Exists($path))
# throwing an exception will abort the job
throw (New-Object System.IO.FileNotFoundException("File not found: $path", $path))
# anything after this will not be executed on error...
This should fail the job entirely and show the error message in the job's history.
I don't think the return value / error code of the job has anything to do with whatever value the script returns.
If you want to fail with an error message, try this:
# make sure to stop on errors
$ErrorActionPreference = 'Stop'
$path = 'C:DataFileDrop.done'
# check for file explicitly (in case a directory with that name exists)
if(![System.IO.File]::Exists($path))
# throwing an exception will abort the job
throw (New-Object System.IO.FileNotFoundException("File not found: $path", $path))
# anything after this will not be executed on error...
This should fail the job entirely and show the error message in the job's history.
edited Nov 15 '18 at 12:36
answered Nov 15 '18 at 10:22
marszemarsze
5,87132042
5,87132042
If the OP doesn't actually care about the setting the exit code and just wants to ensure that the job fails in this condition then I think this is the correct answer.
– emanresu
Nov 16 '18 at 17:09
add a comment |
If the OP doesn't actually care about the setting the exit code and just wants to ensure that the job fails in this condition then I think this is the correct answer.
– emanresu
Nov 16 '18 at 17:09
If the OP doesn't actually care about the setting the exit code and just wants to ensure that the job fails in this condition then I think this is the correct answer.
– emanresu
Nov 16 '18 at 17:09
If the OP doesn't actually care about the setting the exit code and just wants to ensure that the job fails in this condition then I think this is the correct answer.
– emanresu
Nov 16 '18 at 17:09
add a comment |
Maybe this is what you're looking for:
if(!(Test-Path "C:DataFileDrop.done"))
return 1
else
return 0
add a comment |
Maybe this is what you're looking for:
if(!(Test-Path "C:DataFileDrop.done"))
return 1
else
return 0
add a comment |
Maybe this is what you're looking for:
if(!(Test-Path "C:DataFileDrop.done"))
return 1
else
return 0
Maybe this is what you're looking for:
if(!(Test-Path "C:DataFileDrop.done"))
return 1
else
return 0
answered Nov 15 '18 at 9:27
TobyUTobyU
2,50421122
2,50421122
add a comment |
add a comment |
This is not going to be a great answer because I have not found the documentation that explains this but the use of Exit followed by a number seems to not have any effect on the exit code.
The following example works, with the general idea taken from a blog.
First create a test script like the following:
$host.SetShouldExit(12345)
exit
Next call this script from the Powershell command line as in the following example:
$command = "C:YourTestScriptPathAndName.ps1"
Powershell -NonInteractive -NoProfile -Command $command
The script will run and exit, and we can then check the exit code from the Powershell prompt by writing out the contents of $LASTEXISTCODE
$LASTEXITCODE
In this case $LASTEXISTCODE would contain 12345.
In the case of using this with Test-Path it would look like this:
#using a path that does not exist
if(Test-Path -Path 'C:nope')
$host.SetShouldExit(1234)
else
$host.SetShouldExit(2222)
This sets the exit code to 2222 when invoked from the command line, but when I invoke that test script from another script instead of from the command line the $LASTEXITCODE variable is set to 0 still.
add a comment |
This is not going to be a great answer because I have not found the documentation that explains this but the use of Exit followed by a number seems to not have any effect on the exit code.
The following example works, with the general idea taken from a blog.
First create a test script like the following:
$host.SetShouldExit(12345)
exit
Next call this script from the Powershell command line as in the following example:
$command = "C:YourTestScriptPathAndName.ps1"
Powershell -NonInteractive -NoProfile -Command $command
The script will run and exit, and we can then check the exit code from the Powershell prompt by writing out the contents of $LASTEXISTCODE
$LASTEXITCODE
In this case $LASTEXISTCODE would contain 12345.
In the case of using this with Test-Path it would look like this:
#using a path that does not exist
if(Test-Path -Path 'C:nope')
$host.SetShouldExit(1234)
else
$host.SetShouldExit(2222)
This sets the exit code to 2222 when invoked from the command line, but when I invoke that test script from another script instead of from the command line the $LASTEXITCODE variable is set to 0 still.
add a comment |
This is not going to be a great answer because I have not found the documentation that explains this but the use of Exit followed by a number seems to not have any effect on the exit code.
The following example works, with the general idea taken from a blog.
First create a test script like the following:
$host.SetShouldExit(12345)
exit
Next call this script from the Powershell command line as in the following example:
$command = "C:YourTestScriptPathAndName.ps1"
Powershell -NonInteractive -NoProfile -Command $command
The script will run and exit, and we can then check the exit code from the Powershell prompt by writing out the contents of $LASTEXISTCODE
$LASTEXITCODE
In this case $LASTEXISTCODE would contain 12345.
In the case of using this with Test-Path it would look like this:
#using a path that does not exist
if(Test-Path -Path 'C:nope')
$host.SetShouldExit(1234)
else
$host.SetShouldExit(2222)
This sets the exit code to 2222 when invoked from the command line, but when I invoke that test script from another script instead of from the command line the $LASTEXITCODE variable is set to 0 still.
This is not going to be a great answer because I have not found the documentation that explains this but the use of Exit followed by a number seems to not have any effect on the exit code.
The following example works, with the general idea taken from a blog.
First create a test script like the following:
$host.SetShouldExit(12345)
exit
Next call this script from the Powershell command line as in the following example:
$command = "C:YourTestScriptPathAndName.ps1"
Powershell -NonInteractive -NoProfile -Command $command
The script will run and exit, and we can then check the exit code from the Powershell prompt by writing out the contents of $LASTEXISTCODE
$LASTEXITCODE
In this case $LASTEXISTCODE would contain 12345.
In the case of using this with Test-Path it would look like this:
#using a path that does not exist
if(Test-Path -Path 'C:nope')
$host.SetShouldExit(1234)
else
$host.SetShouldExit(2222)
This sets the exit code to 2222 when invoked from the command line, but when I invoke that test script from another script instead of from the command line the $LASTEXITCODE variable is set to 0 still.
answered Nov 16 '18 at 16:16
emanresuemanresu
40626
40626
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53308618%2freturning-failure-if-file-does-not-exist%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
I'm not sure what the issue is but if you don't need to store the result of test-path then you can just use if(!t(test-path -path $file)). You can also use if((test-path -path $file) -eq $false))
– emanresu
Nov 14 '18 at 21:15
Thank you for your response. The issue is, it exits with code=0 success. How do I fail this if file is not found?
– Lucky
Nov 14 '18 at 21:22
1
Don't escape backslashes in PowerShell string literals:
`
is PowerShell's escape character), so it doesn't need escaping. That said, in file paths double backslashes are usually benign (treated the same as a single backslash). Is the file the job reports as not found reallyC:DataFileDrop.done
? In your invocation scenario, is any exit code from your PowerShell script reflected in the job?– mklement0
Nov 15 '18 at 3:16