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How to modify the script highlighting the lines that contain keywords separated by multiple delimiters

I'm not a programmer, but I need to ease my work.
I found a little script that highlights the red lines containing obscene words. Then I manually copy and save the lines just in case.

However, I would like to automate this. I did not find anything similar on the Internet. Therefore, I tried to make a script with my own hands. Here is what I did:

 function extractText(str,delimiter)
 if (str && delimiter)
 var firstIndex = str.indexOf(delimiter)+1;
 var lastIndex = str.lastIndexOf(delimiter);
 str = str.substring(firstIndex,lastIndex);
 
 return str;
 
 
 const keywordsString = ""+
 "stopword|stopword1|stopword2";
 const keywords = keywordsString.split(/#/);
 
 
 const pattern = new RegExp(`($keywords.join('#'))`, 'g'); 
 
 const phrase = ""+
 "I like cake, pie and<br>cookies keyword keyword<br> stopword<br>";
 
 const result = phrase.replace(pattern, match => `<span style='background-color:red'>$match</span>`);
 
 setTimeout(function()
 document.getElementById('prep').innerHTML = result;
 
 if (result.indexOf("span") != -1)
 alert(extractText(result),'&#10');
 document.getElementById('prex').innerHTML = extractText(result,'<br>');
 alert("found");

 
 , 100);

<pre id="prep" contenteditable="true"></pre>
<pre id="prex" contenteditable="true"></pre>

I failed to replace br with n.
I can select text between words, but how to make the script get all the lines containing stop words.
Then I need to put them in another text block and delete them in the first block.

At first, I wanted the script to sort the lines broken by n containing swear words by the number of swear words, but it is very difficult, I even failed to select the text.
There you need to use something similar to the Levenshtein distance.

I need to at least find out how to get a set of lines of text that contain stop words separated by n. Then I can try to solve the rest of the problem itself.

 Input
 line of text with words without stopword(two or more)
 line of text with words and <span style='background-color:red'>stopwords</span>
 line of text with words without stopword
 line of text with words and <span style='background-color:red'>stopwords</span>...<span style='background-color:red'>stopwords</span>(two or more)
 line of text with words without stopword

 output1(Filther words)
 line of text with words without stopword(two or more)
 line of text with words without stopword
 line of text with words without stopword

 output2
 line of text with words and <span style='background-color:red'>stopwords</span>
 line of text with words and <span style='background-color:red'>stopwords</span>...<span style='background-color:red'>stopwords</span>(two or more)

I want to save all messages containing stop words to another tag. Leave only those that do not contain them.
I need for filher lines that contains stopword

Using the code bellow I take the lines from first blue text area, and separate them in red (bad) and green(good) text areas.

var myLines = $("#s").val().split("n");

const badWords = ["kaka", "saka", "baka"];
// here we use bKEYWORDb in order to keep whole words only
let myExp = new RegExp("(\b" + badWords.join("\b)|(\b") + "\b)", "g");

var goodLines = ;
var badLines = ;

for (let line of myLines) 
 if (line.match(myExp)) 
 badLines.push(line);
 else 
 goodLines.push(line);
 


$("#r1").val(goodLines.join("n"));
$("#r2").val(badLines.join("n"));

#s background: lightblue;
#r1 background: lightgreen;
#r2 background: red;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<textarea rows="7" id="s" >
line ok
line nok kaka
ok row
 baka this row
sakalento row
lento 'saka' badddd
</textarea>
<textarea rows="5" id="r1"></textarea>
<textarea rows="5" id="r2"></textarea>

In order to replace all occurrences of "<br>" to "n", you can do the following

myString.replace(new RegExp(myDelimiter, 'g'), toReplaceChar)

console example:

>'abc<br>1<br>2<br>3t<br>yyy'.replace(new RegExp("<br>", 'g'), "n")
"abc
1
2
3t
yyy"