Get extensions inside directory bash
Im trying to get all the extensions in the directory passed as $1 parameter.
The problem is that Im getting extensions that are not inside $1. I use cd command to get into the directory in the first line but it seems that it does not work.
cd $1
find . -type f | perl -ne 'print $1 if m/.([^./]+)$/' | sort -u > $1extensions.txt
bash perl directory
edited Nov 11 at 18:37
Cyrus
45.2k43676
asked Nov 11 at 18:31
user10599105
82
add a comment |
Im trying to get all the extensions in the directory passed as $1 parameter.
The problem is that Im getting extensions that are not inside $1. I use cd command to get into the directory in the first line but it seems that it does not work.
cd $1
find . -type f | perl -ne 'print $1 if m/.([^./]+)$/' | sort -u > $1extensions.txt
bash perl directory
edited Nov 11 at 18:37
Cyrus
45.2k43676
asked Nov 11 at 18:31
user10599105
82
See: Difference between single and double quotes in bash
– Cyrus
Nov 11 at 18:36
What exactly do you mean by "extension"? To avoid going into sub directories withfindyou could also use themaxdepthoption, e.g.:find . -maxdepth 1 -type f
– Håkon Hægland
Nov 11 at 19:05
Is thecdperformed in the same shell asfind? Please provide a minimal directory structure and value for$1that demonstrates the problem.
– ikegami
Nov 11 at 19:47
add a comment |
Im trying to get all the extensions in the directory passed as $1 parameter.
The problem is that Im getting extensions that are not inside $1. I use cd command to get into the directory in the first line but it seems that it does not work.
cd $1
find . -type f | perl -ne 'print $1 if m/.([^./]+)$/' | sort -u > $1extensions.txt
bash perl directory
edited Nov 11 at 18:37
Cyrus
45.2k43676
asked Nov 11 at 18:31
user10599105
82
Im trying to get all the extensions in the directory passed as $1 parameter.
The problem is that Im getting extensions that are not inside $1. I use cd command to get into the directory in the first line but it seems that it does not work.
cd $1
find . -type f | perl -ne 'print $1 if m/.([^./]+)$/' | sort -u > $1extensions.txt
bash perl directory
bash perl directory
edited Nov 11 at 18:37
Cyrus
45.2k43676
asked Nov 11 at 18:31
user10599105
82
edited Nov 11 at 18:37
Cyrus
45.2k43676
asked Nov 11 at 18:31
user10599105
82
edited Nov 11 at 18:37
Cyrus
45.2k43676
edited Nov 11 at 18:37
Cyrus
45.2k43676
edited Nov 11 at 18:37
Cyrus
45.2k43676
45.2k43676
asked Nov 11 at 18:31
user10599105
82
asked Nov 11 at 18:31
user10599105
82
asked Nov 11 at 18:31
user10599105
82
82
See: Difference between single and double quotes in bash
– Cyrus
Nov 11 at 18:36
What exactly do you mean by "extension"? To avoid going into sub directories withfindyou could also use themaxdepthoption, e.g.:find . -maxdepth 1 -type f
– Håkon Hægland
Nov 11 at 19:05
Is thecdperformed in the same shell asfind? Please provide a minimal directory structure and value for$1that demonstrates the problem.
– ikegami
Nov 11 at 19:47
add a comment |
See: Difference between single and double quotes in bash
– Cyrus
Nov 11 at 18:36
What exactly do you mean by "extension"? To avoid going into sub directories withfindyou could also use themaxdepthoption, e.g.:find . -maxdepth 1 -type f
– Håkon Hægland
Nov 11 at 19:05
Is thecdperformed in the same shell asfind? Please provide a minimal directory structure and value for$1that demonstrates the problem.
– ikegami
Nov 11 at 19:47
See: Difference between single and double quotes in bash
– Cyrus
Nov 11 at 18:36
See: Difference between single and double quotes in bash
– Cyrus
Nov 11 at 18:36
What exactly do you mean by "extension"? To avoid going into sub directories with
find you could also use the maxdepth option, e.g.: find . -maxdepth 1 -type f– Håkon Hægland
Nov 11 at 19:05
What exactly do you mean by "extension"? To avoid going into sub directories with
find you could also use the maxdepth option, e.g.: find . -maxdepth 1 -type f– Håkon Hægland
Nov 11 at 19:05
Is the
cd performed in the same shell as find? Please provide a minimal directory structure and value for $1 that demonstrates the problem.– ikegami
Nov 11 at 19:47
Is the
cd performed in the same shell as find? Please provide a minimal directory structure and value for $1 that demonstrates the problem.– ikegami
Nov 11 at 19:47
add a comment |
2 Answers
2
active
oldest
votes
You could try the following Perl command:
perl -MList::Util=uniq -sE '
chdir $dir; say for uniq map /.([^./]+)$/ ? $1 : () grep -f, <*>;
' -- -dir="$1" > "$1"-extensions.txt
answered Nov 11 at 19:26
Håkon Hægland
14.9k124287
add a comment |
There's obviously something you're not saying, because there's no bug in find that will list files outside of the specified directory, and there's no bug in your Perl program that will invent extensions.
