Bash add regex values to an array










0















I am trying to write a bash script that will take in a file and look for all values matching a regular expression, and then add those to an array.



As a first step, I wrote a script that adds all lines in the log file to an array, and echoes them. Then, I tried editing that script to search for the regular expression in the log file, which is where I got a tremendous amount of errors.



What I am trying to do is grab the value inside the brackets of the log file. Some lines in the log file contain a syntax like [23423234 s] which is a time stamp. I want to grab the values (digits, space, and the "s") inside the brackets( but not the brackets!) and add those values to an array.



My initial script is below:



#!/bin/bash

echo "STARTING SCRIPT"

getArray()
array=()
while IFS= read -r line
do
array+=("$line")
done <"$1"


getArray "testlog.txt"
for e in "$array[@]"
do
echo "$e"
done

echo "DONE SCRIPT"


The log I am looking at looks like this:



[1542053213 s] Starting Program:
-----------------------------------------
[1542053213 s] PROGRAM ERROR
ERRHAND: 1033
ERRHAND: 233545
ERRHAND: 1
[1542053213 s] Program completed!

[1542053213 s] Config File complete. Stopping!


What I am aiming to do is do something with the following pseudocode:



For each line in file
regex = [dws]


if line matches regex
add to array



for each item in array
echo item



Currently, I have edited my script to look like below:



#!/bin/bash

echo "STARTING SCRIPT"

getArray()
array=()
while IFS= read -r line
do
if [[$line =~ [dws]; then
array+=("$line");
fi
done <"$1"


getArray "log.txt"
for e in "$array[@]"
do
echo "$e"
done

echo "DONE SCRIPT"


But whenever I run it, I get the following set of errors:



[jm@local Home]$ ./Parser.sh 
STARTING SCRIPT
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[-----------------------------------------: command not found
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[: command not found
./Parser.sh: line 9: [[[1542053213: command not found
DONE SCRIPT


Any advice would be greatly appreciated. I have tried looking at other posts but none have been able to really address my problem, which is creating a proper regex for the [2342323 s] pattern, and then adding that to an array. TiA










share|improve this question
























  • if [[$line =~ [dws]; then should be: if [[ $line =~ [a-zA-Z0-9_s] ]]; then

    – anubhava
    Nov 13 '18 at 21:54











  • Hi @anubhava, thank you for the answer. I think you noticed I did miss my closing brackets, but that regular expression returns every line, not just the values enclosed within the brackets.

    – Jerry M.
    Nov 13 '18 at 21:57











  • Yes I knew that regex is wrong but it is equivalent of what you used [dws]. I need more details from you about regex to suggest you the correct one.

    – anubhava
    Nov 13 '18 at 22:00











  • Is sed -En '/[[0-9]+ s]/ s/^.*[([0-9]+ s)].*/1/; p; ' log useful, or do you need it to be a bash script?

    – Paul Hodges
    Nov 13 '18 at 22:00












  • Please read the description of tags before applying them. The "linux" tag was wrong here.

    – Ulrich Eckhardt
    Nov 13 '18 at 22:05















0















I am trying to write a bash script that will take in a file and look for all values matching a regular expression, and then add those to an array.



As a first step, I wrote a script that adds all lines in the log file to an array, and echoes them. Then, I tried editing that script to search for the regular expression in the log file, which is where I got a tremendous amount of errors.



What I am trying to do is grab the value inside the brackets of the log file. Some lines in the log file contain a syntax like [23423234 s] which is a time stamp. I want to grab the values (digits, space, and the "s") inside the brackets( but not the brackets!) and add those values to an array.



My initial script is below:



#!/bin/bash

echo "STARTING SCRIPT"

getArray()
array=()
while IFS= read -r line
do
array+=("$line")
done <"$1"


getArray "testlog.txt"
for e in "$array[@]"
do
echo "$e"
done

echo "DONE SCRIPT"


The log I am looking at looks like this:



[1542053213 s] Starting Program:
-----------------------------------------
[1542053213 s] PROGRAM ERROR
ERRHAND: 1033
ERRHAND: 233545
ERRHAND: 1
[1542053213 s] Program completed!

[1542053213 s] Config File complete. Stopping!


