Byte array to image exception
up vote
0
down vote
favorite
i have a trouble converting byte array to an image by common methods for example:
using (var ms = new MemoryStream(byteArrayIn))
return Image.FromStream(ms); ->exception
and
System.Drawing.ImageConverter converter = new System.Drawing.ImageConverter();
Image img = (Image)converter.ConvertFrom(ImgInBytes); -> exception
The exception is
Parameter is not valid
moreover, i used a 4 byte array length which was initiated by zero value.
it was supposed to show a black image but it didn't
c# image
asked Nov 11 at 0:14
Mr.AF
631816
|
show 9 more comments
up vote
0
down vote
favorite
i have a trouble converting byte array to an image by common methods for example:
using (var ms = new MemoryStream(byteArrayIn))
return Image.FromStream(ms); ->exception
and
System.Drawing.ImageConverter converter = new System.Drawing.ImageConverter();
Image img = (Image)converter.ConvertFrom(ImgInBytes); -> exception
The exception is
Parameter is not valid
moreover, i used a 4 byte array length which was initiated by zero value.
it was supposed to show a black image but it didn't
c# image
asked Nov 11 at 0:14
Mr.AF
631816
you think you can make a image from 4 bytes? That would be just enough data for one pixel. But not actually wich color depth to use or any of the thousand other important inforamtions. You should propably not try to create a image from scratch. Create it from a existing soruce until you got the hang of the basics.
– Christopher
Nov 11 at 0:17
1
Show thebyteArrayInvariable. If you just want to create an empty black image, what stops you from using a new Bitmap? Moreover, from where does your information come that it is supposed to be a black image? How would you decide on width & height of a picture?
– Icepickle
Nov 11 at 0:18
@Christopher why there is not any limitation on byte size?
– Mr.AF
Nov 11 at 0:18
1
@Mr.AF that doesn't mean that any arbitrary content is valid; what format are you trying to represent (streams are broadly comparable to files: it isn't just raw bitmap data); the header for most image formats is more than 4 bytes
– Marc Gravell♦
Nov 11 at 0:21
4
@Mr.AF it isn't just about size: the contents matter; the input needs to be a valid image format -0 0 0 0is not a valid image format. Most images consist of an identification token (png always starts 137 80 78 71 13 10 26 10, for example) - then format-specific encoded metadata - dimensions, color depth, possibly a color palette, maybe date/location/tool metadata; then finally some pixel data, which could use a range of encodings... and that's assuming it is pixed-based (vs vector-based)
– Marc Gravell♦
Nov 11 at 0:29
|
show 9 more comments
up vote
0
down vote
favorite
up vote
0
down vote
favorite
i have a trouble converting byte array to an image by common methods for example:
using (var ms = new MemoryStream(byteArrayIn))
return Image.FromStream(ms); ->exception
and
System.Drawing.ImageConverter converter = new System.Drawing.ImageConverter();
Image img = (Image)converter.ConvertFrom(ImgInBytes); -> exception
The exception is
Parameter is not valid
moreover, i used a 4 byte array length which was initiated by zero value.
it was supposed to show a black image but it didn't
c# image
asked Nov 11 at 0:14
Mr.AF
631816
i have a trouble converting byte array to an image by common methods for example:
using (var ms = new MemoryStream(byteArrayIn))
return Image.FromStream(ms); ->exception
and
System.Drawing.ImageConverter converter = new System.Drawing.ImageConverter();
Image img = (Image)converter.ConvertFrom(ImgInBytes); -> exception
The exception is
Parameter is not valid
moreover, i used a 4 byte array length which was initiated by zero value.
it was supposed to show a black image but it didn't
c# image
c# image
asked Nov 11 at 0:14
Mr.AF
631816
asked Nov 11 at 0:14
Mr.AF
631816
asked Nov 11 at 0:14
Mr.AF
631816
asked Nov 11 at 0:14
Mr.AF
631816
asked Nov 11 at 0:14
Mr.AF
631816
631816
you think you can make a image from 4 bytes? That would be just enough data for one pixel. But not actually wich color depth to use or any of the thousand other important inforamtions. You should propably not try to create a image from scratch. Create it from a existing soruce until you got the hang of the basics.
– Christopher
Nov 11 at 0:17
1
Show thebyteArrayInvariable. If you just want to create an empty black image, what stops you from using a new Bitmap? Moreover, from where does your information come that it is supposed to be a black image? How would you decide on width & height of a picture?
– Icepickle
Nov 11 at 0:18
@Christopher why there is not any limitation on byte size?
– Mr.AF
Nov 11 at 0:18
1
@Mr.AF that doesn't mean that any arbitrary content is valid; what format are you trying to represent (streams are broadly comparable to files: it isn't just raw bitmap data); the header for most image formats is more than 4 bytes
– Marc Gravell♦
Nov 11 at 0:21
4
@Mr.AF it isn't just about size: the contents matter; the input needs to be a valid image format -0 0 0 0is not a valid image format. Most images consist of an identification token (png always starts 137 80 78 71 13 10 26 10, for example) - then format-specific encoded metadata - dimensions, color depth, possibly a color palette, maybe date/location/tool metadata; then finally some pixel data, which could use a range of encodings... and that's assuming it is pixed-based (vs vector-based)
– Marc Gravell♦
Nov 11 at 0:29
|
show 9 more comments
you think you can make a image from 4 bytes? That would be just enough data for one pixel. But not actually wich color depth to use or any of the thousand other important inforamtions. You should propably not try to create a image from scratch. Create it from a existing soruce until you got the hang of the basics.
