How to pass “-L” to an awk script?
I am trying to write an awk script that accepts -L as an argument.
As an example to show you what I want, here is a simple awk script called awktest:
#!/usr/bin/awk -f
BEGIN
print ARGV[1]
If I run this from shell:
$./awktest -w
I get as output:
-w
Which is what I expect. It seems to work for anything I put in except -L.
If I run:
$./awktest -L
I get:
awk: option requires an argument --L
When I am expecting ARGV[1] to just contain -L. What is going on here? Why does it fail on this specific case and how can I make it accept -L in ARGV? Thanks
linux bash shell awk
asked Nov 12 '18 at 22:14
KosKos
624321
add a comment |
I am trying to write an awk script that accepts -L as an argument.
As an example to show you what I want, here is a simple awk script called awktest:
#!/usr/bin/awk -f
BEGIN
print ARGV[1]
If I run this from shell:
$./awktest -w
I get as output:
-w
Which is what I expect. It seems to work for anything I put in except -L.
If I run:
$./awktest -L
I get:
awk: option requires an argument --L
When I am expecting ARGV[1] to just contain -L. What is going on here? Why does it fail on this specific case and how can I make it accept -L in ARGV? Thanks
linux bash shell awk
asked Nov 12 '18 at 22:14
KosKos
624321
2
Only-L?-f,-v,-F, ... pretty much any awk option that requires an argument will show the same results.
– muru
Nov 12 '18 at 23:25
add a comment |
I am trying to write an awk script that accepts -L as an argument.
As an example to show you what I want, here is a simple awk script called awktest:
#!/usr/bin/awk -f
BEGIN
print ARGV[1]
If I run this from shell:
$./awktest -w
I get as output:
-w
Which is what I expect. It seems to work for anything I put in except -L.
If I run:
$./awktest -L
I get:
awk: option requires an argument --L
When I am expecting ARGV[1] to just contain -L. What is going on here? Why does it fail on this specific case and how can I make it accept -L in ARGV? Thanks
linux bash shell awk
asked Nov 12 '18 at 22:14
KosKos
624321
I am trying to write an awk script that accepts -L as an argument.
As an example to show you what I want, here is a simple awk script called awktest:
#!/usr/bin/awk -f
BEGIN
print ARGV[1]
If I run this from shell:
$./awktest -w
I get as output:
-w
Which is what I expect. It seems to work for anything I put in except -L.
If I run:
$./awktest -L
I get:
awk: option requires an argument --L
When I am expecting ARGV[1] to just contain -L. What is going on here? Why does it fail on this specific case and how can I make it accept -L in ARGV? Thanks
linux bash shell awk
linux bash shell awk
asked Nov 12 '18 at 22:14
KosKos
624321
asked Nov 12 '18 at 22:14
KosKos
624321
edited Nov 12 '18 at 22:20
Kos
asked Nov 12 '18 at 22:14
KosKos
624321
asked Nov 12 '18 at 22:14
KosKos
624321
asked Nov 12 '18 at 22:14
KosKos
624321
624321
2
Only-L?-f,-v,-F, ... pretty much any awk option that requires an argument will show the same results.
– muru
Nov 12 '18 at 23:25
add a comment |
2
Only-L?-f,-v,-F, ... pretty much any awk option that requires an argument will show the same results.
– muru
Nov 12 '18 at 23:25
2
2
Only
-L? -f, -v, -F, ... pretty much any awk option that requires an argument will show the same results.– muru
Nov 12 '18 at 23:25
Only
-L? -f, -v, -F, ... pretty much any awk option that requires an argument will show the same results.– muru
Nov 12 '18 at 23:25
add a comment |
1 Answer
1
active
oldest
votes
Wrap your awk script in a shell script:
#!/bin/sh
awk 'BEGIN
print ARGV[1]
' "$@"
Example:
$ ./awktest -L
-L
The problem is that when running a script with a shebang line, the specified program is run with the name of the script and the script's arguments as extra command line arguments. In other words, with your original awktest script, running awktest -L turns into /usr/bin/awk -f /path/to/awktest -L, thus awk treats the -L as an argument to it, and not to the actual script.
If you don't want to use the ./awktest -- -L syntax, you need another layer of indirection to put the script arguments where they need to be.
answered Nov 12 '18 at 23:55
ShawnShawn
3,7521613
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53270876%2fhow-to-pass-l-to-an-awk-script%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Wrap your awk script in a shell script:
#!/bin/sh
awk 'BEGIN
print ARGV[1]
' "$@"
Example:
$ ./awktest -L
-L
The problem is that when running a script with a shebang line, the specified program is run with the name of the script and the script's arguments as extra command line arguments. In other words, with your original awktest script, running awktest -L turns into /usr/bin/awk -f /path/to/awktest -L, thus awk treats the -L as an argument to it, and not to the actual script.
If you don't want to use the ./awktest -- -L syntax, you need another layer of indirection to put the script arguments where they need to be.
answered Nov 12 '18 at 23:55
ShawnShawn
3,7521613
add a comment |
Wrap your awk script in a shell script:
#!/bin/sh
awk 'BEGIN
print ARGV[1]
' "$@"
Example:
$ ./awktest -L
-L
The problem is that when running a script with a shebang line, the specified program is run with the name of the script and the script's arguments as extra command line arguments. In other words, with your original awktest script, running awktest -L turns into /usr/bin/awk -f /path/to/awktest -L, thus awk treats the -L as an argument to it, and not to the actual script.
If you don't want to use the ./awktest -- -L syntax, you need another layer of indirection to put the script arguments where they need to be.
answered Nov 12 '18 at 23:55
ShawnShawn
3,7521613
add a comment |
Wrap your awk script in a shell script:
#!/bin/sh
awk 'BEGIN
print ARGV[1]
' "$@"
Example:
$ ./awktest -L
-L
The problem is that when running a script with a shebang line, the specified program is run with the name of the script and the script's arguments as extra command line arguments. In other words, with your original awktest script, running awktest -L turns into /usr/bin/awk -f /path/to/awktest -L, thus awk treats the -L as an argument to it, and not to the actual script.
If you don't want to use the ./awktest -- -L syntax, you need another layer of indirection to put the script arguments where they need to be.
answered Nov 12 '18 at 23:55
ShawnShawn
3,7521613
Wrap your awk script in a shell script:
#!/bin/sh
awk 'BEGIN
print ARGV[1]
' "$@"
Example:
$ ./awktest -L
-L
The problem is that when running a script with a shebang line, the specified program is run with the name of the script and the script's arguments as extra command line arguments. In other words, with your original awktest script, running awktest -L turns into /usr/bin/awk -f /path/to/awktest -L, thus awk treats the -L as an argument to it, and not to the actual script.
If you don't want to use the ./awktest -- -L syntax, you need another layer of indirection to put the script arguments where they need to be.
answered Nov 12 '18 at 23:55
ShawnShawn
3,7521613
answered Nov 12 '18 at 23:55
ShawnShawn
3,7521613
answered Nov 12 '18 at 23:55
ShawnShawn
3,7521613
answered Nov 12 '18 at 23:55
ShawnShawn
3,7521613
3,7521613
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53270876%2fhow-to-pass-l-to-an-awk-script%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
2
Only
-L?-f,-v,-F, ... pretty much any awk option that requires an argument will show the same results.– muru
Nov 12 '18 at 23:25