JQ Tree Show Only Selected Nodes With Their Parent On Button Click









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0
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I have to show only selected nodes and parents, and hide rest nodes when a button is clicked. Only nothing happens when I click the button.



The jsfiddle



http://jsfiddle.net/375emow0/



The code with commenting
start on button click

$('button[name="psychTree-selected"]').click( function(node)



get the selected nodes
nodesSelected = $('#psychTree').tree('getSelectedNodes');

create an array for shown nodes
nodeIdsToStay = ;

walk through selected nodes
nodesSelected.forEach( function(node)
var path = $('#psychTree').tree('getData');
path.forEach(function(n)
if (nodeIdsToStay.indexOf(n)===-1)
nodeIdsToStay.push(n);

)
)

hide the nodes not in the array
$('#psychTree').find('li').each( function()
if ( nodeIdsToStay.indexOf(this.id) === -1 )
$(this).hide();

)
)


I know how to hide the selected nodes but apparently non selected nodes do not have an identifiable class for me to search and hide by http://jsfiddle.net/tom1nkfr/



`$('button[name="psychTree-selected"]').click( function() `
`$('#psychTree').find('.jqtree-selected').each( function()`
`$(this).hide();`
`)`
`)`









share|improve this question























  • Do you have a specific question/error you're trying to resolve or are you hoping someone will do your work for you?
    – Snake14
    Nov 10 at 20:50














up vote
0
down vote

favorite












I have to show only selected nodes and parents, and hide rest nodes when a button is clicked. Only nothing happens when I click the button.



The jsfiddle



http://jsfiddle.net/375emow0/



The code with commenting
start on button click

$('button[name="psychTree-selected"]').click( function(node)



get the selected nodes
nodesSelected = $('#psychTree').tree('getSelectedNodes');

create an array for shown nodes
nodeIdsToStay = ;

walk through selected nodes
nodesSelected.forEach( function(node)
var path = $('#psychTree').tree('getData');
path.forEach(function(n)
if (nodeIdsToStay.indexOf(n)===-1)
nodeIdsToStay.push(n);

)
)

hide the nodes not in the array
$('#psychTree').find('li').each( function()
if ( nodeIdsToStay.indexOf(this.id) === -1 )
$(this).hide();

)
)


I know how to hide the selected nodes but apparently non selected nodes do not have an identifiable class for me to search and hide by http://jsfiddle.net/tom1nkfr/



`$('button[name="psychTree-selected"]').click( function() `
`$('#psychTree').find('.jqtree-selected').each( function()`
`$(this).hide();`
`)`
`)`









share|improve this question























  • Do you have a specific question/error you're trying to resolve or are you hoping someone will do your work for you?
    – Snake14
    Nov 10 at 20:50












up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have to show only selected nodes and parents, and hide rest nodes when a button is clicked. Only nothing happens when I click the button.



The jsfiddle



http://jsfiddle.net/375emow0/



The code with commenting
start on button click

$('button[name="psychTree-selected"]').click( function(node)



get the selected nodes
nodesSelected = $('#psychTree').tree('getSelectedNodes');

create an array for shown nodes
nodeIdsToStay = ;

walk through selected nodes
nodesSelected.forEach( function(node)
var path = $('#psychTree').tree('getData');
path.forEach(function(n)
if (nodeIdsToStay.indexOf(n)===-1)
nodeIdsToStay.push(n);

)
)

hide the nodes not in the array
$('#psychTree').find('li').each( function()
if ( nodeIdsToStay.indexOf(this.id) === -1 )
$(this).hide();

)
)


I know how to hide the selected nodes but apparently non selected nodes do not have an identifiable class for me to search and hide by http://jsfiddle.net/tom1nkfr/



`$('button[name="psychTree-selected"]').click( function() `
`$('#psychTree').find('.jqtree-selected').each( function()`
`$(this).hide();`
`)`
`)`









share|improve this question















I have to show only selected nodes and parents, and hide rest nodes when a button is clicked. Only nothing happens when I click the button.



