Regex to match string containing two names in any order

120

I need logical AND in regex.

something like

jack AND james

agree with following strings

'hi jack here is james'

'hi james here is jack'

edited Dec 9 '10 at 2:48

codaddict

347k64438490

asked Dec 8 '10 at 16:13

Meloun

3,439114079

1

Possible duplicate: mulitple-words-in-any-order-using-regex

– Anderson Green
Jun 3 '13 at 4:44

add a comment |

120

I need logical AND in regex.

something like

jack AND james

agree with following strings

'hi jack here is james'

'hi james here is jack'

edited Dec 9 '10 at 2:48

codaddict

347k64438490

asked Dec 8 '10 at 16:13

Meloun

3,439114079

1

Possible duplicate: mulitple-words-in-any-order-using-regex

– Anderson Green
Jun 3 '13 at 4:44

add a comment |

120

I need logical AND in regex.

something like

jack AND james

agree with following strings

'hi jack here is james'

'hi james here is jack'

edited Dec 9 '10 at 2:48

codaddict

347k64438490

asked Dec 8 '10 at 16:13

Meloun

3,439114079

I need logical AND in regex.

something like

jack AND james

agree with following strings

'hi jack here is james'

'hi james here is jack'

regex string

edited Dec 9 '10 at 2:48

codaddict

347k64438490

asked Dec 8 '10 at 16:13

Meloun

3,439114079

edited Dec 9 '10 at 2:48

codaddict

347k64438490

asked Dec 8 '10 at 16:13

Meloun

3,439114079

edited Dec 9 '10 at 2:48

codaddict

347k64438490

edited Dec 9 '10 at 2:48

codaddict

347k64438490

edited Dec 9 '10 at 2:48

codaddict

347k64438490

asked Dec 8 '10 at 16:13

Meloun

3,439114079

asked Dec 8 '10 at 16:13

Meloun

3,439114079

asked Dec 8 '10 at 16:13

Meloun

3,439114079

1

Possible duplicate: mulitple-words-in-any-order-using-regex

– Anderson Green
Jun 3 '13 at 4:44

add a comment |

1

Possible duplicate: mulitple-words-in-any-order-using-regex

– Anderson Green
Jun 3 '13 at 4:44

Possible duplicate: mulitple-words-in-any-order-using-regex

– Anderson Green
Jun 3 '13 at 4:44

add a comment |

4 Answers
4

active

oldest

votes

199

You can do checks using lookarounds:

^(?=.*bjackb)(?=.*bjamesb).*$

Test it.

This approach has the advantage that you can easily specify multiple conditions.

^(?=.*bjackb)(?=.*bjamesb)(?=.*bjasonb)(?=.*bjulesb).*$

edited Jan 4 at 8:57

answered Dec 8 '10 at 16:17

Alin Purcaru

35.5k116385

7

Would somebody mind explaining in a bit more detail how this example works?

– bjmc
Jul 7 '14 at 21:37

1

vim syntax: ^(.*<jack>)@=(.*<james>@=).*$ or v^(.*<jack>)@=(.*<james>)@=.*$

– mykhal
Aug 26 '14 at 15:58

Does anyone know why this would break (in JavaScript at least) when I try to search for strings starting with '#'? ^(?=.*b#fridayb)(?=.*b#tgifb).*$ fails to match blah #tgif blah #friday blah but ^(?=.*bfridayb)(?=.*btgifb).*$ works fine.

– btleffler
Aug 24 '15 at 18:27

1

What does b means here?

– VarunAgw
Apr 26 '16 at 12:14

1

@VarunAgw Word boundary. regular-expressions.info/refwordboundaries.html

– Alin Purcaru
Apr 26 '16 at 14:22

|
show 5 more comments

Try:

james.*jack

If you want both at the same time, then or them:

james.*jack|jack.*james

answered Dec 8 '10 at 16:16

icyrock.com

22.4k34973

1

The accepted answer worked. this also worked perfectly for me. For searching code in visual studio 'find results'.

– Yogurt The Wise
May 25 '16 at 13:02

This one works for me and is much more concise & easy to understand than the accepted answer!

– Kumar Manish
Sep 26 '17 at 9:20

I needed a solution that only had two names to match, so this answer is more concise for that case. But the accepted answer becomes more concise beyond 2 since the number of "or"s increases factorially. For 3 names there would be 6 "or"s, 4 names would be 24 "or"s, etc.

