Convert an array into a Map
6
I have a table with a column like
["key":"e","value":["253","203","204"],"key":"st","value":["mi"],"key":"k2","value":["1","2"]]
Which is of the format array<struct<key:string,value:array<string>>>
I want to convert the column into below format :
"e":["253","203","204"],"st":["mi"],"k2":["1","2"]
which is of the type map<string,array<string>>
I have tried exploding the array but that does not work. Any ideas how I can do this in hive.
sql hadoop hive hiveql
edited Nov 12 '18 at 4:50
apandey846
8441019
asked Nov 7 '18 at 16:48
John ConstantineJohn Constantine
1417
add a comment |
6
I have a table with a column like
["key":"e","value":["253","203","204"],"key":"st","value":["mi"],"key":"k2","value":["1","2"]]
Which is of the format array<struct<key:string,value:array<string>>>
I want to convert the column into below format :
"e":["253","203","204"],"st":["mi"],"k2":["1","2"]
which is of the type map<string,array<string>>
I have tried exploding the array but that does not work. Any ideas how I can do this in hive.
sql hadoop hive hiveql
edited Nov 12 '18 at 4:50
apandey846
8441019
asked Nov 7 '18 at 16:48
John ConstantineJohn Constantine
1417
1
I think you will have to write the custom UDF for this. you you can use spark
– Gaurang Shah
Nov 7 '18 at 20:01
2
Your output json is invalid. Don't you think for Map<String,List<String>> should be represented by "e":["253","203","204"],"st":["mi"],"k2":["1","2"] .
– apandey846
Nov 11 '18 at 19:59
add a comment |
6
6
6
1
I have a table with a column like
["key":"e","value":["253","203","204"],"key":"st","value":["mi"],"key":"k2","value":["1","2"]]
Which is of the format array<struct<key:string,value:array<string>>>
I want to convert the column into below format :
"e":["253","203","204"],"st":["mi"],"k2":["1","2"]
which is of the type map<string,array<string>>
I have tried exploding the array but that does not work. Any ideas how I can do this in hive.
sql hadoop hive hiveql
edited Nov 12 '18 at 4:50
apandey846
8441019
asked Nov 7 '18 at 16:48
John ConstantineJohn Constantine
1417
I have a table with a column like
["key":"e","value":["253","203","204"],"key":"st","value":["mi"],"key":"k2","value":["1","2"]]
Which is of the format array<struct<key:string,value:array<string>>>
I want to convert the column into below format :
"e":["253","203","204"],"st":["mi"],"k2":["1","2"]
which is of the type map<string,array<string>>
I have tried exploding the array but that does not work. Any ideas how I can do this in hive.
sql hadoop hive hiveql
sql hadoop hive hiveql
edited Nov 12 '18 at 4:50
apandey846
8441019
asked Nov 7 '18 at 16:48
John ConstantineJohn Constantine
1417
edited Nov 12 '18 at 4:50
apandey846
8441019
asked Nov 7 '18 at 16:48
John ConstantineJohn Constantine
1417
edited Nov 12 '18 at 4:50
apandey846
8441019
edited Nov 12 '18 at 4:50
apandey846
8441019
edited Nov 12 '18 at 4:50
apandey846
8441019
8441019
asked Nov 7 '18 at 16:48
John ConstantineJohn Constantine
1417
asked Nov 7 '18 at 16:48
John ConstantineJohn Constantine
1417
asked Nov 7 '18 at 16:48
John ConstantineJohn Constantine
1417
1417
1
I think you will have to write the custom UDF for this. you you can use spark
– Gaurang Shah
Nov 7 '18 at 20:01
2
Your output json is invalid. Don't you think for Map<String,List<String>> should be represented by "e":["253","203","204"],"st":["mi"],"k2":["1","2"] .
– apandey846
Nov 11 '18 at 19:59
add a comment |
1
I think you will have to write the custom UDF for this. you you can use spark
– Gaurang Shah
Nov 7 '18 at 20:01
2
Your output json is invalid. Don't you think for Map<String,List<String>> should be represented by "e":["253","203","204"],"st":["mi"],"k2":["1","2"] .
– apandey846
Nov 11 '18 at 19:59
1
1
I think you will have to write the custom UDF for this. you you can use spark
– Gaurang Shah
Nov 7 '18 at 20:01
I think you will have to write the custom UDF for this. you you can use spark
– Gaurang Shah
Nov 7 '18 at 20:01
2
2
Your output json is invalid. Don't you think for Map<String,List<String>> should be represented by "e":["253","203","204"],"st":["mi"],"k2":["1","2"] .
– apandey846
Nov 11 '18 at 19:59
Your output json is invalid. Don't you think for Map<String,List<String>> should be represented by "e":["253","203","204"],"st":["mi"],"k2":["1","2"] .
– apandey846
Nov 11 '18 at 19:59
add a comment |
1 Answer
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var Array = ["key":"e","value":["253","203","204"],"key":"st","value":["mi"],"key":"k2","value":["1","2"]];
var obj =
for(var i=0;i<Array.length;i++)
obj[Array[i].key] = Array[i].value
obj will be in the required format
answered Nov 18 '18 at 7:16
Habeeb RahmanHabeeb Rahman
12
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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oldest
votes
active
oldest
votes
0
var Array = ["key":"e","value":["253","203","204"],"key":"st","value":["mi"],"key":"k2","value":["1","2"]];
var obj =
for(var i=0;i<Array.length;i++)
obj[Array[i].key] = Array[i].value
obj will be in the required format
answered Nov 18 '18 at 7:16
Habeeb RahmanHabeeb Rahman
12
add a comment |
0
var Array = ["key":"e","value":["253","203","204"],"key":"st","value":["mi"],"key":"k2","value":["1","2"]];
var obj =
for(var i=0;i<Array.length;i++)
obj[Array[i].key] = Array[i].value
obj will be in the required format
answered Nov 18 '18 at 7:16
Habeeb RahmanHabeeb Rahman
12
add a comment |
0
0
0
var Array = ["key":"e","value":["253","203","204"],"key":"st","value":["mi"],"key":"k2","value":["1","2"]];
var obj =
for(var i=0;i<Array.length;i++)
obj[Array[i].key] = Array[i].value
obj will be in the required format
answered Nov 18 '18 at 7:16
Habeeb RahmanHabeeb Rahman
12
var Array = ["key":"e","value":["253","203","204"],"key":"st","value":["mi"],"key":"k2","value":["1","2"]];
var obj =
for(var i=0;i<Array.length;i++)
obj[Array[i].key] = Array[i].value
obj will be in the required format
answered Nov 18 '18 at 7:16
Habeeb RahmanHabeeb Rahman
12
edited Nov 18 '18 at 7:29
answered Nov 18 '18 at 7:16
Habeeb RahmanHabeeb Rahman
12
answered Nov 18 '18 at 7:16
Habeeb RahmanHabeeb Rahman
12
answered Nov 18 '18 at 7:16
Habeeb RahmanHabeeb Rahman
12
12
add a comment |
add a comment |
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1
I think you will have to write the custom UDF for this. you you can use spark
– Gaurang Shah
Nov 7 '18 at 20:01
2
Your output json is invalid. Don't you think for Map<String,List<String>> should be represented by "e":["253","203","204"],"st":["mi"],"k2":["1","2"] .
– apandey846
Nov 11 '18 at 19:59