How can i call my mock method two times with two different argument value









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Suppose I have to test the mock method GetSegment with exclusive value 0 and 1(two times).



EXPECT_CALL(*mock.get(), GetSegment(refrenceId, _, _, _)).
WillOnce(DoAll(SetArgReferee<1>(numSegment), SetArgPointee<2>(points), SetArgPointee<3>(**exclusive**)));


Thanks,










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    up vote
    1
    down vote

    favorite












    Suppose I have to test the mock method GetSegment with exclusive value 0 and 1(two times).



    EXPECT_CALL(*mock.get(), GetSegment(refrenceId, _, _, _)).
    WillOnce(DoAll(SetArgReferee<1>(numSegment), SetArgPointee<2>(points), SetArgPointee<3>(**exclusive**)));


    Thanks,










    share|improve this question

























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      Suppose I have to test the mock method GetSegment with exclusive value 0 and 1(two times).



      EXPECT_CALL(*mock.get(), GetSegment(refrenceId, _, _, _)).
      WillOnce(DoAll(SetArgReferee<1>(numSegment), SetArgPointee<2>(points), SetArgPointee<3>(**exclusive**)));


      Thanks,










      share|improve this question















      Suppose I have to test the mock method GetSegment with exclusive value 0 and 1(two times).



      EXPECT_CALL(*mock.get(), GetSegment(refrenceId, _, _, _)).
      WillOnce(DoAll(SetArgReferee<1>(numSegment), SetArgPointee<2>(points), SetArgPointee<3>(**exclusive**)));


      Thanks,







      c++ googletest googlemock gmock






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      share|improve this question








      edited Nov 10 at 11:08









      ACupOfBreadTea

      215




      215










      asked Nov 10 at 11:04









      Abhi

      83




      83






















          1 Answer
          1






          active

          oldest

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          up vote
          0
          down vote



          accepted










          Just do several WillOnce - one after another.



          Like:



          EXPECT_CALL(*mock.get(), GetSegment(refrenceId, _, _, _))
          .WillOnce(DoAll(SetArgReferee<1>(numSegment), SetArgPointee<2>(points), SetArgPointee<3>(0))).
          .WillOnce(DoAll(SetArgReferee<1>(numSegment), SetArgPointee<2>(points), SetArgPointee<3>(1)));


          You can read in doc that WillOnce can be used several times in one EXPECT_CALL:




          EXPECT_CALL(mock_object, method(matchers))
          .WillOnce(action) *




          The simplified example that works:



          class MockMM

          public:
          MOCK_METHOD4(GetSegment, void(int refrenceId, int, int, int* a));
          ;

          TEST(A, A)

          MockMM mock;
          EXPECT_CALL(mock, GetSegment(1, _, _, _))
          .WillOnce(SetArgPointee<3>(0))
          .WillOnce(SetArgPointee<3>(1));

          int a;
          int b;
          mock.GetSegment(1, 1, 0, &a);
          mock.GetSegment(1, 0, 1, &b);
          ASSERT_EQ(0, a);
          ASSERT_EQ(1, b);




          You might also use sequences:




          When you have a long chain of sequential expectations, it's easier to
          specify the order using sequences, which don't require you to given
          each expectation in the chain a different name. All expected calls in
          the same sequence must occur in the order they are specified.




          using ::testing::Sequence;
          Sequence s1, s2;
          ...
          EXPECT_CALL(foo, Reset())
          .InSequence(s1, s2)
          .WillOnce(Return(true));
          EXPECT_CALL(foo, GetSize())
          .InSequence(s1)
          .WillOnce(Return(1));
          EXPECT_CALL(foo, Describe(A<const char*>()))
          .InSequence(s2)
          .WillOnce(Return("dummy"));





          share|improve this answer




















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            1 Answer
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            active

            oldest

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            1 Answer
            1






            active

            oldest

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            active

            oldest

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            active

            oldest

            votes








            up vote
            0
            down vote



            accepted










            Just do several WillOnce - one after another.