– WileCau
Oct 24 '18 at 0:46

add a comment |

Explanation of command that i am going to write:-

. means any character, digit can come in place of .

* means zero or more occurrences of thing written just previous to it.

| means 'or'.

So,

james.*jack

would search james , then any number of character until jack comes.

Since you want either jack.*james or james.*jack

Hence Command:

jack.*james|james.*jack

edited Dec 27 '18 at 12:20

Aryeh Beitz

638816

answered Jun 2 '16 at 11:34

Shubham Sharma

1,078719

3

As a side note - you could also have edited @icyrock's answer (which is the same as yours, just 6 years earlier), your explanation is very useful on its own.

– WoJ
Jan 23 '18 at 14:24

1

Thank you for this answer, i however feel the need to point out that in VSCode search, your answer jack.*james | james.*jack will take the spaces between the '|' (or) symbol into consideration during the search. jack.*james|james.*jack works and doesnt look for the spaces

– jgritten
Jun 15 '18 at 17:29

add a comment |

You can do:

bjackb.*bjamesb|bjamesb.*bjackb

answered Dec 8 '10 at 16:16

codaddict

347k64438490

add a comment |

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4 Answers
4

active

oldest

votes

4 Answers
4

active

oldest

votes

199

You can do checks using lookarounds:

^(?=.*bjackb)(?=.*bjamesb).*$

Test it.

This approach has the advantage that you can easily specify multiple conditions.

^(?=.*bjackb)(?=.*bjamesb)(?=.*bjasonb)(?=.*bjulesb).*$

edited Jan 4 at 8:57

answered Dec 8 '10 at 16:17

Alin Purcaru

35.5k116385

7

Would somebody mind explaining in a bit more detail how this example works?

– bjmc
Jul 7 '14 at 21:37

1

vim syntax: ^(.*<jack>)@=(.*<james>@=).*$ or v^(.*<jack>)@=(.*<james>)@=.*$

– mykhal
Aug 26 '14 at 15:58

Does anyone know why this would break (in JavaScript at least) when I try to search for strings starting with '#'? ^(?=.*b#fridayb)(?=.*b#tgifb).*$ fails to match blah #tgif blah #friday blah but ^(?=.*bfridayb)(?=.*btgifb).*$ works fine.

– btleffler
Aug 24 '15 at 18:27

1

What does b means here?

– VarunAgw
Apr 26 '16 at 12:14

1

@VarunAgw Word boundary. regular-expressions.info/refwordboundaries.html

– Alin Purcaru
Apr 26 '16 at 14:22

|
show 5 more comments

199

You can do checks using lookarounds:

^(?=.*bjackb)(?=.*bjamesb).*$

Test it.

This approach has the advantage that you can easily specify multiple conditions.

^(?=.*bjackb)(?=.*bjamesb)(?=.*bjasonb)(?=.*bjulesb).*$

edited Jan 4 at 8:57

answered Dec 8 '10 at 16:17

Alin Purcaru

35.5k116385

7

Would somebody mind explaining in a bit more detail how this example works?

– bjmc
Jul 7 '14 at 21:37

1

vim syntax: ^(.*<jack>)@=(.*<james>@=).*$ or v^(.*<jack>)@=(.*<james>)@=.*$

– mykhal
Aug 26 '14 at 15:58

Does anyone know why this would break (in JavaScript at least) when I try to search for strings starting with '#'? ^(?=.*b#fridayb)(?=.*b#tgifb).*$ fails to match blah #tgif blah #friday blah but ^(?=.*bfridayb)(?=.*btgifb).*$ works fine.

– btleffler
Aug 24 '15 at 18:27

1

What does b means here?

– VarunAgw
Apr 26 '16 at 12:14

1

@VarunAgw Word boundary. regular-expressions.info/refwordboundaries.html

– Alin Purcaru
Apr 26 '16 at 14:22

|
show 5 more comments

199

You can do checks using lookarounds:

^(?=.*bjackb)(?=.*bjamesb).*$

Test it.

This approach has the advantage that you can easily specify multiple conditions.

