Unable to parse JSON with multiple JObjects
I am having a string in the following format. I want to assign each JSON within the projects to a separate JObject. When I am trying to parse it and assign accordingly, I am unable to achieve it. How can I parse it?
"projects": [
"sno": "1",
"project_name": "Abs",
"project_Status": "Live"
,
"sno": "2",
"project_name": "Cgi",
"project_Status": "Live"
]
I have tried the following code;
using (StreamReader streamReader = new StreamReader(Path.Combine(Path.GetTempPath(), "sample.json")))
using (JsonTextReader reader = new JsonTextReader(streamReader))
var serializer = new JsonSerializer();
while (reader.Read())
if (reader.TokenType == JsonToken.StartObject)
JObject jsonPayload = JObject.Load(reader);
jsonProfile = jsonPayload.ToString();
JObject json = JObject.Parse(jsonProfile);
c# .net json json.net
add a comment |
I am having a string in the following format. I want to assign each JSON within the projects to a separate JObject. When I am trying to parse it and assign accordingly, I am unable to achieve it. How can I parse it?
"projects": [
"sno": "1",
"project_name": "Abs",
"project_Status": "Live"
,
"sno": "2",
"project_name": "Cgi",
"project_Status": "Live"
]
I have tried the following code;
using (StreamReader streamReader = new StreamReader(Path.Combine(Path.GetTempPath(), "sample.json")))
using (JsonTextReader reader = new JsonTextReader(streamReader))
var serializer = new JsonSerializer();
while (reader.Read())
if (reader.TokenType == JsonToken.StartObject)
JObject jsonPayload = JObject.Load(reader);
jsonProfile = jsonPayload.ToString();
JObject json = JObject.Parse(jsonProfile);
c# .net json json.net
@dbc Updated my question with the code I have tried
– Harry
Nov 13 '18 at 3:44
This question seems like a duplicate of your question from 16 hours ago except with only one JSON format instead of two. Did the answer to that one not help you?
– Brian Rogers
Nov 13 '18 at 4:10
add a comment |
I am having a string in the following format. I want to assign each JSON within the projects to a separate JObject. When I am trying to parse it and assign accordingly, I am unable to achieve it. How can I parse it?
"projects": [
"sno": "1",
"project_name": "Abs",
"project_Status": "Live"
,
"sno": "2",
"project_name": "Cgi",
"project_Status": "Live"
]
I have tried the following code;
using (StreamReader streamReader = new StreamReader(Path.Combine(Path.GetTempPath(), "sample.json")))
using (JsonTextReader reader = new JsonTextReader(streamReader))
var serializer = new JsonSerializer();
while (reader.Read())
if (reader.TokenType == JsonToken.StartObject)
JObject jsonPayload = JObject.Load(reader);
jsonProfile = jsonPayload.ToString();
JObject json = JObject.Parse(jsonProfile);
c# .net json json.net
I am having a string in the following format. I want to assign each JSON within the projects to a separate JObject. When I am trying to parse it and assign accordingly, I am unable to achieve it. How can I parse it?
"projects": [
"sno": "1",
"project_name": "Abs",
"project_Status": "Live"
,
"sno": "2",
"project_name": "Cgi",
"project_Status": "Live"
]
I have tried the following code;
using (StreamReader streamReader = new StreamReader(Path.Combine(Path.GetTempPath(), "sample.json")))
using (JsonTextReader reader = new JsonTextReader(streamReader))
var serializer = new JsonSerializer();
while (reader.Read())
if (reader.TokenType == JsonToken.StartObject)
JObject jsonPayload = JObject.Load(reader);
jsonProfile = jsonPayload.ToString();
JObject json = JObject.Parse(jsonProfile);
c# .net json json.net
c# .net json json.net
edited Nov 13 '18 at 3:56
Tetsuya Yamamoto
15.5k42240
15.5k42240
asked Nov 13 '18 at 3:41
HarryHarry
207
207
@dbc Updated my question with the code I have tried
– Harry
Nov 13 '18 at 3:44
This question seems like a duplicate of your question from 16 hours ago except with only one JSON format instead of two. Did the answer to that one not help you?
– Brian Rogers
Nov 13 '18 at 4:10
add a comment |
@dbc Updated my question with the code I have tried
– Harry
Nov 13 '18 at 3:44
This question seems like a duplicate of your question from 16 hours ago except with only one JSON format instead of two. Did the answer to that one not help you?
– Brian Rogers
Nov 13 '18 at 4:10
@dbc Updated my question with the code I have tried
– Harry
Nov 13 '18 at 3:44
@dbc Updated my question with the code I have tried
– Harry
Nov 13 '18 at 3:44
This question seems like a duplicate of your question from 16 hours ago except with only one JSON format instead of two. Did the answer to that one not help you?
– Brian Rogers
Nov 13 '18 at 4:10
This question seems like a duplicate of your question from 16 hours ago except with only one JSON format instead of two. Did the answer to that one not help you?
