How do you completely run an if statement before moving to the next one?









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This question is very hard to put into concise wording. How would I modify my code to meet the constraints I'm given in this problem?



public static void main(String args) {
final int test = 1, 6, 11, 16, 21,
2, 7, 12, 17, 22,
3, 8, 13, 18, 23,
4, 9, 14, 19, 24,
5, 10, 15, 20, 25 ;
System.out.println(TwoDOneD.XShape(test));

public static String XShape(int test)
String res = "";
for (int c = 0; c < test[0].length; c++)
for (int r = 0; r < test.length; r++)
if (c == r)
res += test[r][c] + " ";
else if (c + r == 4)
res += test[r][c] + " ";



return res;



The point of this code is to put the integers that make an X pattern into a string and to print the string. This is the output I get whenever I run it:



1 5 7 9 13 17 19 21 25 


But I want the output to look like this (using the first if statement first, adding all of those values into the string, then moving to the other else if statement and adding all of those values into the string):



1 7 13 19 25 21 17 13 9 5









share|improve this question

























    up vote
    1
    down vote

    favorite












    This question is very hard to put into concise wording. How would I modify my code to meet the constraints I'm given in this problem?



    public static void main(String args) {
    final int test = 1, 6, 11, 16, 21,
    2, 7, 12, 17, 22,
    3, 8, 13, 18, 23,
    4, 9, 14, 19, 24,
    5, 10, 15, 20, 25 ;
    System.out.println(TwoDOneD.XShape(test));

    public static String XShape(int test)
    String res = "";
    for (int c = 0; c < test[0].length; c++)
    for (int r = 0; r < test.length; r++)
    if (c == r)
    res += test[r][c] + " ";
    else if (c + r == 4)
    res += test[r][c] + " ";



    return res;



    The point of this code is to put the integers that make an X pattern into a string and to print the string. This is the output I get whenever I run it:



    1 5 7 9 13 17 19 21 25 


    But I want the output to look like this (using the first if statement first, adding all of those values into the string, then moving to the other else if statement and adding all of those values into the string):



    1 7 13 19 25 21 17 13 9 5









    share|improve this question























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      This question is very hard to put into concise wording. How would I modify my code to meet the constraints I'm given in this problem?



      public static void main(String args) {
      final int test = 1, 6, 11, 16, 21,
      2, 7, 12, 17, 22,
      3, 8, 13, 18, 23,
      4, 9, 14, 19, 24,
      5, 10, 15, 20, 25 ;
      System.out.println(TwoDOneD.XShape(test));

      public static String XShape(int test)
      String res = "";
      for (int c = 0; c < test[0].length; c++)
      for (int r = 0; r < test.length; r++)
      if (c == r)
      res += test[r][c] + " ";
      else if (c + r == 4)
      res += test[r][c] + " ";



      return res;



      The point of this code is to put the integers that make an X pattern into a string and to print the string. This is the output I get whenever I run it:



      1 5 7 9 13 17 19 21 25 


      But I want the output to look like this (using the first if statement first, adding all of those values into the string, then moving to the other else if statement and adding all of those values into the string):



      1 7 13 19 25 21 17 13 9 5









      share|improve this question













      This question is very hard to put into concise wording. How would I modify my code to meet the constraints I'm given in this problem?



      public static void main(String args) {
      final int test = 1, 6, 11, 16, 21,
      2, 7, 12, 17, 22,
      3, 8, 13, 18, 23,
      4, 9, 14, 19, 24,
      5, 10, 15, 20, 25 ;
      System.out.println(TwoDOneD.XShape(test));

      public static String XShape(int test)
      String res = "";
      for (int c = 0; c < test[0].length; c++)
      for (int r = 0; r < test.length; r++)
      if (c == r)
      res += test[r][c] + " ";
      else if (c + r == 4)
      res += test[r][c] + " ";



      return res;



      The point of this code is to put the integers that make an X pattern into a string and to print the string. This is the output I get whenever I run it:



      1 5 7 9 13 17 19 21 25 


      But I want the output to look like this (using the first if statement first, adding all of those values into the string, then moving to the other else if statement and adding all of those values into the string):



      1 7 13 19 25 21 17 13 9 5






      java






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 10 at 19:55









      Excel

      478




      478






















          3 Answers
          3






          active

          oldest

          votes

















          up vote
          2
          down vote



          accepted










          You don’t need an extra loop if you use 2 results, then join them at the end:



          String res1, res2 = "";
          for (int c = 0; c < test[0].length; c++)
          for (int r = 0; r < test.length; r++)
          if (c == r)
          res1 += test[r][c] + " ";
          else if (c + r == 4)
          res2 += test[r][c] + " ";



          return res1 + res2;





          share|improve this answer






















          • I feel legally obligated to be incredibly pedantic and remind you that there are two loops in your code. But I see the point you're making and agree with it.
            – Silvio Mayolo
            Nov 10 at 20:39










          • @silvio it’s OK to be pedantic - this is a safe place - and you’re quite right too. I’ve improved the accuracy of my text, and it feels better too.
            – Bohemian
            Nov 10 at 20:55

















          up vote
          1
          down vote













          You need two loops.



