How can I add a new record with multiple actie_gebruiker(s) via the Python shell?










0















Here are the imports:



from django.db import models
from datetime import datetime, timedelta
from django.contrib.auth.models import User


This is the first class I defined. It is the status of the action (Actie) and it has a status-id and a status-name with a max_length attribute of 5 (todo, doing, done)



class Status(models.Model):
id = models.IntegerField(primary_key=True)
status_naam = models.CharField(max_length=5, default='todo')

def __str__(self):
return str(self.id) + " - " + self.status_naam


This is the class Actie (Action or the action the user determines) wich has an id, an action-name, a action-status wich refers to the table Status here above, an action-publish-date, an ending-date (the deadline) and a user-id wich refers to the table Users django gives me.



class Actie(models.Model):
id = models.IntegerField(primary_key=True)
actie_naam = models.CharField(max_length=150, default='-')
actie_status = models.ForeignKey(Status, default=1)
actie_aanmaakdatum = models.DateTimeField(default=datetime.now())
actie_einddatum = models.DateTimeField(default=datetime.now() + timedelta(days=1))
actie_gebruiker = models.ManyToManyField(User)

def __str__(self):
return str(self.id) + " - " + self.actie_naam


My question now is how can I add a new Actie-object with multiple actie_gebruiker(s) via the Python shell like what command do I have to use..?










share|improve this question




























    0















    Here are the imports:



    from django.db import models
    from datetime import datetime, timedelta
    from django.contrib.auth.models import User


    This is the first class I defined. It is the status of the action (Actie) and it has a status-id and a status-name with a max_length attribute of 5 (todo, doing, done)



    class Status(models.Model):
    id = models.IntegerField(primary_key=True)
    status_naam = models.CharField(max_length=5, default='todo')

    def __str__(self):
    return str(self.id) + " - " + self.status_naam


    This is the class Actie (Action or the action the user determines) wich has an id, an action-name, a action-status wich refers to the table Status here above, an action-publish-date, an ending-date (the deadline) and a user-id wich refers to the table Users django gives me.



    class Actie(models.Model):
    id = models.IntegerField(primary_key=True)
    actie_naam = models.CharField(max_length=150, default='-')
    actie_status = models.ForeignKey(Status, default=1)
    actie_aanmaakdatum = models.DateTimeField(default=datetime.now())
    actie_einddatum = models.DateTimeField(default=datetime.now() + timedelta(days=1))
    actie_gebruiker = models.ManyToManyField(User)

    def __str__(self):
    return str(self.id) + " - " + self.actie_naam


    My question now is how can I add a new Actie-object with multiple actie_gebruiker(s) via the Python shell like what command do I have to use..?










    share|improve this question


























      0












      0








      0








      Here are the imports:



      from django.db import models
      from datetime import datetime, timedelta
      from django.contrib.auth.models import User


      This is the first class I defined. It is the status of the action (Actie) and it has a status-id and a status-name with a max_length attribute of 5 (todo, doing, done)



      class Status(models.Model):
      id = models.IntegerField(primary_key=True)
      status_naam = models.CharField(max_length=5, default='todo')

      def __str__(self):
      return str(self.id) + " - " + self.status_naam


      This is the class Actie (Action or the action the user determines) wich has an id, an action-name, a action-status wich refers to the table Status here above, an action-publish-date, an ending-date (the deadline) and a user-id wich refers to the table Users django gives me.



      class Actie(models.Model):
      id = models.IntegerField(primary_key=True)
      actie_naam = models.CharField(max_length=150, default='-')
      actie_status = models.ForeignKey(Status, default=1)
      actie_aanmaakdatum = models.DateTimeField(default=datetime.now())
      actie_einddatum = models.DateTimeField(default=datetime.now() + timedelta(days=1))
      actie_gebruiker = models.ManyToManyField(User)

      def __str__(self):
      return str(self.id) + " - " + self.actie_naam


      My question now is how can I add a new Actie-object with multiple actie_gebruiker(s) via the Python shell like what command do I have to use..?










      share|improve this question
















      Here are the imports:



      from django.db import models
      from datetime import datetime, timedelta
      from django.contrib.auth.models import User


      This is the first class I defined. It is the status of the action (Actie) and it has a status-id and a status-name with a max_length attribute of 5 (todo, doing, done)



      class Status(models.Model):
      id = models.IntegerField(primary_key=True)
      status_naam = models.CharField(max_length=5, default='todo')

      def __str__(self):
      return str(self.id) + " - " + self.status_naam


      This is the class Actie (Action or the action the user determines) wich has an id, an action-name, a action-status wich refers to the table Status here above, an action-publish-date, an ending-date (the deadline) and a user-id wich refers to the table Users django gives me.



