Why do I get the error “cannot infer type” when using futures::ok?
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I know there is join_all
but it cannot infer type:
extern crate futures; // 0.1.25
use futures::future::ok as fut_ok;
fn main()
let tasks = vec![fut_ok(1), fut_ok(2), fut_ok(3)];
println!(":?", futures::future::join_all(tasks).wait().unwrap());
I got this error:
let tasks = vec![fut_ok(1), fut_ok(2), fut_ok(3)];
----- ^^^^^^ cannot infer type for `E`
|
consider giving `tasks` a type
rust future
add a comment |
I know there is join_all
but it cannot infer type:
extern crate futures; // 0.1.25
use futures::future::ok as fut_ok;
fn main()
let tasks = vec![fut_ok(1), fut_ok(2), fut_ok(3)];
println!(":?", futures::future::join_all(tasks).wait().unwrap());
I got this error:
let tasks = vec![fut_ok(1), fut_ok(2), fut_ok(3)];
----- ^^^^^^ cannot infer type for `E`
|
consider giving `tasks` a type
rust future
Have you consider to consider givingtasks
a type ?let tasks : Vec<FutureResult<_, ()>> = vec![fut_ok(1u32), fut_ok(2), fut_ok(3)];
orlet tasks = vec![fut_ok::<_, ()>(1), fut_ok(2), fut_ok(3)];
– Stargateur
Nov 15 '18 at 13:34
add a comment |
I know there is join_all
but it cannot infer type:
extern crate futures; // 0.1.25
use futures::future::ok as fut_ok;
fn main()
let tasks = vec![fut_ok(1), fut_ok(2), fut_ok(3)];
println!(":?", futures::future::join_all(tasks).wait().unwrap());
I got this error:
let tasks = vec![fut_ok(1), fut_ok(2), fut_ok(3)];
----- ^^^^^^ cannot infer type for `E`
|
consider giving `tasks` a type
rust future
I know there is join_all
but it cannot infer type:
extern crate futures; // 0.1.25
use futures::future::ok as fut_ok;
fn main()
let tasks = vec![fut_ok(1), fut_ok(2), fut_ok(3)];
println!(":?", futures::future::join_all(tasks).wait().unwrap());
I got this error:
let tasks = vec![fut_ok(1), fut_ok(2), fut_ok(3)];
----- ^^^^^^ cannot infer type for `E`
|
consider giving `tasks` a type
rust future
rust future
edited Nov 16 '18 at 2:05
Shepmaster
162k16333477
162k16333477
asked Nov 15 '18 at 13:09
rofrolrofrol
7,92534649
7,92534649
Have you consider to consider givingtasks
a type ?let tasks : Vec<FutureResult<_, ()>> = vec![fut_ok(1u32), fut_ok(2), fut_ok(3)];
orlet tasks = vec![fut_ok::<_, ()>(1), fut_ok(2), fut_ok(3)];
– Stargateur
Nov 15 '18 at 13:34
add a comment |
Have you consider to consider givingtasks
a type ?let tasks : Vec<FutureResult<_, ()>> = vec![fut_ok(1u32), fut_ok(2), fut_ok(3)];
orlet tasks = vec![fut_ok::<_, ()>(1), fut_ok(2), fut_ok(3)];
– Stargateur
Nov 15 '18 at 13:34
Have you consider to consider giving
tasks
a type ? let tasks : Vec<FutureResult<_, ()>> = vec![fut_ok(1u32), fut_ok(2), fut_ok(3)];
or let tasks = vec![fut_ok::<_, ()>(1), fut_ok(2), fut_ok(3)];
– Stargateur
Nov 15 '18 at 13:34
Have you consider to consider giving
tasks
a type ? let tasks : Vec<FutureResult<_, ()>> = vec![fut_ok(1u32), fut_ok(2), fut_ok(3)];
or let tasks = vec![fut_ok::<_, ()>(1), fut_ok(2), fut_ok(3)];
– Stargateur
Nov 15 '18 at 13:34
add a comment |
2 Answers
2
active
oldest
votes
The problem is that any future may in theory return an error. So the FutureResult
type (which is returned from fut_ok
) is generic with two type parameters: a type T
for success and a type E
for errors.
If this was real code instead of a toy example, you would have some error handling code that would allow the compiler to infer type E
. In this case you need to specify it, but since you don't use it you can use the empty type ()
. So either of the following should work:
let tasks: Vec<FutureResult<_, ()>> = vec![fut_ok(1), fut_ok(2), fut_ok(3)];
or
let tasks = vec![fut_ok::<_, ()>(1), fut_ok(2), fut_ok(3)];
Note that the first is what the compiler means when it says: "consider giving tasks
a type".
nice. And how to print the result?println!(":?", futures::future::join_all(tasks).wait()?);
the traitstd::error::Error
is not implemented for()
– rofrol
Nov 15 '18 at 13:38
add a comment |
Full example
extern crate futures; // 0.1.25
use futures::future::ok as fut_ok;
use futures::future::FutureResult;
fn main() _
Prints Ok([1, 2, 3])
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The problem is that any future may in theory return an error. So the FutureResult
type (which is returned from fut_ok
) is generic with two type parameters: a type T
for success and a type E
for errors.
