ArrayList Item index is incorrect: Reversing a ArrayList with Recursion









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I'm working on a small problem to reverse a ArrayList of Characters using recusion. I've got it mostly figured out but am currently having some issues with retrieving a item by it's index.



My function is as follows:



 public static ArrayList<Character> reverseArray(ArrayList<Character> array)

if (array.size() == 1)
return array;


// Fetched the last item

ArrayList<Character> lastItem = new ArrayList<Character>();

System.out.println("Index: " + (array.size()-1));
System.out.println("Item at index: "+ (array.size()-1) + "is: " + array.get((array.size()-1)));
lastItem.add(array.get(array.size()-1));

// Remove the last item
array.remove(array.get(array.size()-1));

// Join all arrays until the last entry
lastItem.addAll(reverseArray(array));

return lastItem;




Running the below array list throught the function:



 ArrayList<Character> test1 = new ArrayList<Character>();
test1.add('a');
test1.add('b');
test1.add('c');
test1.add('a');
test1.add('b');
test1.add('c');


The output in the console appears to be: [c, c, b, b, a, a]



I added some console prints to see what was happening, at index 5 it appears to pull the item at index 2. So through to the end it removes index 5 then 2, then 3 then 1. Changing the input array to not have duplicate values makes the function work. It appears to be an issue of having multiples of the same character.



Any ideas to why this would be happening?










share|improve this question

























    up vote
    0
    down vote

    favorite












    I'm working on a small problem to reverse a ArrayList of Characters using recusion. I've got it mostly figured out but am currently having some issues with retrieving a item by it's index.



    My function is as follows:



     public static ArrayList<Character> reverseArray(ArrayList<Character> array)

    if (array.size() == 1)
    return array;


    // Fetched the last item

    ArrayList<Character> lastItem = new ArrayList<Character>();

    System.out.println("Index: " + (array.size()-1));
    System.out.println("Item at index: "+ (array.size()-1) + "is: " + array.get((array.size()-1)));
    lastItem.add(array.get(array.size()-1));

    // Remove the last item
    array.remove(array.get(array.size()-1));

    // Join all arrays until the last entry
    lastItem.addAll(reverseArray(array));

    return lastItem;




    Running the below array list throught the function:



     ArrayList<Character> test1 = new ArrayList<Character>();
    test1.add('a');
    test1.add('b');
    test1.add('c');
    test1.add('a');
    test1.add('b');
    test1.add('c');


    The output in the console appears to be: [c, c, b, b, a, a]



    I added some console prints to see what was happening, at index 5 it appears to pull the item at index 2. So through to the end it removes index 5 then 2, then 3 then 1. Changing the input array to not have duplicate values makes the function work. It appears to be an issue of having multiples of the same character.



    Any ideas to why this would be happening?










    share|improve this question























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I'm working on a small problem to reverse a ArrayList of Characters using recusion. I've got it mostly figured out but am currently having some issues with retrieving a item by it's index.



      My function is as follows:



       public static ArrayList<Character> reverseArray(ArrayList<Character> array)

      if (array.size() == 1)
      return array;


      // Fetched the last item

      ArrayList<Character> lastItem = new ArrayList<Character>();

      System.out.println("Index: " + (array.size()-1));
      System.out.println("Item at index: "+ (array.size()-1) + "is: " + array.get((array.size()-1)));
      lastItem.add(array.get(array.size()-1));

      // Remove the last item
      array.remove(array.get(array.size()-1));

      // Join all arrays until the last entry
      lastItem.addAll(reverseArray(array));

      return lastItem;




      Running the below array list throught the function:



       ArrayList<Character> test1 = new ArrayList<Character>();
      test1.add('a');
      test1.add('b');
      test1.add('c');
      test1.add('a');
      test1.add('b');
      test1.add('c');


      The output in the console appears to be: [c, c, b, b, a, a]



      I added some console prints to see what was happening, at index 5 it appears to pull the item at index 2. So through to the end it removes index 5 then 2, then 3 then 1. Changing the input array to not have duplicate values makes the function work. It appears to be an issue of having multiples of the same character.



      Any ideas to why this would be happening?










      share|improve this question













      I'm working on a small problem to reverse a ArrayList of Characters using recusion. I've got it mostly figured out but am currently having some issues with retrieving a item by it's index.



      My function is as follows:



       public static ArrayList<Character> reverseArray(ArrayList<Character> array)

      if (array.size() == 1)
      return array;


      // Fetched the last item

      ArrayList<Character> lastItem = new ArrayList<Character>();

      System.out.println("Index: " + (array.size()-1));
      System.out.println("Item at index: "+ (array.size()-1) + "is: " + array.get((array.size()-1)));
      lastItem.add(array.get(array.size()-1));

      // Remove the last item
      array.remove(array.get(array.size()-1));

      // Join all arrays until the last entry
      lastItem.addAll(reverseArray(array));

      return lastItem;




      Running the below array list throught the function:



       ArrayList<Character> test1 = new ArrayList<Character>();
      test1.add('a');
      test1.add('b');
      test1.add('c');
      test1.add('a');
      test1.add('b');
      test1.add('c');


      The output in the console appears to be: [c, c, b, b, a, a]



      I added some console prints to see what was happening, at index 5 it appears to pull the item at index 2. So through to the end it removes index 5 then 2, then 3 then 1. Changing the input array to not have duplicate values makes the function work. It appears to be an issue of having multiples of the same character.



      Any ideas to why this would be happening?







      java recursion






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      share|improve this question











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      share|improve this question










      asked Nov 10 at 4:27









      Benjamin Stark

      257




      257






















          2 Answers
          2






          active

          oldest

          votes

















          up vote
          1
          down vote



          accepted










          You are calling the overloaded version of remove that taken the element to be removed.



