http error 404 resource not found in spring mvc [duplicate]

-1

This question already has an answer here:

Why does Spring MVC respond with a 404 and report “No mapping found for HTTP request with URI […] in DispatcherServlet”?

6 answers

web.xml

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee"xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0"> 
 <display-name>ValidationForm</display-name> 
<servlet> 
<servlet-name>spring-dispatcher</servlet-name> 
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> </web-app> spring-dispatcher-servlet.xml <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
 http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0"> 
 <display-name> ValidationForm</display-name> <servlet> 
<servlet-name>spring-dispatcher</servlet-name> 
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> 
<servlet-mapping> 
<servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> 
</web-app>

index.jsp

 <%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%> 
<!DOCTYPE html> 
<html> 
<head> 
<meta charset="ISO-8859-1"> 
<title>Insert title here</title> 
</head> 
<body> 
<form action="/wel" method="post"> 
name:<input type="text" name="name" placeholder="UserName"> 
<br> password:<input type="password" name="pass" placeholder="Password"> 
<br> 
<input type="submit" value="login"> 
</form> 
</body> 
</html>

HomeController.java

 package jbr.springmvc.controller; 
 import javax.servlet.http.HttpServletRequest; 
 import javax.servlet.http.HttpServletResponse; 
 import org.springframework.stereotype.Controller; 
 import org.springframework.web.bind.annotation.RequestMapping; 
 import org.springframework.web.bind.annotation.RequestMethod; 
 import org.springframework.web.servlet.ModelAndView; 

 @Controller public class HomeController 
 @RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
 public ModelAndView hello(HttpServletRequest req,HttpServletResponse res) 

String name=req.getParameter("name");
String pass=req.getParameter("pass"); 

if(name.equals("mohit")&&pass.equals("admin")) 
String messege="Welcome"+name; 

return new ModelAndView("welcomepage","message",messege); 
 
else 
 return new ModelAndView("errorpage","message","Authantication Failed");

in this this will show error 404 resource not found i really dont know what happened into this becoz i am in new on spring. please help guys.
thanks in advance.

edited Nov 14 '18 at 8:11

georges van

2,29622438

asked Nov 14 '18 at 7:56

Mohit Aggarwal

marked as duplicate by Raedwald, BalusC java
Users with the java badge can single-handedly close java questions as duplicates and reopen them as needed.

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Nov 14 '18 at 10:08

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

You have to at least format it properly first, and provide project structure

– nguyentaijs
Nov 14 '18 at 8:10

Have you a welcomepage.jsp?

– achAmháin
Nov 14 '18 at 8:25

yeh i have welcomepage and errorpage as well

– Mohit Aggarwal
Nov 14 '18 at 8:55

add a comment |

-1

This question already has an answer here:

Why does Spring MVC respond with a 404 and report “No mapping found for HTTP request with URI […] in DispatcherServlet”?

6 answers

web.xml

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee"xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0"> 
 <display-name>ValidationForm</display-name> 
<servlet> 
<servlet-name>spring-dispatcher</servlet-name> 
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> </web-app> spring-dispatcher-servlet.xml <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
 http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0"> 
 <display-name> ValidationForm</display-name> <servlet> 
<servlet-name>spring-dispatcher</servlet-name> 
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> 
<servlet-mapping> 
<servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> 
</web-app>

index.jsp

 <%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%> 
<!DOCTYPE html> 
<html> 
<head> 
<meta charset="ISO-8859-1"> 
<title>Insert title here</title> 
</head> 
<body> 
<form action="/wel" method="post"> 
name:<input type="text" name="name" placeholder="UserName"> 
<br> password:<input type="password" name="pass" placeholder="Password"> 
<br> 
<input type="submit" value="login"> 
</form> 
</body> 
</html>

