Why does rxjs 6 combineLatest have type error when upgrading from rxjs 5?
0
I have the following code which compiled without errors in rxjs 5:
a$ = Observable.combineLatest([x$, y$])
.subscribe(([x, y]:[X, Y]) => {
When I update to rxjs 6 the following error occurs:
Argument of type '([x, y]: [X, Y]) => void' is not assignable to parameter of type '(value: Y) => void'.
Types of parameters '__0' and 'value' are incompatible.
Type 'Y' is not assignable to type '[X, Y]'.
Property '0' is missing in type 'Y'.
Also, the error goes away if I change either type X or Y to the any type.
typescript rxjs combinelatest
asked Nov 12 '18 at 22:54
okhobbokhobb
15411
add a comment |
0
I have the following code which compiled without errors in rxjs 5:
a$ = Observable.combineLatest([x$, y$])
.subscribe(([x, y]:[X, Y]) => {
When I update to rxjs 6 the following error occurs:
Argument of type '([x, y]: [X, Y]) => void' is not assignable to parameter of type '(value: Y) => void'.
Types of parameters '__0' and 'value' are incompatible.
Type 'Y' is not assignable to type '[X, Y]'.
Property '0' is missing in type 'Y'.
Also, the error goes away if I change either type X or Y to the any type.
typescript rxjs combinelatest
asked Nov 12 '18 at 22:54
okhobbokhobb
15411
AFAICT, if you pass an array tocombineLatestit's treated as anObservableInput, so an error is appropriate. TryObservable.combineLatest(...[x$, y$]))- but the type inference will depend upon your TypeScript version.
– cartant
Nov 12 '18 at 23:10
1
Thanks for noting that it was an array. Your suggestion seems to have the same error but changing it toObservable.combineLatest(x$, y$)solved the error.
– okhobb
Nov 12 '18 at 23:21
Yeah, the array is unnecessary.
– cartant
Nov 12 '18 at 23:22
Indeed I was updating from TypeScript 2 to 3 at the same time so perhaps the rxjs version was red herring here.
– okhobb
Nov 12 '18 at 23:42
add a comment |
0
0
0
I have the following code which compiled without errors in rxjs 5:
a$ = Observable.combineLatest([x$, y$])
.subscribe(([x, y]:[X, Y]) => {
When I update to rxjs 6 the following error occurs:
Argument of type '([x, y]: [X, Y]) => void' is not assignable to parameter of type '(value: Y) => void'.
Types of parameters '__0' and 'value' are incompatible.
Type 'Y' is not assignable to type '[X, Y]'.
Property '0' is missing in type 'Y'.
Also, the error goes away if I change either type X or Y to the any type.
typescript rxjs combinelatest
asked Nov 12 '18 at 22:54
okhobbokhobb
15411
I have the following code which compiled without errors in rxjs 5:
a$ = Observable.combineLatest([x$, y$])
.subscribe(([x, y]:[X, Y]) => {
When I update to rxjs 6 the following error occurs:
Argument of type '([x, y]: [X, Y]) => void' is not assignable to parameter of type '(value: Y) => void'.
Types of parameters '__0' and 'value' are incompatible.
Type 'Y' is not assignable to type '[X, Y]'.
Property '0' is missing in type 'Y'.
Also, the error goes away if I change either type X or Y to the any type.
typescript rxjs combinelatest
typescript rxjs combinelatest
asked Nov 12 '18 at 22:54
okhobbokhobb
15411
asked Nov 12 '18 at 22:54
okhobbokhobb
15411
edited Nov 12 '18 at 23:21
okhobb
asked Nov 12 '18 at 22:54
okhobbokhobb
15411
asked Nov 12 '18 at 22:54
okhobbokhobb
15411
asked Nov 12 '18 at 22:54
okhobbokhobb
15411
15411
AFAICT, if you pass an array tocombineLatestit's treated as anObservableInput, so an error is appropriate. TryObservable.combineLatest(...[x$, y$]))- but the type inference will depend upon your TypeScript version.
– cartant
Nov 12 '18 at 23:10
1
Thanks for noting that it was an array. Your suggestion seems to have the same error but changing it toObservable.combineLatest(x$, y$)solved the error.
– okhobb
Nov 12 '18 at 23:21
Yeah, the array is unnecessary.
– cartant
Nov 12 '18 at 23:22
Indeed I was updating from TypeScript 2 to 3 at the same time so perhaps the rxjs version was red herring here.
– okhobb
Nov 12 '18 at 23:42
add a comment |
AFAICT, if you pass an array tocombineLatestit's treated as anObservableInput, so an error is appropriate. TryObservable.combineLatest(...[x$, y$]))- but the type inference will depend upon your TypeScript version.
– cartant
Nov 12 '18 at 23:10
1
Thanks for noting that it was an array. Your suggestion seems to have the same error but changing it toObservable.combineLatest(x$, y$)solved the error.
– okhobb
Nov 12 '18 at 23:21
Yeah, the array is unnecessary.
– cartant
Nov 12 '18 at 23:22
Indeed I was updating from TypeScript 2 to 3 at the same time so perhaps the rxjs version was red herring here.
– okhobb
Nov 12 '18 at 23:42
AFAICT, if you pass an array to
combineLatest it's treated as an ObservableInput, so an error is appropriate. Try Observable.combineLatest(...[x$, y$])) - but the type inference will depend upon your TypeScript version.– cartant
Nov 12 '18 at 23:10
AFAICT, if you pass an array to
combineLatest it's treated as an ObservableInput, so an error is appropriate. Try Observable.combineLatest(...[x$, y$])) - but the type inference will depend upon your TypeScript version.– cartant
Nov 12 '18 at 23:10
1
1
Thanks for noting that it was an array. Your suggestion seems to have the same error but changing it to
Observable.combineLatest(x$, y$) solved the error.– okhobb
Nov 12 '18 at 23:21
Thanks for noting that it was an array. Your suggestion seems to have the same error but changing it to
Observable.combineLatest(x$, y$) solved the error.– okhobb
Nov 12 '18 at 23:21
Yeah, the array is unnecessary.
– cartant
Nov 12 '18 at 23:22
Yeah, the array is unnecessary.
– cartant
Nov 12 '18 at 23:22
Indeed I was updating from TypeScript 2 to 3 at the same time so perhaps the rxjs version was red herring here.
– okhobb
Nov 12 '18 at 23:42
Indeed I was updating from TypeScript 2 to 3 at the same time so perhaps the rxjs version was red herring here.
– okhobb
Nov 12 '18 at 23:42
add a comment |
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AFAICT, if you pass an array to
combineLatestit's treated as anObservableInput, so an error is appropriate. TryObservable.combineLatest(...[x$, y$]))- but the type inference will depend upon your TypeScript version.– cartant
Nov 12 '18 at 23:10
1
Thanks for noting that it was an array. Your suggestion seems to have the same error but changing it to
Observable.combineLatest(x$, y$)solved the error.– okhobb
Nov 12 '18 at 23:21
Yeah, the array is unnecessary.
– cartant
Nov 12 '18 at 23:22
Indeed I was updating from TypeScript 2 to 3 at the same time so perhaps the rxjs version was red herring here.
– okhobb
Nov 12 '18 at 23:42