^(?=.*bjackb)(?=.*bjamesb)(?=.*bjasonb)(?=.*bjulesb).*$

edited Jan 4 at 8:57

answered Dec 8 '10 at 16:17

Alin Purcaru

35.5k116385

You can do checks using lookarounds:

^(?=.*bjackb)(?=.*bjamesb).*$

Test it.

This approach has the advantage that you can easily specify multiple conditions.

^(?=.*bjackb)(?=.*bjamesb)(?=.*bjasonb)(?=.*bjulesb).*$

edited Jan 4 at 8:57

answered Dec 8 '10 at 16:17

Alin Purcaru

35.5k116385

edited Jan 4 at 8:57

answered Dec 8 '10 at 16:17

Alin Purcaru

35.5k116385

answered Dec 8 '10 at 16:17

Alin Purcaru

35.5k116385

answered Dec 8 '10 at 16:17

Alin Purcaru

35.5k116385

7

Would somebody mind explaining in a bit more detail how this example works?

– bjmc
Jul 7 '14 at 21:37

1

vim syntax: ^(.*<jack>)@=(.*<james>@=).*$ or v^(.*<jack>)@=(.*<james>)@=.*$

– mykhal
Aug 26 '14 at 15:58

Does anyone know why this would break (in JavaScript at least) when I try to search for strings starting with '#'? ^(?=.*b#fridayb)(?=.*b#tgifb).*$ fails to match blah #tgif blah #friday blah but ^(?=.*bfridayb)(?=.*btgifb).*$ works fine.

– btleffler
Aug 24 '15 at 18:27

1

What does b means here?

– VarunAgw
Apr 26 '16 at 12:14

1

@VarunAgw Word boundary. regular-expressions.info/refwordboundaries.html

– Alin Purcaru
Apr 26 '16 at 14:22

|
show 5 more comments

7

Would somebody mind explaining in a bit more detail how this example works?

– bjmc
Jul 7 '14 at 21:37

1

vim syntax: ^(.*<jack>)@=(.*<james>@=).*$ or v^(.*<jack>)@=(.*<james>)@=.*$

– mykhal
Aug 26 '14 at 15:58

Does anyone know why this would break (in JavaScript at least) when I try to search for strings starting with '#'? ^(?=.*b#fridayb)(?=.*b#tgifb).*$ fails to match blah #tgif blah #friday blah but ^(?=.*bfridayb)(?=.*btgifb).*$ works fine.

– btleffler
Aug 24 '15 at 18:27

1

What does b means here?

– VarunAgw
Apr 26 '16 at 12:14

1

@VarunAgw Word boundary. regular-expressions.info/refwordboundaries.html

– Alin Purcaru
Apr 26 '16 at 14:22

Would somebody mind explaining in a bit more detail how this example works?

– bjmc
Jul 7 '14 at 21:37

vim syntax: ^(.*<jack>)@=(.*<james>@=).*$ or v^(.*<jack>)@=(.*<james>)@=.*$

– mykhal
Aug 26 '14 at 15:58

Does anyone know why this would break (in JavaScript at least) when I try to search for strings starting with '#'? ^(?=.*b#fridayb)(?=.*b#tgifb).*$ fails to match blah #tgif blah #friday blah but ^(?=.*bfridayb)(?=.*btgifb).*$ works fine.

– btleffler
Aug 24 '15 at 18:27

What does b means here?

– VarunAgw
Apr 26 '16 at 12:14

@VarunAgw Word boundary. regular-expressions.info/refwordboundaries.html

– Alin Purcaru
Apr 26 '16 at 14:22

|
show 5 more comments

Try:

james.*jack

If you want both at the same time, then or them:

james.*jack|jack.*james

answered Dec 8 '10 at 16:16

icyrock.com

22.4k34973

1

The accepted answer worked. this also worked perfectly for me. For searching code in visual studio 'find results'.

– Yogurt The Wise
May 25 '16 at 13:02

This one works for me and is much more concise & easy to understand than the accepted answer!

– Kumar Manish
Sep 26 '17 at 9:20

I needed a solution that only had two names to match, so this answer is more concise for that case. But the accepted answer becomes more concise beyond 2 since the number of "or"s increases factorially. For 3 names there would be 6 "or"s, 4 names would be 24 "or"s, etc.