HomeController.java

 package jbr.springmvc.controller; 
 import javax.servlet.http.HttpServletRequest; 
 import javax.servlet.http.HttpServletResponse; 
 import org.springframework.stereotype.Controller; 
 import org.springframework.web.bind.annotation.RequestMapping; 
 import org.springframework.web.bind.annotation.RequestMethod; 
 import org.springframework.web.servlet.ModelAndView; 

 @Controller public class HomeController 
 @RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
 public ModelAndView hello(HttpServletRequest req,HttpServletResponse res) 

String name=req.getParameter("name");
String pass=req.getParameter("pass"); 

if(name.equals("mohit")&&pass.equals("admin")) 
String messege="Welcome"+name; 

return new ModelAndView("welcomepage","message",messege); 
 
else 
 return new ModelAndView("errorpage","message","Authantication Failed");

in this this will show error 404 resource not found i really dont know what happened into this becoz i am in new on spring. please help guys.
thanks in advance.

edited Nov 14 '18 at 8:11

georges van

2,29622438

asked Nov 14 '18 at 7:56

Mohit Aggarwal

marked as duplicate by Raedwald, BalusC java
Users with the java badge can single-handedly close java questions as duplicates and reopen them as needed.

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$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
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StackExchange.helpers.removeMessages();

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Nov 14 '18 at 10:08

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

You have to at least format it properly first, and provide project structure

– nguyentaijs
Nov 14 '18 at 8:10

Have you a welcomepage.jsp?

– achAmháin
Nov 14 '18 at 8:25

yeh i have welcomepage and errorpage as well

– Mohit Aggarwal
Nov 14 '18 at 8:55

add a comment |

-1

This question already has an answer here:

Why does Spring MVC respond with a 404 and report “No mapping found for HTTP request with URI […] in DispatcherServlet”?

6 answers

web.xml

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee"xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0"> 
 <display-name>ValidationForm</display-name> 
<servlet> 
<servlet-name>spring-dispatcher</servlet-name> 
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> </web-app> spring-dispatcher-servlet.xml <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
 http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0"> 
 <display-name> ValidationForm</display-name> <servlet> 
<servlet-name>spring-dispatcher</servlet-name> 
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> 
<servlet-mapping> 
<servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> 
</web-app>

index.jsp

 <%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%> 
<!DOCTYPE html> 
<html> 
<head> 
<meta charset="ISO-8859-1"> 
<title>Insert title here</title> 
</head> 
<body> 
<form action="/wel" method="post"> 
name:<input type="text" name="name" placeholder="UserName"> 
<br> password:<input type="password" name="pass" placeholder="Password"> 
<br> 
<input type="submit" value="login"> 
</form> 
</body> 
</html>

HomeController.java

 package jbr.springmvc.controller; 
 import javax.servlet.http.HttpServletRequest; 
 import javax.servlet.http.HttpServletResponse; 
 import org.springframework.stereotype.Controller; 
 import org.springframework.web.bind.annotation.RequestMapping; 
 import org.springframework.web.bind.annotation.RequestMethod; 
 import org.springframework.web.servlet.ModelAndView; 

 @Controller public class HomeController 
 @RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
 public ModelAndView hello(HttpServletRequest req,HttpServletResponse res) 

String name=req.getParameter("name");
String pass=req.getParameter("pass"); 

if(name.equals("mohit")&&pass.equals("admin")) 
String messege="Welcome"+name; 

return new ModelAndView("welcomepage","message",messege); 
 
else 
 return new ModelAndView("errorpage","message","Authantication Failed");

in this this will show error 404 resource not found i really dont know what happened into this becoz i am in new on spring. please help guys.
thanks in advance.

edited Nov 14 '18 at 8:11

georges van

2,29622438

asked Nov 14 '18 at 7:56

Mohit Aggarwal

This question already has an answer here:

Why does Spring MVC respond with a 404 and report “No mapping found for HTTP request with URI […] in DispatcherServlet”?

