Trying to replace special character in dataframe column
I have a dataframe column that looks like this:
and i'm trying to replace the '-' sign with ''. However if I try:
df_1['x'] = df_1['x'].replace('-', '')
df_1['x'].head()
I get the same data
and if I try this
df_1['x'] = str(df_1['x]).replace('-', '')
my data gets all muddied.
can someone explain what I'm doing wrong here?
python string pandas
edited Nov 12 '18 at 21:45
dustinos3
4491617
asked Nov 12 '18 at 20:11
bullybear17bullybear17
69111
add a comment |
I have a dataframe column that looks like this:
and i'm trying to replace the '-' sign with ''. However if I try:
df_1['x'] = df_1['x'].replace('-', '')
df_1['x'].head()
I get the same data
and if I try this
df_1['x'] = str(df_1['x]).replace('-', '')
my data gets all muddied.
can someone explain what I'm doing wrong here?
python string pandas
edited Nov 12 '18 at 21:45
dustinos3
4491617
asked Nov 12 '18 at 20:11
bullybear17bullybear17
69111
3
Looks like a minus, what if you usedf_1['x'].abs()instead?
– Willem Van Onsem
Nov 12 '18 at 20:13
your data type isn'tstr. The second command has missing'
– src
Nov 12 '18 at 20:14
add a comment |
I have a dataframe column that looks like this:
and i'm trying to replace the '-' sign with ''. However if I try:
df_1['x'] = df_1['x'].replace('-', '')
df_1['x'].head()
I get the same data
and if I try this
df_1['x'] = str(df_1['x]).replace('-', '')
my data gets all muddied.
can someone explain what I'm doing wrong here?
python string pandas
edited Nov 12 '18 at 21:45
dustinos3
4491617
asked Nov 12 '18 at 20:11
bullybear17bullybear17
69111
I have a dataframe column that looks like this:
and i'm trying to replace the '-' sign with ''. However if I try:
df_1['x'] = df_1['x'].replace('-', '')
df_1['x'].head()
I get the same data
and if I try this
df_1['x'] = str(df_1['x]).replace('-', '')
my data gets all muddied.
can someone explain what I'm doing wrong here?
python string pandas
python string pandas
edited Nov 12 '18 at 21:45
dustinos3
4491617
asked Nov 12 '18 at 20:11
bullybear17bullybear17
69111
edited Nov 12 '18 at 21:45
dustinos3
4491617
asked Nov 12 '18 at 20:11
bullybear17bullybear17
69111
edited Nov 12 '18 at 21:45
dustinos3
4491617
edited Nov 12 '18 at 21:45
dustinos3
4491617
edited Nov 12 '18 at 21:45
dustinos3
4491617
4491617
asked Nov 12 '18 at 20:11
bullybear17bullybear17
69111
asked Nov 12 '18 at 20:11
bullybear17bullybear17
69111
asked Nov 12 '18 at 20:11
bullybear17bullybear17
69111
69111
3
Looks like a minus, what if you usedf_1['x'].abs()instead?
– Willem Van Onsem
Nov 12 '18 at 20:13
your data type isn'tstr. The second command has missing'
– src
Nov 12 '18 at 20:14
add a comment |
3
Looks like a minus, what if you usedf_1['x'].abs()instead?
– Willem Van Onsem
Nov 12 '18 at 20:13
your data type isn'tstr. The second command has missing'
– src
Nov 12 '18 at 20:14
3
3
Looks like a minus, what if you use
df_1['x'].abs() instead?– Willem Van Onsem
Nov 12 '18 at 20:13
Looks like a minus, what if you use
df_1['x'].abs() instead?– Willem Van Onsem
Nov 12 '18 at 20:13
your data type isn't
str. The second command has missing '– src
Nov 12 '18 at 20:14
your data type isn't
str. The second command has missing '– src
Nov 12 '18 at 20:14
add a comment |
1 Answer
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and i'm trying to replace the '-' sign with ''
These are (likely) not strings but numbers, the - means it is a negative number. Given that these are negative numbers, it perhaps is not a good idea to remove the minus, since -5 of course is something different than 5.
In case you want to map negative numbers on their positive counterpart, you can use pandas.DataFrame.abs(..) [pandas-doc] for that, to calculate the absolute value:
df_1['x'] = df_1['x'].abs()answered Nov 12 '18 at 20:20
Willem Van OnsemWillem Van Onsem
146k16141230
add a comment |
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1 Answer
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active
oldest
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votes
and i'm trying to replace the '-' sign with ''
These are (likely) not strings but numbers, the - means it is a negative number. Given that these are negative numbers, it perhaps is not a good idea to remove the minus, since -5 of course is something different than 5.
In case you want to map negative numbers on their positive counterpart, you can use pandas.DataFrame.abs(..) [pandas-doc] for that, to calculate the absolute value:
df_1['x'] = df_1['x'].abs()answered Nov 12 '18 at 20:20
Willem Van OnsemWillem Van Onsem
146k16141230
add a comment |
and i'm trying to replace the '-' sign with ''
These are (likely) not strings but numbers, the - means it is a negative number. Given that these are negative numbers, it perhaps is not a good idea to remove the minus, since -5 of course is something different than 5.
In case you want to map negative numbers on their positive counterpart, you can use pandas.DataFrame.abs(..) [pandas-doc] for that, to calculate the absolute value:
df_1['x'] = df_1['x'].abs()answered Nov 12 '18 at 20:20
Willem Van OnsemWillem Van Onsem
146k16141230
add a comment |
and i'm trying to replace the '-' sign with ''
These are (likely) not strings but numbers, the - means it is a negative number. Given that these are negative numbers, it perhaps is not a good idea to remove the minus, since -5 of course is something different than 5.
In case you want to map negative numbers on their positive counterpart, you can use pandas.DataFrame.abs(..) [pandas-doc] for that, to calculate the absolute value:
df_1['x'] = df_1['x'].abs()answered Nov 12 '18 at 20:20
Willem Van OnsemWillem Van Onsem
146k16141230
and i'm trying to replace the '-' sign with ''
These are (likely) not strings but numbers, the - means it is a negative number. Given that these are negative numbers, it perhaps is not a good idea to remove the minus, since -5 of course is something different than 5.
In case you want to map negative numbers on their positive counterpart, you can use pandas.DataFrame.abs(..) [pandas-doc] for that, to calculate the absolute value:
df_1['x'] = df_1['x'].abs()answered Nov 12 '18 at 20:20
Willem Van OnsemWillem Van Onsem
146k16141230
answered Nov 12 '18 at 20:20
Willem Van OnsemWillem Van Onsem
146k16141230
answered Nov 12 '18 at 20:20
Willem Van OnsemWillem Van Onsem
146k16141230
answered Nov 12 '18 at 20:20
Willem Van OnsemWillem Van Onsem
146k16141230
146k16141230
add a comment |
add a comment |
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3
Looks like a minus, what if you use
df_1['x'].abs()instead?– Willem Van Onsem
Nov 12 '18 at 20:13
your data type isn't
str. The second command has missing'– src
Nov 12 '18 at 20:14