BitVector library, changing value in splice of BitVector










0














I have the following code:



from BitVector import BitVector
import struct
import ipaddress

def run_marker_function(marker):
bv = BitVector(size=16) # 16 0s
m(bv, "27.246.2.177", "255.255.255.0")

def m(bv, R, R1):
# converts ipaddr strings to binary
bitForm = bin(int(ipaddress.IPv4Address(R)))[2:]
bitForm1 = bin(int(ipaddress.IPv4Address(R1)))[2:]
# R2 helper fn is the interleaved output of the 32 bit IP addresses in binary form (R2 is 64 bits)
R2 = Interleaved(bitForm, bitForm1)
# splits R2 into list of 8 items, each 8 bits
frags = [R2[i:i+8] for i in range(0, len(R2), 8)]
o = 3
f = frags[o]
# bv[0:3] = 000 initially, I increment by o
offset = bv[0:3].int_val() + o
bv[0:3] = BitVector(intVal=offset, size=3)
# bv[8:16] = 00000000 initially, I want to replace with the 8 bits of f - DOESN'T WORK
frag = bv[8:16].int_val() + int(f,2)
bv[8:16] = BitVector(intVal=frag, size=len(bv[8:16]))


and I get the following error:



 18 frag = bv[8:16].int_val() + int(f,2)
---> 19 bv[8:16] = BitVector(intVal=frag, size=len(bv[8:16]))

/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/BitVector/BitVector.py in __init__(self, *args, **kwargs)
else:
if size < len(bitlist):
raise ValueError('''The value specified for size must be at least as large as for the smallest bit vector possible for intVal''')

ValueError: The value specified for size must be at least as large as for the smallest bit vector possible for intVal


But I don't understand why as I'm putting in the actual length of that splice of the bv. Also, I'm doing the same methodology in



offset = bv[0:3].int_val() + o
bv[0:3] = BitVector(intVal=offset, size=3)


which doesn't throw an error



EDIT
A similar instance of the same bug:



dist = bv[3:8].int_val() + 1
bv[3:8] = BitVector(intVal=dist, size=1)


Gives the error



/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/BitVector/BitVector.py in __setitem__(self, pos, item)
if ( (pos.stop - pos.start) != len(item) ):
raise ValueError('incompatible lengths for slice assignment 7')
for i in range( pos.start, pos.stop ):
self[i] = item[ i - pos.start ]

ValueError: incompatible lengths for slice assignment 7









share|improve this question























  • The issue may be the value of frag, since it has to fit in the size, too. This is what the the error message is complaining about I think. Your example at the end with offset may work simply be its value is small enough to fit.
    – martineau
    Nov 11 at 7:26











  • @martineau thanks that fixed it! I thought solving that would solve another instance of the same issue, but it doesn't (I added in the edit). dist is 1 so how come size=1 throws an error?
    – user1045890
    Nov 11 at 7:37










  • @martineau sorry just added
    – user1045890
    Nov 11 at 7:39










  • A size of 1 means the value dist can only be 0 or 1. That looks doubtful...
    – martineau
    Nov 11 at 7:43










  • @martineau hm I'm not quite sure what's going on anymore, sometimes when i run my code I get no errors but sometimes I get the wrong size errors :/
    – user1045890
    Nov 11 at 7:49















0














I have the following code:



from BitVector import BitVector
import struct
import ipaddress

def run_marker_function(marker):
bv = BitVector(size=16) # 16 0s
m(bv, "27.246.2.177", "255.255.255.0")

def m(bv, R, R1):
# converts ipaddr strings to binary
bitForm = bin(int(ipaddress.IPv4Address(R)))[2:]
bitForm1 = bin(int(ipaddress.IPv4Address(R1)))[2:]
# R2 helper fn is the interleaved output of the 32 bit IP addresses in binary form (R2 is 64 bits)
R2 = Interleaved(bitForm, bitForm1)
# splits R2 into list of 8 items, each 8 bits
frags = [R2[i:i+8] for i in range(0, len(R2), 8)]
o = 3
f = frags[o]
# bv[0:3] = 000 initially, I increment by o
offset = bv[0:3].int_val() + o
bv[0:3] = BitVector(intVal=offset, size=3)
# bv[8:16] = 00000000 initially, I want to replace with the 8 bits of f - DOESN'T WORK
frag = bv[8:16].int_val() + int(f,2)
bv[8:16] = BitVector(intVal=frag, size=len(bv[8:16]))


and I get the following error:



 18 frag = bv[8:16].int_val() + int(f,2)
---> 19 bv[8:16] = BitVector(intVal=frag, size=len(bv[8:16]))

/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/BitVector/BitVector.py in __init__(self, *args, **kwargs)
else:
if size < len(bitlist):
raise ValueError('''The value specified for size must be at least as large as for the smallest bit vector possible for intVal''')

ValueError: The value specified for size must be at least as large as for the smallest bit vector possible for intVal


