Pfthb

I have the following string:

"(rating 1-10, details): 9 is my score"

I want to extract all numbers into a list that occur after :. The desired output is [9]

Assumptions

-Only one colon in expression

-0 or more values after the colon

-text before the colon may or may not contain numbers

-characters between colon and numbers may or may not be just spaces

I tried using this REGEX expression in Python:

':*(d+)'

My logic here is that the program should find the colon and then find digits an undetermined number of characters later. I am not sure how to handle the number of characters between the colon and the number, which varies. How do I do this?

You can use this regex and find all numbers, that appear after colon in your string.

d+(?!.*:)

Explanation:

• 
  d+ --> Matches one or more digits


• 
  (?!.*:) --> Negative look aheads to ensures colon does not appear ahead of numbers where we are not interested to capture

Demo

Here is a sample python code,

import re
s = '(rating 1-10, 56 details): 9 is my 22 jj 45 score'
numbers = re.findall('d+(?!.*:)', s)
print(numbers)

This prints following output,

['9', '22', '45']

And does not capture 1, 10 and 56 as they occur before colon.