How to paginate text in browser?










0















Assume I have the text of War and Peace in a variable wandp.



Is there any way of writing a function such that page(n) would return exactly the correct amount of text to fill the current browser window, where n is a character index into wandp.



I want the text to be the correct amount, i.e. no significant whitespace or scrollbars.



I suppose I'm looking for a text description of an ebook algorithm for browsers.



P.S. I'm sure there are complications around chapters and other layout features, but they can wait.










share|improve this question


























    0















    Assume I have the text of War and Peace in a variable wandp.



    Is there any way of writing a function such that page(n) would return exactly the correct amount of text to fill the current browser window, where n is a character index into wandp.



    I want the text to be the correct amount, i.e. no significant whitespace or scrollbars.



    I suppose I'm looking for a text description of an ebook algorithm for browsers.



    P.S. I'm sure there are complications around chapters and other layout features, but they can wait.










    share|improve this question
























      0












      0








      0








      Assume I have the text of War and Peace in a variable wandp.



      Is there any way of writing a function such that page(n) would return exactly the correct amount of text to fill the current browser window, where n is a character index into wandp.



      I want the text to be the correct amount, i.e. no significant whitespace or scrollbars.



      I suppose I'm looking for a text description of an ebook algorithm for browsers.



      P.S. I'm sure there are complications around chapters and other layout features, but they can wait.










      share|improve this question














      Assume I have the text of War and Peace in a variable wandp.



      Is there any way of writing a function such that page(n) would return exactly the correct amount of text to fill the current browser window, where n is a character index into wandp.



      I want the text to be the correct amount, i.e. no significant whitespace or scrollbars.



      I suppose I'm looking for a text description of an ebook algorithm for browsers.



      P.S. I'm sure there are complications around chapters and other layout features, but they can wait.







      javascript html css browser scrollbar






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 13 '18 at 15:09









      fadedbeefadedbee

      17.4k35108191




      17.4k35108191






















          1 Answer
          1






          active

          oldest

          votes


















          1














          Borrowing an idea from Work out how many characters can fit into DIV with JavaScript, I would create a hidden <div> and set the width of that element equal to the browser window width. Then, I would create a function to add text from wandp, checking the height of the <div> element as you append, until the height of the <div> element is equal to the browser window height.



          It might look something like this:



          HTML:



          ...
          <div id="normalDiv" style="width: 100%; overflow: hidden"></div>
          <div id="hiddenDiv" style="visibility: hidden; width: 100%;"></div>
          ...


          Javascript:



          ...
          var targetHeight = window.innerHeight - 40; //browser window height minus height of last line of text
          var wandp = 'The entire content of War and Peace...';
          var startChar = 0;
          var endChar = 0;
          for(var i=startChar; i < wandp.length; i++)
          endChar = i;
          document.getElementById('hiddenDiv').innerHTML += wandp.charAt(i);
          if (document.getElementById('hiddenDiv').clientHeight > targetHeight)
          endChar--;
          break;


          document.getElementById('normalDiv').innerHTML = wandp.substring(startChar, endChar);
          ...


          Keep in mind, this will result in cut-off text since it will go up to the absolute last character that will fit the constraints. You will need to get a little creative in order to end the text on the page at a reasonable character (last period encountered, before last whitespace encountered, etc).






          share|improve this answer
























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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            Borrowing an idea from Work out how many characters can fit into DIV with JavaScript, I would create a hidden <div> and set the width of that element equal to the browser window width. Then, I would create a function to add text from wandp, checking the height of the <div> element as you append, until the height of the <div> element is equal to the browser window height.



            It might look something like this:



            HTML:



            ...
            <div id="normalDiv" style="width: 100%; overflow: hidden"></div>
            <div id="hiddenDiv" style="visibility: hidden; width: 100%;"></div>
            ...


            Javascript:



            ...
            var targetHeight = window.innerHeight - 40; //browser window height minus height of last line of text
            var wandp = 'The entire content of War and Peace...';
            var startChar = 0;
            var endChar = 0;
            for(var i=startChar; i < wandp.length; i++)
            endChar = i;
            document.getElementById('hiddenDiv').innerHTML += wandp.charAt(i);
            if (document.getElementById('hiddenDiv').clientHeight > targetHeight)
            endChar--;
            break;


            document.getElementById('normalDiv').innerHTML = wandp.substring(startChar, endChar);
            ...


