Pfthb

def quantity():
 global amount 
 amount = input('How many tickets are you looking for? ')
 if amount == range(1,7):
 print('You have selected tickets '.format(amount))
 elif amount == (0):
 print('You have selected 0 tickets')
 else:
 print('Please choose an amount between 0-6')

I'm trying to create ticket cost calculator to jog my memory but I was stumped on the IF statement for the quantity section because it only prints the ELSE even when IF and ELIF are true.

1.The range function in python3 returns an iteration type.

2.The input function in python3 returns a string and should be converted to an integer.
Try this:

amount = int(input('How many tickets are you looking for? '))
if amount in range(1,7):
 print('You have selected tickets '.format(amount))
elif amount == (0):
 print('You have selected 0 tickets')
else:
 print('Please choose an amount between 0-6')

You want

if amount in range(1,7):

rather than what you currently have,

if amount == range(1,7):

It's a bit more complicated in reality (because it returns a generator rather than a list), but you can conceptualize range(1,7) as a function that returns a list of numbers in that range. e.g.

range(1,7) ~~ [1, 2, 3, 4, 5, 6]

If your amount is an integer, you want to see if it's in that range, not if it is that range - after all, an integer cannot be a list at the same time.

[edit]: As one of the other answers pointed out, you might also want to cast the result of your input() to an int - as input() generally returns a string.

Try this code use in for ==

def quantity():
 global amount 
 amount = input('How many tickets are you looking for? ')
 if amount in range(1,7):
 print('You have selected tickets '.format(amount))
 elif amount == (0):
 print('You have selected 0 tickets')
 else:
 print('Please choose an amount between 0-6')

You have to convert the input() from a string into an integer, otherwise you will always run the else statement. You can do that with int(), but will likely have to do some error handling in case the user enters something that cannot be converted to an integer.

I have made some changes to your code. I believe this is what you are looking for.

def quantity():
 global amount
 amount = int(input('How many tickets are you looking for? '))
 if amount in range(1,7):
 print('You have selected tickets '.format(amount))
 elif amount ==0 :
 print('You have selected 0 tickets')
 else:
 print('Please choose an amount between 0-6')

Instead of using if amount == range(1,7): use if amount in range(1,7):

This is the modified code that you should use:

def quantity():
 global amount 
 amount = input('How many tickets are you looking for? ')
 if amount in range(1,7):
 print('You have selected tickets '.format(amount))
 elif amount == (0):
 print('You have selected 0 tickets')
 else:
 print('Please choose an amount between 0-6')

input returns a string, so I guess you should be doing amount = int(input('...')).