Insert JSON String in to PostgreSQL table column










0















Trying to insert following JSON String as is without formatting



str=
"Trial":
"@id": "xxxxx",
"key1": "aaaaaaaa (BAL-8557) aaaaaaaaaaaaaaaaaa",
"key2": "aaaaaaaaaaaaa , aaaaaaaaaaaaaaaaaaa",
"key3": "Yes",
"key4": "No",
"key5":
"key5": [
"@type": "ABC",
"$": "ABC121 "
,

"@type": "ABC",
"$": "ABC12133 "
]
,
"Indications":
"Indication":
"@id": "1308",
"$": "aaaaaa"






in to following PostgreSQL DB



CREATE TABLE records
(
id text,
record json
)


Code I am using to perform the insert operation



cur = conn.cursor()
cur.execute("INSERT INTO trial_records(id, record) VALUES (%s, %s)", ('1', json.dumps(json.loads(str))))


Error I am getting



the JSON object must be str, bytes or bytearray, not 'dict' 


Is this the right syntax to store json string as part of the column










share|improve this question

















  • 2





    You should remove your json.loads call. So it will be json.dumps(str).

    – sashaaero
    Nov 12 '18 at 21:19











  • Thanks that solved it

    – K.Pil
    Nov 12 '18 at 22:52











  • @sashaaero put it as your answer.. So this question will not show in unanswered..

    – dwir182
    Nov 13 '18 at 0:03















0















Trying to insert following JSON String as is without formatting



str=
"Trial":
"@id": "xxxxx",
"key1": "aaaaaaaa (BAL-8557) aaaaaaaaaaaaaaaaaa",
"key2": "aaaaaaaaaaaaa , aaaaaaaaaaaaaaaaaaa",
"key3": "Yes",
"key4": "No",
"key5":
"key5": [
"@type": "ABC",
"$": "ABC121 "
,

"@type": "ABC",
"$": "ABC12133 "
]
,
"Indications":
"Indication":
"@id": "1308",
"$": "aaaaaa"






in to following PostgreSQL DB



CREATE TABLE records
(
id text,
record json
)


Code I am using to perform the insert operation



cur = conn.cursor()
cur.execute("INSERT INTO trial_records(id, record) VALUES (%s, %s)", ('1', json.dumps(json.loads(str))))


Error I am getting



the JSON object must be str, bytes or bytearray, not 'dict' 


Is this the right syntax to store json string as part of the column










share|improve this question

















  • 2





    You should remove your json.loads call. So it will be json.dumps(str).

    – sashaaero
    Nov 12 '18 at 21:19











  • Thanks that solved it

    – K.Pil
    Nov 12 '18 at 22:52











  • @sashaaero put it as your answer.. So this question will not show in unanswered..

    – dwir182
    Nov 13 '18 at 0:03













0












0








0


0






Trying to insert following JSON String as is without formatting



str=
"Trial":
"@id": "xxxxx",
"key1": "aaaaaaaa (BAL-8557) aaaaaaaaaaaaaaaaaa",
"key2": "aaaaaaaaaaaaa , aaaaaaaaaaaaaaaaaaa",
"key3": "Yes",
"key4": "No",
"key5":
"key5": [
"@type": "ABC",
"$": "ABC121 "
,

"@type": "ABC",
"$": "ABC12133 "
]
,
"Indications":
"Indication":
"@id": "1308",
"$": "aaaaaa"






in to following PostgreSQL DB



CREATE TABLE records
(
id text,
record json
)


Code I am using to perform the insert operation



cur = conn.cursor()
cur.execute("INSERT INTO trial_records(id, record) VALUES (%s, %s)", ('1', json.dumps(json.loads(str))))


Error I am getting



the JSON object must be str, bytes or bytearray, not 'dict' 


