different result with scipy integrate.tplquad
With Matematica this integral gives me 3. wolfram alpha
With integrate.tplquad I get -3.
This is Matematica code.
Integrate[1-x, (0,2),(0,3-1.5*x),(0,6-3*x -2*y)]
I can't see what I am doing wrong with ntegrate.tplquad
f = lambda x,y,z: 1-x
x1, x2 = 0,2
y1, y2 = lambda x : 0 , lambda x:3-1.5*x
z1, z2 = lambda x,y:0, lambda x,y: 6 -3*x -2*y
print(integrate.tplquad(f,x1,x2, y1, y2, z1, z2)[0])
-3.0
python scipy wolfram-mathematica
edited Oct 8 at 21:34
kabanus
11.2k31337
asked Oct 8 at 21:16
LetzerWille
3,4162918
add a comment |
With Matematica this integral gives me 3. wolfram alpha
With integrate.tplquad I get -3.
This is Matematica code.
Integrate[1-x, (0,2),(0,3-1.5*x),(0,6-3*x -2*y)]
I can't see what I am doing wrong with ntegrate.tplquad
f = lambda x,y,z: 1-x
x1, x2 = 0,2
y1, y2 = lambda x : 0 , lambda x:3-1.5*x
z1, z2 = lambda x,y:0, lambda x,y: 6 -3*x -2*y
print(integrate.tplquad(f,x1,x2, y1, y2, z1, z2)[0])
-3.0
python scipy wolfram-mathematica
edited Oct 8 at 21:34
kabanus
11.2k31337
asked Oct 8 at 21:16
LetzerWille
3,4162918
@kabanus, I will update with the code. But there is is link to wolfram on the first line.
– LetzerWille
Oct 8 at 21:29
add a comment |
With Matematica this integral gives me 3. wolfram alpha
With integrate.tplquad I get -3.
This is Matematica code.
Integrate[1-x, (0,2),(0,3-1.5*x),(0,6-3*x -2*y)]
I can't see what I am doing wrong with ntegrate.tplquad
f = lambda x,y,z: 1-x
x1, x2 = 0,2
y1, y2 = lambda x : 0 , lambda x:3-1.5*x
z1, z2 = lambda x,y:0, lambda x,y: 6 -3*x -2*y
print(integrate.tplquad(f,x1,x2, y1, y2, z1, z2)[0])
-3.0
python scipy wolfram-mathematica
edited Oct 8 at 21:34
kabanus
11.2k31337
asked Oct 8 at 21:16
LetzerWille
3,4162918
With Matematica this integral gives me 3. wolfram alpha
With integrate.tplquad I get -3.
This is Matematica code.
Integrate[1-x, (0,2),(0,3-1.5*x),(0,6-3*x -2*y)]
I can't see what I am doing wrong with ntegrate.tplquad
f = lambda x,y,z: 1-x
x1, x2 = 0,2
y1, y2 = lambda x : 0 , lambda x:3-1.5*x
z1, z2 = lambda x,y:0, lambda x,y: 6 -3*x -2*y
print(integrate.tplquad(f,x1,x2, y1, y2, z1, z2)[0])
-3.0
python scipy wolfram-mathematica
python scipy wolfram-mathematica
edited Oct 8 at 21:34
kabanus
11.2k31337
asked Oct 8 at 21:16
LetzerWille
3,4162918
edited Oct 8 at 21:34
kabanus
11.2k31337
asked Oct 8 at 21:16
LetzerWille
3,4162918
edited Oct 8 at 21:34
kabanus
11.2k31337
edited Oct 8 at 21:34
kabanus
11.2k31337
edited Oct 8 at 21:34
kabanus
11.2k31337
11.2k31337
asked Oct 8 at 21:16
LetzerWille
3,4162918
asked Oct 8 at 21:16
LetzerWille
3,4162918
asked Oct 8 at 21:16
LetzerWille
3,4162918
3,4162918
@kabanus, I will update with the code. But there is is link to wolfram on the first line.
– LetzerWille
Oct 8 at 21:29
add a comment |
@kabanus, I will update with the code. But there is is link to wolfram on the first line.
– LetzerWille
Oct 8 at 21:29
@kabanus, I will update with the code. But there is is link to wolfram on the first line.
– LetzerWille
Oct 8 at 21:29
@kabanus, I will update with the code. But there is is link to wolfram on the first line.
– LetzerWille
Oct 8 at 21:29
add a comment |
1 Answer
1
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oldest
votes
Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:
f = lambda x, y, z: 1 - z
answered Oct 8 at 21:30
Warren Weckesser
67.8k795130
1
I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34
This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49
add a comment |
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votes
Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:
f = lambda x, y, z: 1 - z
answered Oct 8 at 21:30
Warren Weckesser
67.8k795130
1
I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34
This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49
add a comment |
Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:
f = lambda x, y, z: 1 - z
answered Oct 8 at 21:30
Warren Weckesser
67.8k795130
1
I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34
This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49
add a comment |
Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:
f = lambda x, y, z: 1 - z
answered Oct 8 at 21:30
Warren Weckesser
67.8k795130
Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:
f = lambda x, y, z: 1 - z
answered Oct 8 at 21:30
Warren Weckesser
67.8k795130
answered Oct 8 at 21:30
Warren Weckesser
67.8k795130
answered Oct 8 at 21:30
Warren Weckesser
67.8k795130
answered Oct 8 at 21:30
Warren Weckesser
67.8k795130
67.8k795130
1
I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34
This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49
add a comment |
1
I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34
This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49
1
1
I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34
I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34
This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49
This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49
add a comment |
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@kabanus, I will update with the code. But there is is link to wolfram on the first line.
– LetzerWille
Oct 8 at 21:29