– Christopher
Nov 11 at 0:17
1
Show thebyteArrayInvariable. If you just want to create an empty black image, what stops you from using a new Bitmap? Moreover, from where does your information come that it is supposed to be a black image? How would you decide on width & height of a picture?
– Icepickle
Nov 11 at 0:18
@Christopher why there is not any limitation on byte size?
– Mr.AF
Nov 11 at 0:18
1
@Mr.AF that doesn't mean that any arbitrary content is valid; what format are you trying to represent (streams are broadly comparable to files: it isn't just raw bitmap data); the header for most image formats is more than 4 bytes
– Marc Gravell♦
Nov 11 at 0:21
4
@Mr.AF it isn't just about size: the contents matter; the input needs to be a valid image format -0 0 0 0is not a valid image format. Most images consist of an identification token (png always starts 137 80 78 71 13 10 26 10, for example) - then format-specific encoded metadata - dimensions, color depth, possibly a color palette, maybe date/location/tool metadata; then finally some pixel data, which could use a range of encodings... and that's assuming it is pixed-based (vs vector-based)
– Marc Gravell♦
Nov 11 at 0:29
you think you can make a image from 4 bytes? That would be just enough data for one pixel. But not actually wich color depth to use or any of the thousand other important inforamtions. You should propably not try to create a image from scratch. Create it from a existing soruce until you got the hang of the basics.
– Christopher
Nov 11 at 0:17
you think you can make a image from 4 bytes? That would be just enough data for one pixel. But not actually wich color depth to use or any of the thousand other important inforamtions. You should propably not try to create a image from scratch. Create it from a existing soruce until you got the hang of the basics.
– Christopher
Nov 11 at 0:17
1
1
Show the
byteArrayIn variable. If you just want to create an empty black image, what stops you from using a new Bitmap? Moreover, from where does your information come that it is supposed to be a black image? How would you decide on width & height of a picture?– Icepickle
Nov 11 at 0:18
Show the
byteArrayIn variable. If you just want to create an empty black image, what stops you from using a new Bitmap? Moreover, from where does your information come that it is supposed to be a black image? How would you decide on width & height of a picture?– Icepickle
Nov 11 at 0:18
@Christopher why there is not any limitation on byte size?
– Mr.AF
Nov 11 at 0:18
@Christopher why there is not any limitation on byte size?
– Mr.AF
Nov 11 at 0:18
1
1
@Mr.AF that doesn't mean that any arbitrary content is valid; what format are you trying to represent (streams are broadly comparable to files: it isn't just raw bitmap data); the header for most image formats is more than 4 bytes
– Marc Gravell♦
Nov 11 at 0:21
@Mr.AF that doesn't mean that any arbitrary content is valid; what format are you trying to represent (streams are broadly comparable to files: it isn't just raw bitmap data); the header for most image formats is more than 4 bytes
– Marc Gravell♦
Nov 11 at 0:21
4
4
@Mr.AF it isn't just about size: the contents matter; the input needs to be a valid image format -
0 0 0 0 is not a valid image format. Most images consist of an identification token (png always starts 137 80 78 71 13 10 26 10, for example) - then format-specific encoded metadata - dimensions, color depth, possibly a color palette, maybe date/location/tool metadata; then finally some pixel data, which could use a range of encodings... and that's assuming it is pixed-based (vs vector-based)– Marc Gravell♦
Nov 11 at 0:29
@Mr.AF it isn't just about size: the contents matter; the input needs to be a valid image format -
0 0 0 0 is not a valid image format. Most images consist of an identification token (png always starts 137 80 78 71 13 10 26 10, for example) - then format-specific encoded metadata - dimensions, color depth, possibly a color palette, maybe date/location/tool metadata; then finally some pixel data, which could use a range of encodings... and that's assuming it is pixed-based (vs vector-based)– Marc Gravell♦
Nov 11 at 0:29
|
show 9 more comments
1 Answer
1
active
oldest
votes
up vote
2
down vote
accepted
i used a 4 byte array length which was initiated by zero value.
The API expects a valid image stream; 4 bytes with value zero is not a valid image stream. The method is going to inspect the stream, trying to identify the image format (streams are broadly comparable to files, except without any concept of a filename) - it isn't just looking for pixel data. That means it is going to be looking for an image header that it recognizes (for example, png always starts with the byte values 137 80 78 71 13 10 26 10); once it has identified the format, it'll want to decode the image header (dimensions, color depth, possibly a palette, etc), and then finally there might be some pixel data - or there might not, if it isn't a pixel format (it could be a vector image format). So; there's a lot more to consider than just some pixel data.
