Flask+nginx+uwsgi: only serve url with nginx if flask doesn't have a route for it
nginx config for the server (the main nginx one is the default one on debian 9):
server
listen 80;
server_name subdomain.domain.com;
include /etc/nginx/mime.types;
location /galleries
autoindex on;
alias /srv/galleries/;
location /
include uwsgi_params;
uwsgi_pass unix:/tmp/scraper.sock;
uwsgi config:
[uwsgi]
module = wsgi:app
master = true
processes = 5
socket = /tmp/scraper.sock
chmod-socket = 777
uid = www-data
gid = www-data
vacuum = true
die-on-term = true
plugins = python3
py-autoreload = 1
If I try creating a route for /galleries/whatever, ie like this:
@app.route("/galleries/whatever")
def test():
return "Hello"
I'll just see the indexed files inside /galleries/whatever through nginx instead of going through flask.
Is there a way for me to force nginx to only handle requests if flask returns 404? Alternatively, is there a better way for me to serve files while still having them available under those urls? Keep in mind the /galleries folder is pretty big and generated by another program.
I run the server with "uwsgi --ini server.ini" and nothing else.
python nginx flask uwsgi
asked Nov 13 '18 at 21:52
msaba92msaba92
187110
add a comment |
nginx config for the server (the main nginx one is the default one on debian 9):
server
listen 80;
server_name subdomain.domain.com;
include /etc/nginx/mime.types;
location /galleries
autoindex on;
alias /srv/galleries/;
location /
include uwsgi_params;
uwsgi_pass unix:/tmp/scraper.sock;
uwsgi config:
[uwsgi]
module = wsgi:app
master = true
processes = 5
socket = /tmp/scraper.sock
chmod-socket = 777
uid = www-data
gid = www-data
vacuum = true
die-on-term = true
plugins = python3
py-autoreload = 1
If I try creating a route for /galleries/whatever, ie like this:
@app.route("/galleries/whatever")
def test():
return "Hello"
I'll just see the indexed files inside /galleries/whatever through nginx instead of going through flask.
Is there a way for me to force nginx to only handle requests if flask returns 404? Alternatively, is there a better way for me to serve files while still having them available under those urls? Keep in mind the /galleries folder is pretty big and generated by another program.
I run the server with "uwsgi --ini server.ini" and nothing else.
python nginx flask uwsgi
asked Nov 13 '18 at 21:52
msaba92msaba92
187110
Maybe using a subdomain name is an idea to overcome this problem?
– Peshmerge
Nov 14 '18 at 15:00
You mean using a subdomain specifically for the files, having the rest of the path be identical to flask's routes? That's an option, but I was hoping on some simpler solution - I'd like to make my app portable rather than relying on configuring subdomains every time.
– msaba92
Nov 14 '18 at 15:44
add a comment |
nginx config for the server (the main nginx one is the default one on debian 9):
server
listen 80;
server_name subdomain.domain.com;
include /etc/nginx/mime.types;
location /galleries
autoindex on;
alias /srv/galleries/;
location /
include uwsgi_params;
uwsgi_pass unix:/tmp/scraper.sock;
uwsgi config:
[uwsgi]
module = wsgi:app
master = true
processes = 5
socket = /tmp/scraper.sock
chmod-socket = 777
uid = www-data
gid = www-data
vacuum = true
die-on-term = true
plugins = python3
py-autoreload = 1
If I try creating a route for /galleries/whatever, ie like this:
@app.route("/galleries/whatever")
def test():
return "Hello"
I'll just see the indexed files inside /galleries/whatever through nginx instead of going through flask.
Is there a way for me to force nginx to only handle requests if flask returns 404? Alternatively, is there a better way for me to serve files while still having them available under those urls? Keep in mind the /galleries folder is pretty big and generated by another program.
I run the server with "uwsgi --ini server.ini" and nothing else.
python nginx flask uwsgi
asked Nov 13 '18 at 21:52
msaba92msaba92
187110
nginx config for the server (the main nginx one is the default one on debian 9):
server
listen 80;
server_name subdomain.domain.com;
include /etc/nginx/mime.types;
location /galleries
autoindex on;
alias /srv/galleries/;
location /
include uwsgi_params;
uwsgi_pass unix:/tmp/scraper.sock;
uwsgi config:
[uwsgi]
module = wsgi:app
master = true
processes = 5
socket = /tmp/scraper.sock
chmod-socket = 777
uid = www-data
gid = www-data
vacuum = true
die-on-term = true
plugins = python3
py-autoreload = 1
If I try creating a route for /galleries/whatever, ie like this:
@app.route("/galleries/whatever")
def test():
return "Hello"
I'll just see the indexed files inside /galleries/whatever through nginx instead of going through flask.
Is there a way for me to force nginx to only handle requests if flask returns 404? Alternatively, is there a better way for me to serve files while still having them available under those urls? Keep in mind the /galleries folder is pretty big and generated by another program.
I run the server with "uwsgi --ini server.ini" and nothing else.
python nginx flask uwsgi
python nginx flask uwsgi
asked Nov 13 '18 at 21:52
msaba92msaba92
187110
asked Nov 13 '18 at 21:52
msaba92msaba92
187110
asked Nov 13 '18 at 21:52
msaba92msaba92
187110
asked Nov 13 '18 at 21:52
msaba92msaba92
187110
asked Nov 13 '18 at 21:52
msaba92msaba92
187110
187110
Maybe using a subdomain name is an idea to overcome this problem?
– Peshmerge
Nov 14 '18 at 15:00
You mean using a subdomain specifically for the files, having the rest of the path be identical to flask's routes? That's an option, but I was hoping on some simpler solution - I'd like to make my app portable rather than relying on configuring subdomains every time.
– msaba92
Nov 14 '18 at 15:44
add a comment |
Maybe using a subdomain name is an idea to overcome this problem?
– Peshmerge
Nov 14 '18 at 15:00
You mean using a subdomain specifically for the files, having the rest of the path be identical to flask's routes? That's an option, but I was hoping on some simpler solution - I'd like to make my app portable rather than relying on configuring subdomains every time.
– msaba92
Nov 14 '18 at 15:44
Maybe using a subdomain name is an idea to overcome this problem?
– Peshmerge
Nov 14 '18 at 15:00
Maybe using a subdomain name is an idea to overcome this problem?
– Peshmerge
Nov 14 '18 at 15:00
You mean using a subdomain specifically for the files, having the rest of the path be identical to flask's routes? That's an option, but I was hoping on some simpler solution - I'd like to make my app portable rather than relying on configuring subdomains every time.
– msaba92
Nov 14 '18 at 15:44
You mean using a subdomain specifically for the files, having the rest of the path be identical to flask's routes? That's an option, but I was hoping on some simpler solution - I'd like to make my app portable rather than relying on configuring subdomains every time.
– msaba92
Nov 14 '18 at 15:44
add a comment |
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Maybe using a subdomain name is an idea to overcome this problem?
– Peshmerge
Nov 14 '18 at 15:00
You mean using a subdomain specifically for the files, having the rest of the path be identical to flask's routes? That's an option, but I was hoping on some simpler solution - I'd like to make my app portable rather than relying on configuring subdomains every time.
– msaba92
Nov 14 '18 at 15:44