combine two lists and map to new class object with rxjava
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0
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Consider the following input : Calling network call will retrieve client object
data class Client(
val name: String,
val phoneNumber: String,
val frequentContacts: List<String>,
val allContacts: List<String>
)
what i need to do is to map similar names in frequentContacts and allContacts list in new object and subscribe on the output.
assume the response from network call will return this Client Object
"name": "Jack",
"phoneNumber": "90284302424",
"frequentContacts": [
"John",
"Sam"
],
"allContacts": [
"John",
"Adam",
"Peter",
"Kim",
"Sam"
]
what i need receive in subscribe newly create object .
data class clientViewModel(val name: String,val isFrequent: Boolean)
so in onSuccess i should have instance from clientViewModel
Expected output :
("John", true")
("Adam", false")
("Peter", false")
("Kim", false")
("Sam", true")
here what i am up to
clientRepository.getClientById(clientId)
.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.doAfterTerminate view.hideProgress()
.flatMapit.frequentContacts
.subscribe
onSuccess(item: ClientViewModel)
onError()
onFinish()
but this not work because once i used flat map i lose the allContacts list
any help ?
I read about GroupBy operator but i am using Single...
kotlin rx-java2
add a comment |
up vote
0
down vote
favorite
Consider the following input : Calling network call will retrieve client object
data class Client(
val name: String,
val phoneNumber: String,
val frequentContacts: List<String>,
val allContacts: List<String>
)
what i need to do is to map similar names in frequentContacts and allContacts list in new object and subscribe on the output.
assume the response from network call will return this Client Object
"name": "Jack",
"phoneNumber": "90284302424",
"frequentContacts": [
"John",
"Sam"
],
"allContacts": [
"John",
"Adam",
"Peter",
"Kim",
"Sam"
]
what i need receive in subscribe newly create object .
data class clientViewModel(val name: String,val isFrequent: Boolean)
so in onSuccess i should have instance from clientViewModel
Expected output :
("John", true")
("Adam", false")
("Peter", false")
("Kim", false")
("Sam", true")
here what i am up to
clientRepository.getClientById(clientId)
.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.doAfterTerminate view.hideProgress()
.flatMapit.frequentContacts
.subscribe
onSuccess(item: ClientViewModel)
onError()
onFinish()
but this not work because once i used flat map i lose the allContacts list
any help ?
I read about GroupBy operator but i am using Single...
kotlin rx-java2
What do you think of:.flatMapit.allContacts.mapc->Pair(c,it.frequentContacts.contains(c))
– Raphael
Nov 9 at 19:22
@Raphael i tried it shows me type miss match error Required :SingleSource <out(???)> Found : List<Pair(String, Boolean)>
– Joe Adams
Nov 9 at 19:51
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Consider the following input : Calling network call will retrieve client object
data class Client(
val name: String,
val phoneNumber: String,
val frequentContacts: List<String>,
val allContacts: List<String>
)
what i need to do is to map similar names in frequentContacts and allContacts list in new object and subscribe on the output.
assume the response from network call will return this Client Object
"name": "Jack",
"phoneNumber": "90284302424",
"frequentContacts": [
"John",
"Sam"
],
"allContacts": [
"John",
"Adam",
"Peter",
"Kim",
"Sam"
]
what i need receive in subscribe newly create object .
data class clientViewModel(val name: String,val isFrequent: Boolean)
so in onSuccess i should have instance from clientViewModel
Expected output :
("John", true")
("Adam", false")
("Peter", false")
("Kim", false")
("Sam", true")
here what i am up to
clientRepository.getClientById(clientId)
.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.doAfterTerminate view.hideProgress()
.flatMapit.frequentContacts
.subscribe
onSuccess(item: ClientViewModel)
onError()
onFinish()
but this not work because once i used flat map i lose the allContacts list
any help ?
I read about GroupBy operator but i am using Single...
kotlin rx-java2
Consider the following input : Calling network call will retrieve client object
data class Client(
val name: String,
val phoneNumber: String,
val frequentContacts: List<String>,
val allContacts: List<String>
)
what i need to do is to map similar names in frequentContacts and allContacts list in new object and subscribe on the output.
assume the response from network call will return this Client Object
"name": "Jack",
"phoneNumber": "90284302424",
"frequentContacts": [
"John",
"Sam"
],
"allContacts": [
"John",
"Adam",
"Peter",
"Kim",
"Sam"
]
what i need receive in subscribe newly create object .
data class clientViewModel(val name: String,val isFrequent: Boolean)
so in onSuccess i should have instance from clientViewModel
Expected output :
("John", true")
("Adam", false")
("Peter", false")
("Kim", false")
("Sam", true")
here what i am up to
clientRepository.getClientById(clientId)
.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.doAfterTerminate view.hideProgress()
.flatMapit.frequentContacts
.subscribe
onSuccess(item: ClientViewModel)
onError()
onFinish()
but this not work because once i used flat map i lose the allContacts list
any help ?
