How to identify component name from a object array
Currently I have the following
methodName = () =>
const
collectionOfComponents
...
...
= this.props;
return (
<Wrapper1>
collectionOfComponents.map((oneComponent, index) => (
<Wrapper2
..props
>
oneComponent.component
</Wrapper2>
)
</Wrapper1>
);
;
And for collectionOfComponents I am passing in the following
collectionOfComponents=[
<ComponentOne prop1... prop2... />,
<ComponentOne prop1... prop2... />,
<ComponentTwo prop1... prop2... />
]
Is there a way to identify when ComponentTwo has been passed through so that I can perform a different render. I'm not sure how to do this
EDIT
Sorry, should of made this clear, but i'm not looking to change the render method in the map i'm looking for a separate function to first check to see if componentTwo exists in the array at any time and then (maybe) use a tertiary to call one of two methods which will be two different return methods. I will then call the function in the render method
reactjs ecmascript-6 react-props
add a comment |
Currently I have the following
methodName = () =>
const
collectionOfComponents
...
...
= this.props;
return (
<Wrapper1>
collectionOfComponents.map((oneComponent, index) => (
<Wrapper2
..props
>
oneComponent.component
</Wrapper2>
)
</Wrapper1>
);
;
And for collectionOfComponents I am passing in the following
collectionOfComponents=[
<ComponentOne prop1... prop2... />,
<ComponentOne prop1... prop2... />,
<ComponentTwo prop1... prop2... />
]
Is there a way to identify when ComponentTwo has been passed through so that I can perform a different render. I'm not sure how to do this
EDIT
Sorry, should of made this clear, but i'm not looking to change the render method in the map i'm looking for a separate function to first check to see if componentTwo exists in the array at any time and then (maybe) use a tertiary to call one of two methods which will be two different return methods. I will then call the function in the render method
reactjs ecmascript-6 react-props
add a comment |
Currently I have the following
methodName = () =>
const
collectionOfComponents
...
...
= this.props;
return (
<Wrapper1>
collectionOfComponents.map((oneComponent, index) => (
<Wrapper2
..props
>
oneComponent.component
</Wrapper2>
)
</Wrapper1>
);
;
And for collectionOfComponents I am passing in the following
collectionOfComponents=[
<ComponentOne prop1... prop2... />,
<ComponentOne prop1... prop2... />,
<ComponentTwo prop1... prop2... />
]
Is there a way to identify when ComponentTwo has been passed through so that I can perform a different render. I'm not sure how to do this
EDIT
Sorry, should of made this clear, but i'm not looking to change the render method in the map i'm looking for a separate function to first check to see if componentTwo exists in the array at any time and then (maybe) use a tertiary to call one of two methods which will be two different return methods. I will then call the function in the render method
reactjs ecmascript-6 react-props
Currently I have the following
methodName = () =>
const
collectionOfComponents
...
...
= this.props;
return (
<Wrapper1>
collectionOfComponents.map((oneComponent, index) => (
<Wrapper2
..props
>
oneComponent.component
</Wrapper2>
)
</Wrapper1>
);
;
And for collectionOfComponents I am passing in the following
collectionOfComponents=[
<ComponentOne prop1... prop2... />,
<ComponentOne prop1... prop2... />,
<ComponentTwo prop1... prop2... />
]
Is there a way to identify when ComponentTwo has been passed through so that I can perform a different render. I'm not sure how to do this
EDIT
Sorry, should of made this clear, but i'm not looking to change the render method in the map i'm looking for a separate function to first check to see if componentTwo exists in the array at any time and then (maybe) use a tertiary to call one of two methods which will be two different return methods. I will then call the function in the render method
reactjs ecmascript-6 react-props
reactjs ecmascript-6 react-props
edited Nov 12 '18 at 21:54
zeduke
asked Nov 12 '18 at 21:07
zedukezeduke
8518
8518
add a comment |
add a comment |
4 Answers
4
active
oldest
votes
When you use a component, React creates an Element. Each element has a type property. The type is the class of function for component elements, or a string for DOM elements ('button').
