Java 8 Exception: com.fasterxml.jackson.datatype.jsr310.deser.InstantDeserializer has no default (no arg) constructor









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0
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I have a model class that has a field:



 @JsonDeserialize(using = InstantDeserializer.class)
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSZ")
private OffsetDateTime offsetDt;


When a request of this model is sent to the server, my controller throws an exception:



Caused by: java.lang.IllegalArgumentException: 
Class com.fasterxml.jackson.datatype.jsr310.deser.InstantDeserializer
has no default (no arg) constructor


The pom.xml has the dependency of version 2.8.11:



 <dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
</dependency>


I understand that it is caused by @JsonDeserialize requiring no-arg constructor, but is there a workaround? Many thanks.










share|improve this question























  • InstantDeserializer.class is custom deserializer class?, if i believe in that class you may declared some arg constructor without no-arg constructor
    – Deadpool
    Nov 9 at 20:08










  • @Deadpool no, it is not a custom class.. com.fasterxml.jackson.datatype.jsr310.deser
    – jlp
    Nov 9 at 20:10











  • what does your POM look like?
    – Darren Forsythe
    Nov 9 at 20:15






  • 1




    Look at this answer stackoverflow.com/a/45215515/4727666, you need a class with a constructor that takes no arguments, so you can extend InstantDeserializer to create your own.
    – Julio Daniel Reyes
    Nov 9 at 21:31






  • 1




    For the arguments, take a look at this github.com/FasterXML/jackson-datatype-jsr310/blob/master/src/…
    – Julio Daniel Reyes
    Nov 9 at 21:35














up vote
0
down vote

favorite












I have a model class that has a field:



 @JsonDeserialize(using = InstantDeserializer.class)
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSZ")
private OffsetDateTime offsetDt;


When a request of this model is sent to the server, my controller throws an exception:



Caused by: java.lang.IllegalArgumentException: 
Class com.fasterxml.jackson.datatype.jsr310.deser.InstantDeserializer
has no default (no arg) constructor


The pom.xml has the dependency of version 2.8.11:



 <dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
</dependency>


I understand that it is caused by @JsonDeserialize requiring no-arg constructor, but is there a workaround? Many thanks.










share|improve this question























  • InstantDeserializer.class is custom deserializer class?, if i believe in that class you may declared some arg constructor without no-arg constructor
    – Deadpool
    Nov 9 at 20:08










  • @Deadpool no, it is not a custom class.. com.fasterxml.jackson.datatype.jsr310.deser
    – jlp
    Nov 9 at 20:10











  • what does your POM look like?
    – Darren Forsythe
    Nov 9 at 20:15






  • 1




    Look at this answer stackoverflow.com/a/45215515/4727666, you need a class with a constructor that takes no arguments, so you can extend InstantDeserializer to create your own.
    – Julio Daniel Reyes
    Nov 9 at 21:31






  • 1




    For the arguments, take a look at this github.com/FasterXML/jackson-datatype-jsr310/blob/master/src/…
    – Julio Daniel Reyes
    Nov 9 at 21:35












up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have a model class that has a field:



 @JsonDeserialize(using = InstantDeserializer.class)
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSZ")
private OffsetDateTime offsetDt;


When a request of this model is sent to the server, my controller throws an exception:



Caused by: java.lang.IllegalArgumentException: 
Class com.fasterxml.jackson.datatype.jsr310.deser.InstantDeserializer
has no default (no arg) constructor


The pom.xml has the dependency of version 2.8.11:



 <dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
</dependency>


I understand that it is caused by @JsonDeserialize requiring no-arg constructor, but is there a workaround? Many thanks.










share|improve this question















I have a model class that has a field:



 @JsonDeserialize(using = InstantDeserializer.class)
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSZ")
private OffsetDateTime offsetDt;


When a request of this model is sent to the server, my controller throws an exception:



Caused by: java.lang.IllegalArgumentException: 
Class com.fasterxml.jackson.datatype.jsr310.deser.InstantDeserializer
has no default (no arg) constructor


The pom.xml has the dependency of version 2.8.11:



 <dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
</dependency>


I understand that it is caused by @JsonDeserialize requiring no-arg constructor, but is there a workaround? Many thanks.