            Like:



            EXPECT_CALL(*mock.get(), GetSegment(refrenceId, _, _, _))
            .WillOnce(DoAll(SetArgReferee<1>(numSegment), SetArgPointee<2>(points), SetArgPointee<3>(0))).
            .WillOnce(DoAll(SetArgReferee<1>(numSegment), SetArgPointee<2>(points), SetArgPointee<3>(1)));


            You can read in doc that WillOnce can be used several times in one EXPECT_CALL:




            EXPECT_CALL(mock_object, method(matchers))
            .WillOnce(action) *




            The simplified example that works:



            class MockMM

            public:
            MOCK_METHOD4(GetSegment, void(int refrenceId, int, int, int* a));
            ;

            TEST(A, A)

            MockMM mock;
            EXPECT_CALL(mock, GetSegment(1, _, _, _))
            .WillOnce(SetArgPointee<3>(0))
            .WillOnce(SetArgPointee<3>(1));

            int a;
            int b;
            mock.GetSegment(1, 1, 0, &a);
            mock.GetSegment(1, 0, 1, &b);
            ASSERT_EQ(0, a);
            ASSERT_EQ(1, b);




            You might also use sequences:




            When you have a long chain of sequential expectations, it's easier to
            specify the order using sequences, which don't require you to given
            each expectation in the chain a different name. All expected calls in
            the same sequence must occur in the order they are specified.




            using ::testing::Sequence;
            Sequence s1, s2;
            ...
            EXPECT_CALL(foo, Reset())
            .InSequence(s1, s2)
            .WillOnce(Return(true));
            EXPECT_CALL(foo, GetSize())
            .InSequence(s1)
            .WillOnce(Return(1));
            EXPECT_CALL(foo, Describe(A<const char*>()))
            .InSequence(s2)
            .WillOnce(Return("dummy"));





            share|improve this answer
























              up vote
              0
              down vote



              accepted










              Just do several WillOnce - one after another.



              Like:



              EXPECT_CALL(*mock.get(), GetSegment(refrenceId, _, _, _))
              .WillOnce(DoAll(SetArgReferee<1>(numSegment), SetArgPointee<2>(points), SetArgPointee<3>(0))).
              .WillOnce(DoAll(SetArgReferee<1>(numSegment), SetArgPointee<2>(points), SetArgPointee<3>(1)));


              You can read in doc that WillOnce can be used several times in one EXPECT_CALL:




              EXPECT_CALL(mock_object, method(matchers))
              .WillOnce(action) *




              The simplified example that works:



              class MockMM

              public:
              MOCK_METHOD4(GetSegment, void(int refrenceId, int, int, int* a));
              ;

              TEST(A, A)

              MockMM mock;
              EXPECT_CALL(mock, GetSegment(1, _, _, _))
              .WillOnce(SetArgPointee<3>(0))
              .WillOnce(SetArgPointee<3>(1));

              int a;
              int b;
              mock.GetSegment(1, 1, 0, &a);
              mock.GetSegment(1, 0, 1, &b);
              ASSERT_EQ(0, a);
              ASSERT_EQ(1, b);




              You might also use sequences:




              When you have a long chain of sequential expectations, it's easier to
              specify the order using sequences, which don't require you to given
              each expectation in the chain a different name. All expected calls in
              the same sequence must occur in the order they are specified.




              using ::testing::Sequence;
              Sequence s1, s2;
              ...
              EXPECT_CALL(foo, Reset())
              .InSequence(s1, s2)
              .WillOnce(Return(true));
              EXPECT_CALL(foo, GetSize())
              .InSequence(s1)
              .WillOnce(Return(1));
              EXPECT_CALL(foo, Describe(A<const char*>()))
              .InSequence(s2)
              .WillOnce(Return("dummy"));





              share|improve this answer






















                up vote
                0
                down vote



                accepted







                up vote
                0
                down vote



                accepted






                Just do several WillOnce - one after another.



