Validating age using a function in MySQL
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so i'm having some issues using a function in SQL where i calculate the age given a certain date. The thing is that i need to validate with the current date and the date of birth if it's already the year or not.
For example the date i have in a register is 1994-11-15 and when consulting the information with
select EmployeeID Num_Emloyee, concat(FirstName, " . ", LastName) Name_Employee, Title Puesto, fn_Age(BirthDate) Edad, fn_Age(HireDate) WorkYears
from employees;
It returns 24, however if i only consult with select the function it returns 23, the correct answer.
At the moment this is the function i'm using to validate the age is this:
create function fn_Age(dateVal date)
returns int
begin
declare age int;
if day(now()) and month(now()) >= day(dateVal) and month(dateVal) then
set age=year(now())-year(dateVal);
else
set age=(year(now())-year(dateVal)) - 1;
end if;
return age;
end
Is there anything i'm not considering in the function?
mysql sql
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up vote
0
down vote
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so i'm having some issues using a function in SQL where i calculate the age given a certain date. The thing is that i need to validate with the current date and the date of birth if it's already the year or not.
For example the date i have in a register is 1994-11-15 and when consulting the information with
select EmployeeID Num_Emloyee, concat(FirstName, " . ", LastName) Name_Employee, Title Puesto, fn_Age(BirthDate) Edad, fn_Age(HireDate) WorkYears
from employees;
It returns 24, however if i only consult with select the function it returns 23, the correct answer.
At the moment this is the function i'm using to validate the age is this:
create function fn_Age(dateVal date)
returns int
begin
declare age int;
if day(now()) and month(now()) >= day(dateVal) and month(dateVal) then
set age=year(now())-year(dateVal);
else
set age=(year(now())-year(dateVal)) - 1;
end if;
return age;
end
Is there anything i'm not considering in the function?
mysql sql
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
so i'm having some issues using a function in SQL where i calculate the age given a certain date. The thing is that i need to validate with the current date and the date of birth if it's already the year or not.
For example the date i have in a register is 1994-11-15 and when consulting the information with
select EmployeeID Num_Emloyee, concat(FirstName, " . ", LastName) Name_Employee, Title Puesto, fn_Age(BirthDate) Edad, fn_Age(HireDate) WorkYears
from employees;
It returns 24, however if i only consult with select the function it returns 23, the correct answer.
At the moment this is the function i'm using to validate the age is this:
create function fn_Age(dateVal date)
returns int
begin
declare age int;
if day(now()) and month(now()) >= day(dateVal) and month(dateVal) then
set age=year(now())-year(dateVal);
else
set age=(year(now())-year(dateVal)) - 1;
end if;
return age;
end
Is there anything i'm not considering in the function?
mysql sql
so i'm having some issues using a function in SQL where i calculate the age given a certain date. The thing is that i need to validate with the current date and the date of birth if it's already the year or not.
For example the date i have in a register is 1994-11-15 and when consulting the information with
select EmployeeID Num_Emloyee, concat(FirstName, " . ", LastName) Name_Employee, Title Puesto, fn_Age(BirthDate) Edad, fn_Age(HireDate) WorkYears
from employees;
It returns 24, however if i only consult with select the function it returns 23, the correct answer.
At the moment this is the function i'm using to validate the age is this:
create function fn_Age(dateVal date)
returns int
begin
declare age int;
if day(now()) and month(now()) >= day(dateVal) and month(dateVal) then
set age=year(now())-year(dateVal);
else
set age=(year(now())-year(dateVal)) - 1;
end if;
return age;
end
Is there anything i'm not considering in the function?
mysql sql
mysql sql
asked Nov 9 at 21:30
Space_Shift
436
436
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
day(now()) and month(now()) >= day(dateVal) and month(dateVal)
This logic doesn't make sense. I don't know if an if supports tuples in MySQL. If so, you can do:
(month(now()), date(now())) >= ( month(dateval), day(dateval) )
(this works in a MySQL WHERE clause.)
You can also do:
month(now()) * 100 date(now()) >= month(dateval) * 100 + day(dateval)
add a comment |
up vote
1
down vote
You can also use timestampdiff-function
select timestampdiff(year, '1994-11-15', now());
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
day(now()) and month(now()) >= day(dateVal) and month(dateVal)
This logic doesn't make sense. I don't know if an if supports tuples in MySQL. If so, you can do:
(month(now()), date(now())) >= ( month(dateval), day(dateval) )
(this works in a MySQL WHERE clause.)
You can also do:
month(now()) * 100 date(now()) >= month(dateval) * 100 + day(dateval)
add a comment |
up vote
1
down vote
day(now()) and month(now()) >= day(dateVal) and month(dateVal)
This logic doesn't make sense. I don't know if an if supports tuples in MySQL. If so, you can do:
(month(now()), date(now())) >= ( month(dateval), day(dateval) )
(this works in a MySQL WHERE clause.)
You can also do:
month(now()) * 100 date(now()) >= month(dateval) * 100 + day(dateval)
add a comment |
up vote
1
down vote
up vote
1
down vote
day(now()) and month(now()) >= day(dateVal) and month(dateVal)
This logic doesn't make sense. I don't know if an if supports tuples in MySQL. If so, you can do:
(month(now()), date(now())) >= ( month(dateval), day(dateval) )
(this works in a MySQL WHERE clause.)
You can also do:
month(now()) * 100 date(now()) >= month(dateval) * 100 + day(dateval)
day(now()) and month(now()) >= day(dateVal) and month(dateVal)
This logic doesn't make sense. I don't know if an if supports tuples in MySQL. If so, you can do:
(month(now()), date(now())) >= ( month(dateval), day(dateval) )
(this works in a MySQL WHERE clause.)
You can also do:
month(now()) * 100 date(now()) >= month(dateval) * 100 + day(dateval)
answered Nov 9 at 21:33
Gordon Linoff
745k32285390
745k32285390
add a comment |
add a comment |
up vote
1
down vote
You can also use timestampdiff-function
select timestampdiff(year, '1994-11-15', now());
add a comment |
up vote
1
down vote
You can also use timestampdiff-function
select timestampdiff(year, '1994-11-15', now());
add a comment |
up vote
1
down vote
up vote
1
down vote
You can also use timestampdiff-function
select timestampdiff(year, '1994-11-15', now());
You can also use timestampdiff-function
select timestampdiff(year, '1994-11-15', now());
answered Nov 9 at 22:01
slaakso
2,746818
2,746818
add a comment |
add a comment |
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