– WileCau
Oct 24 '18 at 0:46

add a comment |

Try:

james.*jack

If you want both at the same time, then or them:

james.*jack|jack.*james

answered Dec 8 '10 at 16:16

icyrock.com

22.4k34973

1

The accepted answer worked. this also worked perfectly for me. For searching code in visual studio 'find results'.

– Yogurt The Wise
May 25 '16 at 13:02

This one works for me and is much more concise & easy to understand than the accepted answer!

– Kumar Manish
Sep 26 '17 at 9:20

I needed a solution that only had two names to match, so this answer is more concise for that case. But the accepted answer becomes more concise beyond 2 since the number of "or"s increases factorially. For 3 names there would be 6 "or"s, 4 names would be 24 "or"s, etc.

– WileCau
Oct 24 '18 at 0:46

add a comment |

Try:

james.*jack

If you want both at the same time, then or them:

james.*jack|jack.*james

answered Dec 8 '10 at 16:16

icyrock.com

22.4k34973

Try:

james.*jack

If you want both at the same time, then or them:

james.*jack|jack.*james

answered Dec 8 '10 at 16:16

icyrock.com

22.4k34973

answered Dec 8 '10 at 16:16

icyrock.com

22.4k34973

answered Dec 8 '10 at 16:16

icyrock.com

22.4k34973

answered Dec 8 '10 at 16:16

icyrock.com

22.4k34973

1

The accepted answer worked. this also worked perfectly for me. For searching code in visual studio 'find results'.

– Yogurt The Wise
May 25 '16 at 13:02

This one works for me and is much more concise & easy to understand than the accepted answer!

– Kumar Manish
Sep 26 '17 at 9:20

I needed a solution that only had two names to match, so this answer is more concise for that case. But the accepted answer becomes more concise beyond 2 since the number of "or"s increases factorially. For 3 names there would be 6 "or"s, 4 names would be 24 "or"s, etc.

– WileCau
Oct 24 '18 at 0:46

add a comment |

1

The accepted answer worked. this also worked perfectly for me. For searching code in visual studio 'find results'.

– Yogurt The Wise
May 25 '16 at 13:02

This one works for me and is much more concise & easy to understand than the accepted answer!

– Kumar Manish
Sep 26 '17 at 9:20

I needed a solution that only had two names to match, so this answer is more concise for that case. But the accepted answer becomes more concise beyond 2 since the number of "or"s increases factorially. For 3 names there would be 6 "or"s, 4 names would be 24 "or"s, etc.

– WileCau
Oct 24 '18 at 0:46

The accepted answer worked. this also worked perfectly for me. For searching code in visual studio 'find results'.

– Yogurt The Wise
May 25 '16 at 13:02

This one works for me and is much more concise & easy to understand than the accepted answer!

– Kumar Manish
Sep 26 '17 at 9:20

I needed a solution that only had two names to match, so this answer is more concise for that case. But the accepted answer becomes more concise beyond 2 since the number of "or"s increases factorially. For 3 names there would be 6 "or"s, 4 names would be 24 "or"s, etc.

– WileCau
Oct 24 '18 at 0:46

add a comment |

Explanation of command that i am going to write:-

. means any character, digit can come in place of .

* means zero or more occurrences of thing written just previous to it.

| means 'or'.

So,

james.*jack

would search james , then any number of character until jack comes.

Since you want either jack.*james or james.*jack

Hence Command:

jack.*james|james.*jack

edited Dec 27 '18 at 12:20

Aryeh Beitz

638816

answered Jun 2 '16 at 11:34

Shubham Sharma

1,078719

3

As a side note - you could also have edited @icyrock's answer (which is the same as yours, just 6 years earlier), your explanation is very useful on its own.

– WoJ
Jan 23 '18 at 14:24

1

Thank you for this answer, i however feel the need to point out that in VSCode search, your answer jack.*james | james.*jack will take the spaces between the '|' (or) symbol into consideration during the search. jack.*james|james.*jack works and doesnt look for the spaces

– jgritten
Jun 15 '18 at 17:29

add a comment |

Explanation of command that i am going to write:-

. means any character, digit can come in place of .

* means zero or more occurrences of thing written just previous to it.

| means 'or'.

So,

james.*jack

would search james , then any number of character until jack comes.