          One where c = r and another where c = 4 - r



          You don't need to use nested loops, just one each. You also don't need an if statement.






          share|improve this answer



























            up vote
            1
            down vote













            You have two nested for loops. They're going to run and iterate in column-major order. If you want to iterate in a different order, then you need to use different loops. There's nothing wrong with the if statement.



            for (int c = 0; c < test.length; c++) 
            // Do it for (c, c)

            for (int c = 0; c < test.length; c++)
            // Do it for (c, test.length - c - 1)



            Also, as a tangential note, you use 4 as a magic number in one place and test.length in others. If you always expect the array to be 5x5, then use 5 instead of test.length and put an assertion at the beginning. Otherwise (more likely), use test.length - 1 in place of the magic number 4.






            share|improve this answer






















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              3 Answers
              3






              active

              oldest

              votes








              3 Answers
              3






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes








              up vote
              2
              down vote



              accepted










              You don’t need an extra loop if you use 2 results, then join them at the end:



              String res1, res2 = "";
              for (int c = 0; c < test[0].length; c++)
              for (int r = 0; r < test.length; r++)
              if (c == r)
              res1 += test[r][c] + " ";
              else if (c + r == 4)
              res2 += test[r][c] + " ";



              return res1 + res2;





              share|improve this answer






















              • I feel legally obligated to be incredibly pedantic and remind you that there are two loops in your code. But I see the point you're making and agree with it.
                – Silvio Mayolo
                Nov 10 at 20:39










              • @silvio it’s OK to be pedantic - this is a safe place - and you’re quite right too. I’ve improved the accuracy of my text, and it feels better too.
                – Bohemian
                Nov 10 at 20:55














              up vote
              2
              down vote



              accepted










              You don’t need an extra loop if you use 2 results, then join them at the end:



              String res1, res2 = "";
              for (int c = 0; c < test[0].length; c++)
              for (int r = 0; r < test.length; r++)
              if (c == r)
              res1 += test[r][c] + " ";
              else if (c + r == 4)
              res2 += test[r][c] + " ";



              return res1 + res2;





              share|improve this answer






















              • I feel legally obligated to be incredibly pedantic and remind you that there are two loops in your code. But I see the point you're making and agree with it.
                – Silvio Mayolo
                Nov 10 at 20:39










              • @silvio it’s OK to be pedantic - this is a safe place - and you’re quite right too. I’ve improved the accuracy of my text, and it feels better too.
                – Bohemian
                Nov 10 at 20:55












              up vote
              2
              down vote



              accepted







              up vote
              2
              down vote



              accepted






              You don’t need an extra loop if you use 2 results, then join them at the end:



              String res1, res2 = "";
              for (int c = 0; c < test[0].length; c++)
              for (int r = 0; r < test.length; r++)
              if (c == r)
              res1 += test[r][c] + " ";
              else if (c + r == 4)
              res2 += test[r][c] + " ";



              return res1 + res2;





              share|improve this answer














              You don’t need an extra loop if you use 2 results, then join them at the end:



              String res1, res2 = "";
              for (int c = 0; c < test[0].length; c++)
              for (int r = 0; r < test.length; r++)
              if (c == r)
              res1 += test[r][c] + " ";
              else if (c + r == 4)
              res2 += test[r][c] + " ";



              return res1 + res2;






              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Nov 10 at 20:52

























              answered Nov 10 at 20:11









              Bohemian

              293k63412550




              293k63412550











              • I feel legally obligated to be incredibly pedantic and remind you that there are two loops in your code. But I see the point you're making and agree with it.
                – Silvio Mayolo
                Nov 10 at 20:39










              • @silvio it’s OK to be pedantic - this is a safe place - and you’re quite right too. I’ve improved the accuracy of my text, and it feels better too.
                – Bohemian
                Nov 10 at 20:55
















              • I feel legally obligated to be incredibly pedantic and remind you that there are two loops in your code. But I see the point you're making and agree with it.
                – Silvio Mayolo
                Nov 10 at 20:39










