Using MOD in Pascal
I'm just starting coding and programming and white trying to complete an exercise I noted that the MOD operation doesn't work with variables.
Can someone explain to me why? And also give me some tips on how to do it? Thank you.
program Stack_Overflow;
var
sec, hour, day: real;
begin
WriteLn('Insert a number of seconds.');
ReadLn (sec);
hour := sec div 3600;
writeln (hour);
readln;
end.
pascal
edited Nov 12 '18 at 17:35
MartynA
20.2k32154
asked Nov 12 '18 at 16:56
Sebastião AssunçãoSebastião Assunção
12
|
show 14 more comments
I'm just starting coding and programming and white trying to complete an exercise I noted that the MOD operation doesn't work with variables.
Can someone explain to me why? And also give me some tips on how to do it? Thank you.
program Stack_Overflow;
var
sec, hour, day: real;
begin
WriteLn('Insert a number of seconds.');
ReadLn (sec);
hour := sec div 3600;
writeln (hour);
readln;
end.
pascal
edited Nov 12 '18 at 17:35
MartynA
20.2k32154
asked Nov 12 '18 at 16:56
Sebastião AssunçãoSebastião Assunção
12
1
Please add an expample to help us to help you
– Nifriz
Nov 12 '18 at 16:59
3
MOD certainly does work with variables. Could you show us your code?
– David Dubois
Nov 12 '18 at 16:59
I'm not level 10 in reputation so i can't post photos.
– Sebastião Assunção
Nov 12 '18 at 17:04
But basically I asked the user to provide a number of seconds and then i did hours:= sec mod 600. And it didn't work
– Sebastião Assunção
Nov 12 '18 at 17:05
2
It's good that you can't post photos, because we want the code as text, not as a screenshot. Please post a Minimal, Complete, and Verifiable example and the error message that you get when you try to run the code.
– JJJ
Nov 12 '18 at 17:12
|
show 14 more comments
I'm just starting coding and programming and white trying to complete an exercise I noted that the MOD operation doesn't work with variables.
Can someone explain to me why? And also give me some tips on how to do it? Thank you.
program Stack_Overflow;
var
sec, hour, day: real;
begin
WriteLn('Insert a number of seconds.');
ReadLn (sec);
hour := sec div 3600;
writeln (hour);
readln;
end.
pascal
edited Nov 12 '18 at 17:35
MartynA
20.2k32154
asked Nov 12 '18 at 16:56
Sebastião AssunçãoSebastião Assunção
12
I'm just starting coding and programming and white trying to complete an exercise I noted that the MOD operation doesn't work with variables.
Can someone explain to me why? And also give me some tips on how to do it? Thank you.
program Stack_Overflow;
var
sec, hour, day: real;
begin
WriteLn('Insert a number of seconds.');
ReadLn (sec);
hour := sec div 3600;
writeln (hour);
readln;
end.
pascal
pascal
edited Nov 12 '18 at 17:35
MartynA
20.2k32154
asked Nov 12 '18 at 16:56
Sebastião AssunçãoSebastião Assunção
12
edited Nov 12 '18 at 17:35
MartynA
20.2k32154
asked Nov 12 '18 at 16:56
Sebastião AssunçãoSebastião Assunção
12
edited Nov 12 '18 at 17:35
MartynA
20.2k32154
edited Nov 12 '18 at 17:35
MartynA
20.2k32154
edited Nov 12 '18 at 17:35
MartynA
20.2k32154
20.2k32154
asked Nov 12 '18 at 16:56
Sebastião AssunçãoSebastião Assunção
12
asked Nov 12 '18 at 16:56
Sebastião AssunçãoSebastião Assunção
12
asked Nov 12 '18 at 16:56
Sebastião AssunçãoSebastião Assunção
12
12
1
Please add an expample to help us to help you
– Nifriz
Nov 12 '18 at 16:59
3
MOD certainly does work with variables. Could you show us your code?
– David Dubois
Nov 12 '18 at 16:59
I'm not level 10 in reputation so i can't post photos.
– Sebastião Assunção
Nov 12 '18 at 17:04
But basically I asked the user to provide a number of seconds and then i did hours:= sec mod 600. And it didn't work
– Sebastião Assunção
Nov 12 '18 at 17:05
2
It's good that you can't post photos, because we want the code as text, not as a screenshot. Please post a Minimal, Complete, and Verifiable example and the error message that you get when you try to run the code.
– JJJ
Nov 12 '18 at 17:12
|
show 14 more comments
1
Please add an expample to help us to help you
– Nifriz
Nov 12 '18 at 16:59
3
MOD certainly does work with variables. Could you show us your code?
