Writing text and a variable into HTML using Javascript
here is my code. I would like to print the variable 'fName' and the text prior into the div (with the ID 'feedback').
<script>
function myFunction()
var first = document.getElementById("fName").value;
var last = document.getElementById("lName").value;
document.getElementById("feedback").innerHTML += "Hello" + fName;
</script>
Any help would be appreciated.
javascript html string variables
add a comment |
here is my code. I would like to print the variable 'fName' and the text prior into the div (with the ID 'feedback').
<script>
function myFunction()
var first = document.getElementById("fName").value;
var last = document.getElementById("lName").value;
document.getElementById("feedback").innerHTML += "Hello" + fName;
</script>
Any help would be appreciated.
javascript html string variables
1
okay? what's the problem?
– zfrisch
Nov 12 '18 at 22:16
fName
(variable) is not defined in the code you posted.
– Jeto
Nov 12 '18 at 22:20
add a comment |
here is my code. I would like to print the variable 'fName' and the text prior into the div (with the ID 'feedback').
<script>
function myFunction()
var first = document.getElementById("fName").value;
var last = document.getElementById("lName").value;
document.getElementById("feedback").innerHTML += "Hello" + fName;
</script>
Any help would be appreciated.
javascript html string variables
here is my code. I would like to print the variable 'fName' and the text prior into the div (with the ID 'feedback').
<script>
function myFunction()
var first = document.getElementById("fName").value;
var last = document.getElementById("lName").value;
document.getElementById("feedback").innerHTML += "Hello" + fName;
</script>
Any help would be appreciated.
javascript html string variables
javascript html string variables
asked Nov 12 '18 at 22:15
ArshakArshak
33
33
1
okay? what's the problem?
– zfrisch
Nov 12 '18 at 22:16
fName
(variable) is not defined in the code you posted.
– Jeto
Nov 12 '18 at 22:20
add a comment |
1
okay? what's the problem?
– zfrisch
Nov 12 '18 at 22:16
fName
(variable) is not defined in the code you posted.
– Jeto
Nov 12 '18 at 22:20
1
1
okay? what's the problem?
– zfrisch
Nov 12 '18 at 22:16
okay? what's the problem?
– zfrisch
Nov 12 '18 at 22:16
fName
(variable) is not defined in the code you posted.– Jeto
Nov 12 '18 at 22:20
fName
(variable) is not defined in the code you posted.– Jeto
Nov 12 '18 at 22:20
add a comment |
1 Answer
1
active
oldest
votes
Just use the variables you have defined:
<script>
function myFunction()
var first = document.getElementById("fName").value;
var last = document.getElementById("lName").value;
document.getElementById("feedback").innerHTML += "Hello " + first + " " + last;
</script>
add a comment |
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Just use the variables you have defined:
<script>
function myFunction()
var first = document.getElementById("fName").value;
var last = document.getElementById("lName").value;
document.getElementById("feedback").innerHTML += "Hello " + first + " " + last;
</script>
add a comment |
Just use the variables you have defined:
<script>
function myFunction()
var first = document.getElementById("fName").value;
var last = document.getElementById("lName").value;
document.getElementById("feedback").innerHTML += "Hello " + first + " " + last;
</script>
add a comment |
Just use the variables you have defined:
<script>
function myFunction()
var first = document.getElementById("fName").value;
var last = document.getElementById("lName").value;
document.getElementById("feedback").innerHTML += "Hello " + first + " " + last;
</script>
Just use the variables you have defined:
<script>
function myFunction()
var first = document.getElementById("fName").value;
var last = document.getElementById("lName").value;
document.getElementById("feedback").innerHTML += "Hello " + first + " " + last;
</script>
answered Nov 12 '18 at 22:57
PfoerdiePfoerdie
111
111
add a comment |
add a comment |
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1
okay? what's the problem?
– zfrisch
Nov 12 '18 at 22:16
fName
(variable) is not defined in the code you posted.– Jeto
Nov 12 '18 at 22:20