Weird loop while reading from a file in C
I'm writing a code in C to read matrixes (square matrix with 3 <= dim <= 9) from a .txt file and print it exactly how it is written. The file is arranged as follows:
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
The first number indicates the size of the subsequent matrix.
I wrote the following code:
int main ()
FILE *arquivo;
char A[9][9];
int N;
int i,j;
char temp;
arquivo = fopen("matrizes.txt", "r");
if (!arquivo) printf("Erro.n");
while (fscanf(arquivo, "%d", &N) != EOF)
printf("%d n", N);
fgetc(arquivo);
for (i = 0; ((i < N) && (temp = fgetc(arquivo)) != 'n') ; i++)
for (j = 0; j < N; j++)
A[i][j] = temp;
for (i = 0; i < N; i++)
for(j = 0; j<N; j++)
printf("%c", A[i][j]);
puts(" ");
return 0;
The output is this
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
I honestly have no idea why this is happening. I tried different conditions to stop the loop, bot none of them worked out.
If I change
while (fscanf(arquivo, "%d", &N) != EOF)
into
while (fscanf(arquivo, "%d", &N) == 1)
the output is just
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
The value of the second loop scanf in this case is "0".
How can I fix it and print exactly what is written on the file?
By the way, I know there are other forms to print a .txt exactly how it is made, I mean, I don't need 2D arrays to do this. However, I will use this program to read several matrixes and do some tests with them (also I want to print them as well), so I really need to store the data in a matrix of characters.
c loops fgetc
add a comment |
I'm writing a code in C to read matrixes (square matrix with 3 <= dim <= 9) from a .txt file and print it exactly how it is written. The file is arranged as follows:
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
The first number indicates the size of the subsequent matrix.
I wrote the following code:
int main ()
FILE *arquivo;
char A[9][9];
int N;
int i,j;
char temp;
arquivo = fopen("matrizes.txt", "r");
if (!arquivo) printf("Erro.n");
while (fscanf(arquivo, "%d", &N) != EOF)
printf("%d n", N);
fgetc(arquivo);
for (i = 0; ((i < N) && (temp = fgetc(arquivo)) != 'n') ; i++)
for (j = 0; j < N; j++)
A[i][j] = temp;
for (i = 0; i < N; i++)
for(j = 0; j<N; j++)
printf("%c", A[i][j]);
puts(" ");
return 0;
The output is this
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
I honestly have no idea why this is happening. I tried different conditions to stop the loop, bot none of them worked out.
If I change
while (fscanf(arquivo, "%d", &N) != EOF)
into
while (fscanf(arquivo, "%d", &N) == 1)
the output is just
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
The value of the second loop scanf in this case is "0".
How can I fix it and print exactly what is written on the file?
By the way, I know there are other forms to print a .txt exactly how it is made, I mean, I don't need 2D arrays to do this. However, I will use this program to read several matrixes and do some tests with them (also I want to print them as well), so I really need to store the data in a matrix of characters.
c loops fgetc
add a comment |
I'm writing a code in C to read matrixes (square matrix with 3 <= dim <= 9) from a .txt file and print it exactly how it is written. The file is arranged as follows:
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
The first number indicates the size of the subsequent matrix.
I wrote the following code:
int main ()
FILE *arquivo;
char A[9][9];
int N;
int i,j;
char temp;
arquivo = fopen("matrizes.txt", "r");
if (!arquivo) printf("Erro.n");
while (fscanf(arquivo, "%d", &N) != EOF)
printf("%d n", N);
fgetc(arquivo);
for (i = 0; ((i < N) && (temp = fgetc(arquivo)) != 'n') ; i++)
for (j = 0; j < N; j++)
A[i][j] = temp;
for (i = 0; i < N; i++)
for(j = 0; j<N; j++)
printf("%c", A[i][j]);
puts(" ");
return 0;
The output is this
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
I honestly have no idea why this is happening. I tried different conditions to stop the loop, bot none of them worked out.
If I change
while (fscanf(arquivo, "%d", &N) != EOF)
into
while (fscanf(arquivo, "%d", &N) == 1)
the output is just
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
The value of the second loop scanf in this case is "0".
How can I fix it and print exactly what is written on the file?