              • @silvio it’s OK to be pedantic - this is a safe place - and you’re quite right too. I’ve improved the accuracy of my text, and it feels better too.
                – Bohemian
                Nov 10 at 20:55















              I feel legally obligated to be incredibly pedantic and remind you that there are two loops in your code. But I see the point you're making and agree with it.
              – Silvio Mayolo
              Nov 10 at 20:39




              I feel legally obligated to be incredibly pedantic and remind you that there are two loops in your code. But I see the point you're making and agree with it.
              – Silvio Mayolo
              Nov 10 at 20:39












              @silvio it’s OK to be pedantic - this is a safe place - and you’re quite right too. I’ve improved the accuracy of my text, and it feels better too.
              – Bohemian
              Nov 10 at 20:55




              @silvio it’s OK to be pedantic - this is a safe place - and you’re quite right too. I’ve improved the accuracy of my text, and it feels better too.
              – Bohemian
              Nov 10 at 20:55












              up vote
              1
              down vote













              You need two loops.



              One where c = r and another where c = 4 - r



              You don't need to use nested loops, just one each. You also don't need an if statement.






              share|improve this answer
























                up vote
                1
                down vote













                You need two loops.



                One where c = r and another where c = 4 - r



                You don't need to use nested loops, just one each. You also don't need an if statement.






                share|improve this answer






















                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  You need two loops.



                  One where c = r and another where c = 4 - r



                  You don't need to use nested loops, just one each. You also don't need an if statement.






                  share|improve this answer












                  You need two loops.



                  One where c = r and another where c = 4 - r



                  You don't need to use nested loops, just one each. You also don't need an if statement.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 10 at 19:58









                  Peter Lawrey

                  439k55557958




                  439k55557958




















                      up vote
                      1
                      down vote













                      You have two nested for loops. They're going to run and iterate in column-major order. If you want to iterate in a different order, then you need to use different loops. There's nothing wrong with the if statement.



                      for (int c = 0; c < test.length; c++) 
                      // Do it for (c, c)

                      for (int c = 0; c < test.length; c++)
                      // Do it for (c, test.length - c - 1)



                      Also, as a tangential note, you use 4 as a magic number in one place and test.length in others. If you always expect the array to be 5x5, then use 5 instead of test.length and put an assertion at the beginning. Otherwise (more likely), use test.length - 1 in place of the magic number 4.






                      share|improve this answer


























                        up vote
                        1
                        down vote













                        You have two nested for loops. They're going to run and iterate in column-major order. If you want to iterate in a different order, then you need to use different loops. There's nothing wrong with the if statement.



                        for (int c = 0; c < test.length; c++) 
                        // Do it for (c, c)

                        for (int c = 0; c < test.length; c++)
                        // Do it for (c, test.length - c - 1)



                        Also, as a tangential note, you use 4 as a magic number in one place and test.length in others. If you always expect the array to be 5x5, then use 5 instead of test.length and put an assertion at the beginning. Otherwise (more likely), use test.length - 1 in place of the magic number 4.






                        share|improve this answer
























                          up vote
                          1
                          down vote










                          up vote
                          1
                          down vote









                          You have two nested for loops. They're going to run and iterate in column-major order. If you want to iterate in a different order, then you need to use different loops. There's nothing wrong with the if statement.



                          for (int c = 0; c < test.length; c++) 
                          // Do it for (c, c)

                          for (int c = 0; c < test.length; c++)
                          // Do it for (c, test.length - c - 1)



                          Also, as a tangential note, you use 4 as a magic number in one place and test.length in others. If you always expect the array to be 5x5, then use 5 instead of test.length and put an assertion at the beginning. Otherwise (more likely), use test.length - 1 in place of the magic number 4.






                          share|improve this answer














                          You have two nested for loops. They're going to run and iterate in column-major order. If you want to iterate in a different order, then you need to use different loops. There's nothing wrong with the if statement.



                          for (int c = 0; c < test.length; c++) 
                          // Do it for (c, c)

                          for (int c = 0; c < test.length; c++)
                          // Do it for (c, test.length - c - 1)



                          Also, as a tangential note, you use 4 as a magic number in one place and test.length in others. If you always expect the array to be 5x5, then use 5 instead of test.length and put an assertion at the beginning. Otherwise (more likely), use test.length - 1 in place of the magic number 4.







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited Nov 10 at 20:06

























                          answered Nov 10 at 20:00









                          Silvio Mayolo

                          13.6k22252




                          13.6k22252



























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