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I am trying to create json with spring boot.

class:

public class Person 
 private String name;
 private PersonDetails details;

// getters and setters...

impletentation:

Person person = new Person();
person.setName("Apple");
person.setDetails(new PersonDetails());

So there is a instance of Person with empty details and this is exactly what Jackson is returning:

"person": 
 "name": "Apple",
 "details": 

I want to have json without empty brackets :

"person": 
 "name": "Apple"

This question's didn't helped me:

• How to tell Jackson to ignore empty object during deserialization?


• How to ignore "null" or empty properties in json, globally, using Spring configuration

Update 1:

I'm using Jackson 2.9.6

Without a custom serializer, jackson will include your object.

Solution 1 : Replace new object with null

person.setDetails(new PersonDetails());

with

person.setDetails(null);

and add

@JsonInclude(Include.NON_NULL)
public class Person {

Solution 2: Custom serializer

public class PersonDetailsSerializer extends StdSerializer<PersonDetails> 

 public PersonDetailsSerializer() 
 this(null);
 

 public PersonDetailsSerializer(Class<PersonDetails> t) 
 super(t);
 

 @Override
 public void serialize(
 PersonDetails personDetails, JsonGenerator jgen, SerializerProvider provider)
 throws IOException, JsonProcessingException 
 // custom behavior if you implement equals and hashCode in your code
 if(personDetails.equals(new PersonDetails())
 return;
 
 super.serialize(personDetails,jgen,provider);
 

and in your PersonDetails

public class Person 
 private String name;
 @JsonSerialize(using = PersonDetailsSerializer.class)
 private PersonDetails details;