                Like:



                EXPECT_CALL(*mock.get(), GetSegment(refrenceId, _, _, _))
                .WillOnce(DoAll(SetArgReferee<1>(numSegment), SetArgPointee<2>(points), SetArgPointee<3>(0))).
                .WillOnce(DoAll(SetArgReferee<1>(numSegment), SetArgPointee<2>(points), SetArgPointee<3>(1)));


                You can read in doc that WillOnce can be used several times in one EXPECT_CALL:




                EXPECT_CALL(mock_object, method(matchers))
                .WillOnce(action) *




                The simplified example that works:



                class MockMM

                public:
                MOCK_METHOD4(GetSegment, void(int refrenceId, int, int, int* a));
                ;

                TEST(A, A)

                MockMM mock;
                EXPECT_CALL(mock, GetSegment(1, _, _, _))
                .WillOnce(SetArgPointee<3>(0))
                .WillOnce(SetArgPointee<3>(1));

                int a;
                int b;
                mock.GetSegment(1, 1, 0, &a);
                mock.GetSegment(1, 0, 1, &b);
                ASSERT_EQ(0, a);
                ASSERT_EQ(1, b);




                You might also use sequences:




                When you have a long chain of sequential expectations, it's easier to
                specify the order using sequences, which don't require you to given
                each expectation in the chain a different name. All expected calls in
                the same sequence must occur in the order they are specified.




                using ::testing::Sequence;
                Sequence s1, s2;
                ...
                EXPECT_CALL(foo, Reset())
                .InSequence(s1, s2)
                .WillOnce(Return(true));
                EXPECT_CALL(foo, GetSize())
                .InSequence(s1)
                .WillOnce(Return(1));
                EXPECT_CALL(foo, Describe(A<const char*>()))
                .InSequence(s2)
                .WillOnce(Return("dummy"));





                share|improve this answer












                Just do several WillOnce - one after another.



                Like:



                EXPECT_CALL(*mock.get(), GetSegment(refrenceId, _, _, _))
                .WillOnce(DoAll(SetArgReferee<1>(numSegment), SetArgPointee<2>(points), SetArgPointee<3>(0))).
                .WillOnce(DoAll(SetArgReferee<1>(numSegment), SetArgPointee<2>(points), SetArgPointee<3>(1)));


                You can read in doc that WillOnce can be used several times in one EXPECT_CALL:




                EXPECT_CALL(mock_object, method(matchers))
                .WillOnce(action) *




                The simplified example that works:



                class MockMM

                public:
                MOCK_METHOD4(GetSegment, void(int refrenceId, int, int, int* a));
                ;

                TEST(A, A)

                MockMM mock;
                EXPECT_CALL(mock, GetSegment(1, _, _, _))
                .WillOnce(SetArgPointee<3>(0))
                .WillOnce(SetArgPointee<3>(1));

                int a;
                int b;
                mock.GetSegment(1, 1, 0, &a);
                mock.GetSegment(1, 0, 1, &b);
                ASSERT_EQ(0, a);
                ASSERT_EQ(1, b);




                You might also use sequences:




                When you have a long chain of sequential expectations, it's easier to
                specify the order using sequences, which don't require you to given
                each expectation in the chain a different name. All expected calls in
                the same sequence must occur in the order they are specified.




                using ::testing::Sequence;
                Sequence s1, s2;
                ...
                EXPECT_CALL(foo, Reset())
                .InSequence(s1, s2)
                .WillOnce(Return(true));
                EXPECT_CALL(foo, GetSize())
                .InSequence(s1)
                .WillOnce(Return(1));
                EXPECT_CALL(foo, Describe(A<const char*>()))
                .InSequence(s2)
                .WillOnce(Return("dummy"));






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 14 at 11:38









                PiotrNycz

                15.5k53780




                15.5k53780



























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