How to loop through an array and replacing some of its values?
-3
I have now the following code:
shp = this.getField("shp");
out = this.getField("txt")
p = shp.value.split("");
pn = "";
for (i = 0; i < p.length; i++)
pn += p[i].charCodeAt(0);
;
Now I want to loop through pn and check for values greater than 56,
these values I want to replace with (the value - 63)%10
how can I do that?
So, to be a little bit clearer:
I want to rewrite the following vba code to run it on adobe acrobat:
Function upsp(number)
qsm = 0
For i = 1 To 15
p = Mid(number, i, 1)
If Asc(p) > 57 Then p = (Asc(p) - 63) Mod 10
qsm = qsm + (p * (2 - i Mod 2))
Next
upsp = 10 - (qsm Mod 10)
If upsp = 10 Then upsp = 0
End Function
this code calculate a checksum for a ups tracking number.
javascript for-loop replace
edited Nov 12 '18 at 4:50
Cœur
17.5k9103145
asked Sep 23 '15 at 1:36
renokl2014renokl2014
618
add a comment |
-3
I have now the following code:
shp = this.getField("shp");
out = this.getField("txt")
p = shp.value.split("");
pn = "";
for (i = 0; i < p.length; i++)
pn += p[i].charCodeAt(0);
;
Now I want to loop through pn and check for values greater than 56,
these values I want to replace with (the value - 63)%10
how can I do that?
So, to be a little bit clearer:
I want to rewrite the following vba code to run it on adobe acrobat:
Function upsp(number)
qsm = 0
For i = 1 To 15
p = Mid(number, i, 1)
If Asc(p) > 57 Then p = (Asc(p) - 63) Mod 10
qsm = qsm + (p * (2 - i Mod 2))
Next
upsp = 10 - (qsm Mod 10)
If upsp = 10 Then upsp = 0
End Function
this code calculate a checksum for a ups tracking number.
javascript for-loop replace
edited Nov 12 '18 at 4:50
Cœur
17.5k9103145
asked Sep 23 '15 at 1:36
renokl2014renokl2014
618
1
You have your loop. Now parse, compare, and replace. What are you having trouble with exactly?
– Jasen
Sep 23 '15 at 1:47
add a comment |
-3
-3
-3
I have now the following code:
shp = this.getField("shp");
out = this.getField("txt")
p = shp.value.split("");
pn = "";
for (i = 0; i < p.length; i++)
pn += p[i].charCodeAt(0);
;
Now I want to loop through pn and check for values greater than 56,
these values I want to replace with (the value - 63)%10
how can I do that?
So, to be a little bit clearer:
I want to rewrite the following vba code to run it on adobe acrobat:
Function upsp(number)
qsm = 0
For i = 1 To 15
p = Mid(number, i, 1)
If Asc(p) > 57 Then p = (Asc(p) - 63) Mod 10
qsm = qsm + (p * (2 - i Mod 2))
Next
upsp = 10 - (qsm Mod 10)
If upsp = 10 Then upsp = 0
End Function
this code calculate a checksum for a ups tracking number.
javascript for-loop replace
edited Nov 12 '18 at 4:50
Cœur
17.5k9103145
asked Sep 23 '15 at 1:36
renokl2014renokl2014
618
I have now the following code:
shp = this.getField("shp");
out = this.getField("txt")
p = shp.value.split("");
pn = "";
for (i = 0; i < p.length; i++)
pn += p[i].charCodeAt(0);
;
Now I want to loop through pn and check for values greater than 56,
these values I want to replace with (the value - 63)%10
how can I do that?
