Draw only part of geojson using d3?



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0















https://raw.githubusercontent.com/Neogeografen/dagi/master/geojson/kommuner.geojson



What if for example I only want to draw regions where property X has value Y?



Current code for drawing all of a geojson:



 let u = d3.select('#el')
.selectAll('path')
.data(features);

u.enter()
.append('path')
.attr('d', geoGenerator)









share|improve this question

















  • 1





    just apply a Array.filter() on your features Array

    – rioV8
    Nov 15 '18 at 18:02

















0















https://raw.githubusercontent.com/Neogeografen/dagi/master/geojson/kommuner.geojson



What if for example I only want to draw regions where property X has value Y?



Current code for drawing all of a geojson:



 let u = d3.select('#el')
.selectAll('path')
.data(features);

u.enter()
.append('path')
.attr('d', geoGenerator)









share|improve this question

















  • 1





    just apply a Array.filter() on your features Array

    – rioV8
    Nov 15 '18 at 18:02













0












0








0








https://raw.githubusercontent.com/Neogeografen/dagi/master/geojson/kommuner.geojson



What if for example I only want to draw regions where property X has value Y?



Current code for drawing all of a geojson:



 let u = d3.select('#el')
.selectAll('path')
.data(features);

u.enter()
.append('path')
.attr('d', geoGenerator)









share|improve this question














https://raw.githubusercontent.com/Neogeografen/dagi/master/geojson/kommuner.geojson



What if for example I only want to draw regions where property X has value Y?



Current code for drawing all of a geojson:



 let u = d3.select('#el')
.selectAll('path')
.data(features);

u.enter()
.append('path')
.attr('d', geoGenerator)






d3.js geojson






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 15 '18 at 17:16









user3761308user3761308

137415




137415







  • 1





    just apply a Array.filter() on your features Array

    – rioV8
    Nov 15 '18 at 18:02












  • 1





    just apply a Array.filter() on your features Array

    – rioV8
    Nov 15 '18 at 18:02







1




1





just apply a Array.filter() on your features Array

– rioV8
Nov 15 '18 at 18:02





just apply a Array.filter() on your features Array

– rioV8
Nov 15 '18 at 18:02












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