XSLT: How to select siblings with a condition



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0















I have the following XML:



 <?xml version="1.0" encoding="UTF-8"?>
<thesaurus xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">

<term id="01">
<name>
<value>green</value>
</name>
<info>
<ref rid="12" obj-type="Building" />
</info>
<info>
<ref rid="13" obj-type="House" />
</info>
<info>
<ref rid="14" obj-type="Apartment"/>
</info>
</term>
<term id="02">
<name>
<value>blue</value>
</name>
<info>
<ref rid="24" obj-type="Unknown"/>
</info>
<info>
<ref rid="26" obj-type="Unknown"/>
</info>
<info>
<ref rid="29" obj-type="Unknown"/>
</info>
</term>
<term id="03">
<name>
<value>yellow</value>
</name>
</term>
<term id="04">
<name>
<value>red</value>
</name>
<info>
<ref rid="40" obj-type="Hotel"/>
</info>
<info>
<ref rid="41" obj-type="Building"/>
</info>
<info>
<ref rid="43" obj-type="House"/>
</info>
</term>
<term id="05">
<name>
<value>purple</value>
</name>
</term>
<term id="06">
<name>
<value>magenta</value>
</name>

<info>
<ref rid="60" obj-type="Building"/>
</info>
<info>
<ref rid="62" obj-type="Unknown"/>
</info>
<info>
<ref rid="64" obj-type="House"/>
</info>
</term>
</thesaurus>



What I want is this:



1) Select all <term> tags that without an <info> tag. This is
already accomplished with the first apply-templates:
select="term[not(info)]" in the XSLT below.



2) Select all <term> tags when its <ref> tag contains an
obj-type="Unknown" alone or multiple times, but don't select it if
it's surrounded by obj-types with values different than "Unknown"
(like Building or House).



*** Inside an <info> tag, when having obj-type siblings with other values,
it takes at least one value of 'Unknown' for the <term> tag to not
be selected.





If the XSLT works well, the tags selected will be:



02, 03, 05



where:




01 won't be selected because it contains <info> tags, and none of those tags has a obj-type='Unknown'



02 will be selected because there are three multiple values of 'Unknown', and
no other values different than 'Unknown'



03 will be selected because it does not contains <info> tags



04 won't be selected because it contains <info> tags with obj-type values different than 'Unknown'.



05 will be selected because there are no info tags.



06 won't be selected because although there is one value of 'Unknown',
all the other <ref> siblings have a value obj-type different than 'Unknown'.



*** REMEMBER: Inside an <info> tag, when having obj-type siblings with other values, it takes at least one value of
'Unknown' for the <term> tag to not be selected.





I'm using the XSLT below. With the first apply-templates I can select all the tags without an <info> tag.



With the second apply-templates I can select all the <term> tags that contain a <ref> tag with an obj-type="Unknown", but I don't know how to tell the XSLT that if there are obj-types with a different value, don't select the corresponding <term> tag.



I tried to use a for-each and a conditional, to iterate through all the <ref> children and check whether one of the siblings had a different value than 'Unknown' to not select its <term> parent, but to no avail.



<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > 
<xsl:output method="text"/>

<xsl:template match="/thesaurus">

<xsl:apply-templates select="term[not(info)]"/>

<xsl:apply-templates select="term[info/ref[@obj-type='Unknown']]"/>

</xsl:template>

<xsl:template match="term">

<xsl:value-of select="@id"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="name"/>
<xsl:text>,</xsl:text>
<xsl:text>
</xsl:text>

</xsl:template>

<xsl:template match="term[info/ref]">

<xsl:value-of select="@id"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="name"/>
<xsl:text>,</xsl:text>
<xsl:text>
</xsl:text>

</xsl:template>

</xsl:stylesheet>


I hope it's clear.










share|improve this question




























    0















    I have the following XML:



     <?xml version="1.0" encoding="UTF-8"?>
    <thesaurus xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">