java json jackson fasterxml jsr310






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 9 at 20:50

























asked Nov 9 at 20:03









jlp

4091822




4091822











  • InstantDeserializer.class is custom deserializer class?, if i believe in that class you may declared some arg constructor without no-arg constructor
    – Deadpool
    Nov 9 at 20:08










  • @Deadpool no, it is not a custom class.. com.fasterxml.jackson.datatype.jsr310.deser
    – jlp
    Nov 9 at 20:10











  • what does your POM look like?
    – Darren Forsythe
    Nov 9 at 20:15






  • 1




    Look at this answer stackoverflow.com/a/45215515/4727666, you need a class with a constructor that takes no arguments, so you can extend InstantDeserializer to create your own.
    – Julio Daniel Reyes
    Nov 9 at 21:31






  • 1




    For the arguments, take a look at this github.com/FasterXML/jackson-datatype-jsr310/blob/master/src/…
    – Julio Daniel Reyes
    Nov 9 at 21:35
















  • InstantDeserializer.class is custom deserializer class?, if i believe in that class you may declared some arg constructor without no-arg constructor
    – Deadpool
    Nov 9 at 20:08










  • @Deadpool no, it is not a custom class.. com.fasterxml.jackson.datatype.jsr310.deser
    – jlp
    Nov 9 at 20:10











  • what does your POM look like?
    – Darren Forsythe
    Nov 9 at 20:15






  • 1




    Look at this answer stackoverflow.com/a/45215515/4727666, you need a class with a constructor that takes no arguments, so you can extend InstantDeserializer to create your own.
    – Julio Daniel Reyes
    Nov 9 at 21:31






  • 1




    For the arguments, take a look at this github.com/FasterXML/jackson-datatype-jsr310/blob/master/src/…
    – Julio Daniel Reyes
    Nov 9 at 21:35















InstantDeserializer.class is custom deserializer class?, if i believe in that class you may declared some arg constructor without no-arg constructor
– Deadpool
Nov 9 at 20:08




InstantDeserializer.class is custom deserializer class?, if i believe in that class you may declared some arg constructor without no-arg constructor
– Deadpool
Nov 9 at 20:08












@Deadpool no, it is not a custom class.. com.fasterxml.jackson.datatype.jsr310.deser
– jlp
Nov 9 at 20:10





@Deadpool no, it is not a custom class.. com.fasterxml.jackson.datatype.jsr310.deser
– jlp
Nov 9 at 20:10













what does your POM look like?
– Darren Forsythe
Nov 9 at 20:15




what does your POM look like?
– Darren Forsythe
Nov 9 at 20:15




1




1




Look at this answer stackoverflow.com/a/45215515/4727666, you need a class with a constructor that takes no arguments, so you can extend InstantDeserializer to create your own.
– Julio Daniel Reyes
Nov 9 at 21:31




Look at this answer stackoverflow.com/a/45215515/4727666, you need a class with a constructor that takes no arguments, so you can extend InstantDeserializer to create your own.
– Julio Daniel Reyes
Nov 9 at 21:31




1




1




For the arguments, take a look at this github.com/FasterXML/jackson-datatype-jsr310/blob/master/src/…
– Julio Daniel Reyes
Nov 9 at 21:35




For the arguments, take a look at this github.com/FasterXML/jackson-datatype-jsr310/blob/master/src/…
– Julio Daniel Reyes
Nov 9 at 21:35












1 Answer
1






active

oldest

votes

















up vote
1
down vote



accepted










The error says that you need a class with no arg constructor, so you could extend from InstantDeserializer. (Take as example the code in InstantDeserializer for the arguments of super())



public class DefaultInstantDeserializer extends InstantDeserializer<OffsetDateTime> 
public DefaultInstantDeserializer()
super(OffsetDateTime.class, DateTimeFormatter.ISO_OFFSET_DATE_TIME,
OffsetDateTime::from,
a -> OffsetDateTime.ofInstant(Instant.ofEpochMilli(a.value), a.zoneId),
a -> OffsetDateTime.ofInstant(Instant.ofEpochSecond(a.integer, a.fraction), a.zoneId),
(d, z) -> d.withOffsetSameInstant(z.getRules().getOffset(d.toLocalDateTime())),
true);