What I am aiming to do is do something with the following pseudocode:



For each line in file
regex = [dws]


if line matches regex
add to array



for each item in array
echo item



Currently, I have edited my script to look like below:



#!/bin/bash

echo "STARTING SCRIPT"

getArray()
array=()
while IFS= read -r line
do
if [[$line =~ [dws]; then
array+=("$line");
fi
done <"$1"


getArray "log.txt"
for e in "$array[@]"
do
echo "$e"
done

echo "DONE SCRIPT"


But whenever I run it, I get the following set of errors:



[jm@local Home]$ ./Parser.sh 
STARTING SCRIPT
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[-----------------------------------------: command not found
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[: command not found
./Parser.sh: line 9: [[[1542053213: command not found
DONE SCRIPT


Any advice would be greatly appreciated. I have tried looking at other posts but none have been able to really address my problem, which is creating a proper regex for the [2342323 s] pattern, and then adding that to an array. TiA










share|improve this question
























  • if [[$line =~ [dws]; then should be: if [[ $line =~ [a-zA-Z0-9_s] ]]; then

    – anubhava
    Nov 13 '18 at 21:54











  • Hi @anubhava, thank you for the answer. I think you noticed I did miss my closing brackets, but that regular expression returns every line, not just the values enclosed within the brackets.

    – Jerry M.
    Nov 13 '18 at 21:57











  • Yes I knew that regex is wrong but it is equivalent of what you used [dws]. I need more details from you about regex to suggest you the correct one.

    – anubhava
    Nov 13 '18 at 22:00











  • Is sed -En '/[[0-9]+ s]/ s/^.*[([0-9]+ s)].*/1/; p; ' log useful, or do you need it to be a bash script?

    – Paul Hodges
    Nov 13 '18 at 22:00












  • Please read the description of tags before applying them. The "linux" tag was wrong here.

    – Ulrich Eckhardt
    Nov 13 '18 at 22:05













0












0








0








I am trying to write a bash script that will take in a file and look for all values matching a regular expression, and then add those to an array.



As a first step, I wrote a script that adds all lines in the log file to an array, and echoes them. Then, I tried editing that script to search for the regular expression in the log file, which is where I got a tremendous amount of errors.



What I am trying to do is grab the value inside the brackets of the log file. Some lines in the log file contain a syntax like [23423234 s] which is a time stamp. I want to grab the values (digits, space, and the "s") inside the brackets( but not the brackets!) and add those values to an array.



My initial script is below:



#!/bin/bash

echo "STARTING SCRIPT"

getArray()
array=()
while IFS= read -r line
do
array+=("$line")
done <"$1"


getArray "testlog.txt"
for e in "$array[@]"
do
echo "$e"
done

echo "DONE SCRIPT"


The log I am looking at looks like this:



[1542053213 s] Starting Program:
-----------------------------------------
[1542053213 s] PROGRAM ERROR
ERRHAND: 1033
ERRHAND: 233545
ERRHAND: 1
[1542053213 s] Program completed!

[1542053213 s] Config File complete. Stopping!


What I am aiming to do is do something with the following pseudocode:



For each line in file
regex = [dws]


if line matches regex
add to array



for each item in array
echo item



Currently, I have edited my script to look like below:



#!/bin/bash

echo "STARTING SCRIPT"

getArray()
array=()
while IFS= read -r line
do
if [[$line =~ [dws]; then
array+=("$line");
fi
done <"$1"


getArray "log.txt"
for e in "$array[@]"
do
echo "$e"
done

echo "DONE SCRIPT"


But whenever I run it, I get the following set of errors:



[jm@local Home]$ ./Parser.sh 
STARTING SCRIPT
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[-----------------------------------------: command not found
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[: command not found
./Parser.sh: line 9: [[[1542053213: command not found
DONE SCRIPT


Any advice would be greatly appreciated. I have tried looking at other posts but none have been able to really address my problem, which is creating a proper regex for the [2342323 s] pattern, and then adding that to an array. TiA










share|improve this question
















I am trying to write a bash script that will take in a file and look for all values matching a regular expression, and then add those to an array.



As a first step, I wrote a script that adds all lines in the log file to an array, and echoes them. Then, I tried editing that script to search for the regular expression in the log file, which is where I got a tremendous amount of errors.