    <term id="01">
    <name>
    <value>green</value>
    </name>
    <info>
    <ref rid="12" obj-type="Building" />
    </info>
    <info>
    <ref rid="13" obj-type="House" />
    </info>
    <info>
    <ref rid="14" obj-type="Apartment"/>
    </info>
    </term>
    <term id="02">
    <name>
    <value>blue</value>
    </name>
    <info>
    <ref rid="24" obj-type="Unknown"/>
    </info>
    <info>
    <ref rid="26" obj-type="Unknown"/>
    </info>
    <info>
    <ref rid="29" obj-type="Unknown"/>
    </info>
    </term>
    <term id="03">
    <name>
    <value>yellow</value>
    </name>
    </term>
    <term id="04">
    <name>
    <value>red</value>
    </name>
    <info>
    <ref rid="40" obj-type="Hotel"/>
    </info>
    <info>
    <ref rid="41" obj-type="Building"/>
    </info>
    <info>
    <ref rid="43" obj-type="House"/>
    </info>
    </term>
    <term id="05">
    <name>
    <value>purple</value>
    </name>
    </term>
    <term id="06">
    <name>
    <value>magenta</value>
    </name>

    <info>
    <ref rid="60" obj-type="Building"/>
    </info>
    <info>
    <ref rid="62" obj-type="Unknown"/>
    </info>
    <info>
    <ref rid="64" obj-type="House"/>
    </info>
    </term>
    </thesaurus>



    What I want is this:



    1) Select all <term> tags that without an <info> tag. This is
    already accomplished with the first apply-templates:
    select="term[not(info)]" in the XSLT below.



    2) Select all <term> tags when its <ref> tag contains an
    obj-type="Unknown" alone or multiple times, but don't select it if
    it's surrounded by obj-types with values different than "Unknown"
    (like Building or House).



    *** Inside an <info> tag, when having obj-type siblings with other values,
    it takes at least one value of 'Unknown' for the <term> tag to not
    be selected.





    If the XSLT works well, the tags selected will be:



    02, 03, 05



    where:




    01 won't be selected because it contains <info> tags, and none of those tags has a obj-type='Unknown'



    02 will be selected because there are three multiple values of 'Unknown', and
    no other values different than 'Unknown'



    03 will be selected because it does not contains <info> tags



    04 won't be selected because it contains <info> tags with obj-type values different than 'Unknown'.



    05 will be selected because there are no info tags.



    06 won't be selected because although there is one value of 'Unknown',
    all the other <ref> siblings have a value obj-type different than 'Unknown'.



    *** REMEMBER: Inside an <info> tag, when having obj-type siblings with other values, it takes at least one value of
    'Unknown' for the <term> tag to not be selected.





    I'm using the XSLT below. With the first apply-templates I can select all the tags without an <info> tag.



    With the second apply-templates I can select all the <term> tags that contain a <ref> tag with an obj-type="Unknown", but I don't know how to tell the XSLT that if there are obj-types with a different value, don't select the corresponding <term> tag.



    I tried to use a for-each and a conditional, to iterate through all the <ref> children and check whether one of the siblings had a different value than 'Unknown' to not select its <term> parent, but to no avail.



    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > 
    <xsl:output method="text"/>

    <xsl:template match="/thesaurus">

    <xsl:apply-templates select="term[not(info)]"/>

    <xsl:apply-templates select="term[info/ref[@obj-type='Unknown']]"/>

    </xsl:template>

    <xsl:template match="term">

    <xsl:value-of select="@id"/>
    <xsl:text>,</xsl:text>
    <xsl:value-of select="name"/>
    <xsl:text>,</xsl:text>
    <xsl:text>
    </xsl:text>

    </xsl:template>

    <xsl:template match="term[info/ref]">

    <xsl:value-of select="@id"/>
    <xsl:text>,</xsl:text>
    <xsl:value-of select="name"/>
    <xsl:text>,</xsl:text>
    <xsl:text>
    </xsl:text>

    </xsl:template>

    </xsl:stylesheet>


    I hope it's clear.










    share|improve this question
























      0












      0








      0








      I have the following XML:



       <?xml version="1.0" encoding="UTF-8"?>
      <thesaurus xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">