– David Dubois
Nov 12 '18 at 16:59
I'm not level 10 in reputation so i can't post photos.
– Sebastião Assunção
Nov 12 '18 at 17:04
But basically I asked the user to provide a number of seconds and then i did hours:= sec mod 600. And it didn't work
– Sebastião Assunção
Nov 12 '18 at 17:05
2
It's good that you can't post photos, because we want the code as text, not as a screenshot. Please post a Minimal, Complete, and Verifiable example and the error message that you get when you try to run the code.
– JJJ
Nov 12 '18 at 17:12
1
1
Please add an expample to help us to help you
– Nifriz
Nov 12 '18 at 16:59
Please add an expample to help us to help you
– Nifriz
Nov 12 '18 at 16:59
3
3
MOD certainly does work with variables. Could you show us your code?
– David Dubois
Nov 12 '18 at 16:59
MOD certainly does work with variables. Could you show us your code?
– David Dubois
Nov 12 '18 at 16:59
I'm not level 10 in reputation so i can't post photos.
– Sebastião Assunção
Nov 12 '18 at 17:04
I'm not level 10 in reputation so i can't post photos.
– Sebastião Assunção
Nov 12 '18 at 17:04
But basically I asked the user to provide a number of seconds and then i did hours:= sec mod 600. And it didn't work
– Sebastião Assunção
Nov 12 '18 at 17:05
But basically I asked the user to provide a number of seconds and then i did hours:= sec mod 600. And it didn't work
– Sebastião Assunção
Nov 12 '18 at 17:05
2
2
It's good that you can't post photos, because we want the code as text, not as a screenshot. Please post a Minimal, Complete, and Verifiable example and the error message that you get when you try to run the code.
– JJJ
Nov 12 '18 at 17:12
It's good that you can't post photos, because we want the code as text, not as a screenshot. Please post a Minimal, Complete, and Verifiable example and the error message that you get when you try to run the code.
– JJJ
Nov 12 '18 at 17:12
|
show 14 more comments
2 Answers
2
active
oldest
votes
DIV and MOD operators works only on integers, not on floating point numbers.
Just declare:
var
sec, hour, day: integer;
and you are good to go.
answered Nov 12 '18 at 18:12
LU RDLU RD
28.3k559179
Well yes, as far as one can go with ZIM. <g> +1.
– Rudy Velthuis
Nov 12 '18 at 18:13
@RudyVelthuis, can't be worse than punching cards for the univac, where I started learning programming.
– LU RD
Nov 12 '18 at 18:29
You had cards? Luxury! We had to wire the hardware directly. etc...
– Rudy Velthuis
Nov 13 '18 at 1:05
add a comment |
MOD is well defined for integers only but there are not meant for real. MOD gives you the remainder of integer division a / b , but real division doesn't have remainders.Instead if you want to find the remainder of a real number you can create your own MOD fuction.
//You can either code it as a fuction so its reusability.
Remainder:=Trunc(sec/3600) ; truncate removes the decimal part ang gives you the integer part.This like MOD.
answered Nov 21 '18 at 0:37
lasal22lasal22
11
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
DIV and MOD operators works only on integers, not on floating point numbers.
Just declare:
var
sec, hour, day: integer;
and you are good to go.
answered Nov 12 '18 at 18:12
LU RDLU RD
28.3k559179
Well yes, as far as one can go with ZIM. <g> +1.
– Rudy Velthuis
Nov 12 '18 at 18:13
@RudyVelthuis, can't be worse than punching cards for the univac, where I started learning programming.
– LU RD
Nov 12 '18 at 18:29
You had cards? Luxury! We had to wire the hardware directly. etc...
– Rudy Velthuis
Nov 13 '18 at 1:05
add a comment |
DIV and MOD operators works only on integers, not on floating point numbers.
Just declare:
var
sec, hour, day: integer;
and you are good to go.
answered Nov 12 '18 at 18:12
LU RDLU RD
28.3k559179
Well yes, as far as one can go with ZIM. <g> +1.
– Rudy Velthuis
Nov 12 '18 at 18:13
@RudyVelthuis, can't be worse than punching cards for the univac, where I started learning programming.
– LU RD
Nov 12 '18 at 18:29
You had cards? Luxury! We had to wire the hardware directly. etc...
– Rudy Velthuis
Nov 13 '18 at 1:05
add a comment |
DIV and MOD operators works only on integers, not on floating point numbers.
Just declare:
var
sec, hour, day: integer;
and you are good to go.
answered Nov 12 '18 at 18:12
LU RDLU RD
28.3k559179
DIV and MOD operators works only on integers, not on floating point numbers.