To find the component that created the element, compare the type of the element to the Function of Class that created it:
const ComponentOne = () => 1;
const ComponentTwo = () => 2;
class ComponentThree extends React.Component
render()
return 3;
const Wrapper = ( children ) => (
<div>
React.Children.map(children, (El) =>
switch(El.type)
case ComponentOne:
return <div className="red">El</div>;
case ComponentTwo:
return <div className="blue">El</div>;
case ComponentThree:
return <div className="green">El</div>;
return null;
)
</div>
);
ReactDOM.render(
<Wrapper>
<ComponentOne />
<ComponentOne />
<ComponentTwo />
<ComponentThree />
</Wrapper>,
demo
);.red background: red;
.blue background: blue;
.green background: green; <script crossorigin src="https://unpkg.com/react@16/umd/react.development.js"></script>
<script crossorigin src="https://unpkg.com/react-dom@16/umd/react-dom.development.js"></script>
<div id="demo"></div>
or in the case of needing to compare against strings (for whatever reason)El.type.name.
– rlemon
Nov 12 '18 at 21:42
You should note that functions' and classes' names might change after minification.
– Ori Drori
Nov 12 '18 at 21:46
Is there a way to check if componentTwo exists in a separate function and then decide what to do? e.g. call one function if componentTwo exists, if not call another?
– zeduke
Nov 12 '18 at 21:57
Do whatever you want in the switch. I've returned the element, you call a function that will return something else.
– Ori Drori
Nov 12 '18 at 21:58
add a comment |
const isComponentTwo = collectionOfComponents.some(component => component.type.displayName.includes('ComponentTwo'));
The above will return true if at least one component in the collectionOfComponents is ComponentTwo.
This is not advisable however. Using displayName or type for production should never be used. This is because during, for example, minification the displayName and type will change, so the logic you are expecting will not occur in the way you are expecting.
The following states:
The displayName string is used in debugging messages. Usually, you don’t need to set it explicitly because it’s inferred from the name of the function or class that defines the component. You might want to set it explicitly if you want to display a different name for debugging purposes or when you create a higher-order component
A better solution would be to add some sort of flagProp to your component.
For example
decideWhatToDo = () =>
const flagPropName = this.props;
return flagPropName
? this.methodOne()
: this.methodTwo();
In the two methods you can then decide what you want to do if componentTwo exists or if it doesn't exist
add a comment |
Check in the array using indexOf:
collectionOfComponents.indexOf('ComponentTwo') !== -1 // found
Components will not be unique there could be 5ComponentOneand twoComponentTwoor there could be 7ComponentTwoand 1ComponentOne
– zeduke
Nov 12 '18 at 21:22
Anyways, you are just wondering if that component is found, right?
– Bhojendra Rauniyar
Nov 12 '18 at 21:24
correct if a certain component exists in the array
– zeduke
Nov 12 '18 at 21:25
Let me know if you have any query.
– Bhojendra Rauniyar
Nov 12 '18 at 21:25
add a comment |
Maybe you can use this way or simulary ??
<Wrapper1>
{collectionOfComponents.map((oneComponent, index) => (
<Wrapper2
..props
>
oneComponent.component instanceof ComponentTwo ? renderWasYouWant : otherRender
</Wrapper2>
)
</Wrapper1>
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
When you use a component, React creates an Element. Each element has a type property. The type is the class of function for component elements, or a string for DOM elements ('button').
To find the component that created the element, compare the type of the element to the Function of Class that created it:
const ComponentOne = () => 1;
const ComponentTwo = () => 2;
class ComponentThree extends React.Component
render()
return 3;
const Wrapper = ( children ) => (
<div>
React.Children.map(children, (El) =>
switch(El.type)
case ComponentOne:
return <div className="red">El</div>;
case ComponentTwo:
return <div className="blue">El</div>;
case ComponentThree:
return <div className="green">El</div>;
return null;
)
</div>
);
ReactDOM.render(
<Wrapper>
<ComponentOne />
<ComponentOne />
<ComponentTwo />
<ComponentThree />
</Wrapper>,
demo
);.red background: red;
.blue background: blue;
.green background: green; <script crossorigin src="https://unpkg.com/react@16/umd/react.development.js"></script>
<script crossorigin src="https://unpkg.com/react-dom@16/umd/react-dom.development.js"></script>
<div id="demo"></div>
or in the case of needing to compare against strings (for whatever reason)El.type.name.