The jsfiddle



http://jsfiddle.net/375emow0/



The code with commenting
start on button click

$('button[name="psychTree-selected"]').click( function(node)



get the selected nodes
nodesSelected = $('#psychTree').tree('getSelectedNodes');

create an array for shown nodes
nodeIdsToStay = ;

walk through selected nodes
nodesSelected.forEach( function(node)
var path = $('#psychTree').tree('getData');
path.forEach(function(n)
if (nodeIdsToStay.indexOf(n)===-1)
nodeIdsToStay.push(n);

)
)

hide the nodes not in the array
$('#psychTree').find('li').each( function()
if ( nodeIdsToStay.indexOf(this.id) === -1 )
$(this).hide();

)
)


I know how to hide the selected nodes but apparently non selected nodes do not have an identifiable class for me to search and hide by http://jsfiddle.net/tom1nkfr/



`$('button[name="psychTree-selected"]').click( function() `
`$('#psychTree').find('.jqtree-selected').each( function()`
`$(this).hide();`
`)`
`)`






jquery jqtree






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 10 at 21:57

























asked Nov 10 at 20:45









Chiemi Sayuri

32




32











  • Do you have a specific question/error you're trying to resolve or are you hoping someone will do your work for you?
    – Snake14
    Nov 10 at 20:50
















  • Do you have a specific question/error you're trying to resolve or are you hoping someone will do your work for you?
    – Snake14
    Nov 10 at 20:50















Do you have a specific question/error you're trying to resolve or are you hoping someone will do your work for you?
– Snake14
Nov 10 at 20:50




Do you have a specific question/error you're trying to resolve or are you hoping someone will do your work for you?
– Snake14
Nov 10 at 20:50












1 Answer
1






active

oldest

votes

















up vote
0
down vote



accepted










I'd recommend a simpler approach - it looks like you're trying to find all the nodes that are selected, push those into an array, then iterating over the entire jsTree and hiding any nodes not in the array you created. Instead, leverage the CSS classes that jsTree is already applying to selected nodes and just hide all those that don't have it.



Simplified JS:



$('button[name="psychTree-selected"]').click(function() 
$('#psychTree li.jqtree_common').each(function(index,elem)
if(!$(elem).hasClass('jqtree-folder') && !$(elem).hasClass('jqtree-selected'))
$(elem).hide();

);
)


Still triggered on your button click, but now it iterates through all the tree nodes and hides any that are (1) not selected and (2) not parent/folder nodes.



Working JSFiddle: http://jsfiddle.net/tbwjau5m/






share|improve this answer




















  • Wow thanks. I don't know why I didn't think of just using the classes. I mean I used the class to show only selected. I make things too complicated.
    – Chiemi Sayuri
    Nov 11 at 8:48










  • @ChiemiSayuri - great, glad to hear. If my answer suffices, please accept it.
    – Stevangelista
    Nov 11 at 14:57










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
0
down vote



accepted










I'd recommend a simpler approach - it looks like you're trying to find all the nodes that are selected, push those into an array, then iterating over the entire jsTree and hiding any nodes not in the array you created. Instead, leverage the CSS classes that jsTree is already applying to selected nodes and just hide all those that don't have it.



Simplified JS:



$('button[name="psychTree-selected"]').click(function() 
$('#psychTree li.jqtree_common').each(function(index,elem)
if(!$(elem).hasClass('jqtree-folder') && !$(elem).hasClass('jqtree-selected'))
$(elem).hide();

);
)


Still triggered on your button click, but now it iterates through all the tree nodes and hides any that are (1) not selected and (2) not parent/folder nodes.



Working JSFiddle: http://jsfiddle.net/tbwjau5m/






share|improve this answer




















  • Wow thanks. I don't know why I didn't think of just using the classes. I mean I used the class to show only selected. I make things too complicated.
    – Chiemi Sayuri
    Nov 11 at 8:48










  • @ChiemiSayuri - great, glad to hear. If my answer suffices, please accept it.
    – Stevangelista
    Nov 11 at 14:57














up vote
0
down vote



accepted










I'd recommend a simpler approach - it looks like you're trying to find all the nodes that are selected, push those into an array, then iterating over the entire jsTree and hiding any nodes not in the array you created. Instead, leverage the CSS classes that jsTree is already applying to selected nodes and just hide all those that don't have it.