But I don't understand why as I'm putting in the actual length of that splice of the bv. Also, I'm doing the same methodology in



offset = bv[0:3].int_val() + o
bv[0:3] = BitVector(intVal=offset, size=3)


which doesn't throw an error



EDIT
A similar instance of the same bug:



dist = bv[3:8].int_val() + 1
bv[3:8] = BitVector(intVal=dist, size=1)


Gives the error



/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/BitVector/BitVector.py in __setitem__(self, pos, item)
if ( (pos.stop - pos.start) != len(item) ):
raise ValueError('incompatible lengths for slice assignment 7')
for i in range( pos.start, pos.stop ):
self[i] = item[ i - pos.start ]

ValueError: incompatible lengths for slice assignment 7









share|improve this question























  • The issue may be the value of frag, since it has to fit in the size, too. This is what the the error message is complaining about I think. Your example at the end with offset may work simply be its value is small enough to fit.
    – martineau
    Nov 11 at 7:26











  • @martineau thanks that fixed it! I thought solving that would solve another instance of the same issue, but it doesn't (I added in the edit). dist is 1 so how come size=1 throws an error?
    – user1045890
    Nov 11 at 7:37










  • @martineau sorry just added
    – user1045890
    Nov 11 at 7:39










  • A size of 1 means the value dist can only be 0 or 1. That looks doubtful...
    – martineau
    Nov 11 at 7:43










  • @martineau hm I'm not quite sure what's going on anymore, sometimes when i run my code I get no errors but sometimes I get the wrong size errors :/
    – user1045890
    Nov 11 at 7:49













0












0








0







I have the following code:



from BitVector import BitVector
import struct
import ipaddress

def run_marker_function(marker):
bv = BitVector(size=16) # 16 0s
m(bv, "27.246.2.177", "255.255.255.0")

def m(bv, R, R1):
# converts ipaddr strings to binary
bitForm = bin(int(ipaddress.IPv4Address(R)))[2:]
bitForm1 = bin(int(ipaddress.IPv4Address(R1)))[2:]
# R2 helper fn is the interleaved output of the 32 bit IP addresses in binary form (R2 is 64 bits)
R2 = Interleaved(bitForm, bitForm1)
# splits R2 into list of 8 items, each 8 bits
frags = [R2[i:i+8] for i in range(0, len(R2), 8)]
o = 3
f = frags[o]
# bv[0:3] = 000 initially, I increment by o
offset = bv[0:3].int_val() + o
bv[0:3] = BitVector(intVal=offset, size=3)
# bv[8:16] = 00000000 initially, I want to replace with the 8 bits of f - DOESN'T WORK
frag = bv[8:16].int_val() + int(f,2)
bv[8:16] = BitVector(intVal=frag, size=len(bv[8:16]))


and I get the following error:



 18 frag = bv[8:16].int_val() + int(f,2)
---> 19 bv[8:16] = BitVector(intVal=frag, size=len(bv[8:16]))

/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/BitVector/BitVector.py in __init__(self, *args, **kwargs)
else:
if size < len(bitlist):
raise ValueError('''The value specified for size must be at least as large as for the smallest bit vector possible for intVal''')

ValueError: The value specified for size must be at least as large as for the smallest bit vector possible for intVal


But I don't understand why as I'm putting in the actual length of that splice of the bv. Also, I'm doing the same methodology in



offset = bv[0:3].int_val() + o
bv[0:3] = BitVector(intVal=offset, size=3)


which doesn't throw an error



EDIT
A similar instance of the same bug:



dist = bv[3:8].int_val() + 1
bv[3:8] = BitVector(intVal=dist, size=1)


Gives the error



/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/BitVector/BitVector.py in __setitem__(self, pos, item)
if ( (pos.stop - pos.start) != len(item) ):
raise ValueError('incompatible lengths for slice assignment 7')
for i in range( pos.start, pos.stop ):
self[i] = item[ i - pos.start ]

ValueError: incompatible lengths for slice assignment 7









share|improve this question















I have the following code:



from BitVector import BitVector
import struct
import ipaddress

def run_marker_function(marker):
bv = BitVector(size=16) # 16 0s
m(bv, "27.246.2.177", "255.255.255.0")

def m(bv, R, R1):
# converts ipaddr strings to binary
bitForm = bin(int(ipaddress.IPv4Address(R)))[2:]
bitForm1 = bin(int(ipaddress.IPv4Address(R1)))[2:]
# R2 helper fn is the interleaved output of the 32 bit IP addresses in binary form (R2 is 64 bits)
R2 = Interleaved(bitForm, bitForm1)
# splits R2 into list of 8 items, each 8 bits
frags = [R2[i:i+8] for i in range(0, len(R2), 8)]
o = 3
f = frags[o]
# bv[0:3] = 000 initially, I increment by o
offset = bv[0:3].int_val() + o
bv[0:3] = BitVector(intVal=offset, size=3)
# bv[8:16] = 00000000 initially, I want to replace with the 8 bits of f - DOESN'T WORK
frag = bv[8:16].int_val() + int(f,2)
bv[8:16] = BitVector(intVal=frag, size=len(bv[8:16]))


and I get the following error:



 18 frag = bv[8:16].int_val() + int(f,2)
---> 19 bv[8:16] = BitVector(intVal=frag, size=len(bv[8:16]))

/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/BitVector/BitVector.py in __init__(self, *args, **kwargs)
else:
if size < len(bitlist):
raise ValueError('''The value specified for size must be at least as large as for the smallest bit vector possible for intVal''')

ValueError: The value specified for size must be at least as large as for the smallest bit vector possible for intVal


But I don't understand why as I'm putting in the actual length of that splice of the bv. Also, I'm doing the same methodology in



offset = bv[0:3].int_val() + o
bv[0:3] = BitVector(intVal=offset, size=3)


which doesn't throw an error



EDIT
A similar instance of the same bug:



dist = bv[3:8].int_val() + 1
bv[3:8] = BitVector(intVal=dist, size=1)


Gives the error



/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/BitVector/BitVector.py in __setitem__(self, pos, item)
if ( (pos.stop - pos.start) != len(item) ):
raise ValueError('incompatible lengths for slice assignment 7')
for i in range( pos.start, pos.stop ):
self[i] = item[ i - pos.start ]

ValueError: incompatible lengths for slice assignment 7






python python-3.x bitvector






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 11 at 7:46









martineau

65.5k988177




65.5k988177










asked Nov 11 at 5:27









user1045890

996




996











  • The issue may be the value of frag, since it has to fit in the size, too. This is what the the error message is complaining about I think. Your example at the end with offset may work simply be its value is small enough to fit.
    – martineau
    Nov 11 at 7:26











  • @martineau thanks that fixed it! I thought solving that would solve another instance of the same issue, but it doesn't (I added in the edit). dist is 1 so how come size=1 throws an error?
    – user1045890
    Nov 11 at 7:37










  • @martineau sorry just added
    – user1045890
    Nov 11 at 7:39










  • A size of 1 means the value dist can only be 0 or 1. That looks doubtful...
    – martineau
    Nov 11 at 7:43










  • @martineau hm I'm not quite sure what's going on anymore, sometimes when i run my code I get no errors but sometimes I get the wrong size errors :/
    – user1045890
    Nov 11 at 7:49
















  • The issue may be the value of frag, since it has to fit in the size, too. This is what the the error message is complaining about I think. Your example at the end with offset may work simply be its value is small enough to fit.
    – martineau
    Nov 11 at 7:26











  • @martineau thanks that fixed it! I thought solving that would solve another instance of the same issue, but it doesn't (I added in the edit). dist is 1 so how come size=1 throws an error?
    – user1045890
    Nov 11 at 7:37










  • @martineau sorry just added
    – user1045890
    Nov 11 at 7:39










  • A size of 1 means the value dist can only be 0 or 1. That looks doubtful...
    – martineau
    Nov 11 at 7:43










  • @martineau hm I'm not quite sure what's going on anymore, sometimes when i run my code I get no errors but sometimes I get the wrong size errors :/
    – user1045890
    Nov 11 at 7:49















The issue may be the value of frag, since it has to fit in the size, too. This is what the the error message is complaining about I think. Your example at the end with offset may work simply be its value is small enough to fit.
– martineau
Nov 11 at 7:26





The issue may be the value of frag, since it has to fit in the size, too. This is what the the error message is complaining about I think. Your example at the end with offset may work simply be its value is small enough to fit.
– martineau
Nov 11 at 7:26













@martineau thanks that fixed it! I thought solving that would solve another instance of the same issue, but it doesn't (I added in the edit). dist is 1 so how come size=1 throws an error?
– user1045890
Nov 11 at 7:37




@martineau thanks that fixed it! I thought solving that would solve another instance of the same issue, but it doesn't (I added in the edit). dist is 1 so how come size=1 throws an error?
– user1045890
Nov 11 at 7:37












@martineau sorry just added
– user1045890
Nov 11 at 7:39




@martineau sorry just added
– user1045890
Nov 11 at 7:39












A size of 1 means the value dist can only be 0 or 1. That looks doubtful...
– martineau
Nov 11 at 7:43




A size of 1 means the value dist can only be 0 or 1. That looks doubtful...
– martineau
Nov 11 at 7:43












@martineau hm I'm not quite sure what's going on anymore, sometimes when i run my code I get no errors but sometimes I get the wrong size errors :/
– user1045890
Nov 11 at 7:49




@martineau hm I'm not quite sure what's going on anymore, sometimes when i run my code I get no errors but sometimes I get the wrong size errors :/
– user1045890
Nov 11 at 7:49

















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