– rlemon
Nov 12 '18 at 21:42
You should note that functions' and classes' names might change after minification.
– Ori Drori
Nov 12 '18 at 21:46
Is there a way to check if componentTwo exists in a separate function and then decide what to do? e.g. call one function if componentTwo exists, if not call another?
– zeduke
Nov 12 '18 at 21:57
Do whatever you want in the switch. I've returned the element, you call a function that will return something else.
– Ori Drori
Nov 12 '18 at 21:58
add a comment |
When you use a component, React creates an Element. Each element has a type property. The type is the class of function for component elements, or a string for DOM elements ('button').
To find the component that created the element, compare the type of the element to the Function of Class that created it:
const ComponentOne = () => 1;
const ComponentTwo = () => 2;
class ComponentThree extends React.Component
render()
return 3;
const Wrapper = ( children ) => (
<div>
React.Children.map(children, (El) =>
switch(El.type)
case ComponentOne:
return <div className="red">El</div>;
case ComponentTwo:
return <div className="blue">El</div>;
case ComponentThree:
return <div className="green">El</div>;
return null;
)
</div>
);
ReactDOM.render(
<Wrapper>
<ComponentOne />
<ComponentOne />
<ComponentTwo />
<ComponentThree />
</Wrapper>,
demo
);.red background: red;
.blue background: blue;
.green background: green; <script crossorigin src="https://unpkg.com/react@16/umd/react.development.js"></script>
<script crossorigin src="https://unpkg.com/react-dom@16/umd/react-dom.development.js"></script>
<div id="demo"></div>
or in the case of needing to compare against strings (for whatever reason)El.type.name.
– rlemon
Nov 12 '18 at 21:42
You should note that functions' and classes' names might change after minification.
– Ori Drori
Nov 12 '18 at 21:46
Is there a way to check if componentTwo exists in a separate function and then decide what to do? e.g. call one function if componentTwo exists, if not call another?
– zeduke
Nov 12 '18 at 21:57
Do whatever you want in the switch. I've returned the element, you call a function that will return something else.
– Ori Drori
Nov 12 '18 at 21:58
add a comment |
When you use a component, React creates an Element. Each element has a type property. The type is the class of function for component elements, or a string for DOM elements ('button').
To find the component that created the element, compare the type of the element to the Function of Class that created it:
const ComponentOne = () => 1;
const ComponentTwo = () => 2;
class ComponentThree extends React.Component
render()
return 3;
const Wrapper = ( children ) => (
<div>
React.Children.map(children, (El) =>
switch(El.type)
case ComponentOne:
return <div className="red">El</div>;
case ComponentTwo:
return <div className="blue">El</div>;
case ComponentThree:
return <div className="green">El</div>;
return null;
)
</div>
);
ReactDOM.render(
<Wrapper>
<ComponentOne />
<ComponentOne />
<ComponentTwo />
<ComponentThree />
</Wrapper>,
demo
);.red background: red;
.blue background: blue;
.green background: green; <script crossorigin src="https://unpkg.com/react@16/umd/react.development.js"></script>
<script crossorigin src="https://unpkg.com/react-dom@16/umd/react-dom.development.js"></script>
<div id="demo"></div>When you use a component, React creates an Element. Each element has a type property. The type is the class of function for component elements, or a string for DOM elements ('button').