      <term id="01">
      <name>
      <value>green</value>
      </name>
      <info>
      <ref rid="12" obj-type="Building" />
      </info>
      <info>
      <ref rid="13" obj-type="House" />
      </info>
      <info>
      <ref rid="14" obj-type="Apartment"/>
      </info>
      </term>
      <term id="02">
      <name>
      <value>blue</value>
      </name>
      <info>
      <ref rid="24" obj-type="Unknown"/>
      </info>
      <info>
      <ref rid="26" obj-type="Unknown"/>
      </info>
      <info>
      <ref rid="29" obj-type="Unknown"/>
      </info>
      </term>
      <term id="03">
      <name>
      <value>yellow</value>
      </name>
      </term>
      <term id="04">
      <name>
      <value>red</value>
      </name>
      <info>
      <ref rid="40" obj-type="Hotel"/>
      </info>
      <info>
      <ref rid="41" obj-type="Building"/>
      </info>
      <info>
      <ref rid="43" obj-type="House"/>
      </info>
      </term>
      <term id="05">
      <name>
      <value>purple</value>
      </name>
      </term>
      <term id="06">
      <name>
      <value>magenta</value>
      </name>

      <info>
      <ref rid="60" obj-type="Building"/>
      </info>
      <info>
      <ref rid="62" obj-type="Unknown"/>
      </info>
      <info>
      <ref rid="64" obj-type="House"/>
      </info>
      </term>
      </thesaurus>



      What I want is this:



      1) Select all <term> tags that without an <info> tag. This is
      already accomplished with the first apply-templates:
      select="term[not(info)]" in the XSLT below.



      2) Select all <term> tags when its <ref> tag contains an
      obj-type="Unknown" alone or multiple times, but don't select it if
      it's surrounded by obj-types with values different than "Unknown"
      (like Building or House).



      *** Inside an <info> tag, when having obj-type siblings with other values,
      it takes at least one value of 'Unknown' for the <term> tag to not
      be selected.





      If the XSLT works well, the tags selected will be:



      02, 03, 05



      where:




      01 won't be selected because it contains <info> tags, and none of those tags has a obj-type='Unknown'



      02 will be selected because there are three multiple values of 'Unknown', and
      no other values different than 'Unknown'



      03 will be selected because it does not contains <info> tags



      04 won't be selected because it contains <info> tags with obj-type values different than 'Unknown'.



      05 will be selected because there are no info tags.



      06 won't be selected because although there is one value of 'Unknown',
      all the other <ref> siblings have a value obj-type different than 'Unknown'.



      *** REMEMBER: Inside an <info> tag, when having obj-type siblings with other values, it takes at least one value of
      'Unknown' for the <term> tag to not be selected.





      I'm using the XSLT below. With the first apply-templates I can select all the tags without an <info> tag.



      With the second apply-templates I can select all the <term> tags that contain a <ref> tag with an obj-type="Unknown", but I don't know how to tell the XSLT that if there are obj-types with a different value, don't select the corresponding <term> tag.



      I tried to use a for-each and a conditional, to iterate through all the <ref> children and check whether one of the siblings had a different value than 'Unknown' to not select its <term> parent, but to no avail.



      <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > 
      <xsl:output method="text"/>

      <xsl:template match="/thesaurus">

      <xsl:apply-templates select="term[not(info)]"/>

      <xsl:apply-templates select="term[info/ref[@obj-type='Unknown']]"/>

      </xsl:template>

      <xsl:template match="term">

      <xsl:value-of select="@id"/>
      <xsl:text>,</xsl:text>
      <xsl:value-of select="name"/>
      <xsl:text>,</xsl:text>
      <xsl:text>
      </xsl:text>

      </xsl:template>

      <xsl:template match="term[info/ref]">

      <xsl:value-of select="@id"/>
      <xsl:text>,</xsl:text>
      <xsl:value-of select="name"/>
      <xsl:text>,</xsl:text>
      <xsl:text>
      </xsl:text>

      </xsl:template>

      </xsl:stylesheet>


      I hope it's clear.










      share|improve this question














      I have the following XML:



       <?xml version="1.0" encoding="UTF-8"?>
      <thesaurus xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">

