How to quickly test if a URL exists and has content in java?
I am looking to test to see if hundreds of URLs exist, and the current way I have takes too much time. This is what I have found so far:
public static boolean checkURL(URL u)
HttpURLConnection connection = null;
try
connection = (HttpURLConnection) u.openConnection();
connection.setRequestMethod("HEAD");
int code = connection.getResponseCode();
System.out.println("" + code);
// You can determine on HTTP return code received. 200 is success.
if (code == 200)
return true;
else
return false;
catch (MalformedURLException e)
// TODO Auto-generated catch block
// e.printStackTrace();
System.out.println("error");
catch (IOException e)
System.out.println("error2");
// TODO Auto-generated catch block
// e.printStackTrace();
finally
if (connection != null)
connection.disconnect();
return false;
Although this does successfully find whether a URL exists and has content, it does so in a lengthy period of time, with the program often taking upwards of five minutes to execute. Does anyone know more efficient ways to test this?
Note: It is important to test that not only the url returns 200, but also that the website doesn't timeout.
java performance url timeout
add a comment |
I am looking to test to see if hundreds of URLs exist, and the current way I have takes too much time. This is what I have found so far:
public static boolean checkURL(URL u)
HttpURLConnection connection = null;
try
connection = (HttpURLConnection) u.openConnection();
connection.setRequestMethod("HEAD");
int code = connection.getResponseCode();
System.out.println("" + code);
// You can determine on HTTP return code received. 200 is success.
if (code == 200)
return true;
else
return false;
catch (MalformedURLException e)
// TODO Auto-generated catch block
// e.printStackTrace();
System.out.println("error");
catch (IOException e)
System.out.println("error2");
// TODO Auto-generated catch block
// e.printStackTrace();
finally
if (connection != null)
connection.disconnect();
return false;
Although this does successfully find whether a URL exists and has content, it does so in a lengthy period of time, with the program often taking upwards of five minutes to execute. Does anyone know more efficient ways to test this?
Note: It is important to test that not only the url returns 200, but also that the website doesn't timeout.
java performance url timeout
How can you test that a website doesn't time out without waiting for it to time out?
– shmosel
Nov 14 '18 at 1:10
It seems to me that pinging takes a lot less time than this method, although I'm unsure on how to execute that
– Alex Reed
Nov 14 '18 at 1:20
Did you try searching?
– shmosel
Nov 14 '18 at 1:21
I did, when I found questions about pinging websites and tried the solutions, the program still returned sites that timed out.
– Alex Reed
Nov 14 '18 at 1:32
add a comment |
I am looking to test to see if hundreds of URLs exist, and the current way I have takes too much time. This is what I have found so far:
public static boolean checkURL(URL u)
HttpURLConnection connection = null;
try
connection = (HttpURLConnection) u.openConnection();
connection.setRequestMethod("HEAD");
int code = connection.getResponseCode();
System.out.println("" + code);
// You can determine on HTTP return code received. 200 is success.
if (code == 200)
return true;
else
return false;
catch (MalformedURLException e)
// TODO Auto-generated catch block
// e.printStackTrace();
System.out.println("error");
catch (IOException e)
System.out.println("error2");
// TODO Auto-generated catch block
// e.printStackTrace();
finally
if (connection != null)
connection.disconnect();
return false;
Although this does successfully find whether a URL exists and has content, it does so in a lengthy period of time, with the program often taking upwards of five minutes to execute. Does anyone know more efficient ways to test this?
Note: It is important to test that not only the url returns 200, but also that the website doesn't timeout.
java performance url timeout
I am looking to test to see if hundreds of URLs exist, and the current way I have takes too much time. This is what I have found so far:
public static boolean checkURL(URL u)
HttpURLConnection connection = null;
try
connection = (HttpURLConnection) u.openConnection();
connection.setRequestMethod("HEAD");
int code = connection.getResponseCode();
System.out.println("" + code);
// You can determine on HTTP return code received. 200 is success.
if (code == 200)
return true;
else
return false;
catch (MalformedURLException e)
// TODO Auto-generated catch block
// e.printStackTrace();
System.out.println("error");
catch (IOException e)
System.out.println("error2");
// TODO Auto-generated catch block
// e.printStackTrace();
finally
if (connection != null)
connection.disconnect();
return false;
Although this does successfully find whether a URL exists and has content, it does so in a lengthy period of time, with the program often taking upwards of five minutes to execute. Does anyone know more efficient ways to test this?