            Keep in mind, this will result in cut-off text since it will go up to the absolute last character that will fit the constraints. You will need to get a little creative in order to end the text on the page at a reasonable character (last period encountered, before last whitespace encountered, etc).






            share|improve this answer





























              1














              Borrowing an idea from Work out how many characters can fit into DIV with JavaScript, I would create a hidden <div> and set the width of that element equal to the browser window width. Then, I would create a function to add text from wandp, checking the height of the <div> element as you append, until the height of the <div> element is equal to the browser window height.



              It might look something like this:



              HTML:



              ...
              <div id="normalDiv" style="width: 100%; overflow: hidden"></div>
              <div id="hiddenDiv" style="visibility: hidden; width: 100%;"></div>
              ...


              Javascript:



              ...
              var targetHeight = window.innerHeight - 40; //browser window height minus height of last line of text
              var wandp = 'The entire content of War and Peace...';
              var startChar = 0;
              var endChar = 0;
              for(var i=startChar; i < wandp.length; i++)
              endChar = i;
              document.getElementById('hiddenDiv').innerHTML += wandp.charAt(i);
              if (document.getElementById('hiddenDiv').clientHeight > targetHeight)
              endChar--;
              break;


              document.getElementById('normalDiv').innerHTML = wandp.substring(startChar, endChar);
              ...


              Keep in mind, this will result in cut-off text since it will go up to the absolute last character that will fit the constraints. You will need to get a little creative in order to end the text on the page at a reasonable character (last period encountered, before last whitespace encountered, etc).






              share|improve this answer



























                1












                1








                1







                Borrowing an idea from Work out how many characters can fit into DIV with JavaScript, I would create a hidden <div> and set the width of that element equal to the browser window width. Then, I would create a function to add text from wandp, checking the height of the <div> element as you append, until the height of the <div> element is equal to the browser window height.



                It might look something like this:



                HTML:



                ...
                <div id="normalDiv" style="width: 100%; overflow: hidden"></div>
                <div id="hiddenDiv" style="visibility: hidden; width: 100%;"></div>
                ...


                Javascript:



                ...
                var targetHeight = window.innerHeight - 40; //browser window height minus height of last line of text
                var wandp = 'The entire content of War and Peace...';
                var startChar = 0;
                var endChar = 0;
                for(var i=startChar; i < wandp.length; i++)
                endChar = i;
                document.getElementById('hiddenDiv').innerHTML += wandp.charAt(i);
                if (document.getElementById('hiddenDiv').clientHeight > targetHeight)
                endChar--;
                break;


                document.getElementById('normalDiv').innerHTML = wandp.substring(startChar, endChar);
                ...


                Keep in mind, this will result in cut-off text since it will go up to the absolute last character that will fit the constraints. You will need to get a little creative in order to end the text on the page at a reasonable character (last period encountered, before last whitespace encountered, etc).






                share|improve this answer















                Borrowing an idea from Work out how many characters can fit into DIV with JavaScript, I would create a hidden <div> and set the width of that element equal to the browser window width. Then, I would create a function to add text from wandp, checking the height of the <div> element as you append, until the height of the <div> element is equal to the browser window height.



                It might look something like this:



                HTML:



                ...
                <div id="normalDiv" style="width: 100%; overflow: hidden"></div>
                <div id="hiddenDiv" style="visibility: hidden; width: 100%;"></div>
                ...


                Javascript:



                ...
                var targetHeight = window.innerHeight - 40; //browser window height minus height of last line of text
                var wandp = 'The entire content of War and Peace...';
                var startChar = 0;
                var endChar = 0;
                for(var i=startChar; i < wandp.length; i++)
                endChar = i;
                document.getElementById('hiddenDiv').innerHTML += wandp.charAt(i);
                if (document.getElementById('hiddenDiv').clientHeight > targetHeight)
                endChar--;
                break;


                document.getElementById('normalDiv').innerHTML = wandp.substring(startChar, endChar);
                ...


                Keep in mind, this will result in cut-off text since it will go up to the absolute last character that will fit the constraints. You will need to get a little creative in order to end the text on the page at a reasonable character (last period encountered, before last whitespace encountered, etc).







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 13 '18 at 15:59

























                answered Nov 13 '18 at 15:53









                Justin T.Justin T.

                596313




                596313





























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