So, to be a little bit clearer:
I want to rewrite the following vba code to run it on adobe acrobat:
Function upsp(number)
qsm = 0
For i = 1 To 15
p = Mid(number, i, 1)
If Asc(p) > 57 Then p = (Asc(p) - 63) Mod 10
qsm = qsm + (p * (2 - i Mod 2))
Next
upsp = 10 - (qsm Mod 10)
If upsp = 10 Then upsp = 0
End Function
this code calculate a checksum for a ups tracking number.
javascript for-loop replace
javascript for-loop replace
edited Nov 12 '18 at 4:50
Cœur
17.5k9103145
asked Sep 23 '15 at 1:36
renokl2014renokl2014
618
edited Nov 12 '18 at 4:50
Cœur
17.5k9103145
asked Sep 23 '15 at 1:36
renokl2014renokl2014
618
edited Nov 12 '18 at 4:50
Cœur
17.5k9103145
edited Nov 12 '18 at 4:50
Cœur
17.5k9103145
edited Nov 12 '18 at 4:50
Cœur
17.5k9103145
17.5k9103145
asked Sep 23 '15 at 1:36
renokl2014renokl2014
618
asked Sep 23 '15 at 1:36
renokl2014renokl2014
618
asked Sep 23 '15 at 1:36
renokl2014renokl2014
618
618
1
You have your loop. Now parse, compare, and replace. What are you having trouble with exactly?
– Jasen
Sep 23 '15 at 1:47
add a comment |
1
You have your loop. Now parse, compare, and replace. What are you having trouble with exactly?
– Jasen
Sep 23 '15 at 1:47
1
1
You have your loop. Now parse, compare, and replace. What are you having trouble with exactly?
– Jasen
Sep 23 '15 at 1:47
You have your loop. Now parse, compare, and replace. What are you having trouble with exactly?
– Jasen
Sep 23 '15 at 1:47
add a comment |
2 Answers
2
active
oldest
votes
0
Try this:
shp = this.getField("shp");
out = this.getField("txt")
p = shp.value.split("");
pn = "";
for (i = 0; i < p.length; i++)
// pn += p[i].charCodeAt(0);
if (p[i]>56) p[i] = (p[i] - 63)%10;
;
answered Sep 23 '15 at 2:06
Olivier De MeulderOlivier De Meulder
2,30431927
add a comment |
0
Why not your code but with
for (i = 0; i < p.length; i++)
if(p[i].charCodeAt(0) > 56) pn += (p[i].charCodeAt(0) -63)%10;//do you want 10 percent or modulus of 10? %10 will be the modulus /10 woul be 10 percent
else
pn += p[i].charCodeAt(0);
;
If it's not what you're looking for you should rephrase the question, because I honestly didn't get it.
answered Sep 23 '15 at 2:25
Caio WilsonCaio Wilson
154110
ps.: why are you using charcodeat()? Stating what you're trying to accomplish might help us answering. :)
– Caio Wilson
Sep 23 '15 at 2:27
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Try this:
shp = this.getField("shp");
out = this.getField("txt")
p = shp.value.split("");
pn = "";
for (i = 0; i < p.length; i++)
// pn += p[i].charCodeAt(0);
if (p[i]>56) p[i] = (p[i] - 63)%10;
;
answered Sep 23 '15 at 2:06
Olivier De MeulderOlivier De Meulder
2,30431927
add a comment |
0
Try this:
shp = this.getField("shp");
out = this.getField("txt")
p = shp.value.split("");
pn = "";
for (i = 0; i < p.length; i++)
// pn += p[i].charCodeAt(0);
if (p[i]>56) p[i] = (p[i] - 63)%10;
;
answered Sep 23 '15 at 2:06
Olivier De MeulderOlivier De Meulder
2,30431927
add a comment |
0
0
0
Try this:
shp = this.getField("shp");
out = this.getField("txt")
p = shp.value.split("");
pn = "";
for (i = 0; i < p.length; i++)
// pn += p[i].charCodeAt(0);
if (p[i]>56) p[i] = (p[i] - 63)%10;
;
answered Sep 23 '15 at 2:06
Olivier De MeulderOlivier De Meulder
2,30431927
Try this:
shp = this.getField("shp");
out = this.getField("txt")
p = shp.value.split("");
pn = "";
for (i = 0; i < p.length; i++)
// pn += p[i].charCodeAt(0);
if (p[i]>56) p[i] = (p[i] - 63)%10;
;
answered Sep 23 '15 at 2:06
Olivier De MeulderOlivier De Meulder
2,30431927
answered Sep 23 '15 at 2:06
Olivier De MeulderOlivier De Meulder
2,30431927
answered Sep 23 '15 at 2:06
Olivier De MeulderOlivier De Meulder
2,30431927
answered Sep 23 '15 at 2:06
Olivier De MeulderOlivier De Meulder
2,30431927
2,30431927
add a comment |
add a comment |
0
Why not your code but with
for (i = 0; i < p.length; i++)
if(p[i].charCodeAt(0) > 56) pn += (p[i].charCodeAt(0) -63)%10;//do you want 10 percent or modulus of 10? %10 will be the modulus /10 woul be 10 percent
else
pn += p[i].charCodeAt(0);
;
If it's not what you're looking for you should rephrase the question, because I honestly didn't get it.
