Map nested data by row r










2















I have data that look like this (thanks once again dput!):



dat <- structure(list(vars = c("var_1", "var_2"), data = list(structure(list(
time = 1:10, value = c(1:10
)), row.names = c(NA, -10L), class = c("tbl_df", "tbl", "data.frame"
)), structure(list(time = 1:10, value = c(11:20
)), row.names = c(NA, -10L), class = c("tbl_df", "tbl", "data.frame"
))), mu = c(1, 2), stdev = c(1,2)), class = c("tbl_df", "tbl", "data.frame"),
row.names = c(NA,-2L))


I am trying to mutate an extra column which maps a function over each row. e.g calculate dnorm for each element of the nested variable in dat$data[[1]]$value using dat$mu[1] and dat$stdev[1] and the go on to do the same for row two.



The column I would like to mutate is a tibble [10 x 1] for each row containing this as the output:



dnorm(dat$data[[1]]$value, mean = dat$mu[1], sd = dat$stdev[1])
dnorm(dat$data[[2]]$value, mean = dat$mu[2], sd = dat$stdev[2])


Things I have tried that don't work but might be close?:



# This alternates between mean and stdev for each element of each nested variable
dat_1 <- dat %>%
mutate(z = map(data, ~ dnorm(.x$value, mean = dat$mu, sd = dat$stdev)))
# apply by row has structure issues
dat_2 <- dat %>%
apply(MARGIN = 1, function(x)
mutate(x, z = map(data, ~ dnorm(.x$value, mean = dat$mu, sd = dat$stdev)))
)


a basic map function like this dat_3 <- dat %>% mutate(sigma = map(data, ~ sum(.x$value))) works fine without referencing other values in the df. This is early days for me using nested data and map in this way - been looking at the documentation for all the map functions to try solve this but no luck yet! If that's clear as mud I can try clarify - thanks in advance!










share|improve this question


























    2















    I have data that look like this (thanks once again dput!):



    dat <- structure(list(vars = c("var_1", "var_2"), data = list(structure(list(
    time = 1:10, value = c(1:10
    )), row.names = c(NA, -10L), class = c("tbl_df", "tbl", "data.frame"
    )), structure(list(time = 1:10, value = c(11:20
    )), row.names = c(NA, -10L), class = c("tbl_df", "tbl", "data.frame"
    ))), mu = c(1, 2), stdev = c(1,2)), class = c("tbl_df", "tbl", "data.frame"),
    row.names = c(NA,-2L))


    I am trying to mutate an extra column which maps a function over each row. e.g calculate dnorm for each element of the nested variable in dat$data[[1]]$value using dat$mu[1] and dat$stdev[1] and the go on to do the same for row two.



    The column I would like to mutate is a tibble [10 x 1] for each row containing this as the output:



    dnorm(dat$data[[1]]$value, mean = dat$mu[1], sd = dat$stdev[1])
    dnorm(dat$data[[2]]$value, mean = dat$mu[2], sd = dat$stdev[2])


    Things I have tried that don't work but might be close?:



    # This alternates between mean and stdev for each element of each nested variable
    dat_1 <- dat %>%
    mutate(z = map(data, ~ dnorm(.x$value, mean = dat$mu, sd = dat$stdev)))
    # apply by row has structure issues
    dat_2 <- dat %>%
    apply(MARGIN = 1, function(x)
    mutate(x, z = map(data, ~ dnorm(.x$value, mean = dat$mu, sd = dat$stdev)))
    )


    a basic map function like this dat_3 <- dat %>% mutate(sigma = map(data, ~ sum(.x$value))) works fine without referencing other values in the df. This is early days for me using nested data and map in this way - been looking at the documentation for all the map functions to try solve this but no luck yet! If that's clear as mud I can try clarify - thanks in advance!










