Scope of a variable in Insertion Sort code
I came across a working code for insertion sort which is as follows:
function insertionSort(array)
for (let i = 1; i < array.length; i++)
let curr = array[i];
for (var j = i-1; j >= 0 && array[j] > curr; j--)
array[j+1] = array[j];
array[j+1] = curr;
return array;
My question is: shouldn't the j in the line:
array[j+1] = curr;
be out of scope?
What am I missing here?
javascript scope
edited Nov 14 '18 at 9:09
Ahmad
8,30043664
asked Nov 14 '18 at 9:06
Zeeshan MahmoodZeeshan Mahmood
184
add a comment |
I came across a working code for insertion sort which is as follows:
function insertionSort(array)
for (let i = 1; i < array.length; i++)
let curr = array[i];
for (var j = i-1; j >= 0 && array[j] > curr; j--)
array[j+1] = array[j];
array[j+1] = curr;
return array;
My question is: shouldn't the j in the line:
array[j+1] = curr;
be out of scope?
What am I missing here?
javascript scope
edited Nov 14 '18 at 9:09
Ahmad
8,30043664
asked Nov 14 '18 at 9:06
Zeeshan MahmoodZeeshan Mahmood
184
It's always better to start a variable withconstidentifier and make itletas necessary.varscope is function scope.
– Sid
Nov 14 '18 at 9:12
1
Possible duplicate of What is the scope of variables in JavaScript?
– amn
Nov 14 '18 at 9:28
add a comment |
I came across a working code for insertion sort which is as follows:
function insertionSort(array)
for (let i = 1; i < array.length; i++)
let curr = array[i];
for (var j = i-1; j >= 0 && array[j] > curr; j--)
array[j+1] = array[j];
array[j+1] = curr;
return array;
My question is: shouldn't the j in the line:
array[j+1] = curr;
be out of scope?
What am I missing here?
javascript scope
edited Nov 14 '18 at 9:09
Ahmad
8,30043664
asked Nov 14 '18 at 9:06
Zeeshan MahmoodZeeshan Mahmood
184
I came across a working code for insertion sort which is as follows:
function insertionSort(array)
for (let i = 1; i < array.length; i++)
let curr = array[i];
for (var j = i-1; j >= 0 && array[j] > curr; j--)
array[j+1] = array[j];
array[j+1] = curr;
return array;
My question is: shouldn't the j in the line:
array[j+1] = curr;
be out of scope?
What am I missing here?
javascript scope
javascript scope
edited Nov 14 '18 at 9:09
Ahmad
8,30043664
asked Nov 14 '18 at 9:06
Zeeshan MahmoodZeeshan Mahmood
184
edited Nov 14 '18 at 9:09
Ahmad
8,30043664
asked Nov 14 '18 at 9:06
Zeeshan MahmoodZeeshan Mahmood
184
edited Nov 14 '18 at 9:09
Ahmad
8,30043664
edited Nov 14 '18 at 9:09
Ahmad
8,30043664
edited Nov 14 '18 at 9:09
Ahmad
8,30043664
8,30043664
asked Nov 14 '18 at 9:06
Zeeshan MahmoodZeeshan Mahmood
184
asked Nov 14 '18 at 9:06
Zeeshan MahmoodZeeshan Mahmood
184
asked Nov 14 '18 at 9:06
Zeeshan MahmoodZeeshan Mahmood
184
184
It's always better to start a variable withconstidentifier and make itletas necessary.varscope is function scope.
– Sid
Nov 14 '18 at 9:12
1
Possible duplicate of What is the scope of variables in JavaScript?
– amn
Nov 14 '18 at 9:28
add a comment |
It's always better to start a variable withconstidentifier and make itletas necessary.varscope is function scope.
– Sid
Nov 14 '18 at 9:12
1
Possible duplicate of What is the scope of variables in JavaScript?
– amn
Nov 14 '18 at 9:28
It's always better to start a variable with
const identifier and make it let as necessary. var scope is function scope.– Sid
Nov 14 '18 at 9:12
It's always better to start a variable with
const identifier and make it let as necessary. var scope is function scope.– Sid
Nov 14 '18 at 9:12
1
1
Possible duplicate of What is the scope of variables in JavaScript?
– amn
Nov 14 '18 at 9:28
Possible duplicate of What is the scope of variables in JavaScript?
– amn
Nov 14 '18 at 9:28
add a comment |
1 Answer
1
active
oldest
votes
Declaring javascript variables using var makes the scope of the variable be the bounds of the entire function it is declared inside.
Opposed to let, which restricts the scope to the block it is defined inside.
So, no. It will not be out of scope.
answered Nov 14 '18 at 9:11
AhmadAhmad
8,30043664
add a comment |
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votes
Declaring javascript variables using var makes the scope of the variable be the bounds of the entire function it is declared inside.
Opposed to let, which restricts the scope to the block it is defined inside.
So, no. It will not be out of scope.
answered Nov 14 '18 at 9:11
AhmadAhmad
8,30043664
add a comment |
Declaring javascript variables using var makes the scope of the variable be the bounds of the entire function it is declared inside.
Opposed to let, which restricts the scope to the block it is defined inside.
So, no. It will not be out of scope.
answered Nov 14 '18 at 9:11
AhmadAhmad
8,30043664
add a comment |
Declaring javascript variables using var makes the scope of the variable be the bounds of the entire function it is declared inside.
Opposed to let, which restricts the scope to the block it is defined inside.
So, no. It will not be out of scope.
answered Nov 14 '18 at 9:11
AhmadAhmad
8,30043664
Declaring javascript variables using var makes the scope of the variable be the bounds of the entire function it is declared inside.
Opposed to let, which restricts the scope to the block it is defined inside.
So, no. It will not be out of scope.
answered Nov 14 '18 at 9:11
AhmadAhmad
8,30043664
answered Nov 14 '18 at 9:11
AhmadAhmad
8,30043664
answered Nov 14 '18 at 9:11
AhmadAhmad
8,30043664
answered Nov 14 '18 at 9:11
AhmadAhmad
8,30043664
8,30043664
add a comment |
add a comment |
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It's always better to start a variable with
constidentifier and make itletas necessary.varscope is function scope.– Sid
Nov 14 '18 at 9:12
1
Possible duplicate of What is the scope of variables in JavaScript?
– amn
Nov 14 '18 at 9:28