$ find
.
./foo
./foo/a.good
./a.bad
./script
$ cat ./script
#!/bin/bash
cd $1
find . -type f | perl -ne 'print $1 if m/.([^./]+)$/' | sort -u > $1extensions.txt
$ ./script foo
$ cat foo/fooextensions.txt
good
txt <-- From the output file you created inside the directory in which you search.
answered Nov 11 at 19:54
ikegami
261k11176396
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You could try the following Perl command:
perl -MList::Util=uniq -sE '
chdir $dir; say for uniq map /.([^./]+)$/ ? $1 : () grep -f, <*>;
' -- -dir="$1" > "$1"-extensions.txt
answered Nov 11 at 19:26
Håkon Hægland
14.9k124287
add a comment |
You could try the following Perl command:
perl -MList::Util=uniq -sE '
chdir $dir; say for uniq map /.([^./]+)$/ ? $1 : () grep -f, <*>;
' -- -dir="$1" > "$1"-extensions.txt
answered Nov 11 at 19:26
Håkon Hægland
14.9k124287
add a comment |
You could try the following Perl command:
perl -MList::Util=uniq -sE '
chdir $dir; say for uniq map /.([^./]+)$/ ? $1 : () grep -f, <*>;
' -- -dir="$1" > "$1"-extensions.txt
answered Nov 11 at 19:26
Håkon Hægland
14.9k124287
You could try the following Perl command:
perl -MList::Util=uniq -sE '
chdir $dir; say for uniq map /.([^./]+)$/ ? $1 : () grep -f, <*>;
' -- -dir="$1" > "$1"-extensions.txt
answered Nov 11 at 19:26
Håkon Hægland
14.9k124287
answered Nov 11 at 19:26
Håkon Hægland
14.9k124287
answered Nov 11 at 19:26
Håkon Hægland
14.9k124287
answered Nov 11 at 19:26
Håkon Hægland
14.9k124287
14.9k124287
add a comment |
add a comment |
There's obviously something you're not saying, because there's no bug in find that will list files outside of the specified directory, and there's no bug in your Perl program that will invent extensions.
$ find
.
./foo
./foo/a.good
./a.bad
./script
$ cat ./script
#!/bin/bash
cd $1
find . -type f | perl -ne 'print $1 if m/.([^./]+)$/' | sort -u > $1extensions.txt
$ ./script foo
$ cat foo/fooextensions.txt
good
txt <-- From the output file you created inside the directory in which you search.
answered Nov 11 at 19:54
ikegami
261k11176396
add a comment |
There's obviously something you're not saying, because there's no bug in find that will list files outside of the specified directory, and there's no bug in your Perl program that will invent extensions.
$ find
.
./foo
./foo/a.good
./a.bad
./script
$ cat ./script
#!/bin/bash
cd $1
find . -type f | perl -ne 'print $1 if m/.([^./]+)$/' | sort -u > $1extensions.txt
$ ./script foo
$ cat foo/fooextensions.txt
good
txt <-- From the output file you created inside the directory in which you search.
answered Nov 11 at 19:54
ikegami
261k11176396
add a comment |
There's obviously something you're not saying, because there's no bug in find that will list files outside of the specified directory, and there's no bug in your Perl program that will invent extensions.
$ find
.
./foo
./foo/a.good
./a.bad
./script
$ cat ./script
#!/bin/bash
cd $1
find . -type f | perl -ne 'print $1 if m/.([^./]+)$/' | sort -u > $1extensions.txt
$ ./script foo
$ cat foo/fooextensions.txt
good
txt <-- From the output file you created inside the directory in which you search.
answered Nov 11 at 19:54
ikegami
261k11176396
There's obviously something you're not saying, because there's no bug in find that will list files outside of the specified directory, and there's no bug in your Perl program that will invent extensions.
$ find
.
./foo
./foo/a.good
./a.bad
./script
$ cat ./script
#!/bin/bash
cd $1
find . -type f | perl -ne 'print $1 if m/.([^./]+)$/' | sort -u > $1extensions.txt
$ ./script foo
$ cat foo/fooextensions.txt
good
txt <-- From the output file you created inside the directory in which you search.
answered Nov 11 at 19:54
ikegami
261k11176396
edited Nov 12 at 4:21
answered Nov 11 at 19:54
ikegami
261k11176396
answered Nov 11 at 19:54
ikegami
261k11176396
answered Nov 11 at 19:54
ikegami
261k11176396
261k11176396
add a comment |
add a comment |
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See: Difference between single and double quotes in bash
– Cyrus
Nov 11 at 18:36
What exactly do you mean by "extension"? To avoid going into sub directories with
findyou could also use themaxdepthoption, e.g.:find . -maxdepth 1 -type f– Håkon Hægland
Nov 11 at 19:05
Is the
cdperformed in the same shell asfind? Please provide a minimal directory structure and value for$1that demonstrates the problem.– ikegami
Nov 11 at 19:47