Since you want either jack.*james or james.*jack

Hence Command:

jack.*james|james.*jack

edited Dec 27 '18 at 12:20

Aryeh Beitz

638816

answered Jun 2 '16 at 11:34

Shubham Sharma

1,078719

3

As a side note - you could also have edited @icyrock's answer (which is the same as yours, just 6 years earlier), your explanation is very useful on its own.

– WoJ
Jan 23 '18 at 14:24

1

Thank you for this answer, i however feel the need to point out that in VSCode search, your answer jack.*james | james.*jack will take the spaces between the '|' (or) symbol into consideration during the search. jack.*james|james.*jack works and doesnt look for the spaces

– jgritten
Jun 15 '18 at 17:29

add a comment |

Explanation of command that i am going to write:-

. means any character, digit can come in place of .

* means zero or more occurrences of thing written just previous to it.

| means 'or'.

So,

james.*jack

would search james , then any number of character until jack comes.

Since you want either jack.*james or james.*jack

Hence Command:

jack.*james|james.*jack

edited Dec 27 '18 at 12:20

Aryeh Beitz

638816

answered Jun 2 '16 at 11:34

Shubham Sharma

1,078719

Explanation of command that i am going to write:-

. means any character, digit can come in place of .

* means zero or more occurrences of thing written just previous to it.

| means 'or'.

So,

james.*jack

would search james , then any number of character until jack comes.

Since you want either jack.*james or james.*jack

Hence Command:

jack.*james|james.*jack

edited Dec 27 '18 at 12:20

Aryeh Beitz

638816

answered Jun 2 '16 at 11:34

Shubham Sharma

1,078719

edited Dec 27 '18 at 12:20

Aryeh Beitz

638816

edited Dec 27 '18 at 12:20

Aryeh Beitz

638816

edited Dec 27 '18 at 12:20

Aryeh Beitz

638816

answered Jun 2 '16 at 11:34

Shubham Sharma

1,078719

answered Jun 2 '16 at 11:34

Shubham Sharma

1,078719

answered Jun 2 '16 at 11:34

Shubham Sharma

1,078719

3

As a side note - you could also have edited @icyrock's answer (which is the same as yours, just 6 years earlier), your explanation is very useful on its own.

– WoJ
Jan 23 '18 at 14:24

1

Thank you for this answer, i however feel the need to point out that in VSCode search, your answer jack.*james | james.*jack will take the spaces between the '|' (or) symbol into consideration during the search. jack.*james|james.*jack works and doesnt look for the spaces

– jgritten
Jun 15 '18 at 17:29

add a comment |

3

As a side note - you could also have edited @icyrock's answer (which is the same as yours, just 6 years earlier), your explanation is very useful on its own.

– WoJ
Jan 23 '18 at 14:24

1

Thank you for this answer, i however feel the need to point out that in VSCode search, your answer jack.*james | james.*jack will take the spaces between the '|' (or) symbol into consideration during the search. jack.*james|james.*jack works and doesnt look for the spaces

– jgritten
Jun 15 '18 at 17:29

As a side note - you could also have edited @icyrock's answer (which is the same as yours, just 6 years earlier), your explanation is very useful on its own.

– WoJ
Jan 23 '18 at 14:24

Thank you for this answer, i however feel the need to point out that in VSCode search, your answer jack.*james | james.*jack will take the spaces between the '|' (or) symbol into consideration during the search. jack.*james|james.*jack works and doesnt look for the spaces

– jgritten
Jun 15 '18 at 17:29

add a comment |

You can do:

bjackb.*bjamesb|bjamesb.*bjackb

answered Dec 8 '10 at 16:16

codaddict

347k64438490

add a comment |

You can do:

bjackb.*bjamesb|bjamesb.*bjackb

answered Dec 8 '10 at 16:16

codaddict

347k64438490

add a comment |

You can do:

bjackb.*bjamesb|bjamesb.*bjackb

answered Dec 8 '10 at 16:16

codaddict

347k64438490

You can do:

bjackb.*bjamesb|bjamesb.*bjackb

answered Dec 8 '10 at 16:16

codaddict

347k64438490

answered Dec 8 '10 at 16:16

codaddict

347k64438490

answered Dec 8 '10 at 16:16

codaddict

347k64438490

answered Dec 8 '10 at 16:16

codaddict

347k64438490

add a comment |

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