different result with scipy integrate.tplquad

With Matematica this integral gives me 3. wolfram alpha
With integrate.tplquad I get -3.

This is Matematica code.

Integrate[1-x, (0,2),(0,3-1.5*x),(0,6-3*x -2*y)]

I can't see what I am doing wrong with ntegrate.tplquad

f = lambda x,y,z: 1-x 

x1, x2 = 0,2

y1, y2 = lambda x : 0 , lambda x:3-1.5*x

z1, z2 = lambda x,y:0, lambda x,y: 6 -3*x -2*y

print(integrate.tplquad(f,x1,x2, y1, y2, z1, z2)[0])
-3.0

edited Oct 8 at 21:34

kabanus

11.2k31337

asked Oct 8 at 21:16

LetzerWille

3,4162918

@kabanus, I will update with the code. But there is is link to wolfram on the first line.
– LetzerWille
Oct 8 at 21:29

add a comment |

With Matematica this integral gives me 3. wolfram alpha
With integrate.tplquad I get -3.

This is Matematica code.

Integrate[1-x, (0,2),(0,3-1.5*x),(0,6-3*x -2*y)]

I can't see what I am doing wrong with ntegrate.tplquad

f = lambda x,y,z: 1-x 

x1, x2 = 0,2

y1, y2 = lambda x : 0 , lambda x:3-1.5*x

z1, z2 = lambda x,y:0, lambda x,y: 6 -3*x -2*y

print(integrate.tplquad(f,x1,x2, y1, y2, z1, z2)[0])
-3.0

edited Oct 8 at 21:34

kabanus

11.2k31337

asked Oct 8 at 21:16

LetzerWille

3,4162918

@kabanus, I will update with the code. But there is is link to wolfram on the first line.
– LetzerWille
Oct 8 at 21:29

add a comment |

With Matematica this integral gives me 3. wolfram alpha
With integrate.tplquad I get -3.

This is Matematica code.

Integrate[1-x, (0,2),(0,3-1.5*x),(0,6-3*x -2*y)]

I can't see what I am doing wrong with ntegrate.tplquad

f = lambda x,y,z: 1-x 

x1, x2 = 0,2

y1, y2 = lambda x : 0 , lambda x:3-1.5*x

z1, z2 = lambda x,y:0, lambda x,y: 6 -3*x -2*y

print(integrate.tplquad(f,x1,x2, y1, y2, z1, z2)[0])
-3.0

edited Oct 8 at 21:34

kabanus

11.2k31337

asked Oct 8 at 21:16

LetzerWille

3,4162918

With Matematica this integral gives me 3. wolfram alpha
With integrate.tplquad I get -3.

This is Matematica code.

Integrate[1-x, (0,2),(0,3-1.5*x),(0,6-3*x -2*y)]

I can't see what I am doing wrong with ntegrate.tplquad

f = lambda x,y,z: 1-x 

x1, x2 = 0,2

y1, y2 = lambda x : 0 , lambda x:3-1.5*x

z1, z2 = lambda x,y:0, lambda x,y: 6 -3*x -2*y

print(integrate.tplquad(f,x1,x2, y1, y2, z1, z2)[0])
-3.0

python scipy wolfram-mathematica

edited Oct 8 at 21:34

kabanus

11.2k31337

asked Oct 8 at 21:16

LetzerWille

3,4162918

edited Oct 8 at 21:34

kabanus

11.2k31337

asked Oct 8 at 21:16

LetzerWille

3,4162918

edited Oct 8 at 21:34

kabanus

11.2k31337

edited Oct 8 at 21:34

kabanus

11.2k31337

edited Oct 8 at 21:34

kabanus

11.2k31337

asked Oct 8 at 21:16

LetzerWille

3,4162918

asked Oct 8 at 21:16

LetzerWille

3,4162918

asked Oct 8 at 21:16

LetzerWille

3,4162918

@kabanus, I will update with the code. But there is is link to wolfram on the first line.
– LetzerWille
Oct 8 at 21:29

add a comment |

@kabanus, I will update with the code. But there is is link to wolfram on the first line.
– LetzerWille
Oct 8 at 21:29

@kabanus, I will update with the code. But there is is link to wolfram on the first line.
– LetzerWille
Oct 8 at 21:29

add a comment |

1 Answer
1

active

oldest

votes

Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:

 f = lambda x, y, z: 1 - z

answered Oct 8 at 21:30

Warren Weckesser

67.8k795130

1

I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34

This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49

add a comment |

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1 Answer
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1 Answer
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active

oldest

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Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:

 f = lambda x, y, z: 1 - z

answered Oct 8 at 21:30

Warren Weckesser

67.8k795130

1

I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34

This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49

add a comment |

Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:

 f = lambda x, y, z: 1 - z

answered Oct 8 at 21:30

Warren Weckesser

67.8k795130

1

I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34

This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49

add a comment |

Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:

 f = lambda x, y, z: 1 - z

answered Oct 8 at 21:30

Warren Weckesser

67.8k795130

Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:

 f = lambda x, y, z: 1 - z

answered Oct 8 at 21:30

Warren Weckesser

67.8k795130

answered Oct 8 at 21:30

Warren Weckesser

67.8k795130

answered Oct 8 at 21:30

Warren Weckesser

67.8k795130

answered Oct 8 at 21:30

Warren Weckesser

67.8k795130

1

I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34

This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49

add a comment |

1

I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34

This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49

I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34

This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49

add a comment |

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