How should I convert a float32 image to an uint8 image?
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0
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I want to convert a float32 image into uint8 image in Python using the openCV library. I used the following code, but I do not know whether it is correct or not.
Here I is the float32 image.
J = I*255
J = J.astype(np.uint8)
I really appreciate if can you help me.
python opencv image-processing
edited Nov 10 at 7:54
Greenonline
97121424
asked Nov 10 at 2:56
Hamidreza
145
add a comment |
up vote
0
down vote
favorite
I want to convert a float32 image into uint8 image in Python using the openCV library. I used the following code, but I do not know whether it is correct or not.
Here I is the float32 image.
J = I*255
J = J.astype(np.uint8)
I really appreciate if can you help me.
python opencv image-processing
edited Nov 10 at 7:54
Greenonline
97121424
asked Nov 10 at 2:56
Hamidreza
145
Since no one explicitly said it, so long as your values are between 0 and 1 in your float image, then yes, your code is correct.
– Alexander Reynolds
Nov 10 at 5:30
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I want to convert a float32 image into uint8 image in Python using the openCV library. I used the following code, but I do not know whether it is correct or not.
Here I is the float32 image.
J = I*255
J = J.astype(np.uint8)
I really appreciate if can you help me.
python opencv image-processing
edited Nov 10 at 7:54
Greenonline
97121424
asked Nov 10 at 2:56
Hamidreza
145
I want to convert a float32 image into uint8 image in Python using the openCV library. I used the following code, but I do not know whether it is correct or not.
Here I is the float32 image.
J = I*255
J = J.astype(np.uint8)
I really appreciate if can you help me.
python opencv image-processing
python opencv image-processing
edited Nov 10 at 7:54
Greenonline
97121424
asked Nov 10 at 2:56
Hamidreza
145
edited Nov 10 at 7:54
Greenonline
97121424
asked Nov 10 at 2:56
Hamidreza
145
edited Nov 10 at 7:54
Greenonline
97121424
edited Nov 10 at 7:54
Greenonline
97121424
edited Nov 10 at 7:54
Greenonline
97121424
97121424
asked Nov 10 at 2:56
Hamidreza
145
asked Nov 10 at 2:56
Hamidreza
145
asked Nov 10 at 2:56
Hamidreza
145
145
Since no one explicitly said it, so long as your values are between 0 and 1 in your float image, then yes, your code is correct.
– Alexander Reynolds
Nov 10 at 5:30
add a comment |
Since no one explicitly said it, so long as your values are between 0 and 1 in your float image, then yes, your code is correct.
– Alexander Reynolds
Nov 10 at 5:30
Since no one explicitly said it, so long as your values are between 0 and 1 in your float image, then yes, your code is correct.
– Alexander Reynolds
Nov 10 at 5:30
Since no one explicitly said it, so long as your values are between 0 and 1 in your float image, then yes, your code is correct.
– Alexander Reynolds
Nov 10 at 5:30
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
If you to convert your image from float32 to uint8 numpy and opencv in python offers two convenient approaches.
If you know that your image have a range between 0 and 255 or between 0 and 1 then you can simply make the convertion the way you already do:
I *= 255 # or any coefficient
I = I.astype(np.uint8)
If you don't know the range I suggest you to apply a min max normalization
i.e. : (value - min) / (max - min)
opencv have that already implemented:
I = cv2.normalize(I,None,0,255,cv2.NORM_MINMAX,cv2.CV_8U)
The returned I will already have the type np.uint8 and a range between 0 and 255
Using numpy you can also write something similar:
def norm8(I):
mn = I.min()
mx = I.max()
mx -= mn
I = (I - mn)/mx
return I.astype(np.uint8)
answered Nov 10 at 5:19
John_Sharp1318
399311
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
If you to convert your image from float32 to uint8 numpy and opencv in python offers two convenient approaches.
If you know that your image have a range between 0 and 255 or between 0 and 1 then you can simply make the convertion the way you already do:
I *= 255 # or any coefficient
I = I.astype(np.uint8)
If you don't know the range I suggest you to apply a min max normalization
i.e. : (value - min) / (max - min)
opencv have that already implemented:
I = cv2.normalize(I,None,0,255,cv2.NORM_MINMAX,cv2.CV_8U)
The returned I will already have the type np.uint8 and a range between 0 and 255
Using numpy you can also write something similar:
def norm8(I):
mn = I.min()
mx = I.max()
mx -= mn
I = (I - mn)/mx
return I.astype(np.uint8)
answered Nov 10 at 5:19
John_Sharp1318
399311
add a comment |
up vote
0
down vote
If you to convert your image from float32 to uint8 numpy and opencv in python offers two convenient approaches.
If you know that your image have a range between 0 and 255 or between 0 and 1 then you can simply make the convertion the way you already do:
I *= 255 # or any coefficient
I = I.astype(np.uint8)
If you don't know the range I suggest you to apply a min max normalization
i.e. : (value - min) / (max - min)
opencv have that already implemented:
I = cv2.normalize(I,None,0,255,cv2.NORM_MINMAX,cv2.CV_8U)
The returned I will already have the type np.uint8 and a range between 0 and 255
Using numpy you can also write something similar:
def norm8(I):
mn = I.min()
mx = I.max()
mx -= mn
I = (I - mn)/mx
return I.astype(np.uint8)
answered Nov 10 at 5:19
John_Sharp1318
399311
add a comment |
up vote
0
down vote
up vote
0
down vote
If you to convert your image from float32 to uint8 numpy and opencv in python offers two convenient approaches.
If you know that your image have a range between 0 and 255 or between 0 and 1 then you can simply make the convertion the way you already do:
I *= 255 # or any coefficient
I = I.astype(np.uint8)
If you don't know the range I suggest you to apply a min max normalization
i.e. : (value - min) / (max - min)
opencv have that already implemented:
I = cv2.normalize(I,None,0,255,cv2.NORM_MINMAX,cv2.CV_8U)
The returned I will already have the type np.uint8 and a range between 0 and 255
Using numpy you can also write something similar:
def norm8(I):
mn = I.min()
mx = I.max()
mx -= mn
I = (I - mn)/mx
return I.astype(np.uint8)
answered Nov 10 at 5:19
John_Sharp1318
399311
If you to convert your image from float32 to uint8 numpy and opencv in python offers two convenient approaches.
If you know that your image have a range between 0 and 255 or between 0 and 1 then you can simply make the convertion the way you already do:
I *= 255 # or any coefficient
I = I.astype(np.uint8)
If you don't know the range I suggest you to apply a min max normalization
i.e. : (value - min) / (max - min)
opencv have that already implemented:
I = cv2.normalize(I,None,0,255,cv2.NORM_MINMAX,cv2.CV_8U)
The returned I will already have the type np.uint8 and a range between 0 and 255
Using numpy you can also write something similar:
def norm8(I):
mn = I.min()
mx = I.max()
mx -= mn
I = (I - mn)/mx
return I.astype(np.uint8)
answered Nov 10 at 5:19
John_Sharp1318
399311
answered Nov 10 at 5:19
John_Sharp1318
399311
answered Nov 10 at 5:19
John_Sharp1318
399311
answered Nov 10 at 5:19
John_Sharp1318
399311
399311
add a comment |
add a comment |
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Since no one explicitly said it, so long as your values are between 0 and 1 in your float image, then yes, your code is correct.
– Alexander Reynolds
Nov 10 at 5:30