Note: It is important to test that not only the url returns 200, but also that the website doesn't timeout.
java performance url timeout
java performance url timeout
asked Nov 14 '18 at 1:08
Alex ReedAlex Reed
325
325
How can you test that a website doesn't time out without waiting for it to time out?
– shmosel
Nov 14 '18 at 1:10
It seems to me that pinging takes a lot less time than this method, although I'm unsure on how to execute that
– Alex Reed
Nov 14 '18 at 1:20
Did you try searching?
– shmosel
Nov 14 '18 at 1:21
I did, when I found questions about pinging websites and tried the solutions, the program still returned sites that timed out.
– Alex Reed
Nov 14 '18 at 1:32
add a comment |
How can you test that a website doesn't time out without waiting for it to time out?
– shmosel
Nov 14 '18 at 1:10
It seems to me that pinging takes a lot less time than this method, although I'm unsure on how to execute that
– Alex Reed
Nov 14 '18 at 1:20
Did you try searching?
– shmosel
Nov 14 '18 at 1:21
I did, when I found questions about pinging websites and tried the solutions, the program still returned sites that timed out.
– Alex Reed
Nov 14 '18 at 1:32
How can you test that a website doesn't time out without waiting for it to time out?
– shmosel
Nov 14 '18 at 1:10
How can you test that a website doesn't time out without waiting for it to time out?
– shmosel
Nov 14 '18 at 1:10
It seems to me that pinging takes a lot less time than this method, although I'm unsure on how to execute that
– Alex Reed
Nov 14 '18 at 1:20
It seems to me that pinging takes a lot less time than this method, although I'm unsure on how to execute that
– Alex Reed
Nov 14 '18 at 1:20
Did you try searching?
– shmosel
Nov 14 '18 at 1:21
Did you try searching?
– shmosel
Nov 14 '18 at 1:21
I did, when I found questions about pinging websites and tried the solutions, the program still returned sites that timed out.
– Alex Reed
Nov 14 '18 at 1:32
I did, when I found questions about pinging websites and tried the solutions, the program still returned sites that timed out.
– Alex Reed
Nov 14 '18 at 1:32
add a comment |
1 Answer
1
active
oldest
votes
Your code looks good and it should be the easiest way to check for url. You might want to add a timeout in the HttpURLConnection.
Sample code for reference.
enter code here
import java.net.HttpURLConnection;
import java.net.URL;
public class UrlChecker
public static void main(String args)
System.out.println(URLExists("http://slowwly.robertomurray.co.uk/delay/
3000/url/http://www.google.co.uk"));
public static boolean URLExists(String targetUrl)
HttpURLConnection urlConnection;
try
urlConnection = (HttpURLConnection) new
URL(targetUrl).openConnection();
urlConnection.setRequestMethod("HEAD");
// Set timeouts 2000 in milliseconds and throw exception
urlConnection.setConnectTimeout(2000);
urlConnection.setReadTimeout(2000);
/* Set timeouts 4000 in milliseconds and it should work as the url
should return back in 3 seconds.
httpUrlConn.setConnectTimeout(4000);
httpUrlConn.setReadTimeout(4000);
*/
System.out.println("Response Code =>"+
urlConnection.getResponseCode());
System.out.println("Response Msg =>"+
urlConnection.getResponseMessage());
return (urlConnection.getResponseCode() ==
HttpURLConnection.HTTP_OK);
catch (Exception e)
System.out.println("Exception => " + e.getMessage());
return false;
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your code looks good and it should be the easiest way to check for url. You might want to add a timeout in the HttpURLConnection.
Sample code for reference.
enter code here
import java.net.HttpURLConnection;
import java.net.URL;
public class UrlChecker
public static void main(String args)
System.out.println(URLExists("http://slowwly.robertomurray.co.uk/delay/
3000/url/http://www.google.co.uk"));
public static boolean URLExists(String targetUrl)
HttpURLConnection urlConnection;
try
urlConnection = (HttpURLConnection) new
URL(targetUrl).openConnection();
urlConnection.setRequestMethod("HEAD");
// Set timeouts 2000 in milliseconds and throw exception
urlConnection.setConnectTimeout(2000);
urlConnection.setReadTimeout(2000);
/* Set timeouts 4000 in milliseconds and it should work as the url
should return back in 3 seconds.
httpUrlConn.setConnectTimeout(4000);
httpUrlConn.setReadTimeout(4000);
*/
System.out.println("Response Code =>"+
urlConnection.getResponseCode());
System.out.println("Response Msg =>"+
urlConnection.getResponseMessage());
return (urlConnection.getResponseCode() ==
HttpURLConnection.HTTP_OK);
catch (Exception e)
System.out.println("Exception => " + e.getMessage());
return false;
add a comment |
Your code looks good and it should be the easiest way to check for url. You might want to add a timeout in the HttpURLConnection.