If you want a black image: perhaps start with Bitmap - maybe see this answer
answered Nov 11 at 0:39
Marc Gravell♦
775k19021242538
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53244685%2fbyte-array-to-image-exception%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
i used a 4 byte array length which was initiated by zero value.
The API expects a valid image stream; 4 bytes with value zero is not a valid image stream. The method is going to inspect the stream, trying to identify the image format (streams are broadly comparable to files, except without any concept of a filename) - it isn't just looking for pixel data. That means it is going to be looking for an image header that it recognizes (for example, png always starts with the byte values 137 80 78 71 13 10 26 10); once it has identified the format, it'll want to decode the image header (dimensions, color depth, possibly a palette, etc), and then finally there might be some pixel data - or there might not, if it isn't a pixel format (it could be a vector image format). So; there's a lot more to consider than just some pixel data.
If you want a black image: perhaps start with Bitmap - maybe see this answer
answered Nov 11 at 0:39
Marc Gravell♦
775k19021242538
add a comment |
up vote
2
down vote
accepted
i used a 4 byte array length which was initiated by zero value.
The API expects a valid image stream; 4 bytes with value zero is not a valid image stream. The method is going to inspect the stream, trying to identify the image format (streams are broadly comparable to files, except without any concept of a filename) - it isn't just looking for pixel data. That means it is going to be looking for an image header that it recognizes (for example, png always starts with the byte values 137 80 78 71 13 10 26 10); once it has identified the format, it'll want to decode the image header (dimensions, color depth, possibly a palette, etc), and then finally there might be some pixel data - or there might not, if it isn't a pixel format (it could be a vector image format). So; there's a lot more to consider than just some pixel data.
If you want a black image: perhaps start with Bitmap - maybe see this answer
answered Nov 11 at 0:39
Marc Gravell♦
775k19021242538
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
i used a 4 byte array length which was initiated by zero value.
The API expects a valid image stream; 4 bytes with value zero is not a valid image stream. The method is going to inspect the stream, trying to identify the image format (streams are broadly comparable to files, except without any concept of a filename) - it isn't just looking for pixel data. That means it is going to be looking for an image header that it recognizes (for example, png always starts with the byte values 137 80 78 71 13 10 26 10); once it has identified the format, it'll want to decode the image header (dimensions, color depth, possibly a palette, etc), and then finally there might be some pixel data - or there might not, if it isn't a pixel format (it could be a vector image format). So; there's a lot more to consider than just some pixel data.
If you want a black image: perhaps start with Bitmap - maybe see this answer
answered Nov 11 at 0:39
Marc Gravell♦
775k19021242538
i used a 4 byte array length which was initiated by zero value.
The API expects a valid image stream; 4 bytes with value zero is not a valid image stream. The method is going to inspect the stream, trying to identify the image format (streams are broadly comparable to files, except without any concept of a filename) - it isn't just looking for pixel data. That means it is going to be looking for an image header that it recognizes (for example, png always starts with the byte values 137 80 78 71 13 10 26 10); once it has identified the format, it'll want to decode the image header (dimensions, color depth, possibly a palette, etc), and then finally there might be some pixel data - or there might not, if it isn't a pixel format (it could be a vector image format). So; there's a lot more to consider than just some pixel data.
If you want a black image: perhaps start with Bitmap - maybe see this answer
answered Nov 11 at 0:39
Marc Gravell♦
775k19021242538
answered Nov 11 at 0:39
Marc Gravell♦
775k19021242538
answered Nov 11 at 0:39
Marc Gravell♦
775k19021242538
answered Nov 11 at 0:39
Marc Gravell♦
775k19021242538
775k19021242538
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53244685%2fbyte-array-to-image-exception%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
you think you can make a image from 4 bytes? That would be just enough data for one pixel. But not actually wich color depth to use or any of the thousand other important inforamtions. You should propably not try to create a image from scratch. Create it from a existing soruce until you got the hang of the basics.
– Christopher
Nov 11 at 0:17
1
Show the
byteArrayInvariable. If you just want to create an empty black image, what stops you from using a new Bitmap? Moreover, from where does your information come that it is supposed to be a black image? How would you decide on width & height of a picture?– Icepickle
Nov 11 at 0:18
@Christopher why there is not any limitation on byte size?
– Mr.AF
Nov 11 at 0:18
1
@Mr.AF that doesn't mean that any arbitrary content is valid; what format are you trying to represent (streams are broadly comparable to files: it isn't just raw bitmap data); the header for most image formats is more than 4 bytes
– Marc Gravell♦
Nov 11 at 0:21
4
@Mr.AF it isn't just about size: the contents matter; the input needs to be a valid image format -
0 0 0 0is not a valid image format. Most images consist of an identification token (png always starts 137 80 78 71 13 10 26 10, for example) - then format-specific encoded metadata - dimensions, color depth, possibly a color palette, maybe date/location/tool metadata; then finally some pixel data, which could use a range of encodings... and that's assuming it is pixed-based (vs vector-based)– Marc Gravell♦
Nov 11 at 0:29