I read about GroupBy operator but i am using Single...
kotlin rx-java2
kotlin rx-java2
edited Nov 12 at 8:26
Jayson Minard
35.2k13103170
35.2k13103170
asked Nov 9 at 18:56
Joe Adams
11
11
What do you think of:.flatMapit.allContacts.mapc->Pair(c,it.frequentContacts.contains(c))
– Raphael
Nov 9 at 19:22
@Raphael i tried it shows me type miss match error Required :SingleSource <out(???)> Found : List<Pair(String, Boolean)>
– Joe Adams
Nov 9 at 19:51
add a comment |
What do you think of:.flatMapit.allContacts.mapc->Pair(c,it.frequentContacts.contains(c))
– Raphael
Nov 9 at 19:22
@Raphael i tried it shows me type miss match error Required :SingleSource <out(???)> Found : List<Pair(String, Boolean)>
– Joe Adams
Nov 9 at 19:51
What do you think of:
.flatMapit.allContacts.mapc->Pair(c,it.frequentContacts.contains(c)) – Raphael
Nov 9 at 19:22
What do you think of:
.flatMapit.allContacts.mapc->Pair(c,it.frequentContacts.contains(c)) – Raphael
Nov 9 at 19:22
@Raphael i tried it shows me type miss match error Required :SingleSource <out(???)> Found : List<Pair(String, Boolean)>
– Joe Adams
Nov 9 at 19:51
@Raphael i tried it shows me type miss match error Required :SingleSource <out(???)> Found : List<Pair(String, Boolean)>
– Joe Adams
Nov 9 at 19:51
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
Honestly I'd just do this:
clientRepository.getClientById(clientId)
.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.doFinally view.hideProgress()
.map client ->
client.allContacts.map contact ->
clientViewModel(name = contact, isFrequent = client.frequentContacts.contains(contact))
.subscribeBy(onSuccess = list: List<clientViewModel> ->
...
, onError = err -> ... )
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Honestly I'd just do this:
clientRepository.getClientById(clientId)
.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.doFinally view.hideProgress()
.map client ->
client.allContacts.map contact ->
clientViewModel(name = contact, isFrequent = client.frequentContacts.contains(contact))
.subscribeBy(onSuccess = list: List<clientViewModel> ->
...
, onError = err -> ... )
add a comment |
up vote
0
down vote
Honestly I'd just do this:
clientRepository.getClientById(clientId)
.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.doFinally view.hideProgress()
.map client ->
client.allContacts.map contact ->
clientViewModel(name = contact, isFrequent = client.frequentContacts.contains(contact))
.subscribeBy(onSuccess = list: List<clientViewModel> ->
...
, onError = err -> ... )
add a comment |
up vote
0
down vote
up vote
0
down vote
Honestly I'd just do this:
clientRepository.getClientById(clientId)
.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.doFinally view.hideProgress()
.map client ->
client.allContacts.map contact ->
clientViewModel(name = contact, isFrequent = client.frequentContacts.contains(contact))
.subscribeBy(onSuccess = list: List<clientViewModel> ->
...
, onError = err -> ... )
Honestly I'd just do this:
clientRepository.getClientById(clientId)
.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.doFinally view.hideProgress()
.map client ->
client.allContacts.map contact ->
clientViewModel(name = contact, isFrequent = client.frequentContacts.contains(contact))
.subscribeBy(onSuccess = list: List<clientViewModel> ->
...
, onError = err -> ... )
answered Nov 9 at 19:39
EpicPandaForce
46.1k14121239
46.1k14121239
add a comment |
add a comment |
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What do you think of:
.flatMapit.allContacts.mapc->Pair(c,it.frequentContacts.contains(c))– Raphael
Nov 9 at 19:22
@Raphael i tried it shows me type miss match error Required :SingleSource <out(???)> Found : List<Pair(String, Boolean)>
– Joe Adams
Nov 9 at 19:51