    share|improve this question
























      2












      2








      2








      I have data that look like this (thanks once again dput!):



      dat <- structure(list(vars = c("var_1", "var_2"), data = list(structure(list(
      time = 1:10, value = c(1:10
      )), row.names = c(NA, -10L), class = c("tbl_df", "tbl", "data.frame"
      )), structure(list(time = 1:10, value = c(11:20
      )), row.names = c(NA, -10L), class = c("tbl_df", "tbl", "data.frame"
      ))), mu = c(1, 2), stdev = c(1,2)), class = c("tbl_df", "tbl", "data.frame"),
      row.names = c(NA,-2L))


      I am trying to mutate an extra column which maps a function over each row. e.g calculate dnorm for each element of the nested variable in dat$data[[1]]$value using dat$mu[1] and dat$stdev[1] and the go on to do the same for row two.



      The column I would like to mutate is a tibble [10 x 1] for each row containing this as the output:



      dnorm(dat$data[[1]]$value, mean = dat$mu[1], sd = dat$stdev[1])
      dnorm(dat$data[[2]]$value, mean = dat$mu[2], sd = dat$stdev[2])


      Things I have tried that don't work but might be close?:



      # This alternates between mean and stdev for each element of each nested variable
      dat_1 <- dat %>%
      mutate(z = map(data, ~ dnorm(.x$value, mean = dat$mu, sd = dat$stdev)))
      # apply by row has structure issues
      dat_2 <- dat %>%
      apply(MARGIN = 1, function(x)
      mutate(x, z = map(data, ~ dnorm(.x$value, mean = dat$mu, sd = dat$stdev)))
      )


      a basic map function like this dat_3 <- dat %>% mutate(sigma = map(data, ~ sum(.x$value))) works fine without referencing other values in the df. This is early days for me using nested data and map in this way - been looking at the documentation for all the map functions to try solve this but no luck yet! If that's clear as mud I can try clarify - thanks in advance!










      share|improve this question














      I have data that look like this (thanks once again dput!):



      dat <- structure(list(vars = c("var_1", "var_2"), data = list(structure(list(
      time = 1:10, value = c(1:10
      )), row.names = c(NA, -10L), class = c("tbl_df", "tbl", "data.frame"
      )), structure(list(time = 1:10, value = c(11:20
      )), row.names = c(NA, -10L), class = c("tbl_df", "tbl", "data.frame"
      ))), mu = c(1, 2), stdev = c(1,2)), class = c("tbl_df", "tbl", "data.frame"),
      row.names = c(NA,-2L))


      I am trying to mutate an extra column which maps a function over each row. e.g calculate dnorm for each element of the nested variable in dat$data[[1]]$value using dat$mu[1] and dat$stdev[1] and the go on to do the same for row two.



      The column I would like to mutate is a tibble [10 x 1] for each row containing this as the output:



      dnorm(dat$data[[1]]$value, mean = dat$mu[1], sd = dat$stdev[1])
      dnorm(dat$data[[2]]$value, mean = dat$mu[2], sd = dat$stdev[2])


      Things I have tried that don't work but might be close?:



      # This alternates between mean and stdev for each element of each nested variable
      dat_1 <- dat %>%
      mutate(z = map(data, ~ dnorm(.x$value, mean = dat$mu, sd = dat$stdev)))
      # apply by row has structure issues
      dat_2 <- dat %>%
      apply(MARGIN = 1, function(x)
      mutate(x, z = map(data, ~ dnorm(.x$value, mean = dat$mu, sd = dat$stdev)))
      )


      a basic map function like this dat_3 <- dat %>% mutate(sigma = map(data, ~ sum(.x$value))) works fine without referencing other values in the df. This is early days for me using nested data and map in this way - been looking at the documentation for all the map functions to try solve this but no luck yet! If that's clear as mud I can try clarify - thanks in advance!







      r nested apply purrr






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      asked Nov 13 '18 at 3:36