6 answers

web.xml

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee"xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0"> 
 <display-name>ValidationForm</display-name> 
<servlet> 
<servlet-name>spring-dispatcher</servlet-name> 
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> </web-app> spring-dispatcher-servlet.xml <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
 http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0"> 
 <display-name> ValidationForm</display-name> <servlet> 
<servlet-name>spring-dispatcher</servlet-name> 
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> 
<servlet-mapping> 
<servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> 
</web-app>

index.jsp

 <%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%> 
<!DOCTYPE html> 
<html> 
<head> 
<meta charset="ISO-8859-1"> 
<title>Insert title here</title> 
</head> 
<body> 
<form action="/wel" method="post"> 
name:<input type="text" name="name" placeholder="UserName"> 
<br> password:<input type="password" name="pass" placeholder="Password"> 
<br> 
<input type="submit" value="login"> 
</form> 
</body> 
</html>

HomeController.java

 package jbr.springmvc.controller; 
 import javax.servlet.http.HttpServletRequest; 
 import javax.servlet.http.HttpServletResponse; 
 import org.springframework.stereotype.Controller; 
 import org.springframework.web.bind.annotation.RequestMapping; 
 import org.springframework.web.bind.annotation.RequestMethod; 
 import org.springframework.web.servlet.ModelAndView; 

 @Controller public class HomeController 
 @RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
 public ModelAndView hello(HttpServletRequest req,HttpServletResponse res) 

String name=req.getParameter("name");
String pass=req.getParameter("pass"); 

if(name.equals("mohit")&&pass.equals("admin")) 
String messege="Welcome"+name; 

return new ModelAndView("welcomepage","message",messege); 
 
else 
 return new ModelAndView("errorpage","message","Authantication Failed");

in this this will show error 404 resource not found i really dont know what happened into this becoz i am in new on spring. please help guys.
thanks in advance.

This question already has an answer here:

Why does Spring MVC respond with a 404 and report “No mapping found for HTTP request with URI […] in DispatcherServlet”?

6 answers

java xml spring spring-mvc servlets

edited Nov 14 '18 at 8:11

georges van

2,29622438

asked Nov 14 '18 at 7:56

Mohit Aggarwal

edited Nov 14 '18 at 8:11

georges van

2,29622438

asked Nov 14 '18 at 7:56

Mohit Aggarwal

edited Nov 14 '18 at 8:11

georges van

2,29622438

edited Nov 14 '18 at 8:11

georges van

2,29622438

edited Nov 14 '18 at 8:11

georges van

2,29622438

asked Nov 14 '18 at 7:56

Mohit Aggarwal

asked Nov 14 '18 at 7:56

Mohit Aggarwal

asked Nov 14 '18 at 7:56

Mohit Aggarwal

marked as duplicate by Raedwald, BalusC java
Users with the java badge can single-handedly close java questions as duplicates and reopen them as needed.

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$hover.showInfoMessage('',
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Nov 14 '18 at 10:08

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

marked as duplicate by Raedwald, BalusC java
Users with the java badge can single-handedly close java questions as duplicates and reopen them as needed.

StackExchange.ready(function()
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$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();

);
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Nov 14 '18 at 10:08

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

You have to at least format it properly first, and provide project structure

– nguyentaijs
Nov 14 '18 at 8:10

Have you a welcomepage.jsp?

– achAmháin
Nov 14 '18 at 8:25

yeh i have welcomepage and errorpage as well

– Mohit Aggarwal
Nov 14 '18 at 8:55

add a comment |

You have to at least format it properly first, and provide project structure

– nguyentaijs
Nov 14 '18 at 8:10

Have you a welcomepage.jsp?

– achAmháin
Nov 14 '18 at 8:25

yeh i have welcomepage and errorpage as well

– Mohit Aggarwal
Nov 14 '18 at 8:55

You have to at least format it properly first, and provide project structure

– nguyentaijs
Nov 14 '18 at 8:10

Have you a welcomepage.jsp?