      <term id="01">
      <name>
      <value>green</value>
      </name>
      <info>
      <ref rid="12" obj-type="Building" />
      </info>
      <info>
      <ref rid="13" obj-type="House" />
      </info>
      <info>
      <ref rid="14" obj-type="Apartment"/>
      </info>
      </term>
      <term id="02">
      <name>
      <value>blue</value>
      </name>
      <info>
      <ref rid="24" obj-type="Unknown"/>
      </info>
      <info>
      <ref rid="26" obj-type="Unknown"/>
      </info>
      <info>
      <ref rid="29" obj-type="Unknown"/>
      </info>
      </term>
      <term id="03">
      <name>
      <value>yellow</value>
      </name>
      </term>
      <term id="04">
      <name>
      <value>red</value>
      </name>
      <info>
      <ref rid="40" obj-type="Hotel"/>
      </info>
      <info>
      <ref rid="41" obj-type="Building"/>
      </info>
      <info>
      <ref rid="43" obj-type="House"/>
      </info>
      </term>
      <term id="05">
      <name>
      <value>purple</value>
      </name>
      </term>
      <term id="06">
      <name>
      <value>magenta</value>
      </name>

      <info>
      <ref rid="60" obj-type="Building"/>
      </info>
      <info>
      <ref rid="62" obj-type="Unknown"/>
      </info>
      <info>
      <ref rid="64" obj-type="House"/>
      </info>
      </term>
      </thesaurus>



      What I want is this:



      1) Select all <term> tags that without an <info> tag. This is
      already accomplished with the first apply-templates:
      select="term[not(info)]" in the XSLT below.



      2) Select all <term> tags when its <ref> tag contains an
      obj-type="Unknown" alone or multiple times, but don't select it if
      it's surrounded by obj-types with values different than "Unknown"
      (like Building or House).



      *** Inside an <info> tag, when having obj-type siblings with other values,
      it takes at least one value of 'Unknown' for the <term> tag to not
      be selected.





      If the XSLT works well, the tags selected will be:



      02, 03, 05



      where:




      01 won't be selected because it contains <info> tags, and none of those tags has a obj-type='Unknown'



      02 will be selected because there are three multiple values of 'Unknown', and
      no other values different than 'Unknown'



      03 will be selected because it does not contains <info> tags



      04 won't be selected because it contains <info> tags with obj-type values different than 'Unknown'.



      05 will be selected because there are no info tags.



      06 won't be selected because although there is one value of 'Unknown',
      all the other <ref> siblings have a value obj-type different than 'Unknown'.



      *** REMEMBER: Inside an <info> tag, when having obj-type siblings with other values, it takes at least one value of
      'Unknown' for the <term> tag to not be selected.





      I'm using the XSLT below. With the first apply-templates I can select all the tags without an <info> tag.



      With the second apply-templates I can select all the <term> tags that contain a <ref> tag with an obj-type="Unknown", but I don't know how to tell the XSLT that if there are obj-types with a different value, don't select the corresponding <term> tag.



      I tried to use a for-each and a conditional, to iterate through all the <ref> children and check whether one of the siblings had a different value than 'Unknown' to not select its <term> parent, but to no avail.



      <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > 
      <xsl:output method="text"/>

      <xsl:template match="/thesaurus">

      <xsl:apply-templates select="term[not(info)]"/>

      <xsl:apply-templates select="term[info/ref[@obj-type='Unknown']]"/>

      </xsl:template>

      <xsl:template match="term">

      <xsl:value-of select="@id"/>
      <xsl:text>,</xsl:text>
      <xsl:value-of select="name"/>
      <xsl:text>,</xsl:text>
      <xsl:text>
      </xsl:text>

      </xsl:template>

      <xsl:template match="term[info/ref]">

      <xsl:value-of select="@id"/>
      <xsl:text>,</xsl:text>
      <xsl:value-of select="name"/>
      <xsl:text>,</xsl:text>
      <xsl:text>
      </xsl:text>

      </xsl:template>

      </xsl:stylesheet>


      I hope it's clear.







      xml xslt






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 15 '18 at 16:11









      mistervelamistervela

      4910




      4910






















          1 Answer
          1






          active

          oldest

          votes


















          1














          You could try selecting the terms who doesn't contain something other than Unknown



          <xsl:apply-templates select="term[not(info/ref[@obj-type!='Unknown'])]"/>


          Or adding an if statement in your term[info/ref] template



          <xsl:template match="term[info/ref]">
          <xsl:if test="not(info/ref[@obj-type!='Unknown'])">
          <xsl:value-of select="@id"/>
          <xsl:text>,</xsl:text>
          <xsl:value-of select="name"/>
          <xsl:text>,</xsl:text>
          <xsl:text>
          </xsl:text>
          </xsl:if>

          </xsl:template>





          share|improve this answer























          • It works. Thank you so much for taking your time to go through this code. I knew it was something that simple. I tried to use an IF but couldn't properly construct it in XSLT terms. Thanks again.