To find the component that created the element, compare the type of the element to the Function of Class that created it:
const ComponentOne = () => 1;
const ComponentTwo = () => 2;
class ComponentThree extends React.Component
render()
return 3;
const Wrapper = ( children ) => (
<div>
React.Children.map(children, (El) =>
switch(El.type)
case ComponentOne:
return <div className="red">El</div>;
case ComponentTwo:
return <div className="blue">El</div>;
case ComponentThree:
return <div className="green">El</div>;
return null;
)
</div>
);
ReactDOM.render(
<Wrapper>
<ComponentOne />
<ComponentOne />
<ComponentTwo />
<ComponentThree />
</Wrapper>,
demo
);.red background: red;
.blue background: blue;
.green background: green; <script crossorigin src="https://unpkg.com/react@16/umd/react.development.js"></script>
<script crossorigin src="https://unpkg.com/react-dom@16/umd/react-dom.development.js"></script>
<div id="demo"></div>const ComponentOne = () => 1;
const ComponentTwo = () => 2;
class ComponentThree extends React.Component
render()
return 3;
const Wrapper = ( children ) => (
<div>
React.Children.map(children, (El) =>
switch(El.type)
case ComponentOne:
return <div className="red">El</div>;
case ComponentTwo:
return <div className="blue">El</div>;
case ComponentThree:
return <div className="green">El</div>;
return null;
)
</div>
);
ReactDOM.render(
<Wrapper>
<ComponentOne />
<ComponentOne />
<ComponentTwo />
<ComponentThree />
</Wrapper>,
demo
);.red background: red;
.blue background: blue;
.green background: green; <script crossorigin src="https://unpkg.com/react@16/umd/react.development.js"></script>
<script crossorigin src="https://unpkg.com/react-dom@16/umd/react-dom.development.js"></script>
<div id="demo"></div>const ComponentOne = () => 1;
const ComponentTwo = () => 2;
class ComponentThree extends React.Component
render()
return 3;
const Wrapper = ( children ) => (
<div>
React.Children.map(children, (El) =>
switch(El.type)
case ComponentOne:
return <div className="red">El</div>;
case ComponentTwo:
return <div className="blue">El</div>;
case ComponentThree:
return <div className="green">El</div>;
return null;
)
</div>
);
ReactDOM.render(
<Wrapper>
<ComponentOne />
<ComponentOne />
<ComponentTwo />
<ComponentThree />
</Wrapper>,
demo
);.red background: red;
.blue background: blue;
.green background: green; <script crossorigin src="https://unpkg.com/react@16/umd/react.development.js"></script>
<script crossorigin src="https://unpkg.com/react-dom@16/umd/react-dom.development.js"></script>
<div id="demo"></div>answered Nov 12 '18 at 21:40
Ori DroriOri Drori
76k138092
76k138092
or in the case of needing to compare against strings (for whatever reason)El.type.name.
– rlemon
Nov 12 '18 at 21:42
You should note that functions' and classes' names might change after minification.
– Ori Drori
Nov 12 '18 at 21:46
Is there a way to check if componentTwo exists in a separate function and then decide what to do? e.g. call one function if componentTwo exists, if not call another?
– zeduke
Nov 12 '18 at 21:57
Do whatever you want in the switch. I've returned the element, you call a function that will return something else.
– Ori Drori
Nov 12 '18 at 21:58
add a comment |
or in the case of needing to compare against strings (for whatever reason)El.type.name.
– rlemon
Nov 12 '18 at 21:42
You should note that functions' and classes' names might change after minification.
– Ori Drori
Nov 12 '18 at 21:46
Is there a way to check if componentTwo exists in a separate function and then decide what to do? e.g. call one function if componentTwo exists, if not call another?
– zeduke
Nov 12 '18 at 21:57
Do whatever you want in the switch. I've returned the element, you call a function that will return something else.
– Ori Drori
Nov 12 '18 at 21:58
or in the case of needing to compare against strings (for whatever reason)
El.type.name.– rlemon
Nov 12 '18 at 21:42
or in the case of needing to compare against strings (for whatever reason)
El.type.name.– rlemon
Nov 12 '18 at 21:42
You should note that functions' and classes' names might change after minification.
– Ori Drori
Nov 12 '18 at 21:46
You should note that functions' and classes' names might change after minification.
– Ori Drori
Nov 12 '18 at 21:46
Is there a way to check if componentTwo exists in a separate function and then decide what to do? e.g. call one function if componentTwo exists, if not call another?
– zeduke
Nov 12 '18 at 21:57
Is there a way to check if componentTwo exists in a separate function and then decide what to do? e.g. call one function if componentTwo exists, if not call another?
– zeduke
Nov 12 '18 at 21:57
Do whatever you want in the switch. I've returned the element, you call a function that will return something else.
– Ori Drori
Nov 12 '18 at 21:58
Do whatever you want in the switch. I've returned the element, you call a function that will return something else.
– Ori Drori
Nov 12 '18 at 21:58
add a comment |
const isComponentTwo = collectionOfComponents.some(component => component.type.displayName.includes('ComponentTwo'));
The above will return true if at least one component in the collectionOfComponents is ComponentTwo.