– achAmháin
Nov 14 '18 at 8:25

yeh i have welcomepage and errorpage as well

– Mohit Aggarwal
Nov 14 '18 at 8:55

add a comment |

2 Answers
2

active

oldest

votes

-1

As i checked this code is working:

Web.xml:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>ValidationForm</display-name>


<servlet>
 <servlet-name>spring-dispatcher</servlet-name>
 <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
 <init-param>
 <param-name>contextConfigLocation</param-name>
 <param-value>/WEB-INF/spring-servlet.xml</param-value>
 </init-param>
 <load-on-startup>1</load-on-startup>

</servlet>
<servlet-mapping>
 <servlet-name>spring-dispatcher</servlet-name>
 <url-pattern>/</url-pattern>
</servlet-mapping>

Spring-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc 
http://www.springframework.org/schema/mvc/spring-mvc.xsd
 http://www.springframework.org/schema/beans 
http://www.springframework.org/schema/beans/spring-beans.xsd
 http://www.springframework.org/schema/context 
http://www.springframework.org/schema/context/spring-context.xsd">

<annotation-driven />
<context:component-scan base-package="com.demo.spring" />
<beans:bean
 class="org.springframework.web.servlet.view.InternalResourceViewResolver">
 <beans:property name="prefix" value="/WEB-INF/views/" />
 <beans:property name="suffix" value=".jsp" />
</beans:bean>

HomeController:

package com.demo.spring.controller;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;

@Controller
public class HomeController 
@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView welcome() 
 return new ModelAndView("welcome");


@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req, HttpServletResponse res) 

 String name = req.getParameter("name");
 String pass = req.getParameter("pass");

 if (name.equals("mohit") && pass.equals("admin")) 
 String messege = "Welcome" + name;

 return new ModelAndView("welcome", "message", messege);
 else 
 return new ModelAndView("errorpage", "message", "Authantication Failed");

Try to use it

answered Nov 14 '18 at 9:15

Ravi Developer

7819

add a comment |

-1

You need to configure your view resolver.

1. first create spring-dispatcher.xml file.
2. Add view resolver configuration in your xml file.
 <beans:property name="prefix" value="/WEB-INF/views/" />
 <beans:property name="suffix" value=".jsp" />
3. place jsp file in views folder under webapp--> WEB-INF.
4. Now view resolver will find jsp at this path " /WEB-INF/views/yoursjspname.jsp ".

answered Nov 14 '18 at 9:20

Dildeep Singh

447

add a comment |

2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

-1

As i checked this code is working:

Web.xml:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>ValidationForm</display-name>


<servlet>
 <servlet-name>spring-dispatcher</servlet-name>
 <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
 <init-param>
 <param-name>contextConfigLocation</param-name>
 <param-value>/WEB-INF/spring-servlet.xml</param-value>
 </init-param>
 <load-on-startup>1</load-on-startup>

</servlet>
<servlet-mapping>
 <servlet-name>spring-dispatcher</servlet-name>
 <url-pattern>/</url-pattern>
</servlet-mapping>

Spring-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc 
http://www.springframework.org/schema/mvc/spring-mvc.xsd
 http://www.springframework.org/schema/beans 
http://www.springframework.org/schema/beans/spring-beans.xsd
 http://www.springframework.org/schema/context 
http://www.springframework.org/schema/context/spring-context.xsd">

<annotation-driven />
<context:component-scan base-package="com.demo.spring" />
<beans:bean
 class="org.springframework.web.servlet.view.InternalResourceViewResolver">
 <beans:property name="prefix" value="/WEB-INF/views/" />
 <beans:property name="suffix" value=".jsp" />
</beans:bean>

HomeController:

package com.demo.spring.controller;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;

@Controller
public class HomeController 
@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView welcome() 
 return new ModelAndView("welcome");


@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req, HttpServletResponse res) 

 String name = req.getParameter("name");
 String pass = req.getParameter("pass");

 if (name.equals("mohit") && pass.equals("admin")) 
 String messege = "Welcome" + name;

 return new ModelAndView("welcome", "message", messege);
 else 
 return new ModelAndView("errorpage", "message", "Authantication Failed");

