JS - Get top 5 max elemenets from array
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How can I get top 5 max elements from array of ints, which in its turn is a property of js object.
Thanks for help.
javascript arrays
asked Aug 31 '16 at 16:01
Dmitriy Kovalenko
1,110419
add a comment |
up vote
0
down vote
favorite
How can I get top 5 max elements from array of ints, which in its turn is a property of js object.
Thanks for help.
javascript arrays
asked Aug 31 '16 at 16:01
Dmitriy Kovalenko
1,110419
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
How can I get top 5 max elements from array of ints, which in its turn is a property of js object.
Thanks for help.
javascript arrays
asked Aug 31 '16 at 16:01
Dmitriy Kovalenko
1,110419
How can I get top 5 max elements from array of ints, which in its turn is a property of js object.
Thanks for help.
javascript arrays
javascript arrays
asked Aug 31 '16 at 16:01
Dmitriy Kovalenko
1,110419
asked Aug 31 '16 at 16:01
Dmitriy Kovalenko
1,110419
asked Aug 31 '16 at 16:01
Dmitriy Kovalenko
1,110419
asked Aug 31 '16 at 16:01
Dmitriy Kovalenko
1,110419
asked Aug 31 '16 at 16:01
Dmitriy Kovalenko
1,110419
1,110419
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
2
down vote
accepted
A solution in ES6 :
values = [1,65,8,98,689,12,33,2,3,789];
var topValues = values.sort((a,b) => a>b).slice(0,5);
console.log(topValues); // [ 1, 2, 3, 8, 12 ]
Many others exist, ask if you need more
answered Aug 31 '16 at 16:07
kevin ternet
2,458716
2
(a,b) => a>b- well, not really.
– georg
Aug 31 '16 at 17:18
[2, 6, 8, 1].sort((a, b) => b>a) [2, 6, 8 1] incorrect [2, 6, 8, 1].sort((a, b) => b - a) [8, 6, 2, 1] correct, the sort function should be(a,b) => b - a
– Cody Moniz
Nov 9 at 21:39
add a comment |
up vote
0
down vote
[2, 6, 8, 1, 10, 11].sort((a, b) => b - a).slice(0,5)
[11, 10, 8, 6, 2]
answered Nov 9 at 21:40
Cody Moniz
1,91521215
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
A solution in ES6 :
values = [1,65,8,98,689,12,33,2,3,789];
var topValues = values.sort((a,b) => a>b).slice(0,5);
console.log(topValues); // [ 1, 2, 3, 8, 12 ]
Many others exist, ask if you need more
answered Aug 31 '16 at 16:07
kevin ternet
2,458716
2
(a,b) => a>b- well, not really.
– georg
Aug 31 '16 at 17:18
[2, 6, 8, 1].sort((a, b) => b>a) [2, 6, 8 1] incorrect [2, 6, 8, 1].sort((a, b) => b - a) [8, 6, 2, 1] correct, the sort function should be(a,b) => b - a
– Cody Moniz
Nov 9 at 21:39
add a comment |
up vote
2
down vote
accepted
A solution in ES6 :
values = [1,65,8,98,689,12,33,2,3,789];
var topValues = values.sort((a,b) => a>b).slice(0,5);
console.log(topValues); // [ 1, 2, 3, 8, 12 ]
Many others exist, ask if you need more
answered Aug 31 '16 at 16:07
kevin ternet
2,458716
2
(a,b) => a>b- well, not really.
– georg
Aug 31 '16 at 17:18
[2, 6, 8, 1].sort((a, b) => b>a) [2, 6, 8 1] incorrect [2, 6, 8, 1].sort((a, b) => b - a) [8, 6, 2, 1] correct, the sort function should be(a,b) => b - a
– Cody Moniz
Nov 9 at 21:39
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
A solution in ES6 :
values = [1,65,8,98,689,12,33,2,3,789];
var topValues = values.sort((a,b) => a>b).slice(0,5);
console.log(topValues); // [ 1, 2, 3, 8, 12 ]
Many others exist, ask if you need more
answered Aug 31 '16 at 16:07
kevin ternet
2,458716
A solution in ES6 :
values = [1,65,8,98,689,12,33,2,3,789];
var topValues = values.sort((a,b) => a>b).slice(0,5);
console.log(topValues); // [ 1, 2, 3, 8, 12 ]
Many others exist, ask if you need more
answered Aug 31 '16 at 16:07
kevin ternet
2,458716
answered Aug 31 '16 at 16:07
kevin ternet
2,458716
answered Aug 31 '16 at 16:07
kevin ternet
2,458716
answered Aug 31 '16 at 16:07
kevin ternet
2,458716
2,458716
2
(a,b) => a>b- well, not really.
– georg
Aug 31 '16 at 17:18
[2, 6, 8, 1].sort((a, b) => b>a) [2, 6, 8 1] incorrect [2, 6, 8, 1].sort((a, b) => b - a) [8, 6, 2, 1] correct, the sort function should be(a,b) => b - a
– Cody Moniz
Nov 9 at 21:39
add a comment |
2
(a,b) => a>b- well, not really.
– georg
Aug 31 '16 at 17:18
[2, 6, 8, 1].sort((a, b) => b>a) [2, 6, 8 1] incorrect [2, 6, 8, 1].sort((a, b) => b - a) [8, 6, 2, 1] correct, the sort function should be(a,b) => b - a
– Cody Moniz
Nov 9 at 21:39
2
2
(a,b) => a>b - well, not really.– georg
Aug 31 '16 at 17:18
(a,b) => a>b - well, not really.– georg
Aug 31 '16 at 17:18
[2, 6, 8, 1].sort((a, b) => b>a) [2, 6, 8 1] incorrect [2, 6, 8, 1].sort((a, b) => b - a) [8, 6, 2, 1] correct, the sort function should be
(a,b) => b - a– Cody Moniz
Nov 9 at 21:39
[2, 6, 8, 1].sort((a, b) => b>a) [2, 6, 8 1] incorrect [2, 6, 8, 1].sort((a, b) => b - a) [8, 6, 2, 1] correct, the sort function should be
(a,b) => b - a– Cody Moniz
Nov 9 at 21:39
add a comment |
up vote
0
down vote
[2, 6, 8, 1, 10, 11].sort((a, b) => b - a).slice(0,5)
[11, 10, 8, 6, 2]
answered Nov 9 at 21:40
Cody Moniz
1,91521215
add a comment |
up vote
0
down vote
[2, 6, 8, 1, 10, 11].sort((a, b) => b - a).slice(0,5)
[11, 10, 8, 6, 2]
answered Nov 9 at 21:40
Cody Moniz
1,91521215
add a comment |
up vote
0
down vote
up vote
0
down vote
[2, 6, 8, 1, 10, 11].sort((a, b) => b - a).slice(0,5)
[11, 10, 8, 6, 2]
answered Nov 9 at 21:40
Cody Moniz
1,91521215
[2, 6, 8, 1, 10, 11].sort((a, b) => b - a).slice(0,5)
[11, 10, 8, 6, 2]
answered Nov 9 at 21:40
Cody Moniz
1,91521215
answered Nov 9 at 21:40
Cody Moniz
1,91521215
answered Nov 9 at 21:40
Cody Moniz
1,91521215
answered Nov 9 at 21:40
Cody Moniz
1,91521215
1,91521215
add a comment |
add a comment |
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