            – mistervela
            Nov 16 '18 at 10:11











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          1 Answer
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          active

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          active

          oldest

          votes






          active

          oldest

          votes









          1














          You could try selecting the terms who doesn't contain something other than Unknown



          <xsl:apply-templates select="term[not(info/ref[@obj-type!='Unknown'])]"/>


          Or adding an if statement in your term[info/ref] template



          <xsl:template match="term[info/ref]">
          <xsl:if test="not(info/ref[@obj-type!='Unknown'])">
          <xsl:value-of select="@id"/>
          <xsl:text>,</xsl:text>
          <xsl:value-of select="name"/>
          <xsl:text>,</xsl:text>
          <xsl:text>
          </xsl:text>
          </xsl:if>

          </xsl:template>





          share|improve this answer























          • It works. Thank you so much for taking your time to go through this code. I knew it was something that simple. I tried to use an IF but couldn't properly construct it in XSLT terms. Thanks again.

            – mistervela
            Nov 16 '18 at 10:11















          1














          You could try selecting the terms who doesn't contain something other than Unknown



          <xsl:apply-templates select="term[not(info/ref[@obj-type!='Unknown'])]"/>


          Or adding an if statement in your term[info/ref] template



          <xsl:template match="term[info/ref]">
          <xsl:if test="not(info/ref[@obj-type!='Unknown'])">
          <xsl:value-of select="@id"/>
          <xsl:text>,</xsl:text>
          <xsl:value-of select="name"/>
          <xsl:text>,</xsl:text>
          <xsl:text>
          </xsl:text>
          </xsl:if>

          </xsl:template>





          share|improve this answer























          • It works. Thank you so much for taking your time to go through this code. I knew it was something that simple. I tried to use an IF but couldn't properly construct it in XSLT terms. Thanks again.

            – mistervela
            Nov 16 '18 at 10:11













          1












          1








          1







          You could try selecting the terms who doesn't contain something other than Unknown



          <xsl:apply-templates select="term[not(info/ref[@obj-type!='Unknown'])]"/>


          Or adding an if statement in your term[info/ref] template



          <xsl:template match="term[info/ref]">
          <xsl:if test="not(info/ref[@obj-type!='Unknown'])">
          <xsl:value-of select="@id"/>
          <xsl:text>,</xsl:text>
          <xsl:value-of select="name"/>
          <xsl:text>,</xsl:text>
          <xsl:text>
          </xsl:text>
          </xsl:if>

          </xsl:template>





          share|improve this answer













          You could try selecting the terms who doesn't contain something other than Unknown



          <xsl:apply-templates select="term[not(info/ref[@obj-type!='Unknown'])]"/>


          Or adding an if statement in your term[info/ref] template



          <xsl:template match="term[info/ref]">
          <xsl:if test="not(info/ref[@obj-type!='Unknown'])">
          <xsl:value-of select="@id"/>
          <xsl:text>,</xsl:text>
          <xsl:value-of select="name"/>
          <xsl:text>,</xsl:text>
          <xsl:text>
          </xsl:text>
          </xsl:if>

          </xsl:template>






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 15 '18 at 17:38









          NeskuNesku

          4211412




          4211412












          • It works. Thank you so much for taking your time to go through this code. I knew it was something that simple. I tried to use an IF but couldn't properly construct it in XSLT terms. Thanks again.

            – mistervela
            Nov 16 '18 at 10:11

















          • It works. Thank you so much for taking your time to go through this code. I knew it was something that simple. I tried to use an IF but couldn't properly construct it in XSLT terms. Thanks again.

            – mistervela
            Nov 16 '18 at 10:11
















          It works. Thank you so much for taking your time to go through this code. I knew it was something that simple. I tried to use an IF but couldn't properly construct it in XSLT terms. Thanks again.

          – mistervela
          Nov 16 '18 at 10:11





          It works. Thank you so much for taking your time to go through this code. I knew it was something that simple. I tried to use an IF but couldn't properly construct it in XSLT terms. Thanks again.

          – mistervela
          Nov 16 '18 at 10:11



















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