Try to use it

answered Nov 14 '18 at 9:15

Ravi Developer

7819

add a comment |

-1

As i checked this code is working:

Web.xml:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>ValidationForm</display-name>


<servlet>
 <servlet-name>spring-dispatcher</servlet-name>
 <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
 <init-param>
 <param-name>contextConfigLocation</param-name>
 <param-value>/WEB-INF/spring-servlet.xml</param-value>
 </init-param>
 <load-on-startup>1</load-on-startup>

</servlet>
<servlet-mapping>
 <servlet-name>spring-dispatcher</servlet-name>
 <url-pattern>/</url-pattern>
</servlet-mapping>

Spring-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc 
http://www.springframework.org/schema/mvc/spring-mvc.xsd
 http://www.springframework.org/schema/beans 
http://www.springframework.org/schema/beans/spring-beans.xsd
 http://www.springframework.org/schema/context 
http://www.springframework.org/schema/context/spring-context.xsd">

<annotation-driven />
<context:component-scan base-package="com.demo.spring" />
<beans:bean
 class="org.springframework.web.servlet.view.InternalResourceViewResolver">
 <beans:property name="prefix" value="/WEB-INF/views/" />
 <beans:property name="suffix" value=".jsp" />
</beans:bean>

HomeController:

package com.demo.spring.controller;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;

@Controller
public class HomeController 
@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView welcome() 
 return new ModelAndView("welcome");


@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req, HttpServletResponse res) 

 String name = req.getParameter("name");
 String pass = req.getParameter("pass");

 if (name.equals("mohit") && pass.equals("admin")) 
 String messege = "Welcome" + name;

 return new ModelAndView("welcome", "message", messege);
 else 
 return new ModelAndView("errorpage", "message", "Authantication Failed");

Try to use it

answered Nov 14 '18 at 9:15

Ravi Developer

7819

add a comment |

-1

As i checked this code is working:

Web.xml:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>ValidationForm</display-name>


<servlet>
 <servlet-name>spring-dispatcher</servlet-name>
 <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
 <init-param>
 <param-name>contextConfigLocation</param-name>
 <param-value>/WEB-INF/spring-servlet.xml</param-value>
 </init-param>
 <load-on-startup>1</load-on-startup>

</servlet>
<servlet-mapping>
 <servlet-name>spring-dispatcher</servlet-name>
 <url-pattern>/</url-pattern>
</servlet-mapping>

Spring-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc 
http://www.springframework.org/schema/mvc/spring-mvc.xsd
 http://www.springframework.org/schema/beans 
http://www.springframework.org/schema/beans/spring-beans.xsd
 http://www.springframework.org/schema/context 
http://www.springframework.org/schema/context/spring-context.xsd">

<annotation-driven />
<context:component-scan base-package="com.demo.spring" />
<beans:bean
 class="org.springframework.web.servlet.view.InternalResourceViewResolver">
 <beans:property name="prefix" value="/WEB-INF/views/" />
 <beans:property name="suffix" value=".jsp" />
</beans:bean>

HomeController:

package com.demo.spring.controller;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;

@Controller
public class HomeController 
@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView welcome() 
 return new ModelAndView("welcome");


@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req, HttpServletResponse res) 

 String name = req.getParameter("name");
 String pass = req.getParameter("pass");

 if (name.equals("mohit") && pass.equals("admin")) 
 String messege = "Welcome" + name;

 return new ModelAndView("welcome", "message", messege);
 else 
 return new ModelAndView("errorpage", "message", "Authantication Failed");

Try to use it

answered Nov 14 '18 at 9:15

Ravi Developer

7819

As i checked this code is working:

Web.xml:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>ValidationForm</display-name>