Sample code for reference.
enter code here
import java.net.HttpURLConnection;
import java.net.URL;
public class UrlChecker
public static void main(String args)
System.out.println(URLExists("http://slowwly.robertomurray.co.uk/delay/
3000/url/http://www.google.co.uk"));
public static boolean URLExists(String targetUrl)
HttpURLConnection urlConnection;
try
urlConnection = (HttpURLConnection) new
URL(targetUrl).openConnection();
urlConnection.setRequestMethod("HEAD");
// Set timeouts 2000 in milliseconds and throw exception
urlConnection.setConnectTimeout(2000);
urlConnection.setReadTimeout(2000);
/* Set timeouts 4000 in milliseconds and it should work as the url
should return back in 3 seconds.
httpUrlConn.setConnectTimeout(4000);
httpUrlConn.setReadTimeout(4000);
*/
System.out.println("Response Code =>"+
urlConnection.getResponseCode());
System.out.println("Response Msg =>"+
urlConnection.getResponseMessage());
return (urlConnection.getResponseCode() ==
HttpURLConnection.HTTP_OK);
catch (Exception e)
System.out.println("Exception => " + e.getMessage());
return false;
add a comment |
Your code looks good and it should be the easiest way to check for url. You might want to add a timeout in the HttpURLConnection.
Sample code for reference.
enter code here
import java.net.HttpURLConnection;
import java.net.URL;
public class UrlChecker
public static void main(String args)
System.out.println(URLExists("http://slowwly.robertomurray.co.uk/delay/
3000/url/http://www.google.co.uk"));
public static boolean URLExists(String targetUrl)
HttpURLConnection urlConnection;
try
urlConnection = (HttpURLConnection) new
URL(targetUrl).openConnection();
urlConnection.setRequestMethod("HEAD");
// Set timeouts 2000 in milliseconds and throw exception
urlConnection.setConnectTimeout(2000);
urlConnection.setReadTimeout(2000);
/* Set timeouts 4000 in milliseconds and it should work as the url
should return back in 3 seconds.
httpUrlConn.setConnectTimeout(4000);
httpUrlConn.setReadTimeout(4000);
*/
System.out.println("Response Code =>"+
urlConnection.getResponseCode());
System.out.println("Response Msg =>"+
urlConnection.getResponseMessage());
return (urlConnection.getResponseCode() ==
HttpURLConnection.HTTP_OK);
catch (Exception e)
System.out.println("Exception => " + e.getMessage());
return false;
Your code looks good and it should be the easiest way to check for url. You might want to add a timeout in the HttpURLConnection.
Sample code for reference.
enter code here
import java.net.HttpURLConnection;
import java.net.URL;
public class UrlChecker
public static void main(String args)
System.out.println(URLExists("http://slowwly.robertomurray.co.uk/delay/
3000/url/http://www.google.co.uk"));
public static boolean URLExists(String targetUrl)
HttpURLConnection urlConnection;
try
urlConnection = (HttpURLConnection) new
URL(targetUrl).openConnection();
urlConnection.setRequestMethod("HEAD");
// Set timeouts 2000 in milliseconds and throw exception
urlConnection.setConnectTimeout(2000);
urlConnection.setReadTimeout(2000);
/* Set timeouts 4000 in milliseconds and it should work as the url
should return back in 3 seconds.
httpUrlConn.setConnectTimeout(4000);
httpUrlConn.setReadTimeout(4000);
*/
System.out.println("Response Code =>"+
urlConnection.getResponseCode());
System.out.println("Response Msg =>"+
urlConnection.getResponseMessage());
return (urlConnection.getResponseCode() ==
HttpURLConnection.HTTP_OK);
catch (Exception e)
System.out.println("Exception => " + e.getMessage());
return false;
answered Nov 14 '18 at 2:57
SK -SK -
796
796
add a comment |
add a comment |
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How can you test that a website doesn't time out without waiting for it to time out?
– shmosel
Nov 14 '18 at 1:10
It seems to me that pinging takes a lot less time than this method, although I'm unsure on how to execute that
– Alex Reed
Nov 14 '18 at 1:20
Did you try searching?
– shmosel
Nov 14 '18 at 1:21
I did, when I found questions about pinging websites and tried the solutions, the program still returned sites that timed out.
– Alex Reed
Nov 14 '18 at 1:32