          When you remove c, the third element gets removed. So, on the next recursive call, the last element (c) remains.



          You need to remove the element by position



          array.remove(array.size() - 1);





          share|improve this answer




















          • Perfect! I didn't catch that. Thanks very much.
            – Benjamin Stark
            Nov 10 at 4:55

















          up vote
          0
          down vote













          I think you do it in wrong manner. You create too many useless temporary arrays. You just need just replace respective elements in ArrayList.



          public static void reverseArray(List<Character> arr, int pos) 
          if (arr.isEmpty())
          return;

          int index = arr.size() - pos - 1;

          if (pos >= index)
          return;

          char ch = arr.get(pos);
          arr.set(pos, arr.get(index));
          arr.set(index, ch);

          reverseArray(arr, ++pos);



          Client code:



          List<Character> arr = new ArrayList<>();
          arr.add('a');
          arr.add('b');
          arr.add('d');
          arr.add('e');

          reverseArray(arr, 0);





          share|improve this answer




















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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            1
            down vote



            accepted










            You are calling the overloaded version of remove that taken the element to be removed.



            When you remove c, the third element gets removed. So, on the next recursive call, the last element (c) remains.



            You need to remove the element by position



            array.remove(array.size() - 1);





            share|improve this answer




















            • Perfect! I didn't catch that. Thanks very much.
              – Benjamin Stark
              Nov 10 at 4:55














            up vote
            1
            down vote



            accepted










            You are calling the overloaded version of remove that taken the element to be removed.



            When you remove c, the third element gets removed. So, on the next recursive call, the last element (c) remains.



            You need to remove the element by position



            array.remove(array.size() - 1);





            share|improve this answer




















            • Perfect! I didn't catch that. Thanks very much.
              – Benjamin Stark
              Nov 10 at 4:55












            up vote
            1
            down vote



            accepted







            up vote
            1
            down vote



            accepted






            You are calling the overloaded version of remove that taken the element to be removed.



            When you remove c, the third element gets removed. So, on the next recursive call, the last element (c) remains.



            You need to remove the element by position



            array.remove(array.size() - 1);





            share|improve this answer












            You are calling the overloaded version of remove that taken the element to be removed.



            When you remove c, the third element gets removed. So, on the next recursive call, the last element (c) remains.



            You need to remove the element by position



            array.remove(array.size() - 1);






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 10 at 4:47









            user7

            8,73132038




            8,73132038











            • Perfect! I didn't catch that. Thanks very much.
              – Benjamin Stark
              Nov 10 at 4:55
















            • Perfect! I didn't catch that. Thanks very much.
              – Benjamin Stark
              Nov 10 at 4:55















            Perfect! I didn't catch that. Thanks very much.
            – Benjamin Stark
            Nov 10 at 4:55




            Perfect! I didn't catch that. Thanks very much.
            – Benjamin Stark
            Nov 10 at 4:55












            up vote
            0
            down vote













            I think you do it in wrong manner. You create too many useless temporary arrays. You just need just replace respective elements in ArrayList.



            public static void reverseArray(List<Character> arr, int pos) 
            if (arr.isEmpty())
            return;

            int index = arr.size() - pos - 1;

            if (pos >= index)
            return;

            char ch = arr.get(pos);
            arr.set(pos, arr.get(index));
            arr.set(index, ch);

            reverseArray(arr, ++pos);



            Client code:



            List<Character> arr = new ArrayList<>();
            arr.add('a');
            arr.add('b');
            arr.add('d');
            arr.add('e');

            reverseArray(arr, 0);





            share|improve this answer
























              up vote
              0
              down vote













              I think you do it in wrong manner. You create too many useless temporary arrays. You just need just replace respective elements in ArrayList.



              public static void reverseArray(List<Character> arr, int pos) 
              if (arr.isEmpty())
              return;

              int index = arr.size() - pos - 1;

              if (pos >= index)
              return;

              char ch = arr.get(pos);
              arr.set(pos, arr.get(index));
              arr.set(index, ch);

              reverseArray(arr, ++pos);



              Client code:



              List<Character> arr = new ArrayList<>();
              arr.add('a');
              arr.add('b');
              arr.add('d');
              arr.add('e');

              reverseArray(arr, 0);





              share|improve this answer






















                up vote
                0
                down vote










                up vote
                0
                down vote









                I think you do it in wrong manner. You create too many useless temporary arrays. You just need just replace respective elements in ArrayList.



                public static void reverseArray(List<Character> arr, int pos) 
                if (arr.isEmpty())
                return;

                int index = arr.size() - pos - 1;

                if (pos >= index)
                return;

                char ch = arr.get(pos);
                arr.set(pos, arr.get(index));
                arr.set(index, ch);

                reverseArray(arr, ++pos);



                Client code:



                List<Character> arr = new ArrayList<>();
                arr.add('a');
                arr.add('b');
                arr.add('d');
                arr.add('e');

                reverseArray(arr, 0);





                share|improve this answer












                I think you do it in wrong manner. You create too many useless temporary arrays. You just need just replace respective elements in ArrayList.



                public static void reverseArray(List<Character> arr, int pos) 
                if (arr.isEmpty())
                return;

                int index = arr.size() - pos - 1;

                if (pos >= index)
                return;

                char ch = arr.get(pos);
                arr.set(pos, arr.get(index));
                arr.set(index, ch);

                reverseArray(arr, ++pos);



                Client code:



                List<Character> arr = new ArrayList<>();
                arr.add('a');
                arr.add('b');
                arr.add('d');
                arr.add('e');

                reverseArray(arr, 0);






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 10 at 4:50









                oleg.cherednik

                4,5932916




                4,5932916



























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