– Brian Rogers
Nov 13 '18 at 4:10
add a comment |
1 Answer
1
active
oldest
votes
you can use DeserializeAnonymousType as a simpler solution to parse json.
var definition = new
projects = new
new
sno="1",
project_name= "Abs",
project_Status= "Live"
;
string json1 = @"
'projects': [
'sno': '1',
'project_name': 'Abs',
'project_Status': 'Live'
,
'sno': '2',
'project_name': 'Cgi',
'project_Status': 'Live'
]
";
var projects = JsonConvert.DeserializeAnonymousType(json1, definition);
but if you do want to use strong type
, you'd better to use JsonProperty
public class Project
[JsonProperty("sno")]
public string Sno get; set;
[JsonProperty("project_name")]
public string ProjectName get; set;
[JsonProperty("project_Status")]
public string ProjectStatus get; set;
public class JsonModel
[JsonProperty("Projects")]
public List<Project> projects get; set;
JsonConvert.DeserializeObject<JsonModel>(json_Data);
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
you can use DeserializeAnonymousType as a simpler solution to parse json.
var definition = new
projects = new
new
sno="1",
project_name= "Abs",
project_Status= "Live"
;
string json1 = @"
'projects': [
'sno': '1',
'project_name': 'Abs',
'project_Status': 'Live'
,
'sno': '2',
'project_name': 'Cgi',
'project_Status': 'Live'
]
";
var projects = JsonConvert.DeserializeAnonymousType(json1, definition);
but if you do want to use strong type
, you'd better to use JsonProperty
public class Project
[JsonProperty("sno")]
public string Sno get; set;
[JsonProperty("project_name")]
public string ProjectName get; set;
[JsonProperty("project_Status")]
public string ProjectStatus get; set;
public class JsonModel
[JsonProperty("Projects")]
public List<Project> projects get; set;
JsonConvert.DeserializeObject<JsonModel>(json_Data);
add a comment |
you can use DeserializeAnonymousType as a simpler solution to parse json.
var definition = new
projects = new
new
sno="1",
project_name= "Abs",
project_Status= "Live"
;
string json1 = @"
'projects': [
'sno': '1',
'project_name': 'Abs',
'project_Status': 'Live'
,
'sno': '2',
'project_name': 'Cgi',
'project_Status': 'Live'
]
";
var projects = JsonConvert.DeserializeAnonymousType(json1, definition);
but if you do want to use strong type
, you'd better to use JsonProperty
public class Project
[JsonProperty("sno")]
public string Sno get; set;
[JsonProperty("project_name")]
public string ProjectName get; set;
[JsonProperty("project_Status")]
public string ProjectStatus get; set;
public class JsonModel
[JsonProperty("Projects")]
public List<Project> projects get; set;
JsonConvert.DeserializeObject<JsonModel>(json_Data);
add a comment |
you can use DeserializeAnonymousType as a simpler solution to parse json.
var definition = new
projects = new
new
sno="1",
project_name= "Abs",
project_Status= "Live"
;
string json1 = @"
'projects': [
'sno': '1',
'project_name': 'Abs',
'project_Status': 'Live'
,
'sno': '2',
'project_name': 'Cgi',
'project_Status': 'Live'
]
";
var projects = JsonConvert.DeserializeAnonymousType(json1, definition);
but if you do want to use strong type
, you'd better to use JsonProperty
public class Project
[JsonProperty("sno")]
public string Sno get; set;
[JsonProperty("project_name")]
public string ProjectName get; set;
[JsonProperty("project_Status")]
public string ProjectStatus get; set;
public class JsonModel
[JsonProperty("Projects")]
public List<Project> projects get; set;
JsonConvert.DeserializeObject<JsonModel>(json_Data);
you can use DeserializeAnonymousType as a simpler solution to parse json.
var definition = new
projects = new
new
sno="1",
project_name= "Abs",
project_Status= "Live"
;
string json1 = @"
'projects': [
'sno': '1',
'project_name': 'Abs',
'project_Status': 'Live'
,
'sno': '2',
'project_name': 'Cgi',
'project_Status': 'Live'
]
";
var projects = JsonConvert.DeserializeAnonymousType(json1, definition);
but if you do want to use strong type
, you'd better to use JsonProperty
public class Project
[JsonProperty("sno")]
public string Sno get; set;
[JsonProperty("project_name")]
public string ProjectName get; set;
[JsonProperty("project_Status")]
public string ProjectStatus get; set;
public class JsonModel
[JsonProperty("Projects")]
public List<Project> projects get; set;
JsonConvert.DeserializeObject<JsonModel>(json_Data);
answered Nov 13 '18 at 4:03
DongdongDongdong
841511
841511
add a comment |
add a comment |
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@dbc Updated my question with the code I have tried
– Harry
Nov 13 '18 at 3:44
This question seems like a duplicate of your question from 16 hours ago except with only one JSON format instead of two. Did the answer to that one not help you?
– Brian Rogers
Nov 13 '18 at 4:10