      QAsenaQAsena

      505




      505






















          1 Answer
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          2














          We can use a parallel map:



          library(purrr)
          library(dplyr)

          expected_out1 <- dnorm(dat$data[[1]]$value, mean = dat$mu[1], sd = dat$stdev[1])
          expected_out2 <- dnorm(dat$data[[2]]$value, mean = dat$mu[2], sd = dat$stdev[2])

          out <-
          dat %>%
          mutate(z = pmap(list(map(data, "value"), mu, stdev), dnorm))

          all.equal(out$z, list(expected_out1, expected_out2))
          # [1] TRUE





          share|improve this answer

























          • Amazing, thank you! I was struggling to understand pmap, makes much more sense now!

            – QAsena
            Nov 13 '18 at 19:59










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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          We can use a parallel map:



          library(purrr)
          library(dplyr)

          expected_out1 <- dnorm(dat$data[[1]]$value, mean = dat$mu[1], sd = dat$stdev[1])
          expected_out2 <- dnorm(dat$data[[2]]$value, mean = dat$mu[2], sd = dat$stdev[2])

          out <-
          dat %>%
          mutate(z = pmap(list(map(data, "value"), mu, stdev), dnorm))

          all.equal(out$z, list(expected_out1, expected_out2))
          # [1] TRUE





          share|improve this answer

























          • Amazing, thank you! I was struggling to understand pmap, makes much more sense now!

            – QAsena
            Nov 13 '18 at 19:59















          2














          We can use a parallel map:



          library(purrr)
          library(dplyr)

          expected_out1 <- dnorm(dat$data[[1]]$value, mean = dat$mu[1], sd = dat$stdev[1])
          expected_out2 <- dnorm(dat$data[[2]]$value, mean = dat$mu[2], sd = dat$stdev[2])

          out <-
          dat %>%
          mutate(z = pmap(list(map(data, "value"), mu, stdev), dnorm))

          all.equal(out$z, list(expected_out1, expected_out2))
          # [1] TRUE





          share|improve this answer

























          • Amazing, thank you! I was struggling to understand pmap, makes much more sense now!

            – QAsena
            Nov 13 '18 at 19:59













          2












          2








          2







          We can use a parallel map:



          library(purrr)
          library(dplyr)

          expected_out1 <- dnorm(dat$data[[1]]$value, mean = dat$mu[1], sd = dat$stdev[1])
          expected_out2 <- dnorm(dat$data[[2]]$value, mean = dat$mu[2], sd = dat$stdev[2])

          out <-
          dat %>%
          mutate(z = pmap(list(map(data, "value"), mu, stdev), dnorm))

          all.equal(out$z, list(expected_out1, expected_out2))
          # [1] TRUE





          share|improve this answer















          We can use a parallel map:



          library(purrr)
          library(dplyr)

          expected_out1 <- dnorm(dat$data[[1]]$value, mean = dat$mu[1], sd = dat$stdev[1])
          expected_out2 <- dnorm(dat$data[[2]]$value, mean = dat$mu[2], sd = dat$stdev[2])

          out <-
          dat %>%
          mutate(z = pmap(list(map(data, "value"), mu, stdev), dnorm))

          all.equal(out$z, list(expected_out1, expected_out2))
          # [1] TRUE






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 13 '18 at 15:24

























          answered Nov 13 '18 at 15:07









          AurèleAurèle

          6,42111533




          6,42111533












          • Amazing, thank you! I was struggling to understand pmap, makes much more sense now!

            – QAsena
            Nov 13 '18 at 19:59

















          • Amazing, thank you! I was struggling to understand pmap, makes much more sense now!

            – QAsena
            Nov 13 '18 at 19:59
















          Amazing, thank you! I was struggling to understand pmap, makes much more sense now!

          – QAsena
          Nov 13 '18 at 19:59





          Amazing, thank you! I was struggling to understand pmap, makes much more sense now!

          – QAsena
          Nov 13 '18 at 19:59

















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