Just declare:
var
sec, hour, day: integer;
and you are good to go.
answered Nov 12 '18 at 18:12
LU RDLU RD
28.3k559179
answered Nov 12 '18 at 18:12
LU RDLU RD
28.3k559179
answered Nov 12 '18 at 18:12
LU RDLU RD
28.3k559179
answered Nov 12 '18 at 18:12
LU RDLU RD
28.3k559179
28.3k559179
Well yes, as far as one can go with ZIM. <g> +1.
– Rudy Velthuis
Nov 12 '18 at 18:13
@RudyVelthuis, can't be worse than punching cards for the univac, where I started learning programming.
– LU RD
Nov 12 '18 at 18:29
You had cards? Luxury! We had to wire the hardware directly. etc...
– Rudy Velthuis
Nov 13 '18 at 1:05
add a comment |
Well yes, as far as one can go with ZIM. <g> +1.
– Rudy Velthuis
Nov 12 '18 at 18:13
@RudyVelthuis, can't be worse than punching cards for the univac, where I started learning programming.
– LU RD
Nov 12 '18 at 18:29
You had cards? Luxury! We had to wire the hardware directly. etc...
– Rudy Velthuis
Nov 13 '18 at 1:05
Well yes, as far as one can go with ZIM. <g> +1.
– Rudy Velthuis
Nov 12 '18 at 18:13
Well yes, as far as one can go with ZIM. <g> +1.
– Rudy Velthuis
Nov 12 '18 at 18:13
@RudyVelthuis, can't be worse than punching cards for the univac, where I started learning programming.
– LU RD
Nov 12 '18 at 18:29
@RudyVelthuis, can't be worse than punching cards for the univac, where I started learning programming.
– LU RD
Nov 12 '18 at 18:29
You had cards? Luxury! We had to wire the hardware directly. etc...
– Rudy Velthuis
Nov 13 '18 at 1:05
You had cards? Luxury! We had to wire the hardware directly. etc...
– Rudy Velthuis
Nov 13 '18 at 1:05
add a comment |
MOD is well defined for integers only but there are not meant for real. MOD gives you the remainder of integer division a / b , but real division doesn't have remainders.Instead if you want to find the remainder of a real number you can create your own MOD fuction.
//You can either code it as a fuction so its reusability.
Remainder:=Trunc(sec/3600) ; truncate removes the decimal part ang gives you the integer part.This like MOD.
answered Nov 21 '18 at 0:37
lasal22lasal22
11
add a comment |
MOD is well defined for integers only but there are not meant for real. MOD gives you the remainder of integer division a / b , but real division doesn't have remainders.Instead if you want to find the remainder of a real number you can create your own MOD fuction.
//You can either code it as a fuction so its reusability.
Remainder:=Trunc(sec/3600) ; truncate removes the decimal part ang gives you the integer part.This like MOD.
answered Nov 21 '18 at 0:37
lasal22lasal22
11
add a comment |
MOD is well defined for integers only but there are not meant for real. MOD gives you the remainder of integer division a / b , but real division doesn't have remainders.Instead if you want to find the remainder of a real number you can create your own MOD fuction.
//You can either code it as a fuction so its reusability.
Remainder:=Trunc(sec/3600) ; truncate removes the decimal part ang gives you the integer part.This like MOD.
answered Nov 21 '18 at 0:37
lasal22lasal22
11
MOD is well defined for integers only but there are not meant for real. MOD gives you the remainder of integer division a / b , but real division doesn't have remainders.Instead if you want to find the remainder of a real number you can create your own MOD fuction.
//You can either code it as a fuction so its reusability.
Remainder:=Trunc(sec/3600) ; truncate removes the decimal part ang gives you the integer part.This like MOD.
answered Nov 21 '18 at 0:37
lasal22lasal22
11
answered Nov 21 '18 at 0:37
lasal22lasal22
11
answered Nov 21 '18 at 0:37
lasal22lasal22
11
answered Nov 21 '18 at 0:37
lasal22lasal22
11
11
add a comment |
add a comment |
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1
Please add an expample to help us to help you
– Nifriz
Nov 12 '18 at 16:59
3
MOD certainly does work with variables. Could you show us your code?
– David Dubois
Nov 12 '18 at 16:59
I'm not level 10 in reputation so i can't post photos.
– Sebastião Assunção
Nov 12 '18 at 17:04
But basically I asked the user to provide a number of seconds and then i did hours:= sec mod 600. And it didn't work
– Sebastião Assunção
Nov 12 '18 at 17:05
2
It's good that you can't post photos, because we want the code as text, not as a screenshot. Please post a Minimal, Complete, and Verifiable example and the error message that you get when you try to run the code.
– JJJ
Nov 12 '18 at 17:12