      class Actie(models.Model):
      id = models.IntegerField(primary_key=True)
      actie_naam = models.CharField(max_length=150, default='-')
      actie_status = models.ForeignKey(Status, default=1)
      actie_aanmaakdatum = models.DateTimeField(default=datetime.now())
      actie_einddatum = models.DateTimeField(default=datetime.now() + timedelta(days=1))
      actie_gebruiker = models.ManyToManyField(User)

      def __str__(self):
      return str(self.id) + " - " + self.actie_naam


      My question now is how can I add a new Actie-object with multiple actie_gebruiker(s) via the Python shell like what command do I have to use..?







      python django shell django-models revitpythonshell






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 13 '18 at 13:53









      ikkuh

      2,56931423




      2,56931423










      asked Nov 13 '18 at 13:49









      E. ArslanE. Arslan

      245




      245






















          1 Answer
          1






          active

          oldest

          votes


















          0














          You can use add method from a ManyToManyField field relation to add objects. Take a look to the Django documentation for ManyToManyField



          actie = Actie.objects.create() # put some parameters inside create
          user1 = # get or create user
          actie.actie_gebruiker.add(user1)
          user2 = # get or create user
          actie.actie_gebruiker.add(user2)





          share|improve this answer























          • Thank you very much, it worked :)

            – E. Arslan
            Nov 14 '18 at 15:19












          • I'm glad it has worked ;)

            – grouchoboy
            Nov 14 '18 at 15:21










          Your Answer






          StackExchange.ifUsing("editor", function ()
          StackExchange.using("externalEditor", function ()
          StackExchange.using("snippets", function ()
          StackExchange.snippets.init();
          );
          );
          , "code-snippets");

          StackExchange.ready(function()
          var channelOptions =
          tags: "".split(" "),
          id: "1"
          ;
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function()
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled)
          StackExchange.using("snippets", function()
          createEditor();
          );

          else
          createEditor();

          );

          function createEditor()
          StackExchange.prepareEditor(
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader:
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          ,
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          );



          );













          draft saved

          draft discarded


















          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53282509%2fhow-can-i-add-a-new-record-with-multiple-actie-gebruikers-via-the-python-shell%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          You can use add method from a ManyToManyField field relation to add objects. Take a look to the Django documentation for ManyToManyField



          actie = Actie.objects.create() # put some parameters inside create
          user1 = # get or create user
          actie.actie_gebruiker.add(user1)
          user2 = # get or create user
          actie.actie_gebruiker.add(user2)





          share|improve this answer























          • Thank you very much, it worked :)

            – E. Arslan
            Nov 14 '18 at 15:19












          • I'm glad it has worked ;)

            – grouchoboy
            Nov 14 '18 at 15:21















          0














          You can use add method from a ManyToManyField field relation to add objects. Take a look to the Django documentation for ManyToManyField



          actie = Actie.objects.create() # put some parameters inside create
          user1 = # get or create user
          actie.actie_gebruiker.add(user1)
          user2 = # get or create user
          actie.actie_gebruiker.add(user2)





          share|improve this answer























          • Thank you very much, it worked :)

            – E. Arslan
            Nov 14 '18 at 15:19












          • I'm glad it has worked ;)

            – grouchoboy
            Nov 14 '18 at 15:21













          0












          0








          0







          You can use add method from a ManyToManyField field relation to add objects. Take a look to the Django documentation for ManyToManyField



          actie = Actie.objects.create() # put some parameters inside create
          user1 = # get or create user
          actie.actie_gebruiker.add(user1)
          user2 = # get or create user
          actie.actie_gebruiker.add(user2)





          share|improve this answer













          You can use add method from a ManyToManyField field relation to add objects. Take a look to the Django documentation for ManyToManyField



          actie = Actie.objects.create() # put some parameters inside create
          user1 = # get or create user
          actie.actie_gebruiker.add(user1)
          user2 = # get or create user
          actie.actie_gebruiker.add(user2)






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 13 '18 at 15:29









          grouchoboygrouchoboy

          46038




          46038












          • Thank you very much, it worked :)

            – E. Arslan
            Nov 14 '18 at 15:19












          • I'm glad it has worked ;)

            – grouchoboy
            Nov 14 '18 at 15:21

















          • Thank you very much, it worked :)

            – E. Arslan
            Nov 14 '18 at 15:19












          • I'm glad it has worked ;)

            – grouchoboy
            Nov 14 '18 at 15:21
















          Thank you very much, it worked :)

          – E. Arslan
          Nov 14 '18 at 15:19






          Thank you very much, it worked :)

          – E. Arslan
          Nov 14 '18 at 15:19














          I'm glad it has worked ;)

          – grouchoboy
          Nov 14 '18 at 15:21





          I'm glad it has worked ;)

          – grouchoboy
          Nov 14 '18 at 15:21



















          draft saved

          draft discarded
















































          Thanks for contributing an answer to Stack Overflow!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid


          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.

          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53282509%2fhow-can-i-add-a-new-record-with-multiple-actie-gebruikers-via-the-python-shell%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Use pre created SQLite database for Android project in kotlin

          Darth Vader #20

          Ondo