What I am trying to do is grab the value inside the brackets of the log file. Some lines in the log file contain a syntax like [23423234 s] which is a time stamp. I want to grab the values (digits, space, and the "s") inside the brackets( but not the brackets!) and add those values to an array.



My initial script is below:



#!/bin/bash

echo "STARTING SCRIPT"

getArray()
array=()
while IFS= read -r line
do
array+=("$line")
done <"$1"


getArray "testlog.txt"
for e in "$array[@]"
do
echo "$e"
done

echo "DONE SCRIPT"


The log I am looking at looks like this:



[1542053213 s] Starting Program:
-----------------------------------------
[1542053213 s] PROGRAM ERROR
ERRHAND: 1033
ERRHAND: 233545
ERRHAND: 1
[1542053213 s] Program completed!

[1542053213 s] Config File complete. Stopping!


What I am aiming to do is do something with the following pseudocode:



For each line in file
regex = [dws]


if line matches regex
add to array



for each item in array
echo item



Currently, I have edited my script to look like below:



#!/bin/bash

echo "STARTING SCRIPT"

getArray()
array=()
while IFS= read -r line
do
if [[$line =~ [dws]; then
array+=("$line");
fi
done <"$1"


getArray "log.txt"
for e in "$array[@]"
do
echo "$e"
done

echo "DONE SCRIPT"


But whenever I run it, I get the following set of errors:



[jm@local Home]$ ./Parser.sh 
STARTING SCRIPT
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[-----------------------------------------: command not found
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[: command not found
./Parser.sh: line 9: [[[1542053213: command not found
DONE SCRIPT


Any advice would be greatly appreciated. I have tried looking at other posts but none have been able to really address my problem, which is creating a proper regex for the [2342323 s] pattern, and then adding that to an array. TiA







regex bash shell






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 22:04









Ulrich Eckhardt

12.7k11737




12.7k11737










asked Nov 13 '18 at 21:51









Jerry M.Jerry M.

6361622




6361622












  • if [[$line =~ [dws]; then should be: if [[ $line =~ [a-zA-Z0-9_s] ]]; then

    – anubhava
    Nov 13 '18 at 21:54











  • Hi @anubhava, thank you for the answer. I think you noticed I did miss my closing brackets, but that regular expression returns every line, not just the values enclosed within the brackets.

    – Jerry M.
    Nov 13 '18 at 21:57











  • Yes I knew that regex is wrong but it is equivalent of what you used [dws]. I need more details from you about regex to suggest you the correct one.

    – anubhava
    Nov 13 '18 at 22:00











  • Is sed -En '/[[0-9]+ s]/ s/^.*[([0-9]+ s)].*/1/; p; ' log useful, or do you need it to be a bash script?

    – Paul Hodges
    Nov 13 '18 at 22:00












  • Please read the description of tags before applying them. The "linux" tag was wrong here.

    – Ulrich Eckhardt
    Nov 13 '18 at 22:05

















  • if [[$line =~ [dws]; then should be: if [[ $line =~ [a-zA-Z0-9_s] ]]; then

    – anubhava
    Nov 13 '18 at 21:54











  • Hi @anubhava, thank you for the answer. I think you noticed I did miss my closing brackets, but that regular expression returns every line, not just the values enclosed within the brackets.

    – Jerry M.
    Nov 13 '18 at 21:57











  • Yes I knew that regex is wrong but it is equivalent of what you used [dws]. I need more details from you about regex to suggest you the correct one.

    – anubhava
    Nov 13 '18 at 22:00











  • Is sed -En '/[[0-9]+ s]/ s/^.*[([0-9]+ s)].*/1/; p; ' log useful, or do you need it to be a bash script?

    – Paul Hodges
    Nov 13 '18 at 22:00












  • Please read the description of tags before applying them. The "linux" tag was wrong here.

    – Ulrich Eckhardt
    Nov 13 '18 at 22:05
















if [[$line =~ [dws]; then should be: if [[ $line =~ [a-zA-Z0-9_s] ]]; then

– anubhava
Nov 13 '18 at 21:54





if [[$line =~ [dws]; then should be: if [[ $line =~ [a-zA-Z0-9_s] ]]; then

– anubhava
Nov 13 '18 at 21:54













Hi @anubhava, thank you for the answer. I think you noticed I did miss my closing brackets, but that regular expression returns every line, not just the values enclosed within the brackets.