By the way, I know there are other forms to print a .txt exactly how it is made, I mean, I don't need 2D arrays to do this. However, I will use this program to read several matrixes and do some tests with them (also I want to print them as well), so I really need to store the data in a matrix of characters.
c loops fgetc
I'm writing a code in C to read matrixes (square matrix with 3 <= dim <= 9) from a .txt file and print it exactly how it is written. The file is arranged as follows:
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
The first number indicates the size of the subsequent matrix.
I wrote the following code:
int main ()
FILE *arquivo;
char A[9][9];
int N;
int i,j;
char temp;
arquivo = fopen("matrizes.txt", "r");
if (!arquivo) printf("Erro.n");
while (fscanf(arquivo, "%d", &N) != EOF)
printf("%d n", N);
fgetc(arquivo);
for (i = 0; ((i < N) && (temp = fgetc(arquivo)) != 'n') ; i++)
for (j = 0; j < N; j++)
A[i][j] = temp;
for (i = 0; i < N; i++)
for(j = 0; j<N; j++)
printf("%c", A[i][j]);
puts(" ");
return 0;
The output is this
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
6
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
XXXXXX
I honestly have no idea why this is happening. I tried different conditions to stop the loop, bot none of them worked out.
If I change
while (fscanf(arquivo, "%d", &N) != EOF)
into
while (fscanf(arquivo, "%d", &N) == 1)
the output is just
5
AAAAA
AAAAA
AAAAA
AAAAA
AAAAA
The value of the second loop scanf in this case is "0".
How can I fix it and print exactly what is written on the file?
By the way, I know there are other forms to print a .txt exactly how it is made, I mean, I don't need 2D arrays to do this. However, I will use this program to read several matrixes and do some tests with them (also I want to print them as well), so I really need to store the data in a matrix of characters.
c loops fgetc
c loops fgetc
asked Nov 14 '18 at 2:58
LucasLucas
1031
1031
add a comment |
add a comment |
1 Answer
1
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oldest
votes
The problem is here.
for (i = 0; ((i < N) && (temp = fgetc(arquivo)) != 'n') ; i++)
for (j = 0; j < N; j++)
A[i][j] = temp;
The loop will exit once it sees a newline and start the while
loop again.
Instead you want to read N lines.
for (i = 0; i < N; i++)
for(j = 0; (temp = fgetc(arquivo)) != 'n'; j++ )
A[i][j] = temp;
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The problem is here.
for (i = 0; ((i < N) && (temp = fgetc(arquivo)) != 'n') ; i++)
for (j = 0; j < N; j++)
A[i][j] = temp;
The loop will exit once it sees a newline and start the while
loop again.
Instead you want to read N lines.
for (i = 0; i < N; i++)
for(j = 0; (temp = fgetc(arquivo)) != 'n'; j++ )
A[i][j] = temp;
add a comment |
The problem is here.
for (i = 0; ((i < N) && (temp = fgetc(arquivo)) != 'n') ; i++)
for (j = 0; j < N; j++)
A[i][j] = temp;
The loop will exit once it sees a newline and start the while
loop again.
Instead you want to read N lines.
for (i = 0; i < N; i++)
for(j = 0; (temp = fgetc(arquivo)) != 'n'; j++ )
A[i][j] = temp;
add a comment |
The problem is here.
for (i = 0; ((i < N) && (temp = fgetc(arquivo)) != 'n') ; i++)
for (j = 0; j < N; j++)
A[i][j] = temp;
The loop will exit once it sees a newline and start the while
loop again.
Instead you want to read N lines.
for (i = 0; i < N; i++)
for(j = 0; (temp = fgetc(arquivo)) != 'n'; j++ )
A[i][j] = temp;
The problem is here.
for (i = 0; ((i < N) && (temp = fgetc(arquivo)) != 'n') ; i++)
for (j = 0; j < N; j++)
A[i][j] = temp;
The loop will exit once it sees a newline and start the while
loop again.
Instead you want to read N lines.
for (i = 0; i < N; i++)
for(j = 0; (temp = fgetc(arquivo)) != 'n'; j++ )
A[i][j] = temp;
answered Nov 14 '18 at 3:09
SchwernSchwern
90.3k17102233
90.3k17102233
add a comment |
add a comment |
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