This is not advisable however. Using displayName or type for production should never be used. This is because during, for example, minification the displayName and type will change, so the logic you are expecting will not occur in the way you are expecting.
The following states:
The displayName string is used in debugging messages. Usually, you don’t need to set it explicitly because it’s inferred from the name of the function or class that defines the component. You might want to set it explicitly if you want to display a different name for debugging purposes or when you create a higher-order component
A better solution would be to add some sort of flagProp to your component.
For example
decideWhatToDo = () =>
const flagPropName = this.props;
return flagPropName
? this.methodOne()
: this.methodTwo();
In the two methods you can then decide what you want to do if componentTwo exists or if it doesn't exist
add a comment |
const isComponentTwo = collectionOfComponents.some(component => component.type.displayName.includes('ComponentTwo'));
The above will return true if at least one component in the collectionOfComponents is ComponentTwo.
This is not advisable however. Using displayName or type for production should never be used. This is because during, for example, minification the displayName and type will change, so the logic you are expecting will not occur in the way you are expecting.
The following states:
The displayName string is used in debugging messages. Usually, you don’t need to set it explicitly because it’s inferred from the name of the function or class that defines the component. You might want to set it explicitly if you want to display a different name for debugging purposes or when you create a higher-order component
A better solution would be to add some sort of flagProp to your component.
For example
decideWhatToDo = () =>
const flagPropName = this.props;
return flagPropName
? this.methodOne()
: this.methodTwo();
In the two methods you can then decide what you want to do if componentTwo exists or if it doesn't exist
add a comment |
const isComponentTwo = collectionOfComponents.some(component => component.type.displayName.includes('ComponentTwo'));
The above will return true if at least one component in the collectionOfComponents is ComponentTwo.
This is not advisable however. Using displayName or type for production should never be used. This is because during, for example, minification the displayName and type will change, so the logic you are expecting will not occur in the way you are expecting.
The following states:
The displayName string is used in debugging messages. Usually, you don’t need to set it explicitly because it’s inferred from the name of the function or class that defines the component. You might want to set it explicitly if you want to display a different name for debugging purposes or when you create a higher-order component
A better solution would be to add some sort of flagProp to your component.
For example
decideWhatToDo = () =>
const flagPropName = this.props;
return flagPropName
? this.methodOne()
: this.methodTwo();
In the two methods you can then decide what you want to do if componentTwo exists or if it doesn't exist
const isComponentTwo = collectionOfComponents.some(component => component.type.displayName.includes('ComponentTwo'));
The above will return true if at least one component in the collectionOfComponents is ComponentTwo.
This is not advisable however. Using displayName or type for production should never be used. This is because during, for example, minification the displayName and type will change, so the logic you are expecting will not occur in the way you are expecting.
The following states:
The displayName string is used in debugging messages. Usually, you don’t need to set it explicitly because it’s inferred from the name of the function or class that defines the component. You might want to set it explicitly if you want to display a different name for debugging purposes or when you create a higher-order component
A better solution would be to add some sort of flagProp to your component.
For example
decideWhatToDo = () =>
const flagPropName = this.props;
return flagPropName
? this.methodOne()
: this.methodTwo();
In the two methods you can then decide what you want to do if componentTwo exists or if it doesn't exist
edited Nov 25 '18 at 14:27
answered Nov 13 '18 at 20:46
zedukezeduke
8518
8518
add a comment |
add a comment |
Check in the array using indexOf:
collectionOfComponents.indexOf('ComponentTwo') !== -1 // found
Components will not be unique there could be 5ComponentOneand twoComponentTwoor there could be 7ComponentTwoand 1ComponentOne
– zeduke
Nov 12 '18 at 21:22
Anyways, you are just wondering if that component is found, right?
– Bhojendra Rauniyar
Nov 12 '18 at 21:24
correct if a certain component exists in the array
– zeduke
Nov 12 '18 at 21:25
Let me know if you have any query.
– Bhojendra Rauniyar
Nov 12 '18 at 21:25
add a comment |
Check in the array using indexOf:
collectionOfComponents.indexOf('ComponentTwo') !== -1 // found
Components will not be unique there could be 5ComponentOneand twoComponentTwoor there could be 7ComponentTwoand 1ComponentOne
– zeduke
Nov 12 '18 at 21:22
Anyways, you are just wondering if that component is found, right?