Simplified JS:



$('button[name="psychTree-selected"]').click(function() 
$('#psychTree li.jqtree_common').each(function(index,elem)
if(!$(elem).hasClass('jqtree-folder') && !$(elem).hasClass('jqtree-selected'))
$(elem).hide();

);
)


Still triggered on your button click, but now it iterates through all the tree nodes and hides any that are (1) not selected and (2) not parent/folder nodes.



Working JSFiddle: http://jsfiddle.net/tbwjau5m/






share|improve this answer




















  • Wow thanks. I don't know why I didn't think of just using the classes. I mean I used the class to show only selected. I make things too complicated.
    – Chiemi Sayuri
    Nov 11 at 8:48










  • @ChiemiSayuri - great, glad to hear. If my answer suffices, please accept it.
    – Stevangelista
    Nov 11 at 14:57












up vote
0
down vote



accepted







up vote
0
down vote



accepted






I'd recommend a simpler approach - it looks like you're trying to find all the nodes that are selected, push those into an array, then iterating over the entire jsTree and hiding any nodes not in the array you created. Instead, leverage the CSS classes that jsTree is already applying to selected nodes and just hide all those that don't have it.



Simplified JS:



$('button[name="psychTree-selected"]').click(function() 
$('#psychTree li.jqtree_common').each(function(index,elem)
if(!$(elem).hasClass('jqtree-folder') && !$(elem).hasClass('jqtree-selected'))
$(elem).hide();

);
)


Still triggered on your button click, but now it iterates through all the tree nodes and hides any that are (1) not selected and (2) not parent/folder nodes.



Working JSFiddle: http://jsfiddle.net/tbwjau5m/






share|improve this answer












I'd recommend a simpler approach - it looks like you're trying to find all the nodes that are selected, push those into an array, then iterating over the entire jsTree and hiding any nodes not in the array you created. Instead, leverage the CSS classes that jsTree is already applying to selected nodes and just hide all those that don't have it.



Simplified JS:



$('button[name="psychTree-selected"]').click(function() 
$('#psychTree li.jqtree_common').each(function(index,elem)
if(!$(elem).hasClass('jqtree-folder') && !$(elem).hasClass('jqtree-selected'))
$(elem).hide();

);
)


Still triggered on your button click, but now it iterates through all the tree nodes and hides any that are (1) not selected and (2) not parent/folder nodes.



Working JSFiddle: http://jsfiddle.net/tbwjau5m/







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 11 at 0:20









Stevangelista

1,6291615




1,6291615











  • Wow thanks. I don't know why I didn't think of just using the classes. I mean I used the class to show only selected. I make things too complicated.
    – Chiemi Sayuri
    Nov 11 at 8:48










  • @ChiemiSayuri - great, glad to hear. If my answer suffices, please accept it.
    – Stevangelista
    Nov 11 at 14:57
















  • Wow thanks. I don't know why I didn't think of just using the classes. I mean I used the class to show only selected. I make things too complicated.
    – Chiemi Sayuri
    Nov 11 at 8:48










  • @ChiemiSayuri - great, glad to hear. If my answer suffices, please accept it.
    – Stevangelista
    Nov 11 at 14:57















Wow thanks. I don't know why I didn't think of just using the classes. I mean I used the class to show only selected. I make things too complicated.
– Chiemi Sayuri
Nov 11 at 8:48




Wow thanks. I don't know why I didn't think of just using the classes. I mean I used the class to show only selected. I make things too complicated.
– Chiemi Sayuri
Nov 11 at 8:48












@ChiemiSayuri - great, glad to hear. If my answer suffices, please accept it.
– Stevangelista
Nov 11 at 14:57




@ChiemiSayuri - great, glad to hear. If my answer suffices, please accept it.
– Stevangelista
Nov 11 at 14:57

















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