Then you can use it:



@JsonDeserialize(using = DefaultInstantDeserializer.class)





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    active

    oldest

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    active

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    active

    oldest

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    up vote
    1
    down vote



    accepted










    The error says that you need a class with no arg constructor, so you could extend from InstantDeserializer. (Take as example the code in InstantDeserializer for the arguments of super())



    public class DefaultInstantDeserializer extends InstantDeserializer<OffsetDateTime> 
    public DefaultInstantDeserializer()
    super(OffsetDateTime.class, DateTimeFormatter.ISO_OFFSET_DATE_TIME,
    OffsetDateTime::from,
    a -> OffsetDateTime.ofInstant(Instant.ofEpochMilli(a.value), a.zoneId),
    a -> OffsetDateTime.ofInstant(Instant.ofEpochSecond(a.integer, a.fraction), a.zoneId),
    (d, z) -> d.withOffsetSameInstant(z.getRules().getOffset(d.toLocalDateTime())),
    true);




    Then you can use it:



    @JsonDeserialize(using = DefaultInstantDeserializer.class)





    share|improve this answer
























      up vote
      1
      down vote



      accepted










      The error says that you need a class with no arg constructor, so you could extend from InstantDeserializer. (Take as example the code in InstantDeserializer for the arguments of super())



      public class DefaultInstantDeserializer extends InstantDeserializer<OffsetDateTime> 
      public DefaultInstantDeserializer()
      super(OffsetDateTime.class, DateTimeFormatter.ISO_OFFSET_DATE_TIME,
      OffsetDateTime::from,
      a -> OffsetDateTime.ofInstant(Instant.ofEpochMilli(a.value), a.zoneId),
      a -> OffsetDateTime.ofInstant(Instant.ofEpochSecond(a.integer, a.fraction), a.zoneId),
      (d, z) -> d.withOffsetSameInstant(z.getRules().getOffset(d.toLocalDateTime())),
      true);




      Then you can use it:



      @JsonDeserialize(using = DefaultInstantDeserializer.class)





      share|improve this answer






















        up vote
        1
        down vote



        accepted







        up vote
        1
        down vote



        accepted






        The error says that you need a class with no arg constructor, so you could extend from InstantDeserializer. (Take as example the code in InstantDeserializer for the arguments of super())



        public class DefaultInstantDeserializer extends InstantDeserializer<OffsetDateTime> 
        public DefaultInstantDeserializer()
        super(OffsetDateTime.class, DateTimeFormatter.ISO_OFFSET_DATE_TIME,
        OffsetDateTime::from,
        a -> OffsetDateTime.ofInstant(Instant.ofEpochMilli(a.value), a.zoneId),
        a -> OffsetDateTime.ofInstant(Instant.ofEpochSecond(a.integer, a.fraction), a.zoneId),
        (d, z) -> d.withOffsetSameInstant(z.getRules().getOffset(d.toLocalDateTime())),
        true);




        Then you can use it:



        @JsonDeserialize(using = DefaultInstantDeserializer.class)





        share|improve this answer












        The error says that you need a class with no arg constructor, so you could extend from InstantDeserializer. (Take as example the code in InstantDeserializer for the arguments of super())



        public class DefaultInstantDeserializer extends InstantDeserializer<OffsetDateTime> 
        public DefaultInstantDeserializer()
        super(OffsetDateTime.class, DateTimeFormatter.ISO_OFFSET_DATE_TIME,
        OffsetDateTime::from,
        a -> OffsetDateTime.ofInstant(Instant.ofEpochMilli(a.value), a.zoneId),
        a -> OffsetDateTime.ofInstant(Instant.ofEpochSecond(a.integer, a.fraction), a.zoneId),
        (d, z) -> d.withOffsetSameInstant(z.getRules().getOffset(d.toLocalDateTime())),
        true);




        Then you can use it:



        @JsonDeserialize(using = DefaultInstantDeserializer.class)






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 12 at 4:30









        Julio Daniel Reyes

        1,977815




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