If this was real code instead of a toy example, you would have some error handling code that would allow the compiler to infer type E
. In this case you need to specify it, but since you don't use it you can use the empty type ()
. So either of the following should work:
let tasks: Vec<FutureResult<_, ()>> = vec![fut_ok(1), fut_ok(2), fut_ok(3)];
or
let tasks = vec![fut_ok::<_, ()>(1), fut_ok(2), fut_ok(3)];
Note that the first is what the compiler means when it says: "consider giving tasks
a type".
nice. And how to print the result?println!(":?", futures::future::join_all(tasks).wait()?);
the traitstd::error::Error
is not implemented for()
– rofrol
Nov 15 '18 at 13:38
add a comment |
The problem is that any future may in theory return an error. So the FutureResult
type (which is returned from fut_ok
) is generic with two type parameters: a type T
for success and a type E
for errors.
If this was real code instead of a toy example, you would have some error handling code that would allow the compiler to infer type E
. In this case you need to specify it, but since you don't use it you can use the empty type ()
. So either of the following should work:
let tasks: Vec<FutureResult<_, ()>> = vec![fut_ok(1), fut_ok(2), fut_ok(3)];
or
let tasks = vec![fut_ok::<_, ()>(1), fut_ok(2), fut_ok(3)];
Note that the first is what the compiler means when it says: "consider giving tasks
a type".
nice. And how to print the result?println!(":?", futures::future::join_all(tasks).wait()?);
the traitstd::error::Error
is not implemented for()
– rofrol
Nov 15 '18 at 13:38
add a comment |
The problem is that any future may in theory return an error. So the FutureResult
type (which is returned from fut_ok
) is generic with two type parameters: a type T
for success and a type E
for errors.
If this was real code instead of a toy example, you would have some error handling code that would allow the compiler to infer type E
. In this case you need to specify it, but since you don't use it you can use the empty type ()
. So either of the following should work:
let tasks: Vec<FutureResult<_, ()>> = vec![fut_ok(1), fut_ok(2), fut_ok(3)];
or
let tasks = vec![fut_ok::<_, ()>(1), fut_ok(2), fut_ok(3)];
Note that the first is what the compiler means when it says: "consider giving tasks
a type".
The problem is that any future may in theory return an error. So the FutureResult
type (which is returned from fut_ok
) is generic with two type parameters: a type T
for success and a type E
for errors.
If this was real code instead of a toy example, you would have some error handling code that would allow the compiler to infer type E
. In this case you need to specify it, but since you don't use it you can use the empty type ()
. So either of the following should work:
let tasks: Vec<FutureResult<_, ()>> = vec![fut_ok(1), fut_ok(2), fut_ok(3)];
or
let tasks = vec![fut_ok::<_, ()>(1), fut_ok(2), fut_ok(3)];
Note that the first is what the compiler means when it says: "consider giving tasks
a type".
answered Nov 15 '18 at 13:34
JmbJmb
2,960525
2,960525
nice. And how to print the result?println!(":?", futures::future::join_all(tasks).wait()?);
the traitstd::error::Error
is not implemented for()
– rofrol
Nov 15 '18 at 13:38
add a comment |
nice. And how to print the result?println!(":?", futures::future::join_all(tasks).wait()?);
the traitstd::error::Error
is not implemented for()
– rofrol
Nov 15 '18 at 13:38
nice. And how to print the result?
println!(":?", futures::future::join_all(tasks).wait()?);
the trait std::error::Error
is not implemented for ()
– rofrol
Nov 15 '18 at 13:38
nice. And how to print the result?
println!(":?", futures::future::join_all(tasks).wait()?);
the trait std::error::Error
is not implemented for ()
– rofrol
Nov 15 '18 at 13:38
add a comment |
Full example
extern crate futures; // 0.1.25
use futures::future::ok as fut_ok;
use futures::future::FutureResult;
fn main() _
Prints Ok([1, 2, 3])
add a comment |
Full example
extern crate futures; // 0.1.25
use futures::future::ok as fut_ok;
use futures::future::FutureResult;
fn main() _
Prints Ok([1, 2, 3])
add a comment |
Full example
extern crate futures; // 0.1.25
use futures::future::ok as fut_ok;
use futures::future::FutureResult;
fn main() _
Prints Ok([1, 2, 3])
Full example
extern crate futures; // 0.1.25
use futures::future::ok as fut_ok;
use futures::future::FutureResult;
fn main() _
Prints Ok([1, 2, 3])
answered Nov 15 '18 at 15:20
rofrolrofrol
7,92534649
7,92534649
add a comment |
add a comment |
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Have you consider to consider giving
tasks
a type ?let tasks : Vec<FutureResult<_, ()>> = vec![fut_ok(1u32), fut_ok(2), fut_ok(3)];
orlet tasks = vec![fut_ok::<_, ()>(1), fut_ok(2), fut_ok(3)];
– Stargateur
Nov 15 '18 at 13:34