Validating age using a function in MySQL









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so i'm having some issues using a function in SQL where i calculate the age given a certain date. The thing is that i need to validate with the current date and the date of birth if it's already the year or not.



For example the date i have in a register is 1994-11-15 and when consulting the information with



select EmployeeID Num_Emloyee, concat(FirstName, " . ", LastName) Name_Employee, Title Puesto, fn_Age(BirthDate) Edad, fn_Age(HireDate) WorkYears
from employees;



It returns 24, however if i only consult with select the function it returns 23, the correct answer.



At the moment this is the function i'm using to validate the age is this:



create function fn_Age(dateVal date)
returns int
begin
declare age int;

if day(now()) and month(now()) >= day(dateVal) and month(dateVal) then
set age=year(now())-year(dateVal);
else
set age=(year(now())-year(dateVal)) - 1;
end if;

return age;
end


Is there anything i'm not considering in the function?










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    up vote
    0
    down vote

    favorite












    so i'm having some issues using a function in SQL where i calculate the age given a certain date. The thing is that i need to validate with the current date and the date of birth if it's already the year or not.



    For example the date i have in a register is 1994-11-15 and when consulting the information with



    select EmployeeID Num_Emloyee, concat(FirstName, " . ", LastName) Name_Employee, Title Puesto, fn_Age(BirthDate) Edad, fn_Age(HireDate) WorkYears
    from employees;



    It returns 24, however if i only consult with select the function it returns 23, the correct answer.



    At the moment this is the function i'm using to validate the age is this:



    create function fn_Age(dateVal date)
    returns int
    begin
    declare age int;

    if day(now()) and month(now()) >= day(dateVal) and month(dateVal) then
    set age=year(now())-year(dateVal);
    else
    set age=(year(now())-year(dateVal)) - 1;
    end if;

    return age;
    end


    Is there anything i'm not considering in the function?










    share|improve this question























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      so i'm having some issues using a function in SQL where i calculate the age given a certain date. The thing is that i need to validate with the current date and the date of birth if it's already the year or not.



      For example the date i have in a register is 1994-11-15 and when consulting the information with



      select EmployeeID Num_Emloyee, concat(FirstName, " . ", LastName) Name_Employee, Title Puesto, fn_Age(BirthDate) Edad, fn_Age(HireDate) WorkYears
      from employees;



      It returns 24, however if i only consult with select the function it returns 23, the correct answer.



      At the moment this is the function i'm using to validate the age is this:



      create function fn_Age(dateVal date)
      returns int
      begin
      declare age int;

      if day(now()) and month(now()) >= day(dateVal) and month(dateVal) then
      set age=year(now())-year(dateVal);
      else
      set age=(year(now())-year(dateVal)) - 1;
      end if;

      return age;
      end


      Is there anything i'm not considering in the function?










      share|improve this question













      so i'm having some issues using a function in SQL where i calculate the age given a certain date. The thing is that i need to validate with the current date and the date of birth if it's already the year or not.



      For example the date i have in a register is 1994-11-15 and when consulting the information with



      select EmployeeID Num_Emloyee, concat(FirstName, " . ", LastName) Name_Employee, Title Puesto, fn_Age(BirthDate) Edad, fn_Age(HireDate) WorkYears
      from employees;



      It returns 24, however if i only consult with select the function it returns 23, the correct answer.



      At the moment this is the function i'm using to validate the age is this:



      create function fn_Age(dateVal date)
      returns int
      begin
      declare age int;

      if day(now()) and month(now()) >= day(dateVal) and month(dateVal) then
      set age=year(now())-year(dateVal);
      else
      set age=(year(now())-year(dateVal)) - 1;
      end if;

      return age;
      end


      Is there anything i'm not considering in the function?







      mysql sql






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      share|improve this question











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      asked Nov 9 at 21:30









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          2 Answers
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          1
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          day(now()) and month(now()) >= day(dateVal) and month(dateVal)


          This logic doesn't make sense. I don't know if an if supports tuples in MySQL. If so, you can do:



          (month(now()), date(now())) >= ( month(dateval), day(dateval) )


          (this works in a MySQL WHERE clause.)



          You can also do:



          month(now()) * 100 date(now()) >= month(dateval) * 100 + day(dateval)





          share|improve this answer



























            up vote
            1
            down vote













            You can also use timestampdiff-function



            select timestampdiff(year, '1994-11-15', now());





            share|improve this answer




















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              up vote
              1
              down vote













              day(now()) and month(now()) >= day(dateVal) and month(dateVal)


              This logic doesn't make sense. I don't know if an if supports tuples in MySQL. If so, you can do:



              (month(now()), date(now())) >= ( month(dateval), day(dateval) )


              (this works in a MySQL WHERE clause.)



              You can also do:



              month(now()) * 100 date(now()) >= month(dateval) * 100 + day(dateval)





              share|improve this answer
























                up vote
                1
                down vote













                day(now()) and month(now()) >= day(dateVal) and month(dateVal)


                This logic doesn't make sense. I don't know if an if supports tuples in MySQL. If so, you can do:



                (month(now()), date(now())) >= ( month(dateval), day(dateval) )


                (this works in a MySQL WHERE clause.)



                You can also do:



                month(now()) * 100 date(now()) >= month(dateval) * 100 + day(dateval)





                share|improve this answer






















                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  day(now()) and month(now()) >= day(dateVal) and month(dateVal)


                  This logic doesn't make sense. I don't know if an if supports tuples in MySQL. If so, you can do:



                  (month(now()), date(now())) >= ( month(dateval), day(dateval) )


                  (this works in a MySQL WHERE clause.)



                  You can also do:



                  month(now()) * 100 date(now()) >= month(dateval) * 100 + day(dateval)





                  share|improve this answer












                  day(now()) and month(now()) >= day(dateVal) and month(dateVal)


                  This logic doesn't make sense. I don't know if an if supports tuples in MySQL. If so, you can do:



                  (month(now()), date(now())) >= ( month(dateval), day(dateval) )


                  (this works in a MySQL WHERE clause.)



                  You can also do:



                  month(now()) * 100 date(now()) >= month(dateval) * 100 + day(dateval)






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 9 at 21:33









                  Gordon Linoff

                  745k32285390




                  745k32285390






















                      up vote
                      1
                      down vote













                      You can also use timestampdiff-function



                      select timestampdiff(year, '1994-11-15', now());





                      share|improve this answer
























                        up vote
                        1
                        down vote













                        You can also use timestampdiff-function



                        select timestampdiff(year, '1994-11-15', now());





                        share|improve this answer






















                          up vote
                          1
                          down vote










                          up vote
                          1
                          down vote









                          You can also use timestampdiff-function



                          select timestampdiff(year, '1994-11-15', now());





                          share|improve this answer












                          You can also use timestampdiff-function



                          select timestampdiff(year, '1994-11-15', now());






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 9 at 22:01









                          slaakso

                          2,746818




                          2,746818



























                               

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