answered Sep 23 '15 at 2:25
Caio WilsonCaio Wilson
154110
ps.: why are you using charcodeat()? Stating what you're trying to accomplish might help us answering. :)
– Caio Wilson
Sep 23 '15 at 2:27
add a comment |
0
Why not your code but with
for (i = 0; i < p.length; i++)
if(p[i].charCodeAt(0) > 56) pn += (p[i].charCodeAt(0) -63)%10;//do you want 10 percent or modulus of 10? %10 will be the modulus /10 woul be 10 percent
else
pn += p[i].charCodeAt(0);
;
If it's not what you're looking for you should rephrase the question, because I honestly didn't get it.
answered Sep 23 '15 at 2:25
Caio WilsonCaio Wilson
154110
ps.: why are you using charcodeat()? Stating what you're trying to accomplish might help us answering. :)
– Caio Wilson
Sep 23 '15 at 2:27
add a comment |
0
0
0
Why not your code but with
for (i = 0; i < p.length; i++)
if(p[i].charCodeAt(0) > 56) pn += (p[i].charCodeAt(0) -63)%10;//do you want 10 percent or modulus of 10? %10 will be the modulus /10 woul be 10 percent
else
pn += p[i].charCodeAt(0);
;
If it's not what you're looking for you should rephrase the question, because I honestly didn't get it.
answered Sep 23 '15 at 2:25
Caio WilsonCaio Wilson
154110
Why not your code but with
for (i = 0; i < p.length; i++)
if(p[i].charCodeAt(0) > 56) pn += (p[i].charCodeAt(0) -63)%10;//do you want 10 percent or modulus of 10? %10 will be the modulus /10 woul be 10 percent
else
pn += p[i].charCodeAt(0);
;
If it's not what you're looking for you should rephrase the question, because I honestly didn't get it.
answered Sep 23 '15 at 2:25
Caio WilsonCaio Wilson
154110
answered Sep 23 '15 at 2:25
Caio WilsonCaio Wilson
154110
answered Sep 23 '15 at 2:25
Caio WilsonCaio Wilson
154110
answered Sep 23 '15 at 2:25
Caio WilsonCaio Wilson
154110
154110
ps.: why are you using charcodeat()? Stating what you're trying to accomplish might help us answering. :)
– Caio Wilson
Sep 23 '15 at 2:27
add a comment |
ps.: why are you using charcodeat()? Stating what you're trying to accomplish might help us answering. :)
– Caio Wilson
Sep 23 '15 at 2:27
ps.: why are you using charcodeat()? Stating what you're trying to accomplish might help us answering. :)
– Caio Wilson
Sep 23 '15 at 2:27
ps.: why are you using charcodeat()? Stating what you're trying to accomplish might help us answering. :)
– Caio Wilson
Sep 23 '15 at 2:27
add a comment |
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1
You have your loop. Now parse, compare, and replace. What are you having trouble with exactly?
– Jasen
Sep 23 '15 at 1:47