– Jerry M.
Nov 13 '18 at 21:57





Hi @anubhava, thank you for the answer. I think you noticed I did miss my closing brackets, but that regular expression returns every line, not just the values enclosed within the brackets.

– Jerry M.
Nov 13 '18 at 21:57













Yes I knew that regex is wrong but it is equivalent of what you used [dws]. I need more details from you about regex to suggest you the correct one.

– anubhava
Nov 13 '18 at 22:00





Yes I knew that regex is wrong but it is equivalent of what you used [dws]. I need more details from you about regex to suggest you the correct one.

– anubhava
Nov 13 '18 at 22:00













Is sed -En '/[[0-9]+ s]/ s/^.*[([0-9]+ s)].*/1/; p; ' log useful, or do you need it to be a bash script?

– Paul Hodges
Nov 13 '18 at 22:00






Is sed -En '/[[0-9]+ s]/ s/^.*[([0-9]+ s)].*/1/; p; ' log useful, or do you need it to be a bash script?

– Paul Hodges
Nov 13 '18 at 22:00














Please read the description of tags before applying them. The "linux" tag was wrong here.

– Ulrich Eckhardt
Nov 13 '18 at 22:05





Please read the description of tags before applying them. The "linux" tag was wrong here.

– Ulrich Eckhardt
Nov 13 '18 at 22:05












1 Answer
1






active

oldest

votes


















3














As pointed out in the comments




  • if [[ is missing its closing ]].

  • In a regex [ is not a literal, but starts a character group. To match something like [1234 s] you have to write [[0-9]* s].

To extract just the number 1234 from [1234 s] you can use tr, sed, perl -P, or a second grep -o.



Overall, your script seems way too complicated. You can drastically simplify it. Replace the for loop by mapfile and use grep -o to extract matches. You can replace your whole script with this



mapfile -t array < <(grep -o '[[0-9]* s]' logfile | tr -d ' s')
printf '%sn' "$array[@]"


Note that if you only want to print the matches then you don't need an array. Just the grep part would be sufficient:



grep -o '[[0-9]* s]' logfile | tr -d ' s'





share|improve this answer

























  • Hi @Socowi I appreciate your response. This solves my problem. Thank you.

    – Jerry M.
    Nov 13 '18 at 22:27











  • If I wanted to just get the numbers, and not the space and 's', might you have advice on how to edit the given regex to match that condition (this is more for my personal learning)

    – Jerry M.
    Nov 13 '18 at 22:28











  • @JerryM. Glad I could help. I edited the answer such that only the numbers are extracted.

    – Socowi
    Nov 14 '18 at 11:20










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














As pointed out in the comments




  • if [[ is missing its closing ]].

  • In a regex [ is not a literal, but starts a character group. To match something like [1234 s] you have to write [[0-9]* s].

To extract just the number 1234 from [1234 s] you can use tr, sed, perl -P, or a second grep -o.



Overall, your script seems way too complicated. You can drastically simplify it. Replace the for loop by mapfile and use grep -o to extract matches. You can replace your whole script with this



mapfile -t array < <(grep -o '[[0-9]* s]' logfile | tr -d ' s')
printf '%sn' "$array[@]"


Note that if you only want to print the matches then you don't need an array. Just the grep part would be sufficient:



grep -o '[[0-9]* s]' logfile | tr -d ' s'





share|improve this answer

























  • Hi @Socowi I appreciate your response. This solves my problem. Thank you.

    – Jerry M.
    Nov 13 '18 at 22:27











  • If I wanted to just get the numbers, and not the space and 's', might you have advice on how to edit the given regex to match that condition (this is more for my personal learning)

    – Jerry M.
    Nov 13 '18 at 22:28











  • @JerryM. Glad I could help. I edited the answer such that only the numbers are extracted.

    – Socowi
    Nov 14 '18 at 11:20















3














As pointed out in the comments




  • if [[ is missing its closing ]].

  • In a regex [ is not a literal, but starts a character group. To match something like [1234 s] you have to write [[0-9]* s].

To extract just the number 1234 from [1234 s] you can use tr, sed, perl -P, or a second grep -o.