Is this the right syntax to store json string as part of the column










share|improve this question














Trying to insert following JSON String as is without formatting



str=
"Trial":
"@id": "xxxxx",
"key1": "aaaaaaaa (BAL-8557) aaaaaaaaaaaaaaaaaa",
"key2": "aaaaaaaaaaaaa , aaaaaaaaaaaaaaaaaaa",
"key3": "Yes",
"key4": "No",
"key5":
"key5": [
"@type": "ABC",
"$": "ABC121 "
,

"@type": "ABC",
"$": "ABC12133 "
]
,
"Indications":
"Indication":
"@id": "1308",
"$": "aaaaaa"






in to following PostgreSQL DB



CREATE TABLE records
(
id text,
record json
)


Code I am using to perform the insert operation



cur = conn.cursor()
cur.execute("INSERT INTO trial_records(id, record) VALUES (%s, %s)", ('1', json.dumps(json.loads(str))))


Error I am getting



the JSON object must be str, bytes or bytearray, not 'dict' 


Is this the right syntax to store json string as part of the column







python json postgresql






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 12 '18 at 21:14









K.PilK.Pil

10219




10219







  • 2





    You should remove your json.loads call. So it will be json.dumps(str).

    – sashaaero
    Nov 12 '18 at 21:19











  • Thanks that solved it

    – K.Pil
    Nov 12 '18 at 22:52











  • @sashaaero put it as your answer.. So this question will not show in unanswered..

    – dwir182
    Nov 13 '18 at 0:03












  • 2





    You should remove your json.loads call. So it will be json.dumps(str).

    – sashaaero
    Nov 12 '18 at 21:19











  • Thanks that solved it

    – K.Pil
    Nov 12 '18 at 22:52











  • @sashaaero put it as your answer.. So this question will not show in unanswered..

    – dwir182
    Nov 13 '18 at 0:03







2




2





You should remove your json.loads call. So it will be json.dumps(str).

– sashaaero
Nov 12 '18 at 21:19





You should remove your json.loads call. So it will be json.dumps(str).

– sashaaero
Nov 12 '18 at 21:19













Thanks that solved it

– K.Pil
Nov 12 '18 at 22:52





Thanks that solved it

– K.Pil
Nov 12 '18 at 22:52













@sashaaero put it as your answer.. So this question will not show in unanswered..

– dwir182
Nov 13 '18 at 0:03





@sashaaero put it as your answer.. So this question will not show in unanswered..

– dwir182
Nov 13 '18 at 0:03












1 Answer
1






active

oldest

votes


















2














json.loads(obj) creates json object from string data.



json.dumps(obj) creates string from json object.



So you should change json.dumps(json.loads(str)) to json.dumps(str).



P.S.: I'd also don't recommend to call your variables as type names like str, int. You are making str() and int() call unable from current scope.






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    1 Answer
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    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    json.loads(obj) creates json object from string data.



    json.dumps(obj) creates string from json object.



    So you should change json.dumps(json.loads(str)) to json.dumps(str).



    P.S.: I'd also don't recommend to call your variables as type names like str, int. You are making str() and int() call unable from current scope.






    share|improve this answer



























      2














      json.loads(obj) creates json object from string data.



      json.dumps(obj) creates string from json object.



      So you should change json.dumps(json.loads(str)) to json.dumps(str).



      P.S.: I'd also don't recommend to call your variables as type names like str, int. You are making str() and int() call unable from current scope.






      share|improve this answer

























        2












        2








        2







        json.loads(obj) creates json object from string data.



        json.dumps(obj) creates string from json object.



        So you should change json.dumps(json.loads(str)) to json.dumps(str).



        P.S.: I'd also don't recommend to call your variables as type names like str, int. You are making str() and int() call unable from current scope.






        share|improve this answer













        json.loads(obj) creates json object from string data.



        json.dumps(obj) creates string from json object.



        So you should change json.dumps(json.loads(str)) to json.dumps(str).



        P.S.: I'd also don't recommend to call your variables as type names like str, int. You are making str() and int() call unable from current scope.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 13 '18 at 0:35









        sashaaerosashaaero

        8531720




        8531720



























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