– Bhojendra Rauniyar
Nov 12 '18 at 21:24
correct if a certain component exists in the array
– zeduke
Nov 12 '18 at 21:25
Let me know if you have any query.
– Bhojendra Rauniyar
Nov 12 '18 at 21:25
add a comment |
Check in the array using indexOf:
collectionOfComponents.indexOf('ComponentTwo') !== -1 // found
Check in the array using indexOf:
collectionOfComponents.indexOf('ComponentTwo') !== -1 // found
edited Nov 12 '18 at 21:25
answered Nov 12 '18 at 21:15
Bhojendra RauniyarBhojendra Rauniyar
50.9k2079125
50.9k2079125
Components will not be unique there could be 5ComponentOneand twoComponentTwoor there could be 7ComponentTwoand 1ComponentOne
– zeduke
Nov 12 '18 at 21:22
Anyways, you are just wondering if that component is found, right?
– Bhojendra Rauniyar
Nov 12 '18 at 21:24
correct if a certain component exists in the array
– zeduke
Nov 12 '18 at 21:25
Let me know if you have any query.
– Bhojendra Rauniyar
Nov 12 '18 at 21:25
add a comment |
Components will not be unique there could be 5ComponentOneand twoComponentTwoor there could be 7ComponentTwoand 1ComponentOne
– zeduke
Nov 12 '18 at 21:22
Anyways, you are just wondering if that component is found, right?
– Bhojendra Rauniyar
Nov 12 '18 at 21:24
correct if a certain component exists in the array
– zeduke
Nov 12 '18 at 21:25
Let me know if you have any query.
– Bhojendra Rauniyar
Nov 12 '18 at 21:25
Components will not be unique there could be 5
ComponentOne and two ComponentTwo or there could be 7ComponentTwo and 1 ComponentOne– zeduke
Nov 12 '18 at 21:22
Components will not be unique there could be 5
ComponentOne and two ComponentTwo or there could be 7ComponentTwo and 1 ComponentOne– zeduke
Nov 12 '18 at 21:22
Anyways, you are just wondering if that component is found, right?
– Bhojendra Rauniyar
Nov 12 '18 at 21:24
Anyways, you are just wondering if that component is found, right?
– Bhojendra Rauniyar
Nov 12 '18 at 21:24
correct if a certain component exists in the array
– zeduke
Nov 12 '18 at 21:25
correct if a certain component exists in the array
– zeduke
Nov 12 '18 at 21:25
Let me know if you have any query.
– Bhojendra Rauniyar
Nov 12 '18 at 21:25
Let me know if you have any query.
– Bhojendra Rauniyar
Nov 12 '18 at 21:25
add a comment |
Maybe you can use this way or simulary ??
<Wrapper1>
{collectionOfComponents.map((oneComponent, index) => (
<Wrapper2
..props
>
oneComponent.component instanceof ComponentTwo ? renderWasYouWant : otherRender
</Wrapper2>
)
</Wrapper1>
add a comment |
Maybe you can use this way or simulary ??
<Wrapper1>
{collectionOfComponents.map((oneComponent, index) => (
<Wrapper2
..props
>
oneComponent.component instanceof ComponentTwo ? renderWasYouWant : otherRender
</Wrapper2>
)
</Wrapper1>
add a comment |
Maybe you can use this way or simulary ??
<Wrapper1>
{collectionOfComponents.map((oneComponent, index) => (
<Wrapper2
..props
>
oneComponent.component instanceof ComponentTwo ? renderWasYouWant : otherRender
</Wrapper2>
)
</Wrapper1>
Maybe you can use this way or simulary ??
<Wrapper1>
{collectionOfComponents.map((oneComponent, index) => (
<Wrapper2
..props
>
oneComponent.component instanceof ComponentTwo ? renderWasYouWant : otherRender
</Wrapper2>
)
</Wrapper1>
edited Nov 12 '18 at 21:54
answered Nov 12 '18 at 21:47
A.VincentA.Vincent
487
487
add a comment |
add a comment |
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