Overall, your script seems way too complicated. You can drastically simplify it. Replace the for loop by mapfile and use grep -o to extract matches. You can replace your whole script with this



mapfile -t array < <(grep -o '[[0-9]* s]' logfile | tr -d ' s')
printf '%sn' "$array[@]"


Note that if you only want to print the matches then you don't need an array. Just the grep part would be sufficient:



grep -o '[[0-9]* s]' logfile | tr -d ' s'





share|improve this answer

























  • Hi @Socowi I appreciate your response. This solves my problem. Thank you.

    – Jerry M.
    Nov 13 '18 at 22:27











  • If I wanted to just get the numbers, and not the space and 's', might you have advice on how to edit the given regex to match that condition (this is more for my personal learning)

    – Jerry M.
    Nov 13 '18 at 22:28











  • @JerryM. Glad I could help. I edited the answer such that only the numbers are extracted.

    – Socowi
    Nov 14 '18 at 11:20













3












3








3







As pointed out in the comments




  • if [[ is missing its closing ]].

  • In a regex [ is not a literal, but starts a character group. To match something like [1234 s] you have to write [[0-9]* s].

To extract just the number 1234 from [1234 s] you can use tr, sed, perl -P, or a second grep -o.



Overall, your script seems way too complicated. You can drastically simplify it. Replace the for loop by mapfile and use grep -o to extract matches. You can replace your whole script with this



mapfile -t array < <(grep -o '[[0-9]* s]' logfile | tr -d ' s')
printf '%sn' "$array[@]"


Note that if you only want to print the matches then you don't need an array. Just the grep part would be sufficient:



grep -o '[[0-9]* s]' logfile | tr -d ' s'





share|improve this answer















As pointed out in the comments




  • if [[ is missing its closing ]].

  • In a regex [ is not a literal, but starts a character group. To match something like [1234 s] you have to write [[0-9]* s].

To extract just the number 1234 from [1234 s] you can use tr, sed, perl -P, or a second grep -o.



Overall, your script seems way too complicated. You can drastically simplify it. Replace the for loop by mapfile and use grep -o to extract matches. You can replace your whole script with this



mapfile -t array < <(grep -o '[[0-9]* s]' logfile | tr -d ' s')
printf '%sn' "$array[@]"


Note that if you only want to print the matches then you don't need an array. Just the grep part would be sufficient:



grep -o '[[0-9]* s]' logfile | tr -d ' s'






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 14 '18 at 11:19

























answered Nov 13 '18 at 22:00









SocowiSocowi

6,8072725




6,8072725












  • Hi @Socowi I appreciate your response. This solves my problem. Thank you.

    – Jerry M.
    Nov 13 '18 at 22:27











  • If I wanted to just get the numbers, and not the space and 's', might you have advice on how to edit the given regex to match that condition (this is more for my personal learning)

    – Jerry M.
    Nov 13 '18 at 22:28











  • @JerryM. Glad I could help. I edited the answer such that only the numbers are extracted.

    – Socowi
    Nov 14 '18 at 11:20

















  • Hi @Socowi I appreciate your response. This solves my problem. Thank you.

    – Jerry M.
    Nov 13 '18 at 22:27











  • If I wanted to just get the numbers, and not the space and 's', might you have advice on how to edit the given regex to match that condition (this is more for my personal learning)

    – Jerry M.
    Nov 13 '18 at 22:28











  • @JerryM. Glad I could help. I edited the answer such that only the numbers are extracted.

    – Socowi
    Nov 14 '18 at 11:20
















Hi @Socowi I appreciate your response. This solves my problem. Thank you.

– Jerry M.
Nov 13 '18 at 22:27





Hi @Socowi I appreciate your response. This solves my problem. Thank you.

– Jerry M.
Nov 13 '18 at 22:27













If I wanted to just get the numbers, and not the space and 's', might you have advice on how to edit the given regex to match that condition (this is more for my personal learning)

– Jerry M.
Nov 13 '18 at 22:28





If I wanted to just get the numbers, and not the space and 's', might you have advice on how to edit the given regex to match that condition (this is more for my personal learning)

– Jerry M.
Nov 13 '18 at 22:28













@JerryM. Glad I could help. I edited the answer such that only the numbers are extracted.

– Socowi
Nov 14 '18 at 11:20





@JerryM. Glad I could help. I edited the answer such that only the numbers are extracted.

– Socowi
Nov 14 '18 at 11:20



















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