<servlet>
 <servlet-name>spring-dispatcher</servlet-name>
 <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
 <init-param>
 <param-name>contextConfigLocation</param-name>
 <param-value>/WEB-INF/spring-servlet.xml</param-value>
 </init-param>
 <load-on-startup>1</load-on-startup>

</servlet>
<servlet-mapping>
 <servlet-name>spring-dispatcher</servlet-name>
 <url-pattern>/</url-pattern>
</servlet-mapping>

Spring-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc 
http://www.springframework.org/schema/mvc/spring-mvc.xsd
 http://www.springframework.org/schema/beans 
http://www.springframework.org/schema/beans/spring-beans.xsd
 http://www.springframework.org/schema/context 
http://www.springframework.org/schema/context/spring-context.xsd">

<annotation-driven />
<context:component-scan base-package="com.demo.spring" />
<beans:bean
 class="org.springframework.web.servlet.view.InternalResourceViewResolver">
 <beans:property name="prefix" value="/WEB-INF/views/" />
 <beans:property name="suffix" value=".jsp" />
</beans:bean>

HomeController:

package com.demo.spring.controller;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;

@Controller
public class HomeController 
@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView welcome() 
 return new ModelAndView("welcome");


@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req, HttpServletResponse res) 

 String name = req.getParameter("name");
 String pass = req.getParameter("pass");

 if (name.equals("mohit") && pass.equals("admin")) 
 String messege = "Welcome" + name;

 return new ModelAndView("welcome", "message", messege);
 else 
 return new ModelAndView("errorpage", "message", "Authantication Failed");

Try to use it

answered Nov 14 '18 at 9:15

Ravi Developer

7819

answered Nov 14 '18 at 9:15

Ravi Developer

7819

answered Nov 14 '18 at 9:15

Ravi Developer

7819

answered Nov 14 '18 at 9:15

Ravi Developer

7819

add a comment |

-1

You need to configure your view resolver.

1. first create spring-dispatcher.xml file.
2. Add view resolver configuration in your xml file.
 <beans:property name="prefix" value="/WEB-INF/views/" />
 <beans:property name="suffix" value=".jsp" />
3. place jsp file in views folder under webapp--> WEB-INF.
4. Now view resolver will find jsp at this path " /WEB-INF/views/yoursjspname.jsp ".

answered Nov 14 '18 at 9:20

Dildeep Singh

447

add a comment |

-1

You need to configure your view resolver.

1. first create spring-dispatcher.xml file.
2. Add view resolver configuration in your xml file.
 <beans:property name="prefix" value="/WEB-INF/views/" />
 <beans:property name="suffix" value=".jsp" />
3. place jsp file in views folder under webapp--> WEB-INF.
4. Now view resolver will find jsp at this path " /WEB-INF/views/yoursjspname.jsp ".

answered Nov 14 '18 at 9:20

Dildeep Singh

447

add a comment |

-1

You need to configure your view resolver.

1. first create spring-dispatcher.xml file.
2. Add view resolver configuration in your xml file.
 <beans:property name="prefix" value="/WEB-INF/views/" />
 <beans:property name="suffix" value=".jsp" />
3. place jsp file in views folder under webapp--> WEB-INF.
4. Now view resolver will find jsp at this path " /WEB-INF/views/yoursjspname.jsp ".

answered Nov 14 '18 at 9:20

Dildeep Singh

447

You need to configure your view resolver.

1. first create spring-dispatcher.xml file.
2. Add view resolver configuration in your xml file.
 <beans:property name="prefix" value="/WEB-INF/views/" />
 <beans:property name="suffix" value=".jsp" />
3. place jsp file in views folder under webapp--> WEB-INF.
4. Now view resolver will find jsp at this path " /WEB-INF/views/yoursjspname.jsp ".

answered Nov 14 '18 at 9:20

Dildeep Singh

447

answered Nov 14 '18 at 9:20

Dildeep Singh

447

answered Nov 14 '18 at 9:20

Dildeep Singh

447

answered Nov 14 '18 at 9:20

Dildeep Singh

447

add a comment |

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